Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The compound with mol. Mass 180 is acetylated with CH_(3)COCl to get acetylated compound with mol. Mass 390. The number of amino groups present per molecule of the compound is

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2
5
4
6

Solution :`R - NH_(2) + ClCOCH_(3) rarr R - NHCOCH_(3) + HCl`
The INCREASE in mass PER acetyl group = 42 AMU
Total increase in mass `= 390 - 180 = 210`
`:.` The number of acetyl groups ADDED `= (210)/(42) = 5`
2.

The compound with an isopropyl group is

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2,2,3,3-Tetramethylpentane
2,2-Dimethylpentane
2,2,3, TRIMETHYLPENTANE
2-Methylpentane

Answer :D
3.

The compound which will give red colour in Victor Meyer's test is

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Propan-2-ol
Butan-1-ol
Butan-2-ol
tert-Butyl alcohol

Solution :`underset("Butanol-1")(H_(3)C-CH_(2)-CH_(2)-OVERSET(1^(@))(C)H_(2)-OH)`
4.

The compound which undergoes dehydration very easily is :

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2-Methylpropan-2-ol
Ethyl alcohol
3-Methylbutan-2-ol
n-Propyl alcohol

Solution :`underset((A 3^(@) "alcohol"))underset("2-Methyl propan-2-ol") (CH_(3)-underset(OH)underset(|)OVERSET(CH_(3))overset(|)(C)-CH_(3))`
Being TERTIARY in nature, the alcohol UNDERGOES DEHYDRATION most easily.
5.

The compound which produces propane on heating with HI in presence of red phosphorus is a)

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<P>`CH_3 CH_2CH_2I`
`CH_3CH_2CHO`
`CH_3CH_2CH_2OH`
All the THREE

SOLUTION :`CH_3CH_2 CH_2 I , CH_3CH_2CHO, CH_3CH_2CH_2OH`
All PRODUCE porpane on REDUCTION with HI/red P.
6.

The compound which possessestheantifluorite structure is

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`Rb_(2)S`
`PbF_(2)`
Amorphous sphalerite
`BaCl_(2)`

Solution :Some common substances with antifluorite structure are `Na_(2)O, Li_(2)O, Rb_(2)O and Rb_(2)S`.
7.

Thecompoundwhichis NOTresentasimpurityin crudeNaClis ____

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`CaSO_(4)`
`CaCl_(2)`
`MgCl_(2)`
`HCI`

ANSWER :D
8.

The compound which is not isomeric with diethyl ether is….

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METHYL n-propyl ether
butanol-1
2-methyl propan-2-ol
butanone

Answer :D
9.

The compound which is not formed during dry distillation of a mixture of calcium formate and calcium acetate is

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Methanal
Propanal
Propanone
Ethanol

Answer :D
10.

The compound which has molecular nature in gas phase but ionic in solid state is

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`PCl_(5)`
`C Cl_(4)`
`PCl_(3)`
`POCl_(3)`

SOLUTION :`PCl_(5)` EXISTS as `[PCl_(4)]^(+)[PCl_(6)]^(-)` in the SOLID state and as `PCl_(5)` molecules in the gas phase.
11.

The compound which gives the most stable carbonium ion on dehydration is :

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`(CH_(3))_(2)CHCH_(2)OH`
`(CH_(3))_(3)COH`
`CH_(3)CH_(2)CH_(2)CH_(2)OH`
`CH_(3)CHOHCH_(2)CH_(3)`

Solution :The stability of carbonium ions (carbocations) is in the ORDER `3^(@) gt 2^(@) 1^(@)`. As such a `3^(@)` alcohol will give the most STABLE CARBOCATION.
12.

The compound which gives the most stable carbonium ion on dehydrataion is

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`CH_(3) - CH_(2) - CH_(2) - CH_(2)OH`
`CH_(3) - undersetunderset(OH)(|)CH - CH_(2) - CH_(3)`
`CH_(3) - undersetunderset(CH_(3))(|)oversetoverset(CH_(3))(|)C-OH`
`CH_(3) - undersetunderset(CH_(3))(|)CH-CH_(2)OH`

Solution :`CH_(3) - oversetoverset(CH_(3))(|)undersetunderset(CH_(3))(|)C-OH OVERSET(H^(+))to`
`CH_(3) - undersetunderset(CH_(3))(|)oversetoverset(CH_(3))(|)C-overset(oplus)OH_(2) overset(-H_(2)O)to(CH)overset(oplus)C`
`3^(@)` CARBONIUM ION is more stable
13.

The compound which does not react with bromine easily at room temperature is

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phenol
2-butyne
chlorobenzene
1-pentene

Answer :C
14.

The compound which does not react with lithium aluminium hydride is

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3-penten-2-one
methyl benzoate
2-pentanol
propanenitrile

Answer :C
15.

The compound which decolourises bromine water but does not give white precipitate with Tollen's reagent.

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`C_(2)H_(2)`
`C_(2)H_(4)`
`C_(6)H_(6)`
`CH_(4)`

ANSWER :B
16.

The compound which contains both ionic and covalent bonds is

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`CH_(4)`
`C_(2)H_(2)`
KCN
KCI

Answer :C
17.

The compound which acts as an oxidising as well as a reducing agent is-

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`NaNO_3`
`Na_2O`
`Na_2O_2`
`KNO_3`

ANSWER :C
18.

The compound (where X is an O,P-directing group and Y is m-directing group) is subjected to electrophilic substitution reaction for introduction of Z. the compound formed would be

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All (A) ,(B) and ©

Solution :The ORIENTATION is DECIDED by the activeting GROUP i.e., o,p-directing (B) and (C).
19.

The compound used to manufacture phenol is

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Glycerol
Cumene
Crown ether
Lactic ACID

ANSWER :B
20.

The compound used as refrigerant is

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Westeron
HYDROGEN peroxode
GAMMAXENE
FREON

Solution :Freon
21.

The compound that would yield a 5-oxo-2-methylhexanal on ozonolysis is

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ANSWER :B
22.

The compound that will react most readily with gaseous bromine has the formula

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`C_(4)H_(10)`
`C_(2)H_(4)`
`C_(3)H_(6)`
`C_(2)H_(2)`

Solution :Gaseous Bromine reacts with ALKENE to GIVE ALLYLIC substituted product by fere radical mechanism.
`CH_(3)-CH=CH_(2)overset(Br_(2))rarr underset(Br)underset(|)(CH_(2))-CH=CH_(2)`
23.

The compound that will have a permanent dipole moment among the following is:

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ANSWER :A
24.

The compound that undergoes dehydration most readily is

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Ethyl ALCOHOL
2-methylpropan-2-ol
3-methyl-2-butanol
Propyl alcohol

Solution :Being a `3^@` alcohol, it undergoes dehydration most READILY .
25.

The compoundthat wilreact most readily with gaseous bromine has the formula …………..

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`C_(3)H_(6)`
`C_(2)H_(2)`
`C_(4)H_(10)`
`C_(2)H_(4)`

ANSWER :a
26.

The compound that undergoes decarboxylation most readily under mild conditions are

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ANSWER :B
27.

The compound that is used in nuclearindustry as protective shields and control rods is

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METAL carbonates
metal chlorides
metal oxides
metal borides

Answer :D
28.

The compound that is most reactive with alcoholic KOH is

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`CH_2=CH-Br`
`CH_3CH_2Br`
`(CH_3)_2CH-Br`
`CH_3COCH_2CH_2Br`

ANSWER :D
29.

The compound that does not undergo hydrolysis by S_(N)1 mechanism is

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`CH_(2)=CHCH_(2)CL`
`C_(6)H_(5)Cl`
`C_(6)H_(5)CH_(2)Cl`
`C_(6)H_(5)CH(CH_(3))Cl`

Solution :ARYL halides (`C_(6)H_(5)Cl`) do not undergo hydrolysis by `S_(N)1` mechanism under ordinary conditions.
30.

The compound that does not produce nitrogen gas by thermal decomposition is

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`BA(N_(3))_(2)`
`(NH_(4))_(2)Cr_(2)O_(7)`
`NH_(4)NO_(2)`
`(NH_(4))_(2)SO_(4)`

SOLUTION :Only `(NH_(4))_(2)SO_(4)` on heating does not give `N_(2)` but gives `NH_(3)`
`(NH_(4))_(2)SO_(4)hArr2NH_(3)+H_(2)SO_(4)`
31.

The compound that does NOT liberate CO_(2) , on treatment with aqueous sodium bicarbonate solution is :

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BENZOIC ACID
Benzenesulphonic acid
Salicylic acid
Carbolic acid (PHENOL)

ANSWER :D
32.

The compound that does not give a tribromo derivative on treatment with bromine water is

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Solution :OH group is O, P directing `-SO_(3)H & -COOH` liberate `SO_(3) & CO_(2)` GASES through Ipso substitution.
33.

The compound that decolourises alk. KMnO_4is

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`C_3H_8`
`C_2H_4`
`CH_4`
`"CCL"_4`

ANSWER :B
34.

The compound that can work both as oxidising and reducing agent is _____

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`KMnO_(4)`
`H_(2)O_(2)`
`BaO_(2)`
`K_(2)Cr_(2)O_(7)`

Solution :Hydrogen peroxide `(H_(2)O_(2))` acts as a both OXIDISING and REDUCING AGENT.
35.

The compound that can work both as an oxidizing and reducing agent is

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` KMnO_4`
` H_2O_2`
` Fe_2 (SO_4)3`
`K_2Cr_2O_7`

Solution :`overset(+7)(KMnO_4),overset(-1)(H_2O_2),overset(+3)(Fe_2)(SO_4)_3,K_(2)overset(+6)(Cr_2O_7)`
Element is its intermediate O.S can work both as an O.A &R.A
36.

The compound showing below is cyclic hemiacetal of

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5-Hydroxyheptanal
6-Hydroxy -3-heptanone
5-Hydroxy-2- heptanone
6-Hydroxy heptanal

Solution :
37.

The compound (s) with two lone pairs of electrons on the central atom is (are)

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`BrF_(5)`
`CIF_(3)`
`XeF_(4)`
`Sf_(4)`

SOLUTION :In `BrF_(5),Br` has 7 valence electrons ,five are shared
with five F atoms . Hence, lonepair =1
In`CIF_(3)` Cl has 7 valence electrons, three are
shared with three F atom, lone pairs =2.
In`XeF_(4)`,Xe has 8 valence electrons, FOUR are
shared with four F atoms, lone pairs =2
In`SF_(4),S` has 6 valence electrons, four are shared
with four F atoms, lone pair =1
38.

The compound R is :

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SOLUTION :
39.

The compound Q is :

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SOLUTION :
40.

The compound [Pd(C_(x)H_(y)N_(z)](CIO_(4))_(2) contains 30.15% carbon and 5.06% hydrogen. The compound [Pb(C_(x)H_(y)N_(z)] (SCN)_(2) contains 40.46% carbon and 5.94% hydrogen. Calculate x, y,z.

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Answer :`x = 14, y = 28, Z = 4`
41.

The compound prepared by substitution reaction of benzene is

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ACETOPHENONE 
GLYOXAL 
CYCLOHEXANE
Hexabromo cyclohexane 

ANSWER :A
42.

The compound P is :

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SOLUTION :
43.

The compound of 'X' and 'Y' may be:

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`Na_(2)CO_(3),BaCO_(3)`
`Na_(2)SO_(4),BaSO_(4)`
`Na_(2)S_(2)O_(3),MnO(OH)_(2)`
`Na_(2)SO_(4),(BaSO_(4)+MnO)(OH)_(2))`

ANSWER :B
44.

The compound of which alkali metal gives crimsonred I'm flame test?

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Li
Na
K
Rb

Answer :A
45.

The CompoundM-O-H canactbothas anacid orbasedependinguponthe ionizationenthalpyofthe elementM. Justify by takingelements(M) of the thirdperiodof the periodic table .

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Solution :If theionizationenthalpy of theelements M islow it has astrongtendencyto getoxidisedto `M^(+)` . As aresult the M-OHbond willbreakto produce `M^(+)` and `OH^(-)` ions andhencethe compoundM-OHactsas a base

Furtherlower theionizationenthalpy of THEELEMENT (M) , stronger is the basic strength of thecompound M-O-H.Sincein generalionizationenthalpyincreases fromleftto rightin aperiodthereforebasiccharacterdecreasesin the sameorder. ThusNaOHis thestrongest basicfollowedby Mg `(OH)_(2)` while`A1(OH)_(3)`is theweakestbase. Infact`A1(OH)_(3)`is AMPHOTERICIN character.
On theotherhandif theionizationenthalpyof the elementsM is high is haslittletendency ofgetconvertedinto `M^(+)` ion. Insteadthe compoundM-OH ionizationto produce `H^(+)` ionsand hencethe compoundM-O-H behavesas an acid.

Furtherhigher the IONIZATIONENTHALPY of theelement (M), stronger isthe acidicstrengthof the compound M-O-H.Sincein generalionizationenthalpyincreasesfrom lefttorightin aperiod acidiccharacterincreasesin thesameorder. forexample`Si(OH)_(4) " or" H_(2) SiO_(3)` is the weakestacid O=`P(OH)_(3)" or" H_(3) PO_(4)` is astronger acidthan `H_(2) SiO_(3), O_(2) S(OH)_(2)" or" H_(2)SO_(4)` is amoderratelystrong acidwhile`O_(3) CI(OH)` or `HC1O_(4)` is thestrongest acid .
Thusfrom theabovediscussionit follows that as theionizationenthalpy of the element (M)increases from left to rightin a periodthe basiccharacterof thecompoundMOHdecreases whilethe acidic characterincreases.
46.

The compound insoluble in acetic acid is.....

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CALCIUM oxide
calcium carbonate
calcium oxalate
calcium HYDROXIDE

ANSWER :C
47.

The compound insoluble in acetic acid acid is

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`CAO`
`CaCO_(3)`
CALCIUM oxalate
`Ca(OH)_(2)`

Solution :Calcium oxalate is insoluble in ACETIC acid
48.

The compound in which oxygen number of oxygen is +2 is ………………..

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ANSWER :`OF_(2)`
49.

The compound in which Causes only SP^3hybrid orbitals for bond formation is

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HCOOH
`(NH_(2))_(2)CO`
`(CH_(3))_(3)COH`
`CH_(3)CHO`

SOLUTION :`CH_(3)-overset(CH_(3))overset("|")underset(CH_(3))underset("|")("C")-OH`
All CARBONS are `Sp^(3)` hybridised.
50.

The compound in which cation occupy alternate tetrahedral voids in cubic closed packing (ccp)

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NaCl
ZNS
`Na_(2) O`
CaF_(2)`

Solution :In `ZnS, S^(2-)` ions form fcc (or ccp) lattice in which `ZN^(2+)` (cations) occupy ALTERNATE tetrahedral voids.