Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

AlF_3 is soluble in HF only in presence of KF. It is due to the formation of…

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`AlH_3`
`K[AlF_3H]`
`K_3[AlF_3H_3]`
`K_3[AlF_6]`

SOLUTION :`AlF_3 + 3KF to K_3[AlF_6]`
2.

Aldol condensation proceeds by carbon- carbon bond formation between an enolation donor and a carbonyl acceptor For each of the following aldol products (1 through 4)Match the donor and acceptor compound.

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Solution :`A) Ph-CH_(2)-CHO to`DONOR& Acceeptor

It has `alpha` -H `so donor
B) `HCHO to `Acceptor

It has`alpha -H""alpha -H""because` donor
Ph -CHO TONO `alpha-H ""because "AcceptorBased onProducr"`(D)
has`alpha- H`andactas donor
3.

Aldol addition is nucleophllic addition reaction of carbonyl compound with enolate or enolate ion of aldehyde and ketones. The reaction between two molecules of acetaldehyde takes place as following in the presence of base.Driving force for the aldol condensation is :

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Formation of conjugated carbonyl COMPOUND as a product
Formation and stability of ENOLATE ion
Only the REACTIVITY of carbonyl group for NUCLEOPHILIC addition
all of these

Answer :b
4.

Aldol addition is nucleophllic addition reaction of carbonyl compound with enolate or enolate ion of aldehyde and ketones. The reaction between two molecules of acetaldehyde takes place as following in the presence of base. Which carbonyl compound wll be most reactiove for aldol addition ?

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`C_(6)H_(5)-CH_(2)-CHO`
`CH_(3)-CHO`

Answer :C
5.

Aldol addition is nucleophllic addition reaction of carbonyl compound with enolate or enolate ion of aldehyde and ketones. The reaction between two molecules of acetaldehyde takes place as following in the presence of base. Simple aldol addition is given by :

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`C_(6)H_(5)CHO`
`CX_(3)-CHO`
`O_(2)N-Ph-CHO`
`C_(6)H_(5)-CH_(2)-CHO`

Answer :D
6.

Aldehydes and ketones are.............isomers.

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ANSWER :FUNCTIONAL ISOMERS
7.

Aldehyde can be isomertic functionally with

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ALCOHOLS
ethers
esters
Ketones

Answer :D
8.

Aldehyde and ketones may be prepared by reductive cleavage of carbon-carbon double bonds. A particularly useful reagent for this purpose is ozone under reductive condition in the formation of carbonylcompounds. products Which of the following products is not formed in above reaction.

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`H-UNDERSET(O)underset(||)(S)-H`
`CH_(3)-underset(O)underset(||)(C)-H`

Solution :
9.

Alcohols undergo acid catalysed elimination reactions to produce alkenes. Because water is lost in the elimination , this reaction is called dehydration reaction. Secondary and tertiary alcohols always give E1 reaction in dehydration. Primary alcohols whose beta-carbon is branched also give E1 reaction. The reactivity of alcohol for elimination reaction is tertiary alcohol gt secondary school gt Primary alcohol. Identify the product in the given reaction :

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ANSWER :C
10.

Alcohols undergo acid catalysed elimination reactions to produce alkenes. Because water is lost in the elimination , this reaction is called dehydration reaction. Secondary and tertiary alcohols always give E1 reaction in dehydration. Primary alcohols whose beta-carbon is branched also give E1 reaction. The reactivity of alcohol for elimination reaction is tertiary alcohol gt secondary school gt Primary alcohol. Which of the following dehydration product (major ) is incorrect ?

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`CH_3-undersetunderset(CH_3)(|)oversetoverset(CH_3)(|)C-oversetoverset(OH)(|)CH-CH_3underset(DELTA)OVERSET(conc.H_2SO_4)to CH_3-undersetunderset(CH_3)(|)oversetoverset(CH_3)(|)C-CH=CH_2`
`CH_3CH_2CH_2CH_2OHunderset(Delta)overset(conc.H_2SO_4)to CH_3-CH=CH-CH_3`

ANSWER :B
11.

Alcohols reacts with Grignard reagent to form

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Alkanes
Alkenes
Alkynes
All

Solution :`C_(2)H_(5)OH+CH_(3)MgI RARR CH_(4)+C_(2)H_(5)OMgI`.
12.

Alcohols, phenols and acids can be distinguished by reaction with

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`NaHCO_(3)`
`NaOH`
`FeCl_(3)`
all the above

Solution :(a) ALCOHOLS and phenols can be distinguished by NaOH and `FeCl_(3)` solution (b) Phenol and acid can be distinguised by `NaHCO_(3)`
13.

Alcohols of low molecular weight are

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Soluble in water
Soluble in water on heating
Insoluble in water
Insoluble in all solvents

Solution :These QUESTION are BASED UPON FACTS or formulae
14.

Alcohols may act as

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Oxidisingagent
Reducing agent
LEWIS base
BRONSTED acid

Solution :Alcohols can act as Lewis base.
`R-underset(..)OVERSET(..)(O)-H+H^(+) RARR R-underset(..)overset(H)overset(|)(O^(+))-H`
Alcohols can also act as Bronsted acid.
`R-underset(..)overset(..)(O)-H rarr R-underset(..)overset(..)(O):^(-)+H^(+)`
15.

Alcohols are weaker acids than water. Why ?

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Solution :In alcohol , the alkyl group has `+ I` EFFECT. It INCREASES the electron density on the OXYGEN atom. As a RESULT, the release of `H^(+)` ion from alcohol is more difficult than from water or alcohol is a weaker ACID.
16.

Dehydrohalogenation involves removal of the halogenn atom together with a hydrogen atom from carbon adjacent to the one with halogen atom. Alcoholic KOH is used for dehydrohalogenation. According to saytzeff's rule, when two alkenes may be formed, the alkene which is most substituted is the major product. Q. The ease of dehydrohalogenation for different halogens is in the order

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dehydrogenation
dehalogenation
dehydration
dehydrohalogenation

Answer :D
17.

Alcoholic solution of KOH is a specific reagent for

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DEHYDRATION
dehydrogenation
dehydrohalogenations.
DEHALOGENATION.

ANSWER :C
18.

Alcoholic beverages are made of

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Ethanol
Acetic acid
Formic acid
None of these

Answer :A
19.

Alcohol on refluxing with K_2 Cr_2 O_7 gives .....

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Ester
Aldehyde
SUGAR
CARBOXYLIC ACID

Solution :Carboxylic acid
20.

Alcohol on refluxing with K_(2)Cr_(2)O_(7) gives ...............

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SOLUTION :CARBOXYLIC ACID
21.

Alcohol level in blood is determined by the reaction with K_2Cr_2O_7 solution in acidic medium. Calculate the blood level in mass percent if 10 " mL of " 0.05 M solution of K_2Cr_2O_7 is required for the reaction of a 10.0 g sample of blood.

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SOLUTION :Mole method:
Balance the redox reaction of `C_2H_5OH` with `Cr_2O_7^(2-)` in acidic MEDIUM (Mw of `C_2H_5OH=46g)`
`cancel6e^(-)+Cr_2O_7^(2-)to2Cr^(3+)]xx2`
`underline(C_2H_5OHto2CO_2+cancel(12e^(-))`
`underline(C_2H_5OH+2Cr_2O_7^(2-)to4Cr^(3+)+2CO_2)`
For 2 " mol of "`Cr_2O_7^(2-)-=1 " mol of "C_2H_5OH` is required `10xx0.05xx10^(-3) " mol of "Cr_2O_7^(2-)`
`-=(10xx0.05xx10^(-3))/(2) " mol of "C_2H_5OH`
`-=25xx10^(-5)` " mol of "`C_2H_5OH`
`-=25xx10^(-5)xx46g of C_2H_5OH`
Percent of alcohol `-=(25xx10^(-5)xx46)/(10)xx100=0.115%`
Equivalent method:
`Cr_2O_7^(2-)-=C_2H_5OH`
`1mEq-=1mEq`
`10xx0.05xx6m" Eq of "Cr_2O_7^(2-)=3 mEq-=3 m" Eq of "C_2H_5OH`
`3 mEq-=3 mEq`
`3m" Eq of "C_2H_5OH-=3xx10^(-3)eq-=3xx10^(-3)xx(46)/(12)g`
Percent of alcohol `-=(3xx10^(-3)xx46xx100)/(12XX10)-=0.115%`
22.

Alcohol fermentation is brought about by the action of

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`CO_(2)`
`O_(2)`
INVERTASE
Yeast

Solution :Both invertase and ZYMASE are CONTAINED in yeast.
23.

AlCl_3 molecule is exist in which form ?

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Dimer
Polymer
Monomer
None of the above

Answer :A
24.

AlCl_(3) on hydrolysis gives

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`Al_(2)O_(3).H_(2)O`
`Al(OH)_(3)`
`Al_(2)O_(3)`
`ACl_(3).6H_(2)O`

Solution :`AlCl_(3)` on hydrolysis GIVES `Al(OH)_(3)` and HCL.
`AlCl_(3)+3H_(2)O RARR Al(OH)_(3)+3HCl`
25.

AlCl_(3) is usedas a catalyst in _______.

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WURTZ SYNTHESIS
Saponificationof ESTERS
WILLIAMSON synthesis
friedelcraftreaction

Answer :D
26.

AlCl_3 is a Lewis acid.

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ANSWER :1
27.

AlCl_(3) is a Leis acid than BCl_(3).

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ANSWER :WEAKER
28.

AlCl_(3) is

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An hydrous and COVALENT
An hydrous and IONIC
Covalent and basic
CO - ordinate and acidic

Solution :An hydrous and co-valent.
29.

AlCl_(3) fumes in moist air because

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It is very volatile
It is covalent
HCl is formed in moist air
It is HIGHLY hygroscopic

Solution :Anhydrous `AlCl_(3)` FUMES in moist air because of hydrolysis.
`AlCl_(3)+3H_(2)O rarr Al(OH)_(3)+3HCl`
HCl so produced fumes in moist air.
30.

AlCl_(3) exists as dimer because

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Al has greater IONISATION potential
Al has larger radius
High CHARGE in nucleus
INCOMPLETE p-subshells

Solution :`AlCl_(3)` exist as DIMER because of incomplete p-subshell.
31.

AlCl _(3) is …………. Compound whereas PCl_(5)is …………… compound in terms of octer rule.

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SOLUTION :electron-deficient, hypervalnet
32.

Al[BH_(4)]_(3) contains how many 3 centered -2e^(-) bonds.

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SOLUTION :
33.

Al^(3+) ions replace Na^+ ions at the edge centres of NaCl lattice. The number of vacancies in one mole NaCl is found to bex xx 10^23 . The value of x approximately is

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ANSWER :3
34.

Al^(3+) ions replace Na^(+) ions at the edge centres of NaCl lattice. The number of vacancies in one mole NaCl is found to be x10^(23). The value of xapproximately is

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ANSWER :2
35.

Al_(2)O_(3) formation involves large quantity of heat evolution which makes its use in

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DEOXIDISER
CONFECTIONARY
INDOOR photography
THERMITE welding

Solution : During the thermite welding LARGE heat liber ated
36.

Al_(2)O_(3) can be converted to anhydrous AlCl_(3) by heating

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`Al_(2)O_(3)` with `Cl_(2)` gas
`Al_(2)O_(3)` with HCl gas
`Al_(2)O_(3)` with `NACL` in solid state
a mixture of `Al_(2)O_(3)` and carbon in dry `Cl_(2)` gas

Answer :D
37.

Al_(2)O_(3) can be converted to anhydrous AlCl_(3) by heating :

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A mixture of `Al_(2)O_(3)` and CARBON in dry `Cl_(2)` gas
`Al_(2)O_(3)` with HCl gas
`Al_(2)O_(3)` with `Cl_(2)` gas
`Al_(2)O_(3)` with NaCl in SOLID state

Solution :`Al_(2)O_(3)+C+Cl_(2)overset(DELTA)rarr` anhydrous `AlCl_(3)`
38.

Al_(2)O_(3)becomes anhydrousAlCl_(3) upon heating

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with `NaCl`
with DRY `Cl_(2)` and C
with `Cl_(2)`
with dry `HCl` gas

Solution :`Al_(2)O_(3) + 3Cl_(2) + 3C overset("Heat")rarr2AlCl_(3) + 3 CO`.
39.

Al_(2)(SO_(4))_(3)+NH_(4)OH rarr X,X is

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a white GELATINOUS precipate
insolunle in excess of `NH_4OH`
SOLUBLE in excess of NaOH
amphotericin nature

Solution :`Al_(2)(SO_4)_3+NH_(4)OH rarr (NH_4)_(2)SO_(4)+Al(OH)_3`
X is Al `(OH_3)` which is a white gelatinous precipitate soluble in excess of NaOH and is amphoteric nature
40.

Al reacts with conc. H_(2)SO_(4) and forms Uses of B & Al and their compounds

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`SO_(3)`
`SO_(2)`
`H_(2)`
`S(VAP)`

Answer :B
41.

Al is inert in nature , because ……

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It has HIGH electropositivity .
It forms hard LAYER of `Al_2O_3` on the surface.
Strong REDUCING agent
It forms ALLOY with Cu.

Answer :B
42.

Al having double conductivity as compared to which metal ?

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Solution :Al has DOUBLE CONDUCTIVITY as compared to Cu.
43.

Al and Ga have nearly the same covalent radius, incorrect reason is

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 GREATER shielding effect of s-electrons of GA ATOMS 
Poor shielding effect of s-electrons of Ga atoms 
 Poor shielding effect of d-electrons of Ga atoms
 Greater shileding effect of d-electrons of Ga atoms 

Solution : Due to poor shielding effect of d electrons of Ga atoms
44.

Al and Ga have nearly the same covalent radii, because of

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GREATER shielding EFFECT of 's' electrons of 'Ga' ATOMS
POOR shielding effect of 's' electrons of 'Ga' atoms
Poor shielding effect of 'd' electrons of 'Ga' atoms
Greater shielding effect of 'd' electrons of 'Ga' atoms

Answer :C
45.

aK_(2)Cr_(2)O_(7)+bKCl+cH_(2)SO_(4) to xCrO_(2)Cl_(2)+yKHSO_(4)+zH_(2)O The above equation balances when

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a=2,b=4,c=6 and x=2, y=6, z=3
a=4,b=2,c=6 and x=6,y=2,z=3
a=6,b=4,c=2 AD x=6, y=3,z=2
a=1,bb=4,c=6 and x=2, y=6, z=3

Answer :D
46.

aK_(2)Cr_(2)O_(7)+bKCI+cH_(2)SO_(4)rarrxCrO_(2)CI_(2)+yKHSO_(4)+zH_()O The above equation balance when

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A=2,b=4,c=6 and x=2 , y =6 , z=3
a=4b=2c=6and x=6 y =2 z=3
a=6b=4c=2 and x=6y=3z=2
a=1b=4c=6 and x=2y=6z=3

Solution :
47.

Air pollution is not caused by

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Pollen GRAIN
Hydroelectroc power
Industries
Automobiles

Solution :AIR POLLUTIONN is not CAUSED by hyfdroelectroic power
48.

Air pollutants that produce photochemical oxidants include:

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`CO_(2), CO and SO_(2)`
`N_(2)O, NO and HNO_(3)`
`O_(2), l_(2)` and `HNO_(3)`
`O_(3),Cl_(2)` and `SO_(2)`

Answer :B
49.

Air pollutants that produce photochemical oxidants include

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`CO_(2) CO and SO_(2)`
NITROUS oxide ,nitric oxide and nitric ACID
Oxygen, chlorine nad nitric acid
Ozone, chlorine and suphur dioxide.

Solution :Air pollutant that produce PHOTOCHEMICAL oxidatns INCLUDE nitrous oxide, nitric oxide andnitric acid
50.

Air is cooled from 25^@C to 0^@C. Calculate the decrease in rms speed of the molecules.

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ANSWER :about 4%