Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What is called troposphere? How many layers are present in it? Give their names

Answer»

Solution :(i) The LOWEST layer of the atmosphere is called the troposphere and it extends from 0 10 km from the earth surface.
(ii) About 80% of the MASS of the atmosphere is in this layer. 3 LAYERS are present in it.
(iii) They are (1) Hydrósphere, (2) Lithosphere and (3) BIOSPHERE
Discussion
2.

Under which situtions can be amorphous substance change to crystalline form ?

Answer»

As a RESULT of slow heating and COOLING over a long period, an amorphous solid ACQUIRES some crystalline CHARACTER e.g., window glass of old buildings.

Answer :`(i) to ©, (ii) to (a), (III) to d, (iv) to b `
Discussion
3.

Which are the source of the following acid or present in our body ?(i) Hydrochloric acid (ii) Acetic acid (iii) Ascorbic acid (iv) cytric acid (v) Tartaric acid

Answer»

Solution :(i)Hydrochloric acid : It is secreted as digestive juice in stomach, DAILY 1.2 to 1.5 L secreted. It is required for digestion.
(ii) Acetic Acid It is main component of VINEGAR.
(III) Circtic Acid : It is the main component of LEMON and ORANGE.
(iv) Ascorbic Acid : In lemon and orange juice
(v) Tartaric Acid : In tamarind
Discussion
4.

Which of the following species is not stable ?

Answer»

`[SiCl_6]^(2-)`
`[SiF_6]^(2-)`
`[GeCl_6]^(2-)`
`[SN(OH)_6]^(2-)`

SOLUTION :Ge, Sn, Si FORM these species `[GeCl_6]^(2-) , [Sn(OH)_6]^(2-) , [SiF_6]^(2-)`due to the presence of d-orbital where as Si will not form `[SiCl_6]^(2-)`because Si can accomodate MAXIMUM 4 `Cl^-`
Discussion
5.

What are th oxidation number of the underlined elements in each of the following and how do you rationalize your results ? (a) KI_(3) (b) H_(2)S_(4)O_(6) (c )Fe_(3)O_(4) (d) CH_(3)CH_(2)OH (e )CH_(3)COOH

Answer»

Solution :(A) in `KI_(3)` since the oxidation number of K is +1 therefore the average oxidation number of iodine =-`1//3` but the oxidation numbercannot be fractional therefore we must consider its structure `K^(+)[I-lrarr]^(-)` here a coordinate bond is formed between `I_(2)` moleceul and `T^(-)` ion the oxidation number of two IODIN eatoms forming the `IO_(2)` molecure is zero while that of iodine forming the coordinate bond is -1 thus the O.N of there I atoms atoms in `KI_(3)` are 0,0 and -1 respectively
(b) By conventional method O.N of S in `H_(2)S_(4)O_(6) =overset((+1)H_(2)overset(x)S_(4)overset(-2)O_(6) or 2(+1)`
(b) By conventional method O.N of S in `H_(2)S_(2)O_(6)=H_(2)S_(4)O_(6)`
or 2(+1) +4 x+6 (-2) =0 or x=+2.5 (wrong)
but it is wrong because all the FOIU S atoms cannot be int he same oxidation state by chemical bonding method the structure of `H_(2)S_(4)O_(6)` is show below
`H-O overset(+5)-underset(O)underset(||)overset(O)overset(||)S-overset(S)-overset(0)S-underset(O)underset(||)overset(O)overset(||)Soverset((+5)-OH`
The O.N of each of the S atoms linked witheach other in the middle is zero whilethat of each of the remaining two S atoms is +5
(c ) By conventional method O.N of Fe in `Fe_(3) O_(4)^(-2)` therefore of Fe in `Fe_(3)O_(4)^2` and +3
(d) By conventional method O.N of Cin `H_(3)CH_(2)OH =C_(2)H_(6)O`
or 2x+6(+1)+1 (-2) =0or x=-2
by chemical bonding `C_(2)` is ATTACHED to threeH atoms (less electronegative than carbon ) and one `CH_(2)OH` group (more electronegative than carbon) therefore
`H overset(2)-underset(H)underset(|)overset(H)overset(|)C-underset(H)underset(|)overset(H)overset(|)C-OH`
O.N of `C_(2)=3(+1)+x1(-1)=0 or x=-2`
`C_(1)` is however attachedot one OH (O.N =-1) and one `CH_(3)`(O.N)=+1group
(e ) By conventional method `CH_(3)COOH=C_(2)H_(4)O_(2) or 2x+4-4=0 or x=0`
by chemical bonding method `C_(2)` is attached to three h atomsand one -COOH group (more electronative than carbon)
`H-underset(H)underset(|)overset(H)overset(|)C-overset(O)overset(||)C-OH` n
`C_(1)` is however attached to one oxygen atom by double bond one OH(O.N =-1) and one `CH_(3)(O.N=+1)` group therefore therefore O.N of `C_(1) =+1+x+1(-2)+1 =0 OH or x=+2`
Discussion
6.

Which one of the relationship is wrong?

Answer»

2 Vapour DENSITY -MOL. Mass
At. Mass `="Eq. mass "XX " VALENCY"`
At. Mass `=(6.4)/("Sp. Heat")`
`"Valency"=("Mol. Mas")/("Eq. mass")`

Answer :D
Discussion
7.

Which of the followingelementscan showcovalencygreater than4 ?

Answer»

Be
P
S
B

SOLUTION :Elements Be and B LIE INTHE 2ndperioc. Theycan have amaximumof 8 ELECTRONICIN thevalenceshellInother words they can have amaximumcovalency of `8//2` = 4.Howeverelements P andS havevacant d- orbitalin theirrespectivevalenceshellsand hencecan accommodatemore than8 electrons in their respectivevalencel shells. In otherwordsthey canshow a covalencyof morethan 4. Thus , options ( b)and ( C)are correct.
Discussion
8.

Which of the following species are expected to have spectrum similar to hydrogen?

Answer»

`He^(+)`
`He^(2+)`
`LI^(2+)`
`Li^(+)`

ANSWER :A::C
Discussion
9.

Which of the following represents an electrophilic substitution reaction ?

Answer»

WURTZ reaction
Kolbes electrolysis
Friedel-Crafts ALKYLATION
DEHYDROHALOGENATION

SOLUTION :Friedel-Crafts alkylation
Discussion
10.

The typical reaction of benzene and other aromatic compounds is electrophilic substitution. Presence of electron donating group activates the ring towards electrophilic substitution, while presence of electron withdrawing group deactivates the ring towards electrophilic substitution but at the same time activates the ring towards nucleophilic substitution. Some groups are predominantly meta directing and all of these are deactivating. Except halogen, most of the o- and p- directing groupsare activating groups. (E.A.S = Electrophilic aromatic substation) The reaction of toluene with Cl_2 in presence of FeCl_3 gives predominantly:

Answer»

<P>m-chlorotoluene
Benzoylchloride
BENZYL chloride
o-chloro TOLUENE and p-choro toluene

SOLUTION :`-CH_3 ` Is O and P DIRECTOR
Discussion
11.

The typical reaction of benzene and other aromatic compounds is electrophilic substitution. Presence of electron donating group activates the ring towards electrophilic substitution, while presence of electron withdrawing group deactivates the ring towards electrophilic substitution but at the same time activates the ring towards nucleophilic substitution. Some groups are predominantly meta directing and all of these are deactivating. Except halogen, most of the o- and p- directing groupsare activating groups. (E.A.S = Electrophilic aromatic substation) Presence of nitro group in benzene ring:

Answer»

Deactivates the RING for E.A.S. REACTION
Activates the ring for B.A.S. REACTIONS
No EFFECT the ring for E.A.S reaction
Deactivate the ring for SN reactions

SOLUTION :`-NO_2` is meta directing and deactivate the benzene ring
Discussion
12.

When 159.5g of CuSo_4solution is reacted with KI, then the liberated iodine required 100 ml of 1 M Na_(2) S_(2)O_3for complete reaction, then what is the percentage purity of Cu in CuSO_4solution

Answer»

`10%`
`20% `
` 5%`
`40%`

Solution :No. of milli equivalents `Cu^(+2) = 100 `
`Cu^(+2) = 100 xx63.5 xx10^(-3) = 6.35 g`
159.5 of `CuSO_4` should CONTAIN = 63. 5 g of COPPER
but only 6.35g Cu is PRESENT
% purity = `(6.35 )/(63.5)xx100 = 10%`
Discussion
13.

Which of the following species, do not show disproportionation reaction and why? CIO^(-),CIO_(2)^(-),CIO_(3)^(-)andCIO_(4)^(-) Also write reaction for each of the species that disproportionates.

Answer»

Solution :Among the OXOANIONS of CHLORINE listed above `ClO_(4)^(-)` does not disproportionate because in this oxoanion chlorine is present in its highest oxidation state that is, +7. The disproportionation reactions for the other three oxoanions of chlorine are as FOLLOWS :
`overset(+1)(3ClO^(-))tooverset(-1)(2Cl^(-))+overset(+5)(ClO_(3)^(-))`
`overset(+3)(6ClO_(2)^(-))overset(hv)tooverset(+5)(4ClO_(3)^(-))+overset(-1)(2Cl^(-))`
`overset(+5)(4ClO_(3)^(-))tooverset(-1)(Cl^(-))+overset(+7)(3ClO_(4)^(-))`
Discussion
14.

Which of the following pairs of ions isoelectronic and isostructural ?

Answer»

`CO_3^(2-) , SO_3^(2-)`
`ClO_3^(-) ,CO_3^(2-)`
`SO_3^(2-),NO_3^-`
`ClO_3^(-) , SO_3^(2-)`

SOLUTION :`{:(,ClO_3^(-),SO_3^(2-)),("No. of " E^-, 42 ,42),("HYBRIDISATION",sp^3,sp^3):}`
Both are having one LONE pair on CENTRAL atom hence they are pyramidal.
Discussion
15.

Write the electronic configurations of the elements : Chlorine and Phosphorus.

Answer»

SOLUTION :Chlorine `(._(17)Cl)=1S^(2) 2s^(2) 2p^(6) 3s^(2) 3p_(x)^(2) 3p_(x)^(2) 3p_(Z)^(1)`, Phosphorus `(._(15)P)=1s^(2) 2s^(2) 2p^(6)3s^(2) 3p_(x)^(1) 3p_(y)^(1) 3p_(z)^(1)`
Discussion
16.

Which of the following is a amphoteric metal

Answer»

Bc
Ca
Sr
Ba

Solution :Be is the ampoteric METAL DUE to LOW ELECTROPOSITIVITY and SIZE.
Discussion
17.

What is f-block elements ? Give is characteristics.

Answer»

Solution :The two rows of elements at the bottom of the PERIODIC Table, called the Lanthanoids, Ce (Z = 58) - Lu (Z = 71) and Actinoids, Th (Z = 90) - Lr (Z = 103) are characterised by the outer electronic configuration `(n -2) f^(1-14) (n -1) d^(0-1) ns^(2)`.
The last electron added to each element is filled in f-orbital. These two series of elements are hence called the Inner-Transition Elements - Block Elements).
They are all metals. Within each series, the properties of the elements are quite similar.
The chemistry of the early actinoids is more complicated than the corresponding lanthanolds, due to the large number of oxidation states POSSIBLE for these actinoid elements.
Actinoid elements are radioactive. Many of the actinoid elements have been made only in nanogram quantities or EVEN less by nuclear reactions and their chemistry is not FULLY studied.
The elements after uranium are called Transuranium Elements.
Discussion
18.

Writes short notes on Resonance

Answer»

SOLUTION :Resonance : Certain organic COMPOUNDS be represented by more than ONE structure and they differ only in the position of BONDING and lone pair of electrons . Such structures are called resonance structures ( CANONICAL structures ) and this phenomenon is called resonance .
Discussion
19.

Which is the correct statement about sodium chloride?

Answer»

sodium CHLORIDE MELTS at 1081K
It has a solubility of 36.0g in 100G of water at 273k
The solubility does not INCREASE appreciably with increase in temperature.
All the above are incorrect

Answer :D
Discussion
20.

Write the IUPAC names of the compounds i-iv from their given structures: (i) overset(1)(CH_(3))- overset(2)(CH_(2))- underset(underset(OH)(|))overset(3)(CH)- overset(4)(CH_(2))- overset(5)(CH_(2)) - underset(underset(CH_(3))(|))overset(6)(CH)- overset(7)CH_(2) - overset(8)(CH_(3)) (ii) overset(6)(CH_(3)) - overset(5)(CH_(2))- underset(underset(O)(||))overset(4)(C )- overset(3)(CH_(2)) - underset(underset(O)(||))overset(2)(C )- overset(1)(CH_(3)) (iii) overset(6)(CH_(3)) - underset(underset(O)(||))overset(5)(C )- overset(4)(CH_(2)) - overset(3)(CH_(2)) - overset(2)(CH_(2))- overset(1)(C )OOH (iv) overset(6)(CH) -= overset(5)(C )- overset(4)(CH) = overset(3)(CH) - overset(2)(CH) = overset(1)(CH_(2))

Answer»

Solution :(i) The functional group present is an alcohol (OH). Hence the SUFFIX is .-ol.
The LONGEST chain containing `-OH` has eight carbon atoms. Hence the corresponding saturated HYDROCARBON is octane. The `-OH` is on carbon atom 3. In addition, a methyl group is attached at `6^(th)` carbon. Hence, the systematic name of this compound is 6-Methylocant -3-ol
(ii) The functional group present is ketone
, hence suffix .-one.. Presence of two keto groups is indicated by .di.,hence suffix becomes .dione.. The two keto groups are at carbons 2 adn 4. The longest chain contains 6 carbon atoms, hence, parent hydrocarbon is hexane. Thus, the systematic name is Hexane-2,4-dione
(iii) Here, two functional groups namely ketone and carboxylic acid are present. The PRINCIPAL functional group is the carboxylic acid group, hence the parent chain will be suffixed with .oic. acid.
Numbering of the chain starts from carbon of `-COOH` functional group. The keto group in the chain at carbon 5 is indicated by .oxo.. The longest chain including the principle functional group has 6 carbon atoms, hence the parent hydrocarbon is hexane. The compound is, therefore, named as 5-oxohexanoic acid
(iv) The two `C=C` functional groups are present at carbon atoms 1 and 3, while the `C -=C` functional group is present at carbon 5. These groups are indicated by suffixes .DIENE. and .yne. respectively. The longest chain containing the functional groups has 6 carbon atoms: hence the parent hydrocarbon is hexane. The name of compound, therefore, is Hexa-1, 3-dien-5-yne
Discussion
21.

Write the systematic names of the following bond line formulae : (a)

Answer»


ANSWER :(a) 3 - Pentanone ;
(b) 1,3 - Pentadiene ;
(C ) 2-Chloropropane ACID
Discussion
22.

What is the relationship between wavelength and momentum of a particle ?

Answer»

Solution :`lamda = (H)/(p)` where `lamda` is WAVELENGTH, h is PLANK's constant and p is the MOMENTUM.
Discussion
23.

Write the uses of calcium hydroxide.

Answer»

Solution :Calcium hydroxide is used
(i) in the PREPARATION of mortar, a building material.
(ii) in white wash due to its disinfectant nature.
(iii) in GLASS making and tanning industry
(IV) for the preparation of bleaching powder and for the purification of sugar.
Discussion
24.

Under similar conditions of temperature and pressure the rate of diffusion is very low for the following gas

Answer»

`SO_2`
`CO_2`
`O_2`
`H_2`

ANSWER :D
Discussion
25.

What is the value of n in the following half equation, Cr(OH)_(4)^(-)+ OH^(-) rarrCrO_(4)^(2-)+H_(2)O+"ne"^(-)

Answer»


Solution :`Cr(OH)_(4)+OH^(-)rarrr CrO_(4)^(2-)+H_2O`
Write OXIDATION states, we have .
`[overset(+3)Cr(OH)_(4)]^(-)+OH^(-) rarr[overset(+6)CrO_(4)]^(2-)+H_(2)O`
The VALANCE oxidation state of Cr on both sides , add `3e^(-)` on R.H.S .
Discussion
26.

Use of hot air balloon in sports and metorological observation is an application of

Answer»

Boyle'slaw
NEWTON's LAW
Kelvin's law
BROWN's law

Answer :A
Discussion
27.

Name the species that will be isoelectronic with Ar

Answer»

SOLUTION :`AR (18 ELECTRONS),S^(2-),Cl,P^(3-),K^+,Ca^(2+)`
Discussion
28.

Which elements are present in third period of Mendeleev's periodic table ?

Answer»

Be
MG
SR
All

ANSWER :d
Discussion
29.

Which of the following is basic in nature ?

Answer»

`Be(OH)_(2)`
`MG(OH)_(2)`
`Al(OH)_(3)`
`B(OH)_(3)`

SOLUTION :`(BOH)_(3)` is ACIDIC.
Discussion
30.

Very pure hydrogen (99.9) can be made by which of the following processes.

Answer»

reaction of methane with steam.
mixing NATURAL hydrocarbons of HIGH MOLECULAR WEIGHT.
electrolysis of water.
reaction of salts like hydrides with water.

Answer :D
Discussion
31.

Which of the following is an associated colloid ?

Answer»

Protein + WATER
Soap+ water
Rubber + benzene
Milk.

SOLUTION :A colloidal solution of soap and water is an example of associated COLLOID.
Discussion
32.

Unpaired electronoversetCH_3 occupies

Answer»

sp-HYBRID ORBITAL
`sp^3`-Hybrid orbital
p-Orbital
`sp^3`-Hybrid orbital

Answer :B
Discussion
33.

What are the importance of hydrogen bonding in proteins?

Answer»

Solution :(i) Hydrogen bonds uccur in complex biomolecules such as PROTEINS and in biological systems.
(ii) For example, hydrogen bonds play an important role in the structure of deoxyribonucleic acid (DNA), SINCE it holds together the two helical NUCLEIC acid CHAINS.
(iii) In these systems, hydrogen bonds are FORMED between specific pairs, for example, with a thymine unit in one chain bonding to an adenine unit in another, similarly, a cytosine unit in one chain bonds to a guanine unit in another.
(iv) Intramolecular hydrogen bondong also plays an important role in the structure of polymers, both synthetic and natural.
Discussion
34.

Thermodynamically stable form of C is .......

Answer»

Graphite
Diamond
Fulerenl
Cock

Answer :A
Discussion
35.

Three states of matter are results ?

Answer»

Solution :We have already learnt that INTERMOLECULAR FORCES tend to KEEP the molecules together but thermal ENERGY of the molecules tends to keep them apart.
Three states of MATTER are the result of balance between intermolecular forces and the thermal energy of the molecules.
Discussion
36.

Which one is not the properly of gas ?

Answer»

Gases are mixed with each other.
Gases are compressible.
Gases having FIXED volume.
Molecules of gases are FREE in motion.

ANSWER :C
Discussion
37.

Which of the following molecular orbital has the lowest energy?

Answer»

`rho_(2PZ)`
`pi_(2py)`
`pi_(2pz)`
`rho_(2px)`

Answer :A
Discussion
38.

What isthe energyin joules requriedto shiftthe electronof the hydrogen atom from thefirstBohrorbitto the fifthbohrorbitand whatis thewavelengthof the lightemittedwhen theelectronreturnsto the groundstate? Thegroundstateelectronenergyis 2.18 xx 10^(1) ergs

Answer»

Solution :CALCULATION of transitionenergyof Bohr.s1 to5 orbit.
`10^(7)"earg" =1j`
`2,18 xx 10^(11) "earg"= (?)`
`(2.18xx 10^(11) "earg" xx 11)/( 10^(7)"earg" )= 2.18 xx 10^(18)`
Groundstateenergyof hydrogen`E_(1)=2 .18 xx 10^(18) J`
bohrorbitof hydrogen is one son=1and `E_(1)`
electronrequiredfor transitionof electronin`n_(1)` to`n_(5)` is `Delta E`
Calculationof emittedwavelengthwhenelectronreturnto GROUNDSTATE :
`lambda= (hc )/( Delta E)` `=94 .983 nm =95 nm`
Discussion
39.

Using the periodic Table, predict the formulas of compounds which might be formed by the following pair of elements, aluminium and sulphur.

Answer»

SOLUTION :`Al_2S_3`
Discussion
40.

Using the periodic Table, predict the farmulas of compounds which might be formed by the following pairs of elements, Silicon and bromine.

Answer»

SOLUTION :`SiBr_4`
Discussion
41.

Which of the following can tautomerise.

Answer»

`CD_3- undersetoverset(||)(O)(C) -PH`


SOLUTION :
Discussion
42.

Which of the following statements, about the advantage of roasting of sulphide ore before reduction is not true

Answer»

ROASTING of the SULPHIDE to the OXIDE is thermodynamics feasible
Carbon and hydrogen are suitable reducing AGENTS for metal sulphides
The `delta(FG)^(o0)` of the sulphide is greater than those for `CS_2` and `H_(2)S`
The `delta(fG)^(o)` is negative for roasting of sulphide ore to oxide.

Solution :N//A
Discussion
43.

To an evacuated vessel with movable piston under external pressure of 1 atm, 0.1 mol of He and 1.0 mol of unknown compound (vapour pressure 0.68 atm. At 0^(@)C) are introduced. Considering the ideal gas behaviour the total volume (in litre) of the gases at 0^(@)C is close to

Answer»


Solution :Total volume of the gases in the VESSEL will be equal to the volume of the vessel total pressure of the gases will be equal to the external pressure of 1 atm.
SUPPOSE volume of the vessel=V L
Considering ideal GAS behaviour, for vapour of the compound (solid or liquid ) with 0.68 atm pressure at `0^(@)C`,
PV=nRT
`:.` n (no of moles of vapour)
`=(PV)/(RT)=(0.68xxV)/(0.0821xx273)`
`:.` Total no. of moles (He+vapour)
`=0.1+(0.68V)/(0.0821xx273)`
Total pressure =1 atm
Applying PV=nRT for the mixture,
`1xxV=(0.1+(0.68V)/(0.0821xx273))xx0.0821xx273`
or `""V=0.1xx0.0821xx273+0.68" V"`
or `0.32" V"=2.24" or " V= 7" L"`
Alternatively, total pressure =1 atm
Pressure of the vapour=0.68 atm
`:.` Pressure of Helium =1-0.68=0.32 atm
For ideal gas behaviour, PV=nRT
`:. 0.32xxV=0.1xx0.0821xx273" or "V=7" L"`
Discussion
44.

What do you mean by hydrocarbons ? Give the names of the hydrocarbons that play a key role in our life daily life.

Answer»

Solution :Hydrogens means compounds of CARBON and hydrogen only. Hydrocarbon a play a key ROLE in our daily life.
LPG : (Liquified Petroleum GAS)
CNG : (COMPRESSED Natural Gas)
LNG : (Liquified Natural Gas)
Discussion
45.

What is the equilibrium constantK_(p) " and " K_(c) for the reactionPCl_(5)(g) hArr PCl_(3)(g) + Cl_(2)(g) if the pressure is 1.0atm in 8.0L container at equilibrium.

Answer»

<P>

ANSWER :`K_(C) = 0.04 K_(p) = 1.77`
Discussion
46.

What is true about human blood cell ?

Answer»

There is high concentration of `K^(+)` ion inside the cell
There is LOW concentration of `K^(+)` ion inside the cell
There is high concentration of `NA^(+)` ion inside the cell
There is same concentration of `Na^(+) and K^(+)` ion inside the cell

ANSWER :A
Discussion
47.

Write the chemical formula of “Calgon”.

Answer»

<P>

ANSWER :`Na_(4)P_(6)O_(18)`.
Discussion
48.

Which of the following will have highest DeltaH_"vap" value?

Answer»

ACETONE
ETHANOL
CARBON TETRACHLORIDE
Chloroform

Answer :B
Discussion
49.

The strongest base of the following species is

Answer»

`NH^(2-)`
`OH^(-)`
`O^(2-)`
`S^(2-)`

Solution :Due to highest electron DENSITY on N in `NH^(2-)`, it cn accept protons most EASILY and HENCE is the trongest base.
Discussion
50.

Write structural formulas of the following compounds. (i)3,4,4,5-Tetramethylheptane , (ii)2,5-Dimethylhexane.

Answer»

SOLUTION :(i)`UNDERSET"3,4,4,5-Tetramethylheptane"(overset1CH_3-overset2CH_2-undersetunderset(H_3C" ")|overset3CH-undersetunderset(CH_3)|oversetoverset(CH_3)|(C^4)-undersetunderset(CH_3)|overset5CH-overset6CH_2-overset7CH_3)`
(II)`underset"2,5-Dimethylhexane"(overset1CH_3 overset2-oversetoverset(" " CH_3)|CH-overset3CH_2-overset4CH_2overset5-oversetoverset(" " CH_3)|CH-overset6CH_3)`
Discussion