Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

How many electrons that can be accommodated in the subshells,p,d,f?

Answer»

SOLUTION :
Discussion
2.

How many electrons required to received by oxidising agent KMnO_(4) to converted into MnO_(4)^(-2),MnO_(2),Mn_(2)O_(3)andMn^(+2) ?

Answer»

4, 3, 1, 5
1, 5, 3, 7
1, 3, 4, 5
3, 5, 7, 1

Solution :`KMnO_(4)OVERSET(+1E^(-))to(MnO_(4))^(-2)" "[Mn(+6)]`
`KMnO_(4)overset(+3E^(-))toMnO_(2)" "[Mn(+4)]`
`KMnO_(4)overset(+4e^(-))to1/2Mn_(2)O_(3)" "[Mn(+3)]`
`KMnO_(4)overset(+5e^(-))toMn^(+2)" "[Mn(+2)]`
Discussion
3.

How many electrons maximum can have n + l = 4 in an atom.

Answer»

8
2
6
18

Solution :`n+ l = 4 , 4 s IMPLIES 2e^- , 3p implies6e^-` ,TOTAL =` 8E^-`
Discussion
4.

How many electrons is an atom with atomic number 30 can have (n + l0 = 4) ?

Answer»

5
6
7
8
Discussion
5.

How many electrons in sulphur (Z = 16) can have n + l = 3 ?

Answer»

Solution :Electronic CONFIGURATION of `._(16)S = 1s^(2) 2S^(2) 2p^(6) 3s^(2) 3p^(4)`
For `1s^(2), N + l = 1 + 0 = 1`. For `2s^(2), n + l = 2 + 0 =2`. For `2p^(6), n + l = 2 + 1 = 3`
For `3s^(2), n + l = 3 + 0 = 3` For `3p^(4), n + l = 3 + 1 = 4`
Thus, `n + l = 3 " for " 2p^(6) and 3s^(2)` electrons, i.e., for 8 electrons
Discussion
6.

How many electrons maximum can have n + 1 = 4 in an atom.

Answer»

8
2
6
18

Answer :A
Discussion
7.

How many electrons in an atom with atomic number 50 can have (n + l) = 5 ?

Answer»

10
12
18
25

Solution :
Discussion
8.

How many electrons in an atom with atomic number 105 can have (n+1)=8?

Answer»

30
17
15
upredictable

Solution :n+1=8
Electronic configuration of atom with atomic number 105 is` [RN]5f^(15)6D^(3)7s^(2)`
Discussion
9.

How many electrons in an atom with atomic number 105 can have (n+1)=8 ?

Answer»

30
17
15
unpredictable

Solution :Number of electrons in atomic orbital is EQUAL to `(N + 1)`
Discussion
10.

How many electrons in an atom with atomic number 105 can have (n + 1) = 8 ?

Answer»

30
17
15
unpredictable

Solution :n+1=8
Electronic configuration of ATOM with atomic NUMBER 105 is `[RN] 5f^(14) 6d^3 7s^2`
Discussion
11.

How many electrons in an atom may have the following quantum numbers? n=4,m_s=-1/2

Answer»

Solution :Total NUMBER of orbitals possible for 4 shell `=n^2=4^2=16` Each ORBITAL can contain one electron with `m_s=-1//2therefore` Number of ELECTRONS possible = 16
Discussion
12.

How many electrons in an atom may have the following quantum numbers ? (a) n = 3, m_(s) = -1//2 (b) n = 4, l = 0

Answer»

SOLUTION :a) 9 ELECTRONS. B) 2 electrons.2
Discussion
13.

How many electrons in an atom may have the following quantum numbers?N = 3, l = 0

Answer»

Solution :n = 3, L = 0 is3s orbital It can contain 2 electrons
Discussion
14.

How many electrons in an atom may have the folling quantum numbers?(a)n=4,m_s=-(1)/(2)(b)n=3,l=0

Answer»

Solution :(a) For n=4
Total NUMBER of elctorns =`2n^(2)2xx16=32`
Half out these will have`m_s=-(1)/(2)`
`therefore`Total electrons with `m_s(-(1)/(2))=16`
(b) For n=3
`l=0,m_l=0,m_s=+(1)/(2),-(1)/(2)("TWO "e^(-))`
Discussion
15.

How many electrons in an atom have the following auantum numbers ? (i) n=4, m_(s)=-1/2 (ii) n=3, l=0.

Answer»

Solution :(i) TOTAL ELECTRONS in `n=4` are `2 n^(2)`, i.e., `2xx4^(2)=32`. Half of them, i.e., 16 electrons have `m_(s)=-1/2`.
(II) `n=3, l=0` means 3s orbital which can have 2 electrons.
Discussion
16.

How many electrons in atom can have n =4, =2, m=-2 and s = +(1)/(2) ?

Answer»

1
2
5
10

Solution :No `2E^- s ` can have same SET of FOUR QUANTUM NUMBERS.
Discussion
17.

How manyelectrons in 2porbitalhave spin quantumnumbers=(1)/(2) ?

Answer»

6
0
2
3

Answer :D
Discussion
18.

How many electrons, electrical charge and hydrogen atom at left side balance half reduction reaction in following redox reaction respectively? Cr^(3+)+ClO_(3)^(-)toCr_(2)O_(7)^(2-)+ClO_(2)^(-) (Acidic)

Answer»

`6,+3,6`
`6,-2,6`
`6,-4,6`
`6,-3,6`

SOLUTION :`underset((+3))(Cr^(3+))+underset((+5))(ClO_(3)^(-))tounderset((+6))(Cr_(2))O_(7)^(2-)+underset((+3))(ClO_(2)^(-))`
`3ClO_(3)^(-)+6H^(+)+6e^(-)to3ClO_(2)^(-)+3H_(2)O`
Discussion
19.

How many electrons can have s+1//2in a d-sub-shell?

Answer»

SOLUTION :d' SUB-shell has FIVE orientations. Each ORIENTATION can accommodate one electron with SPIN quantum number `+1//2` and another electron with `-1//2`. Hence number of electrons with `s+1//2` in 'd' sub shell is 5
Discussion
20.

How many electrons can fit in the orbital for which n = 3 and Z = 1 ?

Answer»

2
6
10
14

Answer :A
Discussion
21.

how many electrons can be accommodated in a sub-shell for which n=3, l=1

Answer»

8
6
18
32

Answer :B
Discussion
22.

How many electrons can fit in the orbital for which n = 3 and l = 1 ?

Answer»

2
6
10
14

Solution :`N = 3, l = 1` REPRESENTS 3p-subshell which has three orbitals. In any of these orbitals, maximum electrons that can be FITTED is 2
Discussion
23.

How many electrons can be accomdated in the shell l,m and n?

Answer»

SOLUTION :
Discussion
24.

How many electrons are transferred in the oxidation of nitrite by hydrogen peroxide?

Answer»

SOLUTION :The chemical equation is
`NO_(2)^(-)+H_(2)O_(2) to NO_(3)^(-)+H_(2)O`
The change in oxidation NUMBER of each reactant is 2
Number of electrons TRANSFERRED =2
Discussion
25.

How many electrons are transferred from reductant to oxidant is the following redox As_(2)S_(3) + HNO_3 rarr H_3ASO_(4) + H_2SO_4+NO

Answer»

2
4
24
84

Solution :Oxidant `[3e^(-)+overset(5+)Nrarroverset(2+)N]xx28`
Reductant `overset(3+)(As_2)rarr2As^(5+)+4E^(-)
S_3^(2-)rarr 3s^(6+)+24e^(-)`
`(As_(2)S_3rarr2A_(s)^(5)+3s^(6+)+28)xx3`
Discussion
26.

How many electrons are there in covalent oond ?

Answer»

Solution :In each covalent bond TWO ELECTRONS are there each atom feature ONE `bar(E)` in bond.
Discussion
27.

How many electrons are shared in a double bond between two atoms ?

Answer»

SOLUTION :4 (FOUR)
Discussion
28.

How many electrons are required for the reduction of 1 mole of MnO_(4)^(-)" to "Mn^(2+) ?

Answer»

`3.011xx10^(24)`
`6.022xx10^(24)`
`1.2044xx10^(24)`
`1.8066xx10^(24)`

SOLUTION :
`therefore` Reduction half reaction :
`MnO_(4)^(-)+5bare+8H^(+)toMn^(2+)+4H_(2)O`
Thus reduction of 1 mole of `MnO_(4)^(-)`
requires 5 mole of electrons
But 1 mole electron = `6.022xx10^(23)` electron
`therefore5" mole electron"=(5xx6.022xx10^(23))/1`
= `30.10xx10^(23)`
= `3.011xx10^(24)` electrons
Discussion
29.

How many electrons are present in the ion ._(26)^(56)Fe^(2+) ?

Answer»

Solution :`._(26)FE` has 26 electrons. Hence, `Fe^(2+)` has `26 - 2 = 24` electrons.
Discussion
30.

How many electrons are present in all subshells (fully - filled) with n + l = 5 ?

Answer»

SOLUTION :Subshells with `n + l = 5` are 5S, 4p, 3D. Hence, electrons present `= 2 + 6 + 10 = 18`
Discussion
31.

How manyelectrons are presentin n= 3 orbit ?

Answer»

2
18
8
32

Solution :No OFELECTRONS`: 2N^(2)= 2(3) ^(2) =18`
Discussion
32.

How many electrons are involved during the oxidation reaction of KMnO_4 in acidic medium ?

Answer»

1
3
5
4

Solution :`MnO_4^(-)+8H^(+)+5E^(-) rarrMn^(2+)+4H_2O`
Discussion
33.

How many electrons and protons are present in the balanced half equation? NO_(2)^(-)rarrNO

Answer»

SOLUTION :`overset(+3)(NO_(2)^(-)) to overset(+2)(NO)`
`NO_(2)^(-)+2H^(+) to NO+H_(2)O`
`NO_(2)^(-)+2H^(+)+E^(-) to NO+H_(2)O`
NUMBER of ELECTRONS =1
Number of protons =2
Discussion
34.

Howmanyelectronin anatommay have thefollowingquantumnumber? (a ) n=4, m_(s )= - (1)/(2)( b) n=3, l =0

Answer»

Solution :( a)n=-4` :. `Totalelectron`=2N^(2)`
HALFOF the32- `m_(s ) `of 16electrons `=(1)/(2)`
( B)n=3 and l=0
3sorbital
3sorbitalhave only 2electrons
Numberof electron=2heving n= 3and l=2
Discussion
35.

How many eclipsed and staggered ethanes is obtained if rotation of ethane of C-C of 0 to 360^(@) ?

Answer»

SOLUTION :THREE eclipsed and three STAGGERED ethane are obtained.
From the initiation after rotation of `120^(@)` elipsed and after `240^(@)` two eclipsed conformaitons.
From the initiation of staggered of C-C CARBON rotation after `120^(@)` and `240^(@)` ONE and two total three staggered conformations are obtained.
Discussion
36.

How many different products (excluding stereoisomer) can be obtained by following reaction

Answer»


SOLUTION :
Discussion
37.

howmany different oxides are formed ?

Answer»


ANSWER :3
Discussion
38.

How many different isomeric alkynes on catalytic hydrogenation can give 2,3,4-trimethyl heptanes?

Answer»


SOLUTION :
Discussion
39.

How many different carboxylic acids are obtained when all the isomeric arenes having the molecular formula C_(8)H_(10) are oxidised with alkalise KMnO_(4) followed by acidification

Answer»


ANSWER :4
Discussion
40.

How many dichlorocyclohexane would be produced upon free radical chlorination of chlorocyclohexane?

Answer»


SOLUTION :NINE dichlorocyclohexane PRODUCTS are FORMED
Discussion
41.

How many dichloro derivatives are possible for cyclopentane?

Answer»


SOLUTION :N//A
Discussion
42.

Howmanydelocalisedpielectronsare present inbenzenemolecule ?

Answer»

Solution :Kekule.s STRUCTURE of `C_(6)H_(6)` is

THREE pi bonds are delocalised. HENCE number of delocalised ELECTRON in 6.
Discussion
43.

How many dibromo dervatives are possible for n-butane?

Answer»


SOLUTION :N//A
Discussion
44.

How many Debye is one coul-m?

Answer»

SOLUTION :Dipolemoment `mu=deltaxxl`
Assuming L as `1A^(@),4.8D=1.6 xx10^(-29)` coul-m `=3XX10^(29)D`.
Discussion
45.

How many structural cyclic isomers of C_(5)H_(10) are possible?

Answer»

SOLUTION :
Discussion
46.

How many cyclic and acyclic isomers (including tautomers) can be made by the formula C_(3)H_(6)O ?

Answer»

4
5
9
10

Solution :9 ISOMERS are POSSIBLE.
Discussion
47.

No. of possible cyclic isomers (including with stereo isomer) for the molecular formulae C_(5)H_(10)

Answer»


SOLUTION :
Discussion
48.

How many cyclic and acyclic isomers are possible for the molecular formula C_(3)H_(6)O?

Answer»

4
5
9
10

Answer :C
Discussion
49.

How many structural isomers are possible for the molecular formula C_(4)H_(8) which can undergo ozonolysis?

Answer»

4
5
9
10

Answer :C
Discussion
50.

How many crystalline allotropic forms of carbon are known ?

Answer»


SOLUTION :FOUR , diamond, GRAPHITE, fullerenes and carbon NANOTUBES.
Discussion