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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2852. |
The massof oneC atomis : |
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Answer» `6.023xx 10^(23) G ` 1 atomof C=`(6.023 xx 10 ^(23) xx6 )/(44 )` `=1.99 xx 10 ^(-23)` |
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| 2853. |
The mass of magnesium oxide formed by burning 1.216 g magnesium in excess oxygen is |
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Answer» 0.416 G `2 xx 24g Mg to 2 xx (24 + 16)` `48 Mg to 80 g MgO` ` therefore 1.216 g Mgto 80/48 xx 1.216` ` = 2.02 g MgO` |
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| 2854. |
The mass of macroscopicmaterialsis litre . |
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| 2855. |
The massof macroscopicmaterialsare mesuredin _________ or______. |
| Answer» SOLUTION :GRAMS , KILOGRAM | |
| 2856. |
The massof anatomis measured in ________. |
| Answer» SOLUTION :atomicmassunit | |
| 2857. |
The mass of anatomis concentratedin a smallregionof spacecalledthe _______. |
| Answer» SOLUTION :NUCLEUS | |
| 2859. |
The marble statue often slowly correded when kept in open for a long time. Assign a suitable explanation. |
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Answer» Solution : `SO_(2), NO_(2)` gases are RELEASED into the atmosphere from various sources. These dissolve in rain water to give acid which CORRODE marble status. `2SO_(2)+O_(2) to 2SO_(3),H_(2)O+SO_(3) to H_(2)SO_(4)` `2NO_(2)+H_(2)O to 2HNO_(3)` `CaCO_(3)+H_(2)SO_(4) to CaSO_(4)+H_(2)O+CO_(2)` `CaCO_(3)+2HNO_(3) to Ca(NO_(3))_(2)+H_(2)O+CO_(2)` |
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| 2860. |
The major ill effect of mono culture practice in forests is on the |
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Answer» BIODIVERSITY which faces large destruction. |
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| 2861. |
The main raw materials required for the manufacture of portland cement are |
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Answer» limestone and clay |
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| 2862. |
The main constituent of vinegar is ___ (ethanol/ethanoic acid) |
| Answer» SOLUTION : ETHANOIC ACID | |
| 2863. |
The main constituents of cement are : |
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Answer» CALCIUM oxide, SILICON dioxide, ALUMINIUM oxide |
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| 2865. |
The main aim of chipko mobement was to conserve |
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Answer» SOIL |
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| 2866. |
The magnification produced by a plane mirror is +1. What does this means. An object is placed at a distance of 10cm from a convex mirror of focal length 15cm .Find the position and nature of the image. |
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Answer» Solution :The positive, sign means IMAGE FORMED by a plane mirror is virtual and erect since the MAGNIFICATION is 1. It means that the size of the image is equal to the size of the object. Focal length of convex mirror, f=+15cm. Object distance, u = -10 cm According to the mirror formula ` rArr 1/v = 1/f - 1/u` ` rArr 1/v = (2 + 3)/(30)` ` rArr 1/v = 5/30` ` rArr 6cm ` Magnification ` = - v/u = (-6)/(-10) = 0.6` The image is located at the distance 6 cm from the mirror on the other SIDE of the mirror. The positive sign and value less than 1 of the magnification indicates that the image formed virtual and erect and diminished. |
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| 2867. |
The loss of water of crystallization to the atmosphere by a compound is termed |
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Answer» DELIQUESCENCE |
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| 2868. |
The longest period in the Modern Periodic Table is the |
| Answer» Answer :D | |
| 2869. |
The long form of periodic table is based upon the …………. Of elements . |
| Answer» SOLUTION :ELECTRONIC CONFIGURATION | |
| 2870. |
The longform of periodic table consists of horizontal rows called group and vertical columncalled period |
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| 2871. |
The liquid with maximum viscosity is |
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Answer» water |
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| 2872. |
The lesser covalency of FeCl_(2) over FeCl_(3) is due to |
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Answer» LOWER POLARIZING POWER of `Fe^(+2)`than that of `Fe^(+3)` ion |
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| 2873. |
The law used by Newlands' to arrange elements is known as _________ . |
| Answer» SOLUTION :NEWLANDS. LAW of OCTAVES | |
| 2874. |
The law of triads is applicable to |
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Answer» `CI, Br, I` |
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| 2875. |
The Law of Octaves was found to be applicable to elements |
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Answer» Oxygen |
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| 2876. |
The law of octaves was given by …………… |
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Answer» LOTHAR meyer |
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| 2877. |
The law of multiple proportion was discovered by |
| Answer» Solution :John Dalton | |
| 2878. |
The last subshell of an element is 3p and there are 3 electrons in it. Write the complete electronic configuration of the element. |
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| 2879. |
The last subshell of an element is 3p and there are 3 electrons in it. Identify its period and group. |
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| 2880. |
The last element authenticated by IUPACis Cn 112 [Copernuicium] . |
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| 2881. |
The larger the value of'1'belonging to the same main energy, higher is the energy associated with it' Comment on this statement. |
| Answer» Solution :When more than one electron is present in one main energy LEVEL, the energy of a particular elec- tron is detennined by the value of '01.' When the electron enters into p-orbital from infinite distance, it has to work tovvards a weaker force of ATTRACTION than that in CASE of 's-' orbital DUE to the screen- ING effect of the 's-' orbital belonging to the same energy level. Hence, the loss of energy is less in case of electron entering the 'p-' orbital than that entering the 's-' orbital. As a result, the electron belonging to 'p-' orbital has higher energy than that belonging to 's-' orbital. Sinularly, 'd-' orbital is associated with higher energy than that of 'p' and . the energy of the 'f-' 'orbital' is the highest providedthey all belong to the same main energy level. | |
| 2882. |
The laboratory method of preparation of CO is |
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Answer» `HCOOH overset(H_2SO_4)to H_2O + CO` |
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| 2884. |
The IUPAC name of H_(3)C-CH_(2)-C-=CH is…………………. |
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Answer» 1- butyne |
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| 2886. |
The IUPAC name of an organic compound is 3-Methyl butan-1-ol. What type compound it is? |
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Answer» Aldehyde `H-underset(H)underset(|)OVERSET(H)overset(|)(C)-underset(CH_(3))underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-OH` This compoundcontains -OH GROUP, i.e. alcohol |
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| 2887. |
The IUPAC name of acetic acid is |
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Answer» Methanoic ACID. |
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| 2889. |
The isotope of hydrogen that contains the same number of protons and neutrons in its nucleus is called |
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Answer» protium |
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| 2890. |
The isotope of Carbon - 12 contains ……………. . |
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Answer» 6 PROTONS and 7 electrons |
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| 2891. |
The …………….is useful to determine the empirical formula and molecular formula. |
| Answer» SOLUTION :PERCENTAGE COMPOSITION | |
| 2892. |
The iron obtained from blast furnace is |
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Answer» steel |
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| 2893. |
The ions present in a dilute aqueous solution of hydrochloric acid are ______ and _____ |
| Answer» SOLUTION :`H_(3)O^(+), CL^(-)` | |
| 2894. |
The ionization energy of elements increases in a period from left to right |
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Answer» Solution :The minimum amount of energy required to remove an ELECTRON from a gaseous atom in its GROUND state to forrn a gaseous ion is CALLED ionization energy The ionization energy INCREASES in a period from left to RIGHT. This is because the force of attraction between valence electron and nucleus increases in a period from left to right. |
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| 2895. |
The ionisation potential of potassium is ________ that of sodium. (gt//lt) |
| Answer» SOLUTION :LESS than | |
| 2896. |
The ionisation energy of nitrogen is more than that of oxygen because |
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Answer» GREATER attraction of electrons by the nucleus |
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| 2897. |
The ionisation energy of potassium is lower than that of sodium. Give reason. |
| Answer» Solution :Because the distance of the OUTERMOST orbit (N-SHELL) from the nucleus of potassium is LARGER than the M-shell of SODIUM. THUS, it is more easy to remove an electron from the outermost shell of potassium atom as compared to sodium. | |
| 2899. |
The ionic product of water is found to be 1 xx 10^(-12) mol^(2)//L^(2) " at " 60^(@)C. What would be the nature of solution with pH = 7 ? Explain giving reasons |
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Answer» Solution :(i) concentration of `H^(+) and OH^(-)` (II) `[H^(+)]//[OH^(-)]` from the given ionic PRODUCT of WATER (iii) calculation of pH from `[H^(+)]` (or) pOH from `[OH^(-)]` (iv) relation between pH value and nature of the solution (v) relation between given pH and nature of the solution |
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| 2900. |
The ionic product of water K_(W) is……….. |
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Answer» `K_(W)=[H_(3)O^(+)][OH^(+)]` |
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