Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The product 'E' is :

Answer»

`CH_3-CH_2-CH=CH_2`
`CH_3-CH=CH-CH_3`
`CH_2=CH_2`
`CH_3-CH=CH_2`

ANSWER :A
Discussion
2.

The product 'F' is :

Answer»

`C_2H_5SH`

`CH_3SH`

ANSWER :C
Discussion
3.

The product C of the following sequence is :

Answer»




SOLUTION :
Discussion
4.

The product {:(CH_(2)OOC CH_(3)),("|"),(CH_(2)OOC CH_(3)):} is obtained by the reaction of

Answer»

Acetone and Glycol
Ethanal and Ethanol
Glycol and `CH_(3)COCL`
GLYCEROL and `(CH_(3)CO)_(2)O`

SOLUTION :Glycol and `CH_(3)COCl`
Discussion
5.

The product A will be

Answer»




Solution :Relative ACID strength of VARIOUS active hydrogens. In the compound is `-overset(O)overset(||)(C)-O-H gt -OH` attched to `NO_(2)` in the benzene ring `gt -OH` to simple benzene ring `gt -C-=C-H`. Hence first TWO active hydrogen will be removed by two `-NH_(2)^(Θ)` ions.
Discussion
6.

The prod electron is transferred towards the attacking reagent it is called ____________

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`+I ` EFFECT
`-I` Effect
`-E` Effect
`+E ` Effect

SOLUTION :N/A
Discussion
7.

The processes commonly used for the separation and purification of organic substances are crystallisation, sublimation and

Answer»

Stearn DISTILLATION
FRACTIONAL distillation
EXTRACTION with SOLVENTS
All of the above

ANSWER :D
Discussion
8.

The process with negative entropy change is

Answer»

Dissolution of iodine in water
Synthesis of ammonia from `N_(2)` and `H_(2)`
Dissociation of `CaSO_(4)(s)` to `CAO(s)` and `SO_(3)(G)`
Sublimation of dry ice.

Solution :`N_(2)(g) + 3H_(2)(g) to 2NH_(3)(g)`
Decrease in number of gaseous molecules.
Discussion
9.

The process whereby a hydrogen atom attached to the alpha-carbon carbonyl compound moves to the cabonyl oxygen atom is nown as enolization or keto-enol tautomerism. Isomeric carbonyll and enol structures are tautomers. Normally, the carbonyll form is favoured but structural factor market affect K_(T). Which of following compounds will not exhibit enolization?.

Answer»




`Ph-OVERSET(O)overset(||)(C)-CH_(3)`

Solution :`ALPHA`.H absent in C
Discussion
10.

The process whereby a hydrogen atom attached to the alpha-carbon carbonyl compound moves to the cabonyl oxygen atom is nown as enolization or keto-enol tautomerism. Isomeric carbonyll and enol structures are tautomers. Normally, the carbonyll form is favoured but structural factor market affect K_(T). Which of the following does not exits in enol forms?

Answer»



`CH_(3)-overset(O)overset(||)(C)-C-UNDERSET(O)underset(||)(C)-CH_(3)`
`CH_(3)-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-CH_(3)`

SOLUTION :Transitoid form is stable Can't for INTERMOLECULAR its bond
Discussion
11.

The process whereby a hydrogen atom attached to the alpha-carbon carbonyl compound moves to the cabonyl oxygen atom is nown as enolization or keto-enol tautomerism. Isomeric carbonyll and enol structures are tautomers. Normally, the carbonyll form is favoured but structural factor market affect K_(T). Arrange the following compounds in decreasing order of k_(T) (Tautomeric constant)

Answer»

`PgtQgtR GTS`
`SgtQgtPgtR`
`QgtRgtPgtS`
`SgtPgtRgtQ`

SOLUTION :RESONANCE and ACTIVE metyle GROUP
Discussion
12.

The process used for the removal of hardness of water is

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Baeyer
Calgon
Hoope
Serpeck

Answer :B
Discussion
13.

The process requiring the absorption of energy is

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`F RARR F^(-)`
`CL rarr Cl^(-)`
`O^(-) rarr O^(-2)`
`H rarr H^(-)`

Answer :C
Discussion
14.

The process requiring absorption of energy is (1) F to F^(-) (2) Cl to Cl^(-) O to O^(2-) (4) H to H^(-)

Answer»


SOLUTION :`O to O^(-)" (is EXOTHERMIC) but "O^(-) to O^(2-)" (is ENDOTHERMIC) and OVERALL " O to O^(2-)" (is endothermic)"`
Discussion
15.

The process of zone refining is used in the purification of

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SI
Al
Ag
Cu

Solution :ZONE REFINING is USED for the PURIFICATION of Si.
Discussion
16.

The process of warming of the earth is known as ……………

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GREEN house EFFECT
Global warming
Both (A) and (B)
OZONE effect

SOLUTION : Both (A) and (B)
Discussion
17.

The process of setting of cement under water is essentially an oxidation process.

Answer»


Solution :Process of SETTING of CEMENT under WATER is essentially an HYDRATION process.
Discussion
18.

The process reduction. involves

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addition of `O_2`or REMOVAL of `H_2`to a MOLECULE
addition of a non-METAL or removal of metal
LOSS of electrons
Addition of electrons

Solution :Oxidation is `rarr`addition of `O_2`
`""rarr`removal of `e^(-)`
`""rarr`removal of Hydrogen
`""rarr` Increase in oxidation no .
Discussion
19.

The process of evaporation of a liquid is accompanised by (A) Increase in enthalpy (B) Increase in entropy ( C) Decrease in Gibbs energy The correct statement(s) is/are

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Only a and C 
Only B and c 
Only a and b 
All

Answer :D
Discussion
20.

The process of eutrophication is due to

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increase in CONCENTRATION of insecticide in water
increase in concentration of fluoride ion in water
the reduction in concentration of the DISSOLVED oxygen in water DUE to phosphate pollution in water
attack of younger leaves of a plant by PEROXYACETYL nitrate

Answer :C
Discussion
21.

The process of 'eutrophication' is due to

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Increase in concentration of INSECTICIDE in water.
increase in concentration of FLUORIDE ION in water.
the reduction in concentration of the dissolved oxygen in water due to phosphate pollution in water.
attack of younger leaves of a plant by PEROXYACETYL nitrate.

Solution :the reduction in concentration of the dissolved oxygen in water due to phosphate pollution in water.
Discussion
22.

The process of eutrophication is due ot

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increase in the concentration of INSECTISIDE in WATER
increase in concentration of lfuroide in waater
the REDUCTION in concentratoion of the dissolved oxygen in water due to phosphate pollution in water
attack of younger leaves of a plant buy peroxyacetylnitrate

Answer :C
Discussion
23.

The process of dialysis finds application in the purification of blood by artifical kidney.In this impure blood is introduced in the artificial kidney, apparatus, where the waste material (electrolyte) diffuses through the membrane. The membrane used in the dialyser is different from the membrane used in osmosis. these membrane allow the movement of ions through them. Blood is a negatively charged sol. The haemogolobin particles carry a positive charge. Blood is slightly alkaline (pH 7.36-7.42). Acidic salts like alum and FeCI_3 decrease the pH of the blood and the denaturation of globular proteins present in blood takes place. Due to denaturation, these globular proteins become fibrous which are insoluble and stop bleeding . Blood is lyophobic in nature. which of the following is/are lyophobic colloids?

Answer»

BLOOD
STARCH
GELATIN
GOLD

ANSWER :A,D
Discussion
24.

The process of dialysis finds application in the purification of blood by artifical kidney.In this impure blood is introduced in the artificial kidney, apparatus, where the waste material (electrolyte) diffuses through the membrane. The membrane used in the dialyser is different from the membrane used in osmosis. these membrane allow the movement of ions through them. Blood is a negatively charged sol. The haemogolobin particles carry a positive charge. Blood is slightly alkaline (pH 7.36-7.42). Acidic salts like alum and FeCI_3 decrease the pH of the blood and the denaturation of globular proteins present in blood takes place. Due to denaturation, these globular proteins become fibrous which are insoluble and stop bleeding . Blood is lyophobic in nature. which of the following statements is/are not true ?

Answer»

Blood is positively charged SOL
soap solution contians ionic micelles as the colloidal particles
blood is purified by the process of dialysis
`CA^(2+)` and `K^(+)` COAGULATION of blood if added in ECESS

ANSWER :A
Discussion
25.

The process of dialysis finds application in the purification of blood by artifical kidney.In this impure blood is introduced in the artificial kidney, apparatus, where the waste material (electrolyte) diffuses through the membrane. The membrane used in the dialyser is different from the membrane used in osmosis. these membrane allow the movement of ions through them. Blood is a negatively charged sol. The haemogolobin particles carry a positive charge. Blood is slightly alkaline (pH 7.36-7.42). Acidic salts like alum and FeCI_3 decrease the pH of the blood and the denaturation of globular proteins present in blood takes place. Due to denaturation, these globular proteins become fibrous which are insoluble and stop bleeding . Blood is lyophobic in nature. The coagulating power of an electrolyte for blood decreases in the order :

Answer»

`NA^+`, `AL^(3+)`, `Ba^(2+)`
`PO_4^3-, SO_4^2-, CI^-`
`Al^(3+),Ba^(2+),Na^+`
`Cl^(-),SO_(4)^(2-),PO_(4)^(3-)`

ANSWER :C
Discussion
26.

The process of dialysis finds application in the purification of blood by artifical kidney.In this impure blood is introduced in the artificial kidney, apparatus, where the waste material (electrolyte) diffuses through the membrane. The membrane used in the dialyser is different from the membrane used in osmosis. these membrane allow the movement of ions through them. Blood is a negatively charged sol. The haemogolobin particles carry a positive charge. Blood is slightly alkaline (pH 7.36-7.42). Acidic salts like alum and FeCI_3 decrease the pH of the blood and the denaturation of globular proteins present in blood takes place. Due to denaturation, these globular proteins become fibrous which are insoluble and stop bleeding . Blood is lyophobic in nature. To stop bleeding , FeCI_3 is applied locally because :

Answer»

`FeCI_3` seals the blood vessels
`FeCI_3` changes the direction of blood FLOW
`FeCI_3` REACTS with blood to form a SOLID substance which seals the blood vessel
`FeCI_3` causes DENATURATION of PROTEINS present in blood

Answer :D
Discussion
27.

The process of dialysis finds application in the purification of blood by artifical kidney.In this impure blood is introduced in the artificial kidney, apparatus, where the waste material (electrolyte) diffuses through the membrane. The membrane used in the dialyser is different from the membrane used in osmosis. these membrane allow the movement of ions through them. Blood is a negatively charged sol. The haemogolobin particles carry a positive charge. Blood is slightly alkaline (pH 7.36-7.42). Acidic salts like alum and FeCI_3 decrease the pH of the blood and the denaturation of globular proteins present in blood takes place. Due to denaturation, these globular proteins become fibrous which are insoluble and stop bleeding . Blood is lyophobic in nature. Which of the following colloidal solutions does not contain negatively charged particles?

Answer»

`FE(OH)_3`
`As_2S_3`
BLOOD
GOLD sol

Answer :A
Discussion
28.

The process of adding impurities to a crystalline substance so as to change its properties like conductivity etc. is called __________

Answer»


ANSWER :DOPING
Discussion
29.

In which process there is no exchange of heat between the system and surrounding during the process ?

Answer»

SOLUTION :ADIABATIC PROCESS
Discussion
30.

The process in which the volume of the system remains constant is called _____

Answer»

SOLUTION :ISOCHORIC PROCESS
Discussion
31.

The process in which liberation of energy associated in the

Answer»

`F to F^-`
`H to H^-`
`CL to Cl^-`
`O to O^(2-)`

Answer :A::B::C
Discussion
32.

The process 1/2 H_(2)(g)+e^(-) to H^(-)(g) is endothermic (DeltaH=+151kJ mol^(-)), still ionic hydrides are known. How do you accound for this:

Answer»

Solution :In the formation of solid ionic hydrides, energy is released as released as ENTHALPY `Delta_(F)H` from the corresponding ions in the GASEOUS state that are involved in the hydride. This compensates the energy which is needed for the formation of `H^(-)` ions from `H_(2)` GAS
Discussion
33.

The process 1/2 H_(2)(g) + e^(-) to H^(-)(g) is endothermic(DeltaH=+151 KJ "mol"^(-1)) , yet salt like hydrides are known. How do you account for this ?

Answer»

Solution :It is true that formation of hydride `(H^(-))` ion is an endothermic process, yet ALKALI and alkaline earth metals form salt like hydrides. This is DUE to the REASON that high lattice ENERGY released (energy released during the formation of solid metal hydrides from their correspoinding gaesous IONS, `M^(+) (g) and H^(-)(g))` more than compensates the energy needed for the formation of `H^(-)` ions from `H_(2)` gas.
Discussion
34.

The probability of finding the electron in the orbital is

Answer»

zero at the NUCLEUS
Maximum on two opposite SIDES of the nucleus ALONG X-axis
Zero on Z-axis
same on all sides around the nucles.

Answer :A::B::C
Discussion
35.

The probability of finding electron in XY plane for P_(Z) - orbital is

Answer»

1
0.5
`99.9%`
0

Answer :D
Discussion
36.

The probability of finding an electron in the P_x orbital is

Answer»

ZERO at nucleus
the same on all the sides AROUND nucleus
zero on the z-axis
maximum on the TWO OPPOSITE sides of the nucleus along the x-axis

Solution :zero at nucleus , zero on the z-axis , maximum on the two opposite sides of the nucleus along the x-axis
Discussion
37.

The probability of finding an electron in p_(y) orbital along the x-axis is

Answer»

Maximum
ZERO
Not determined
Infinite

Solution :For `P_y` ORBITAL XZ is the nodel PLANE
Discussion
38.

The probability density plots of Is and 2s orbitals are given in The density of dots in a region represents the probability density of finding electrons in the region. On the basis of above diagram which of the following statements is incorrect

Answer»

Is and 2s orbitals are SPHERICAL in shape.
Is and 2s orbitals are spherical in shape.
The probability of FINDING the electron at a GIVEN distance is equal in all directions
The probability density of electrons for 2s orbital decreases uniformly as distance from the NUCLEUS INCREASES.

Solution :The probability density of electrons in 2s orbital first increases then decreases and after start to increases again as distance increases from nucleus.
Discussion
39.

The principle which gives a system to fill the electrons in increasing order of energy level is

Answer»

HUND's RULE
PAULI's exclusion PRINCIPLE
Aufbau'sprinciple
None of these

Answer :C
Discussion
40.

The principle involved in paper chromatography is

Answer»

adsorption
partition
solubility
volatility

Solution :Paper CHROMATOGRAPHY is a type of partition chromatography which is based on the principle continuous DIFFERENTIAL partitioning of components of a mixture between STATIONARY and MOBILE phase.
Discussion
41.

The principle involved in paper chromatography is………

Answer»

adsorption
partition
solubility
volatility

Solution :In paper chromatography, separation of the components of a MIXTURE DEPENDS upon their partitioning between water HELD in two STATIONARY phase (i.e., paper) and the liquid present in the mobile phase
Discussion
42.

The principle involved in paper chromatography is ........... .

Answer»

SOLUTION :PARTITION
Discussion
43.

The principle involved in Ammonia-solvay process is

Answer»

Low solubility of `Na_(2)CO_(3)`
High solubility of `Na_(2)HCO_(3)`
Low solubility of `NaHCO_(3)`
High hydration ENERGY and lattice energy of `NaHCO_(3)` 

ANSWER :C
Discussion
44.

The principal quantum number represents

Answer»

Shape of an orbital
Distance of electron from nucleus
Number of electrons in an orbit
Number of ORBITALS in an orbit

Answer :B
Discussion
45.

The principal quantum number of an atom is related to the

Answer»

SIZE of the ORBITAL
spin angular momentum
orbital angular momentum
orientation of the orbital in SPACE

Answer :A
Discussion
46.

The principal organic product formed in the reaction CH_(2) = CH (CH_(2))_(8) COOH + HBr overset("Peroxide")rarr is

Answer»

`CH_(3) CH (Br) (CH_(2))_(8) COOH`
`CH_(2) = CH (CH_(2))_(8) COBr`
`CH_(2)Br (CH_(2))_(9) COOH`
`CH_(2) = CH (CH_(2))_(7) CHBr COOH`

SOLUTION :`H_(2)C = CH(CH_(2))_(8) COOH + HBR OVERSET("Peroxide")rarr CH_(2)Br.(CH_(2))_(9) COOH`
Discussion
47.

The principal products obtained on heating iodine with cold and concentrated caustic soda solution

Answer»

`NaI0_(4) + NAI`
`NaI_(0) + NaI0_(3)`
`NaIO_(3) +NaI_(2)`
NalO + Nal

Solution :`2NaOH+I_(2)rarrNaI+NaOI+H_(2)O`
Discussion
48.

The principal buffer present in human blood is

Answer»

`NaH_(2)PO_(4)+Na_(2)HPO_(4)`
`H_(3)PO_(4)+NaH_(2)PO_(4)`
`Na_(2)HPO_(4) + Na_(3)PO_(4)`
`H_(2)CO_(3)+HCO_(3)^(-)`

Answer :D
Discussion
49.

The primary salt formed when H_2O_2 reacts with NaOH , is

Answer»

`Na_2O_2`
`NaO_2`
`NaHO_2`
`NA(OH)CL`

ANSWER :C
Discussion
50.

The pressure -volume work for an ideal gas canbe calculated by using the expression w= -int_(V_(l))^(V_(f))p_(ex)dV.The workcan also be calculated from the pV - plotby using the area under the curve within the specified limit. When anideal gas is compressed(a)reversibly or (b) irreversibly from volumeV_(i) to V_(f), choose the correct option.

Answer»

<P>W ( reversible)=w ( irreversible)
w( reversible) `lt` w ( irreversible)
w ( reversible) `gt` w ( irreversible)
w(reversible)`=`w ( irreversible) `+p_(EX) DELTAV`

SOLUTION :Look at Fig.page. Area under the curvein Figure. (a) Which is for irreversible compression is more than the area under tha curve in Figure.Which is for reversible compression. Hence, for compression `w( rev) lt w ( "irrev")`.
Discussion