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1.

In ∆ABC, ∠C = 90°, ∠ABC =θ°, BC = 21 units and Ab = 29 unitsShow that : cos2– sin2 =\(\frac{41}{841}.\)

Answer»

Given that AB = 29 units & BC = 21 units and ∠ABC =θ°& ∠ACB = 90°.

Using Pythagoras theorem in right angled triangle ∆ACB,

AB2 = AC2 + BC2

⇒ AC2 = AB2 − BC2

⇒ AC =\(\sqrt{AB^2-BC^2}\)=\(\sqrt{29^2-21^2}\)=\(\sqrt{841-441}=\sqrt{400}\)

=20 units.

(∵ BC = 21, AB = 29)

Now, cosθ =\(\frac{BC}{AB}=\frac{21}{29}.\)(∵ BC = 21, AB = 29)

And sinθ =\(\frac{AC}{AB}=\frac{20}{29}.\)(∵ AC = 20 and AB = 29)

Now, cos2θ− sin2θ =\((\frac{21}{29})^2-(\frac{20}{29})^2\)=\(\frac{21^2-20^2}{29^2}\)

=\(\frac{441 \,- \,400}{841}=\frac{41}{841}.\).

Hence Proved

2.

A student has set up a solar cooker in a box using a black painted aluminium sheet, a black cooking vessel, some glass wool , a transparent glass sheet and a mirror plate. What is the role of black paint, transparent glass sheet and a mirror used in the solar cooker ?

Answer» Black paint absorbs the heat energy quickly and thus helps in increasing the inner temperature. Glass sheet causes green-houses effect to retain the reflected infrared rays of heat, within the solar cooker. Mirror reflects the solar rays so that these rays reach inside the solar cooker.