Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Choose the incorrect statement

Answer»

Empirical formula shows the actual NUMBER of atoms of different ELEMENTS in one MOLECULE of the compound
Ozone (`O_(3)` ) is another form of oxygen gas at room temperature
Gases are EASILY compressible
Pressure is defined as FORCE divided by the area perpendicular to which the force is applied

Answer :A
2.

Choose the incorrect pari:

Answer»

Photochemical smog : `NO_(2)` and `O_(3)`
Classsical smog : `So_(2),So_(3)` and humidity
smog : smoke and fog
NON VIABLE particulate : ALGAE, FUNGI

Solution :Non viable particulate : Algae, Fungi
3.

Choose the incorrect pair.

Answer»

`-OH, -SH, -NH_(2)` Positive mesomeric effect
`-NO_(2) GT CO, -COOH` Negative mesomeric effect
`-F, -CI, -NO_(2)`: Electron withdrawing group
`-C(CH_(3))_(3), -CH(CH_(3))_(3), -CH_(2) -CH_(3)` Electron withdrawing group

Solution :`-F, -CI, -NO_(2)` :Electron withdrawing group
4.

Choose the incorrect pair.

Answer»

1) Work is defined as force MULTIPLIED by the DISPLACEMENT : -w=F. x
2) Enthalpy change : `DeltaH=DeltaU-DeltangRT`
3) Gibbs free energy : `DeltaG=DeltaH -TDeltaS`
4) The entropy of a PERFECTLY crystalline material at absolute zero :Zero

Answer :B
5.

Choose theIncorrect pair

Answer»

Acid MAKING elements : S,P
Gas LIKE elements Oxygen, Hydrogen
Metallic elements : Gold, Lead
Earthy elements : `Cl_2,Br_2`

Answer :d
6.

Choose the disprotionation reaction among the following redox reactions

Answer»

`3 Mg (s) N_(2)(g)rarrMg_(3)N_(2)(s)`
`P_(4)(s)+3NaOH(aq)+3H_(2)O(l)rarrPH_(3)(g)+3NaH_(2)PO_(2)(aq)`
`CI_(2)(g)+2KI(aq)rarr2KCI(Aq)+I_(2)(s)`
`Cr_(2)O_(3)(s)+2AI(s)rarrAI_(2)O_(3)(s)+2cr`

SOLUTION :In reaction (b) `P_(4)` is both reduced to `PH_(3)` and oxidised to `NaH_(2)PO_(2)` thus it is a DISPROPORTION nation reaction butin all other redox reaction different speiced are oxidised / reduced i.e in reactoin(a) Mg is oxidised but `N_(2)` is reduced reaction (c ) `COI_(2)`is reduced AI is oxidised while in reaction (e ) `NA^(+)` is reduced but `H^(-)` oxidised
7.

Choose the disproportionation reaction among the following redox reactions.

Answer»

`3Mg_((s))+N_(2_((g))) to Mg_(3)N_(2_((s)))`.
`P_(4(s))+3NaOH+3H_(2)Oto PH_(3(g))+3NaH_2PO_(2(aq))`.
`CI_(2(g))+2KI_((aq))to2KCI_((aq))+I_(2)`
`Cr_(2)O_(3_((s)))+2AI_((s))toAI_(2)O_(3)(s)+2Cr(s)`

Answer :A::B::C::D
8.

Choose the corrrect pair

Answer»

E=hv
E=`MC^(2)`
`gamma=mv/h`
`gamma=h/p`

ANSWER :D
9.

Choose the corrent pair.

Answer»

`H_(2(G)) + I_(2(g)) hArr 2HI_((g)) : Delta n_(g) = -ve`
`PCl_(5(g)) hArr PCl_(3(g))+ Cl_(2(g)) : Delta n_(g) = -ve`
`N_(2(g)) + O_(2(g)) hArr 2NO_((g)) : Delta n_(g) = + ve`
`2NH_(3(g)) hArr N_(2(g)) + 3 H_(2(g)) : Delta n_(g) = +ve`

Solution :`Delta n_g = 2-2 =0, (b) Delta n_(g) = 2-1=1 : (C) Delta n_(g) =2-2= 0`
10.

Choose the correct statement (s) (i) The energy of an electron in an atom is always negative, because it is negatively charged. (ii) The charge of an electron in an atom is positive (iii) When an electron is at an infinite distance from the nucleus so that there is no electrical interaction , then orbitarily the energy of electron is taken to be zero (iv) As the electron moves closer to the nucleus, energy is released and so its energy becomes less than zero i.e., negative.

Answer»

all are correct
II and IV are correct 
only ii is correct 
no statement is correct. 

Answer :B
11.

Choose the correct statements from the following:

Answer»

Beryllium is not readily attacked by acids because of the PRESENCE of an oxide film on the surface of the METAL.
Beryllium sulphate is readily soluble in water as the greater hydration enthalpy of `Be^(2+)` overcomes the lattice enthalpy factor.
Beryllium EXHIBITS coordination number more than four.
Beryllium oxide is purely acidic in nature.

Solution :Be resembles Al (diagonal RELATION) and form protective film of oxide and not attacked readily by acids. `BeSO_(4)` is soluble in water due to highhydration enthalpy of `Be^(2+)`.
LIKE `Al_(2)O_(3), BeO` is amphoteric in nature.
12.

Choose the correct statements from the following .

Answer»

Beryllium is not readilyattacked by ACIDS because of the presence of an oxide film on the SURFACE of the METAL .
Beryllium sulphate is readily soluble in water as the greater hydration enthalpy of `Be^(2+)` overcomes the lattice enthalpy factor .
Beryllium EXHIBITS coordination NUMBER more than four .
Beryllium oxide is purely acidic in nature .

Answer :A::B
13.

Choose the correct statements from the following :

Answer»

Beryllium is not READILY attacked by acids because of the presence of an oixde film on the surface of the metal
Beryllium sulphate is readily soluble in water as the greater hydration enthalpy of `Be^(2+)` overcomes the LATTICE enthalpy factor.
Beryllium exhibits COORDINATION number more than four.
Beryllium oixde is purely ACIDIC in nature

Solution :(a) and (b) are both CORRECT
14.

The correct statement among the following

Answer»

A node is a POINT in space where the wave-funtion Y has zero AMPLITUDE .
The number of maximum (peaks) in radial probability distribution function is (n-l)
Radial probability density is `4PI r^2 R_(n.l)^2 (r)`
`PSI`represents probability of FINDING electron

Solution :At node `Psi^2 = 0 `
number of radial nodes = n-l-1
nodes of peaks = n-1
15.

Choose the correct statement(s) amongthe following :

Answer»

Internal energyof `H_(2)O` remainsconstantduringconverstion of liquid into its vapour at connstant TEMPERTURE .
Duringfusion of ICE into water enthalpy change and internal energy changeare almost same at constant TEMPERATURE.
Molar heatcapacity of gasaes are temperature DEPENDENT
Duringcomparessionof an ideal gas at constant pressure, the temperature of gas decreases.

Answer :b,c,d
16.

Choose the correct statement(s)

Answer»

The MAXIMUM positive oxidation state shown by any element is equal to the TOTAL number of electrons (s and p) in valence shell
The maximum oxidation state shown by ELEMENTS in a group is also known as group oxidation number
Group oxidation number is the most common or most stable oxidation state for a particular element
All the elements in a group form some compounds in which they EXHIBIT their group oxidation number

Answer :A::B
17.

Choose the correct statements:

Answer»

Temperature, enthalpy and entropy are state functions
For both reversible and irreversible isothermal expansion of an ideal GAS, change in internal energy and enthalpy is zero
For a reaction in which `Delta n_(g) = 0`, entropy change is not always zero
The entropy change associated with reversible isothermal expansion of an ideal gas is equal to 2.303 R `"LOG"_(10) (P_(1))/(P_(2))`

Solution :(a) T, H, S are state functions
(b) `Delta T = 0 rArr Delta E = Delta H= 0`
(c ) even if `Delta n_(g) = 0, S` may change
(d) Reversible isothermal, `Delta S = (q_("rev"))/(T) = R "ln" (V_(2))/(V_(1)) = R "ln " (P_(1))/(P_(2))`
18.

Choose the correct statements

Answer»

Except beryllium ,all other alkaline EARTH metals combine with hydrogen on heating to GORM hydirde `(MH)_(2)`
BERYLIUM hyDride is Covalent in character
Magnesium hydride is covalent in character
all the above

Answer :4
19.

Choose the correct statement(s) :

Answer»

Large REDUCING nature of Be is due to large hydration energy and large VALUE of enthalpy of atomization
Alkaline earth METALS dissolve in liquid ammonia to give deep blue-black SOLUTIONS forming ammoniated ions
From the solutions of (b), AMMONIATES `[M(NH_(3))_(6)]^(2+)` can be recovered
all of the above

Solution :N//A
20.

Choose the correct statement The use of .^(12)C scale has superseded the older scale of atomic mass based on .^(16)O isotope, one important advantage of the former being

Answer»

The atomic masses on `.^(12)C` scale BECAME whole numbers.
`.^(12)C` is more ABUNDANT in the earth's crust than `.^(16)O`
The difference between the physical and chemical atomic masses got narrowed down SIGNIFICANTLY
`.^(12)C` is situated midway between metals and NONMETALS in the periodic table

Solution :The atomic masses on `.^(12)C`. Scale became whole numbers
21.

Choose the correct statement The use ""^(12)C Scale has suspended the older scale of atomic mass based in ""^16O isotope, one important advantage of the former being

Answer»

the atomic masses on `""^12C` scale became WHOLE NUMBERS.
`""^12C` is more abundant in the earth"s crust than `""^16O`
The DIFFERENCE between the physical and chemical atomic masses GOT narrowed down significantly
`""^12C` is situated midway between metals and non-metals in the periodic table

Answer :B
22.

Choose the correct statement (s) regarding the given compound

Answer»

It will not show G.I.
Total numbe of geometrical ISOMERS are two
Double bond equibalent is two
It is a BICYCLO compound

Solution : Restricted ROTATION across
this bond show geometrical isomers becomse all conditions are statified. `to` It has 2 DBE
23.

Choose the correct statement/s:

Answer»

PH of ACIDIC buffer SOLUTION decreases if more salt is added
pH of acidic buffer solution increase if more salt is added
pH of basic buffer DECRASES if more salt is added
pH of basic buffer incrases if more salt is added

Solution :N//A
24.

Choose the correct statement from the ones given below for the two anilinium ion structures .

Answer»

II is not acceptable canonical structure because carbonium ions are less stable than AMMONIUM ions.
II is not an acceptable canonical structure because it is non aromatic.
II is not an acceptable canonical structure because the nitrogen has 10 valence shell electrons .
II is not acceptable canonical structure .

ANSWER :C
25.

Choose the correct statement for the reaction

Answer»

(B) is formed more rapidly at higher
(b) is more volatile than (a)
(a) is more volatle than (b)
(a) is formed in higher yields at LOWER temperature

Solution :(a) Undergoes INTRAMOLECULAR H-bonding.
(b) Undergoes INTERMOLECULAR H-bonding.
26.

Choose the correct statement.

Answer»

1) Raoult's law is applicable to volatile SOLID solute in liquid solvent
2) Henry's law is applicable to SOLUTION containing solid solute in liquid solvent
3) For very dilute solutions, the solvent obeys Raoult's law and the solute obeys Henry's law.
4) For SATURATED solution containing volatile solid solute in liquid solvent both LAWS are obeyed.

Answer :C
27.

Choose the correct statement

Answer»

In REDOX reaction, number of ELECTRONS lost is more than number of electrons gained
In redox reaction, number of electrons lost is less than number of electrons gained
In redox reaction, number of electrons lost is EQUAL number of electrons gained
In redox reaction, no transfer and gain of electrons during the reaction.

Answer :C
28.

Choose the correct statement .

Answer»

Ce , Gd , U are Lanthanoids
Cu , AG , Au are known as coinage metals
LI is strongest reducing agent in AQ`.` SOLUTION
Reducing character decreases down the group

Answer :B::C
29.

Choose the correct set of True/False for following statements

Answer»

Silver chloride in mor soluble in very concentrated sodium choride SOLUTION than in pure water.
The `PH` of a a buffer solution does not change on addition of small amount of an acid or a base
Degree of hydrolysis of ammonia ACETATE does not depend upon the concentration of AMMONIUM acetate solution
A mixture of acetic acid and sodium acetate can act as buffer solution.

Solution :N//A
30.

Choose the correct reactivity order from the following

Answer»

`-CONH_(2) gt -COOR gt -NO_(2) gt -X gt -R`
`-CHO gt -CONH_(2) gt -NH_(2) gt -CO- gt -OH`
`-COOR gt - CONH_(2) gt - C -= N gt -CHO gt -CO-`
`-C -= N gt - COOH gt - NH_(2) gt - COOR gt - CONH_(2)`

Answer :C
31.

Choose the correct pari:

Answer»

CCF : GREEN house effect
CO: Carcinogenic
PAH :Acid RAIN
NO : LUNG injury

Solution : CCF : Green house effect
32.

Choose the correct pair.

Answer»

Chlorobenzene + chloral : DDT
Chloroform + `HNO_3`: Phosgene
Chloroform + `Zn//HCl`:METHYL isocyanide
METHANE + `4Cl_2` : CARBON TETRA chloride

Solution : Chloroform + `Zn//HCl`:Methyl isocyanide
33.

Choose the correct pair.

Answer»

`"(a)"+C(CH_(3))_(3) gt .^(+)CH(CH_(3))_(2) gt CH_(2) - CH_(3) gt CH_(3)` Relative stability of CARBOCATION
`(b)-C(CH_(3))_(3) gt .^(-)CH(CH_(3))_(2) gt .^(-)CH_(2) -CH_(3) gt.^(-)CH_(3)`, Relative stability of carbanion
`"(c)"OH^(-), RO^(-), RCOO^(-)` , Neutal NUCLEOPHILE
`(d)AICI_(3),BF_(3),FeCI_(3)`,Positively CHARGED nucleophile

Solution : `+C(CH_(3))_(3) gt .^(+)CH(CH_(3))_(2) gt CH_(2) - CH_(3) gt CH_(3)` : Relative stability of carbocation
34.

Choose the incorrect pair

Answer»

SODIUM carbonate : `Na_(2)CO_(3)`
Sodium bicarbonate : `NaHCO_(3)`
COOKING salt : NaCl
 Baking soda : `Na_(2) CO_(3)`

Answer :B
35.

Choose the correct pair. {: ( "(a) Homolytic clevage : ", " carbocation"),( "(b)Homolytic clevage : ", " carbanion") , ("(c) Homolytic clevage : " , "free radicals"),(" (d)Hetrolytic clevage :" ,"free radicals"):}

Answer»


SOLUTION :Homolytic CLEVAGE : FREE RADICALS
36.

Choose the correct pair

Answer»

Fluorine oxidation state is -1
`H_(2)` : oxidation state is +1
`Cl_(2)` : oxidation state is -1
`SO_(4)^(2-)` oxidation state of S is -4

Answer :A
37.

Choose the correct order regarding the bond order :

Answer»

`O_2^(2-) GT O_2^(+) gt O_2^(-) gt O_2`
`O_2^(+) gt O_2^(2-) gt O_2^(-) gt O_2`
`O_2^(+) gt O_2 gt O_2^(-) gt O_2^(2-)`
`O_2 gt O_2^(-) gt O_2^(2-) gt O_2^(+)`

Solution :Bond Order
`O_2^(+) = 2.5, O_2= 2, O_2^(-) = 1.5, O_2^(2-) = 1`
38.

Choose the correct order of ionization energy.

Answer»

`NgtOgtF`
`FgtOgtN`
`NgtOltF`
`OgtFgtN`

ANSWER :C
39.

Choose the correct order of atomic redii of flourine and neon (in pm) out of the options given below and justify your answer. {:((i) 72"," 160, (ii) 160","160),((iii) 72","72, (iv) 160"," 72):}

Answer»

Solution :Atomic RADIUS of F is smaller than that of NEON. Therefore, option (i) 72, 160 is correct.
40.

Choose the correct order of atomic radii of fluorine and neon (in pm) out of the options given below and justify your answer. (i) 72, 160 (ii) 160, 160 (iii) 72, 72 (v) 160 ,72

Answer»

Solution :Atomic radius of F is expressed in terms of covalent radius while, atomic radius of neon is USUALLY expressed in terms of van der WAALS. radius. van der Waals. radius of an element is always larger than its covalent radius. THEREFORE, atomic radius of F is smaller than atomic radius of Ne (F = 72 PM, Ne = 160 pm)
41.

Choosethe correctorder ofatomic radiiof fluorineand neon (in pm)out of theoptionsgivenbelow and justifyyouranswer. (i)72, 160(ii)160,160(iii)72, 72(iv)160 ,72

Answer»

SOLUTION :F has acovalentradiu whileNe hasa van derWaalsradius . Sinceby definitionvan derWaalsradiiarebiggerthan covalentradiithereforeatomicradiusof F issmaller(72 PM) whileNe (160pm) hasbiggeratomicradius . Thusoption (i) ISCORRECT .
42.

Choose the correct option(s) that give(s) an aromatic compound as the major product.

Answer»




SOLUTION :
43.

Choose the correct options:

Answer»

Favourable conditions for formation of graphite are high pressure and low TEMPERATURE from equilibrium diamond `(d=3.5g//ml)hArr` graphite `(d=2.3g//ml),Delta=-1.9kJ//"mole"`
For reaction `N_2O_4(g)hArr2NO,(g)`, DEGREE of dissociation `(alpha)` is `sqrt(K/(4P+K_P))` where P is equilibrium pressure.
For reaction `CI_2(g)+3F_2(g)hArr2CIF_3(g),DeltaH=-329kJ` ,dissociation of `CIF_3(g)` will be favoured by ADDITON of INERT gas at constant pressure.
Reaction stops at equilibrium (microscopically).

Answer :B::C
44.

Choose the correct option : T stands for True, F stands for False (A) d-block elements are known as transition metals. (B) Ionization enthalpy of Be gt B. (C) Elements of Group-1 exhibit only +1 oxidation state. (D) Group 17 contains only gaseous elements

Answer»

TFTF
TTTF
FTTT
TTFF

Solution :IONIZATION ENTHALPY of `Be GT B`
45.

Choose the correct option. T stands for True and F stands for False. (i) Tritium can be obtained from natural sources. (ii) In ionic hydride, the oxidation state of hydrogen is +1. (iii) The four atoms of oxygen in H_2O_2 are in the same plane. (iv) Na_2Co_3 removes temporary and permanent hardness of water.

Answer»

TFFF
TFFT
TTTF
TFTT

Answer :A
46.

Choose the correct option from the following to prevent soil pollution.

Answer»

Use CHEMICAL fertilizers in the farm.
Use EXTRACT on Neem, Aak and Dhatura leaves to control PESTS.
Plastic WASTES should be dumped in the soil.
Use chemical PESTICIDES to save crop.

Solution : Use extract on Neem, Aak and Dhatura leaves to control pests.
47.

Choose the correct option for the reaction given below. C_(6) H_(12) O_(6(s)) + 6O_(2(g)) to 6CO_(2(g)) + 6H_(2) O_((l))

Answer»

`Delta H lt Delta U`
`Delta H gt Delta U`
`Delta H = Delta U`
`Delta H LE Delta U`

ANSWER :C
48.

Choose the correct option for bond order and stability for Be_(2) molecule.

Answer»

2, stable
2, unstable
0, stable
0, unstable

Answer :D
49.

Choose the correct option as directed.

Answer»

`CsH gt KH gt NaH gt LIH` (Order of stability)
`H_(2)O lt NH_(3)lt CH_(4)` (Order of dipole moment)
`PH_(3)lt AsH_(3)lt NH_(3)lt SbH_(3)` (Order of boiling point)
`X---H-X, X=O gt F gt N gt S gt Cl` (Order of strength of H-bonding)

Solution :`CsH lt KH lt NaH lt LiH`
The stability of the HYDRIDES of the elements from a particular group decreases with increasing atomic number (going down the group).
`CH_(4)lt NH_(3)lt H_(2)O`
Dipole moment depends upon the difference between the electronegativities of the bonded ATOMS, and the internuclear separation.
`PH_(3)lt AsH_(3)lt NH_(3)lt SbH_(3)`
Boiling point increases with an increase in molecular mass, `NH_(3)` being an exception because of strong hydrogen bonding.
`Cl lt S lt N lt O lt F`
The strength of hydrogen bonding depends upon the ELECTRONEGATIVITY and the size. Higher electronegativity and smaller size increases the strength of hydrogen bonding.
50.

Choose the correct option:

Answer»

A' represents vapour composition and 'B' the liquid composition
A' as well as 'B' represent liquid composition
Both 'A' and 'B' represent vapour composition
A' represents liquid composition and 'B' the vapour composition

Answer :C