Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Atomic hydrogen combines with almost all elements but molecular hydrogen does not. Explain.

Answer»

Solution :Atomic hydrogen is highly unstable and hence it is very reactive. Its electronic configuration is `1s^1`. For stability it ACCEPT 1 more electron and thus it almost COMBINE with all the elements.
Atomic hydrogen make hydride by THREE different type.
(i) If remove one electron and FORM `H^+`
(ii) It accept one electron and form `H^-`
(iii) It share one electron and form covalent single bond. In contrast, the bond dissocia tion energy of H-H bond is very high (435.88 kJ `"mol"^(-1)`). As a result molecular hy drogen is almost inert at room TEMP. and hence reacts only with a few elements.
2.

Atomic and molecular sizes are typically of the order of a few Angstroms. Assuming that a N_2 molecules is spherical in shape with radius (r) = 2 xx 10^(-10) m, calculate the volume of a single N_2 molecule,

Answer»

SOLUTION :`3.35 XX 10^(-23) cm^3`
3.

Atomic and molecular sizes are typically of the order of a few Angstroms. Assuming that a N_2 molecules is spherical in shape with radius (r) = 2 xx 10^(-10) m, calculate the percentage of empty space in one mole of N_2 gas at S.T.P.

Answer»

SOLUTION :`99.9098%`
4.

Atomic and mass numbers can be

Answer»

Negative 
FRACTIONAL 
Zero 
WHOLE number 

Answer :D
5.

Atmospheric pressures recorded in different cities are as follows : {:("Cities","p in N"//m^(2)),("Shimla",1.01xx10^(5)),("Bangalore",1.2xx10^(5)),("Delhi",1.02xx10^(5)),("Mumbai",1.21xx10^(5)):} Consider the above data and mark the place at which liquid will will boil first.

Answer»

Shimla
Bangalore
Delhi
Mumbai

Solution :A LIQUID boils when VAPOUR pressure above it becomes EQUAL to the atmospheric pressure. LOWER the atmospheric pressure, lower is the boiling point.
6.

Atmospheric content of CO_(2) is

Answer»

`0.0034%`
`0.034%`
`0.34%`
`3.4%`

SOLUTION :ATMOSPHERIC CONTENT of `CO_(2)` is 0.034% by VOLUME
7.

Atmosphere pollutant is

Answer»

`CO_(2)`
CO
`O_(2)`
`N_(2)`

SOLUTION :CO is an atmospheric POLLUTANT
8.

Atmosphere, hydrosphere, lithosphere and biosphere are the four main segments of the environment. Atmosphere is a cover of gases that extends to a height of about 1600 km above the surface of the earth and protects the life on the earth from harmful radiations coming from the sun or the outer space. Atmosphere is further divided into four regions such as troposphere, stratosphere, mesosphere and thermosphere. Hydrosphere forms that part of the environment which contains water. Lithosphere is the solid component of the earth consisting of soil, rocks, mountains etc. Biosphere is that part of the above segments where living organisms interact with these parts and live together. The biotic component of the environmentis

Answer»

Lithosphere
BIOSPHERE
HYDROSPHERE
Atmosphere

ANSWER :B
9.

Atmosphere, hydrosphere, lithosphere and biosphere are the four main segments of the environment. Atmosphere is a cover of gases that extends to a height of about 1600 km above the surface of the earth and protects the life on the earth from harmful radiations coming from the sun or the outer space. Atmosphere is further divided into four regions such as troposphere, stratosphere, mesosphere and thermosphere. Hydrosphere forms that part of the environment which contains water. Lithosphere is the solid component of the earth consisting of soil, rocks, mountains etc. Biosphere is that part of the above segments where living organisms interact with these parts and live together. Hydrogen and Helium are found in which of the following regions ?

Answer»

MESOSPHERE
Exosphere
TROPOSPHERE
Stratosphere

ANSWER :B
10.

Atmosphere, hydrosphere, lithosphere and biosphere are the four main segments of the environment. Atmosphere is a cover of gases that extends to a height of about 1600 km above the surface of the earth and protects the life on the earth from harmful radiations coming from the sun or the outer space. Atmosphere is further divided into four regions such as troposphere, stratosphere, mesosphere and thermosphere. Hydrosphere forms that part of the environment which contains water. Lithosphere is the solid component of the earth consisting of soil, rocks, mountains etc. Biosphere is that part of the above segments where living organisms interact with these parts and live together. Which of the following is the coldest region ?

Answer»

MESOSPHERE
Tropospere
STRATOSPHERE
Thermospehere

ANSWER :A
11.

Atmosphere content of CO_2 is

Answer»

`0.0034%`
`0.034%`
`0.34%`
`3.4%`

ANSWER :B
12.

Atmolysis is the method used to separate a mixture of

Answer»

two liquids which differ in their boiling points by at LEAST `40^(@) C`
two gases which differ in their rates of DIFFUSION under similar CONDITIONS of T and P
two gases which have same rates of diffusion under similar conditions of T and P
two gaseswhich react to FORM a solid

Answer :B
13.

Atmolysis is a process of

Answer»

Atomising GAS molecules
The breaking of ATOMS to sub-atomic particles
Separation of gases from their gaseous MIXTURE
Changing of liquids of their vapour state

Solution :ATMOLYSIS is the process of separtion of mixture of unreacting gases by the process of diffusion
14.

The volume of an ideal gas becomes zero at

Answer»

`0^(@)C`
`273 K`
`-273^(@)C`
`273^(@)C`

ANSWER :C
15.

At which temperature kelvin and ""^(@)C are same ?

Answer»

273
-40
-273
Not possible

Answer :B::D
16.

At which situation intermolecular forces becomes effective ?

Answer»

SOLUTION :At high pressure : Attraction forces becomes EFFECTIVE between molecules then CHANGE in pressure is `(an^(2))/(V^(2))`.
`p_("ideal")=p_("real")+(an^(2))/(V^(2))`
At high pressure : Repulsive forces becomes effective between molecules then change in volume in nb.
`V_("ideal")=(V_("real")-nb)`
At very LOW temperature : Intermolecular forces become significant. As the molecules travel with low average speed, these can be captured by one another due to attractive forces.
17.

At which position nitration mainly takes place ?

Answer»


ANSWER :C
18.

At which distance observed for van der Waal.s force ?

Answer»

`8 Å`
`5 Å`
`4.5 Å`
Not decided

Answer :C
19.

At which condition density becomes maximum ?

Answer»

p = 0.5 atm and T = 600 K
p = 2 atm and T = 150 K
p = 1 atm and T = 500 K
p = 1.5 atm and T = 400 K

ANSWER :B
20.

At what temperature will the total kinetic energy of 0.5 moles of He be the same as the total kinetic energy of 0.6 moles of neon at 300K?

Answer»

300 K
360 K
400 K
250 K

Solution :360 K
21.

At what temperature will the total kinetic energy of 0.30 mol of He be same as the total kinectic energy of 0.40 mol of Ar at 400 K ?

Answer»

400 K
300 K
533 K
573 K

Solution :`K.E.=(3)/(2)NRT`
`:. (3)/(2)xx.04xx400=(3)/(2)xx0.3xxT" or "T=533" K"`
22.

At what temperature will the total KE of 0.3 mo of He be the same as the total KE of 0.40 mol of Ar at 400K?

Answer»

533K
400K
346K
300K

Answer :a
23.

At what temperature will the rate of diffusion of N_(2)be 1.6 times the rate of diffusion of SO_(2)at 27°C?

Answer»

`336^@ C`
`300 K`
`50 ^@ K`
`63^@ C`

ANSWER :D
24.

At what temperature, will most probable speed of the molecules of the second member of homologous series C_(n),H_(2n-2) be the same as that of oxygen at 527^(@)C?

Answer»

`1000^(@)C`
`727^(@)C`
`1727^(@)C`
`1044.5^(@)C`

ANSWER :B
25.

At what temperature will hydrogen molecules have the same kinetic energy an nitrogen molecules have at 35^(@)C?

Answer»

`((28xx35)/(2)).^(@)C`
`((2xx35)/(28)).^(@)C`
`((2xx28)/(35)).^(@)C`
`35^(@)C`

ANSWER :d
26.

At what temperature water has maximum density ?

Answer»


ANSWER :`4^(@)C`
27.

At what temperature volume of gas becomes half, initial temperature and volume is 17^(@)C and 400 mL respectively. (Charle.s law)

Answer»


ANSWER :`-128^(@)C`
28.

At what temperature, the volume of a gas would become zero ?

Answer»

`0^(@)C`
`273^(@)C`
`-273.15^(@)C`
273 K

Solution :It becomes ZERO at absolute zero i.e, `-273.15^(2)C`
29.

At what temperature, the volume of 'V' of a certain mass of gas at 37^@C will be doubled, keeping the pressure constant?

Answer»

`327^@ C`
`347^@ C `
`527^@ C`
`54^@ C`

Answer :B
30.

At whattemperature the volume of 28 grams of N_2 will be 1L exerting a pressure of1 atm?

Answer»

SOLUTION :28g of `N_2` at 273K, 1 ATM pressure occupies 22.4L
Charles. law is given as,` (V_1)/(V_2) = (T_1)/(T_2)`
`V_1= 22.4L"" T_1= 273K`
` V_2= 1.0L"" T_2 =?`
The temperature at which 1L of 28g of N, exerts a pressure of 1 atm =` T_2= (V_2T_1)/(V_1) = ( 1 XX 273 )/( 22.4) = 12.2 K=- 260.8^@ C `
31.

At what temperature, the rms velocity of SO_(2) be same as that of O_(2) at 303K ?

Answer»

273 K
606 K
303 K
403 K

Solution :(b) `(U_(rms)(SO_(2)))/(U_(rms)(O_(2)))=SQRT((T(SO_(2)))/(M(SO_(2)))XX(M(O_(2)))/(T(O_(2))))`
i.e. `1=sqrt((T(SO_(2)))/(64)xx(32)/(303))or T(SO_(2))=606 K`
32.

At what temperature the velocity of O_(2) molecules will have the same velocity as SO_(2)at 47°C?

Answer»

`113^@ C `
`160^@ C`
`-113 ^@ C `
`-160^@ C`

ANSWER :C
33.

At what temperature the most probable velocity of O_(2) gas is equal to the RMS velocity of O_(3)at 't'°C?

Answer»

`(273 +t) sqrt(3/2 K)`
`(273 + t)sqrt(2/3 K)`
`(273 + t) K`
`3/2 (273 + t ) K`

SOLUTION :`(U_(MP))_(O_2) = (U_(rms))_(O_3)`
`= sqrt((2RT_2)/(32)) = sqrt((3R(t + 273))/(48))`
`(2T_2)/(32) = (3(t+273))/(48) implies t_2 = (t + 273)k`.
34.

At what temperature the most probable velocity of O_2 gas is equal to the RMS velocity of O_2 at ‘t’^@C?

Answer»

`(273 + t)sqry(3/2K)` 
`(273 + t)sqry(2/3K)` 
`(273 + t)K`
`3/2(273 + t)K`

ANSWER :C
35.

AT what temperature root mean square speed of N_(2) gas is equal to that of propane gas at STP condition?

Answer»

`173.7^(@)C`
173.7K
STP
`-40^(@)C`

ANSWER :B
36.

At what temperature, reduction of lead oxide to lead by carbon i.e., PbO(s) +C(s) rarr Pb(s) + CO(s) becomes spontaneous. For the reaction , Delta Hand Delta S are 108.4 kJ mol^(-1) and 190.0 JK^(-1) mol^(-1) respectively.

Answer»


Solution :At equilibrium, `T = (DeltaH)/(DeltaS) = (108400 J MOL^(-1))/( 190 JK^(-1) mol^(_1)) = 570 . 5K`
Above 570.5 K, `Delta G` will be `-ve` and the reaction will be spontaneous.
37.

At what temperature the kinetic energy of a gas molecule is one-half of its value at 30^@C?

Answer»

Solution :`(K.E.) =3/2 KT`
At TWO different conditions ` ((KE)_1)/((KE)_2) = (T_1) /(T_2) , (1)/( 1//2)= ( 303)/(T_2)`
Temperature at which KINETIC energy is half =`(303)/(2)`
` = 151.5 K =- 121.5^@ C `
38.

At what temperature hydrogen has the same RMSvelocity as that of oxygen at room temperature?

Answer»

Solution :RMS VELOCITY (C ) is given as ` C = sqrt((3RT)/(M))`
For TWO gases, RMS velocity is same.
`(T_(1))/(M_(1)) = (T_(2))/(M_(2))`
`T_(1) =` TEMPERATURE of OXYGEN= 298 K
`T_(2)` = Temperature of hydrogen = ?
Temperature of hydrogen gas ` = T_(2) = (T_(1))/(M_(1)) xx M_(2)`
` = (298 xx 2)/(32) = 18.6K = -254.4^(@)C`
39.

At what temperature does the reaction below change from favoring products to favoring

Answer»

162K
509K
1060K
1540K

Answer :C
40.

At what temperature centigrade will the volume of a gas at 0^(@)C double itself, pressure remaining constant ?

Answer»

Solution :LET the volume of the gas at `0^(@)C`=V mL
THUS, we have : `V_(1)=V mL,V_(2)=2V mL`
`T_(1)=0+273=273 K""T_(2)=?`
By applying, Charles' Law,`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
Substituting the corresponding values, we have
`(V)/(273)=(2V)/(T_(2)),"" T_(2)=(2Vxx273)/(V)=546 K :. T_(2)=546-273=273^(@)C`
41.

At what temperature ""^(@)C=""^(@)F

Answer»

`-30^(@)`
`-40^(@)`
`-20^(@)`
Not possible

Solution :`""^(@)F= 9/5 (""^(@)C)+32 "" F=C`
`""^(@)C=9/5 (""^(@)C)+32`
`5""^(@)C=9""^(@)C+32xx5`
` - 4""^(@)C=32xx5`
`""^(@)C= - 40`
42.

At what temperature and pressure the liquid is vapourise in vapour phase distillation?

Answer»

SOLUTION :At 373K and 1 ATM PRESSURE
43.

At what proportion of carboxy-hemoglobin the oxygen carrying capacity of blood reduces ?

Answer»

4 to 5%
3 to 4%
4 to 6%
3 to 5%

SOLUTION :3 to 4 %
44.

At what pH will a 10−4M solution of an indicator with Kb​=1×10−11change colour?

Answer»


Solution :INDICATOR changes COLOUR when
`PH =pKI_n , pH = 14 -11 =3`
45.

At what molar concentration of aqueous nitrouse acid (K_a = 4.5x10^(-4)) the pH of the aqueous solution is 2.

Answer»

SOLUTION :`0.222M`
46.

At what distance is the radial probability maximum for 1s orbital ? What is this distance called ?

Answer»

SOLUTION :`0.529 F279Å`, BOHR RADIUS
47.

At what concentration of Zn^(2+) (aq) will its electrode potential become equal ot its standard electrode potential ?

Answer»

SOLUTION :At 1 M CONCENTRATION
48.

The ratio of kinetic energies of 2gm of H_2 and 4gm of CH_4 at a given temperature is

Answer»

`1:4`
`4:1`
`2:1`
`8:1`

ANSWER :B
49.

At the time of experiment how the solution with required concentration is prepared?

Answer»

By adding the raw SALT
By adding the stock SOLUTION
By diluting the stock solution
By concentrate the stock solution

Answer :C
50.

At the suggestion of Earnest Rutherford, hans Geiger and ernest Marsden bombarded a thin gold foil by alpha-particles from a polonium source. It was expected that alpha-particles would go right through the foil with hardly any deflection. Although, most of the alpha particles indeed were not deviated by much, a few were scattered through veryi large angles. Some were even scattered in the backward direction. The nly way to explain the results, rutherford found, was to picture an atom as being compoed of a tiny nucleus in which its positive charge and nearly all its mass are concentrated. Scattering of alpha-particles is proportional to target thickness and is inversely proportional to the fourth power of sin((theta)/(2)), where, theta is scattering angle. Distance of closest approach may be calculated as: r_("min")=(Z_(1)Z_(2)e^(2))/(4piepsi_(0)K) where, K=kinetic energy of alpha-particles. Q. Which of the following quantities will be zero for alpha particles at the point of closest approach to the gold atom, in Rutherford's scattering of alpha particles?

Answer»

Acceleration
Kinetic energy
Potential energy
Electrical energy

Answer :B