Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Isopropyl alcohol on treatment with excess hot conc. H_(2)SO_(4) gives a compounds X. X on treatment with HBr gives Y. Y when treated with sodium using ether as solvent gives

Answer»

n-Hexane
2,3-Dimethylbutane
2-Methylpentane
3-Methylpentane

Solution :`underset("Isopropyl alcohol")(CH_(3)-underset(OH)underset(|)(CH)-CH_(3))underset(Delta)OVERSET(Conc. H_(2)SO_(4))rarr CH_(3)CH = CH_(2) overset(HBR)rarrCH_(3)-underset(Br)underset(|)(CH)-CH_(3)underset("ester")overset(Na)rarrunderset("2,3-Dimethylbutane")(CH_(3)-overset(CH_(3))overset(|)(CH)-overset(CH_(3))overset(|)(CH)-CH_(3))`
Discussion
2.

Isopropyl alcohol on oxidation gives

Answer»

ACETONE
Ether
Ethylene
Acetaldehyde

Solution :`(CH_(3))_(2)CH-OH UNDERSET("Mild. OXID")overset([O])rarrunderset("Acetone")((CH_(3))_(2)C=O)`
Discussion
3.

Isoprene is a diene. How are the positions of double bonds located?

Answer»

Solution :The position of multiple bonds PRESENT between carbon atoms can be located by ozonolysis, Isoprene is an unsaturated HYDROCARBON with molecular formula `C_(5)H_(8)` One mole of isoprene on ozonolysis gives two moles of methanal and one mole of 2-oxopropanal. Hence isoprene has two double bonds on terminal carbon atoms and a branch on one of the double BONDED carbon atoms.
ARRANGING the ozonolysis products in a sequence, we GET,
Hence isoprene is 2-methyl-1,3-butdiene.
Discussion
4.

Isopiestic solution have:

Answer»

same vapour
pressure
same OSMOTIC pressure
same FREEZING point

Answer :A
Discussion
5.

Isopentyl is the common name for which alkyl group?

Answer»

`CH_(3)CH_(2)CH_(2)underset(CH_(3))underset("|")("C")H-`
`CH_(3)CH_(2)CH underset(CH_(3))underset("|")("C")H_(2)-`
`CH_(3)underset(CH_(3))underset("|")("C")HCH_(2)CH_(2)-`
`CH_(3)CH_(2)underset(CH_(3))underset("|")("C")H-`

SOLUTION :`CH_(3)-underset(CH_(3))underset("|")("C")H-CH-CH_(2)-` Isopentyl group.
Discussion
6.

Isopentane can form four structurally isomeric mono bromo derivatives. How many of them are cally active?

Answer»

1<BR>2
3
4

Solution :Mono bromo derivatives of ISO pentane are
1) `CH_(3)-overset(CH_(3))overset(|)CH-CH_(2)-CH_(2)-Br`

`CH_(3)-underset(Br)underset(|)overset(CH_(3))overset(|)C-CH_(2)-CH_(3)`

Among (4) isomers TWO are optically active due to the PRESENCE of chiral CENTRE
Discussion
7.

Isopentane can form four structually isomeric mono bromo derivatives. How many of them are optically active?

Answer»

1
2
3
4

Solution :`ClCH_(2)-OVERSET(**)CH(CH_(3))-CH_(2)-CH_(3)`
`CH_(3)-overset(**)CH(Cl)-CH(CH_(3))-CH_(3)`
Discussion
8.

Isopentane and neopentane are the examples for ............... .

Answer»

SOLUTION :CHAIN ISOMERISM
Discussion
9.

Isomers with the same molecular and same strctural formula are called

Answer»

GEOMETRICAL isomers
Optical isomers
Tautomers
Stereoisomers

Answer :D
Discussion
10.

Isomers which can be interconverted through rotation around a single bond are :

Answer»

conformers
diastereomers
enantiomers
positional isomers

Answer :A
Discussion
11.

……….isomers of dibromobenzne

Answer»


ANSWER :THREE
Discussion
12.

Isomerism exhibited by methyl formate and acetic acid is

Answer»

GEOMETRICAL
Stereo
Tautomerism
Functional

Answer :D
Discussion
13.

isomera of a compound must have

Answer»

Same PHYSICAL properties
Same CHEMICAL properties
Same sturtural properties
Same MOLECULAR properties

Answer :d
Discussion
14.

Isoinerisin exhibited by secondary butyl chloride and tertiary.butyl chloride is

Answer»

Chain isomerism
Geometrical isomerism
Optical isomerism
Positional isomerism

Solution :`{:(""Cl),(""|),(CH_(3)-CH-CH_(2)-CH_(3)),(" "1""2""3""4):}""{:(""CH_(3)),(""|),(CH_(3)-C-CH_(3)),(" "1" "2|""3),(""Cl):}`
Secondary butyl CHLORIDE TERTIARY butyl chloride Both are DIFFER in chain arrangement. HENCE they are chain isomers.
Discussion
15.

Isobutylene when subjected to hydroboration oxidation reaction yields

Answer»

sec-Buty alcohol
tert-Butyl alcohol
Isobutyl alcohol
n-Butyl alcohol

Solution :
ANTI MARKOWNIKOFF PRODUCT is FORMED.
Discussion
16.

Isobutyl and sec-butyl represent different alkyl groups. Do Isopropyl and sec-propyl also represent different alkyl groups ? Comment.

Answer»

Solution :Isobutyl group and sec-butyl group represent DIFFERENT structures since isobutyl group has a `CH_(3)` side CHAIN at position 2 and a free valency at position 1 while sec-butyl group has only a free valency at position 2 as shown below.

Since propyl group has three carbon ATOMS, it cannot have a `CH_(3)` side chain but an have only a free valency at position 2. Therefore, it should be actually called as sec-propyl.
`underset("sec-Propyl or Isopropyl")(underset(1)(C)H_(3)-underset(2)overset(|)(C)H-underset(3)(CH_(3)))`
But it is more commonly called as Isopropyl group which is a misnomer. Since there is no ambiguity, therefore, both isopropyl and sec-propyl represent the same alkyl group.
Discussion
17.

Isobutyl alcohol in acidic medium gives tert-butyl alcohol, the reaction is

Answer»

ADDITION REACTION
Substitution reaction
Elimination reaction
Rearrangement reaction

ANSWER :C
Discussion
18.

Isobuty alcohol (2 -mehyl 1 -1-propanol), (CH_(3))_(2)CHCH_(2)OH, can be transformed to each of the compounds (a through 1) listed in the left-hand column. In each case the number of steps the needed to accomplish the change is noted, and an answer box is noted, and answer box is provided for your reagent selections. Fourteen reagents (designated A through N) are listen in the right -hand column. corresponding to the desired compound. Write letters desiganating the raagent or reagents you believe will achieve the desired transformation in the box to the right of the product formula. In the case of a multi-step sequence write the reagents in the order they are to be used. In some cases you may wish to use a previously prepared compound as a reactant. If so, write the number (a to 1) corresponding to the desired compound.

Answer»

SOLUTION :BASIC INFORMATION of ORGANIC REACTION.
Discussion
19.

Iso-propylidene chloride is an example of ………………… .

Answer»

SOLUTION :VICINAL DIHALIDE
Discussion
20.

Iso-octane is added to petrol

Answer»

to PRECIPITATE INORGANIC material
to prevent FREEZING of petrol
to increase the BOILING point
as an antiknocking agent

Answer :D
Discussion
21.

Iso - electronicspeciesare

Answer»

`F^(-),O^(-2) `
`F^(-)O`
`F^(-),O^(+)`
`F^(-),O^(+2)`

ANSWER :A
Discussion
22.

Iso-electronic species are

Answer»

`F^- , O^(-2)`
`F^- , O`
`F^-, O^+`
`F^-, O^(+2)`

ANSWER :A
Discussion
23.

Is zero a significant figure ?

Answer»


ANSWER :31.1
Discussion
24.

_________is used to treat upset stomach and eczema

Answer»

SOLUTION :`CaSO_(4).2H_(2)O`
Discussion
25.

…..is used to convert alcohols directly into gasoline.

Answer»

SOLUTION :ZSM-5 (A TYPE of ZEOLITE)
Discussion
26.

..............is used to bleach paper.

Answer»

SOLUTION :`H_(2)O_(2)`
Discussion
27.

_____is used is fire extinguishers

Answer»

`C Cl_(2)=C Cl_(2)`
`CHCl=C Cl_(2)`
`CH_(2)=C Cl_(2)`
`C Cl_(4)`

SOLUTION :`C Cl_(4)`
Discussion
28.

______is used in the treatment of goitre

Answer»

Halothane
Benzoquinone
Chloromycetin
THYROXINE

Solution :Thyroxine
Discussion
29.

__________is used in purification and refining of sugar.

Answer»

`CA(OH)_2`
`CaO`
`CaCl_2`
`CaCO_3`

Answer :B
Discussion
30.

______is used in making armour plates.

Answer»

SOLUTION :LITHIUM + MAGNESIUM
Discussion
31.

Exudate form ________ is used in making palm sugar

Answer»

SOLUTION :LITHIUM + MAGNESIUM
Discussion
32.

_________is used in dentistry, ornamental works and making casts of statues

Answer»

SOLUTION :`CaSO_(4)1//2 H_(2)O`
Discussion
33.

Is this decomposition reaction of CaCO_3 get equilibrium in open vessel ?CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g))

Answer»

SOLUTION :No, In open VESSEL if the COMPOUND is in GAS PHASE So, equilibrium is not established.
Discussion
34.

Is there nutronin nucleus of hydrogen ?

Answer»

SOLUTION :NOTHERE isnutron in HYDROGEN
Discussion
35.

Is there multiple bond in CO_(2) ? Which is ?

Answer»

SOLUTION :YES, double BOND present between C and O. Total two double bonds in it and two double bonds with CARBON and one double bond with each oxygen.
Discussion
36.

Is there any liquid transition element? If so name it?

Answer»

SOLUTION :There is no liquid TRANSITION ELEMENT. (HG is liquid at room temperature. It is a d- block element, but not a transition element)
Discussion
37.

Is there any change in the hybridization of Boron and Nitrogen atoms as a result of the following reaction ? BF_(3)+NH_(3) rarr F_(3)BNH_(3)

Answer»

SOLUTION :there is no CHANGE In HYBRIDIZATION
Discussion
38.

Is there any change in the hybridization of B and N atoms as a result of the following reaction? BF_(3) + NH_(3) rarr F_(3)B.NH_(3)

Answer»

Solution :In `BF_(3)` hybridization of B is `sp^(2)` but in `F_(3)`B. `NH_(3)` hybridization of B is `sp^(3)`.
In `NH_(3)` hybridization of N `sp^(3)` but in `F_(3)`B. `NH_(3)` hybridization of N is `sp^(3)`.
(In `F_(3)B. NH_(3)` B and F connected by co-ordinate COVALENT bond. B & N has four-four covalent bond. So B & N both has hybridization.)
Discussion
39.

Is there any change in the hybridisation of B and N atoms as a result of the reaction , BF_(3) + NH_(3) to F_(3) B. NH_(3) ?

Answer»

Solution :In `BF_(3) B is sp^(2)`hybridised and in `NH_(3)` , N is `sp^(3)` hybridised . After the reaction, hybridisation of B
CHANGES to `sp^(3)` but that Nremains unchanged .
Discussion
40.

Is there an expansion or a contraction as titanium transforms from hep to body-centered Cubic ?The atomic radius of titanium is 145.8 pm in hep but 142.5 pm is bcc.

Answer»

Expansion of `3.2 %`
Expansion of `1.016`
CONTRACTION of `3.2 %`
Contraction of `1.016`

SOLUTION :The volume CHANGE is a result of two partically contracting factors: (1) different
packing fraction (f), and (2) different RADII
`(V("bcc"))/(V("hcp"))=(f("hcp"))/(f("bcc"))xx(V("bcc"))/(V("hcp"))`
f(hcp)=0.7404,f(bcc)=0.6802
`(V_("bcc"))/(V("hcp"))/(V_("hcp"))=(0.7404)/(0.6802)xx((142.5)^(3))/((145.8)^(3))=1.016`
Discussion
41.

Is there any change in the hybridisation of B and N atoms as a result of the following reaction BF_3+NH_3rarrF_3B . NH_3

Answer»

Solution :Boron is `sp^2` hybridised in `BF_3` and NITROGEN is `sp^3` hybridised in `NH_3`. After the reaction,the hybridisation of B CHANGES to `sp^3`,but the hybirdisation of nitrogen REMAINS UNCHANGED.
Discussion
42.

…………is the structure of 1-chloro-2-, 4-dinitrobenzene

Answer»

SOLUTION :
Discussion
43.

Is the law of conservation of mass valid for nuclear reactions ?

Answer»


ANSWER :No
Discussion
44.

……is the incorrect in the following for inductive effect?

Answer»




ANSWER :C
Discussion
45.

_______is the gold number of hydrophilic colloid, then greater is its protective power:-

Answer»

Higher
LOWER
Constant
None of these

Solution :Lower the GOLD number of a protective colloid the greater is its PROTECTIVELY ACTION.
Discussion
46.

_______is the formula of limestone

Answer»

SOLUTION :`CaCO_(3)`
Discussion
47.

is the final product obtained when one of the following reacted with base .

Answer»




SOLUTION :`NaBH_(4)` cannot REDUCE ESTERS(a)
Discussion
48.

Is the following equation balanced ? C_(2)H_(5)OH + 2O_(2) to 2CO_(2) + 3H_(2)O

Answer»

Solution :Not BALANCED because atoms of OXYGEN are not EQUAL on both SIDES.
Discussion
49.

Is the excluded volume of a real gas equal to the actual E volume of the molecules of a gas ?

Answer»

Solution :No, the excluded VOLUME of a REAL GAS is four TIMES the actual volume of the molecules.
Discussion
50.

Is the definition given below for ionization enthalpy is correct? "Ionization enthalpy is defined as the energy required to remove the most loosely bound electron from the valence shell of an atom"

Answer»

SOLUTION :No. It is not correct. The accurate and absolute definition is as FOLLOWS:
Ionization energy is defined as the MINIMUM amount of the energy REQUIRED to REMOVE the most loosely bound electron from the valence shell of the isolated neutral gaseous atom in its ground state.
Discussion