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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Hey guys what\'s up.... ??? |
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Answer» Jhanvi ye kya ha Yrr no. Q diya tum na apna Hmm..... Bolo Can you all help me???? pls. Hi 8141651335 |
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| 2. |
Chemical formula of Orthoboric acid |
| Answer» H3BO3 | |
| 3. |
Hlo guys.. ? |
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Answer» hey Hii... Hey Hello .Namaskar |
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| 4. |
The number of moles of h2 in 0.224 litre of hydrogen gas at stp is? |
| Answer» H2 mole= 22= 0.22/22= 0.01 | |
| 5. |
How many gram moles present in 20 gram of H2 |
| Answer» 10 moles | |
| 6. |
Define thermodynamic |
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Answer» 5.3 g of na2co3 is dissolved in 90g of water what will be mole fraction of na2co3 and water Thermodynamics in physics is a branch that deals with heat, work and temperature, and their relation to energy, radiation and physical properties of matter. |
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| 7. |
Give the number of electron in the species H2+,H2 and O2+???? |
| Answer» | |
| 8. |
What is covalent radius....? |
| Answer» The covalent radius, rcov, is a measure of the size of an atom that forms part of one covalent bond. It is usually measured either in picometres or angstroms, with 1 Å = 100 pm. In principle, the sum of the two covalent radii should equal the covalent bond length between two atoms, R = r(A) + r(B). | |
| 9. |
Define resonance? |
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Answer» Copy pasting is a very easy thing guys ResonanceIt is given by\xa0Heisenberg.He took a molecule of ozone. Its structure was represented as:According to the structure, it is clearly seen that it has one double bond and another single bond. So, obviously the bond lengths will be different. For double bond between oxygen atoms, the bond length is 121pm and for single bond it is 148pm.But, the bond length was found experimentally to be same for both the bonds that is 128pm .This bond length lies in between the values of single and double bond lengths. |
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| 10. |
Explain why transition elements form coloured compound?? ? |
| Answer» | |
| 11. |
Why the elements of d-block is called as transition elements?? |
| Answer» The position of d-block elements is in between the s-block and p-block elements in the periodic table. These d-block elements are called transition elements because they exhibit transitional behaviour between s-block and p-block elements. Their properties are transitional between highly reactive metallic elements of s-block which are typically ionic compounds and the elements of p-block which are largely covalent. | |
| 12. |
Electronic configuration of Cr and Cu?? ? |
| Answer» The Electronic configuration of Cr and Cu are given below ⇒\xa01. Cr = 24 = 1s² 2s² 2p⁶ 3s² 4p⁶ 4s¹ 3d⁵2. Cu = 29 = 1s² 2s² 2p⁶ 3s² 4p⁶ 4s¹ 3d¹⁰\xa0These electronic configuration are exceptional because electrons entered in 3-d orbitals without filling the 4s orbitals complete.Reason for the Exceptions ⇒ It is said that d orbitals can be stable if it is half filled or full filled.Thus, In the given case, electrons reaches near the half filled and full filled thus due to the attraction one electrons from the s orbitals came in d orbitals. | |
| 13. |
Define Isomers? |
| Answer» Isomerism is the phenomenon in which more than one compounds have the same chemical formula but different chemical structures. Chemical compounds that have identical chemical formulae but differ in properties and the arrangement of atoms in the molecule are called\xa0isomers. Therefore, the compounds that exhibit isomerism are known as isomers.The word “isomer” is derived from the Greek words “isos” and “meros”, which mean “equal parts”. This term was coined by the Swedish chemist Jacob Berzelius in the year 1830. | |
| 14. |
Resonance?? |
| Answer» Resonance is the mixture of all Lewis dot structure of compound | |
| 15. |
What is the value of AMU |
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Answer» Open AppSalaam Rocky BhaiPLAYChal ne ka hukumRuk ne ka hukumZindagi pe hukumMaut pe hukumBandook pe hukumDushman pe hukumLeharon pe hukumBombai pe hukumJaan Bambai ka, jaan Bambai kaJaan Bambai ka jaane reIski aankhon mein aankh na daaloNoch leta hai praan veAag toofan jab bhi milta haiAisa barood paida hota haiAye Khuda zara dekhoLogon ke dil mein sultan dekhoDushman ko yeh hai shaitan dekhoAye Khuda zara rokoRuk ne wala kartaMud ne wala kartaBombai ki galiyan bhiGhabra ke yun bolenge saalaSalaam Rocky bhaiRock, Rock, RockySalaam Rocky bhaiSalaam Rocky BhaiSalam Rocky bhaiIlaaka tera bhaiTu hai sabka bhaimusic........Maa ne dua diyatum to panga liyajeetoge tum duniyakhuda hairaan hogamaksad pura hogaulta tairon dariyankaun isko rokegakaha se layega fauj koek me bhi himmat bhi nahi hai panga lene kojab bhi jaada hai haath loha haijag ko bechain karne ka ye funda haihat zara khatra haiapne wala karzamurne wala karzamumbai ki galiyan bhi ghabra ke bolegi saalaSalaam Rocky bhaiRock, Rock, RockySalaam Rocky bhaiSalaam Rocky BhaiSalam Rocky bhaiIlaaka tera bhaiTu hai sabka bhai An atomic unit of mass is defined as accurately 1/12 the mass of a carbon-12 atom. The carbon-12 atom has six neutrons and six protons in its nucleus. The atomic unit mass is symbolized as AMU or amu.1 AMU = Average of the proton rest mass and the neutron rest mass.1 AMU = 1.67377 x 10\xa0-27\xa0kilogram or 1.67377 x 10\xa0-24\xa0gram. |
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| 16. |
happy diwali to all friends |
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Answer» Happy Diwali Happy deepawali Ok happy diwali if I am friend? |
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| 17. |
Explain shape of orbitals |
| Answer» \tThe boundary surface diagram for the s orbital looks like a sphere having the nucleus as its centre which in two dimensions can be seen as a circle.\tHence, we can say that s-orbitals are spherically symmetric having the probability of finding the\xa0electron\xa0at a given distance equal in all the directions.\tThe size of the s orbital is also found to increase with the increase in the value of the principal quantum number (n), thus,\xa04s > 3s> 2s > 1s. | |
| 18. |
ostwald\'s dilution law |
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Answer» The Ostwald’s Dilution Law is defined for a weak electrolyte as “ the degree of ionization is proportional to the square root of the molar concentration or directly proportional to square root of the volume of the solution which contains one mole of the electrolyte.”Mathematically, we can write\xa0Ostwald’s Dilution Law as below:e α\xa0= √ ka/C = √ kaV Or, α =\xa0√ kb/C =\xa0√ kbV Wilhelm Ostwald’s dilution law is a relationship proposed in 1888 between the dissociation constant Kd and the degree of dissociation α of a weak electrolyte. The law takes the form Where the square brackets denote concentration, and c₀ is the total concentration of electrolyte.\xa0Ostwald\'s dilution law\xa0describes the dissociation constant of the weak electrolyte with the degree of dissociation (α) and the concentration of the weak electrolyte. α = degree of dissociation.\xa0Ostwald\'s dilution law\xa0states that only at infinite\xa0dilution\xa0the weak electrolyte undergoes complete ionization. |
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| 19. |
What are heterocyclic aromatic compounds? Give example |
| Answer» \xa0Aromatic heterocyclic compounds: Aromatic cyclic compounds containing one or more heteroatoms in their molecules are called aromatic heterocyclic compounds. For example, | |
| 20. |
Write the Schrodinger wave equation and explain the terms |
| Answer» Planck\'s law\xa0describes the spectral density of electromagnetic radiation emitted by a black body in thermal equilibrium at a given temperature T. The\xa0law\xa0is named after Max\xa0Planck, who proposed it in 1900. It is a pioneering result of modern physics and quantum theory. | |
| 21. |
Schrodinger Equation? |
| Answer» $$\\hat{H} \\Psi=E \\Psi$$ $$\\hat{H}$$=\thamiltonian operator$$\\Psi$$\t=\twave functionE\t=\tenergy Conservation of EnergySchrodinger equation is written as HΨ = EΨ, where h is said to be a Hamiltonian operator. | |
| 22. |
Eka - francium? |
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Answer» Heey Thanks ? Ununennium, also known as eka-francium or element 119, is the hypothetical chemical element with symbol Uue and atomic number 119. Ununennium and Uue are the temporary systematic IUPAC name and symbol respectively, which are used until the element is discovered, confirmed, and a permanent name is decided upon. Yes sister it\'s a new element |
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| 23. |
the percentage of carbon in CA (HCO3)2is? |
| Answer» electron bandhoota vaidut ridatmakta ko samjhye | |
| 24. |
Reduction reaction? |
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Answer» ReductionReduction is defined as the memoval of oxygen/electronegative element from a substance or addition of hydrogen or electropositive element to a substance.For example, Addition of hydrogen or removal of oxygen... |
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| 25. |
Range of oxidation number of group 16 elements? |
| Answer» The common oxidation state of group 16 elements is +2, +4, +6.The group 16 elements, also known as the\xa0chalcogens\xa0have 6 valence electrons, and hence\xa0they can achieve noble gas configuration either by gaining 2 electrons or by sharing two electrons i.e., by forming M2-\xa0ions, or forming two covalent bonds. The oxidation state of elements is defined as the number of electrons gained or lost to form a bond and its sign is the indication of ionic charge on the element. Oxygen is the most electronegative element after fluorine. The difference in electronegativity between metals and oxygen is generally very high. We know that ionic bond is formed when the difference in electronegativity of any two elements is very high. Thus, metals and oxygen combine to form a metal oxide with oxygen attaining O2-\xa0form, so the oxidation state of oxygen is mostly (-II).Electronegativity of chalcogens decreases down the group in the\xa0periodic table. Other chalcogen elements like sulphur, selenium, and tellurium react with a more electronegative element of group 1, 2 and lanthanides i.e., the uppermost elements of group 1, 2 and lanthanides to form sulphides, selenides, and tellurides. These compounds are the most stable compounds formed by these elements. Compounds formed above can be denoted as S2-, Se2-, and Te2-. The electronegativity difference between the compounds (sulphides, selenides, and tellurides) shows that they are on the borderline of 50% ionic and 50% covalent characters as in the case of PCl5. Phosphorus pentachloride is sometimes covalent in the solid state but is ionic in the aqueous state.The chalcogen group can also share their two electrons with another element to form two covalent bonds for example\xa0H2O,F2O,Cl2O,H2S\xa0and\xa0SCl2. In the given examples the chalcogen elements have the least electronegativity. As we can see in the case of\xa0SCl2\xa0(the electronegativity of chlorine = 3.5 and sulphur =2.5) and the oxidation state of sulphur is (+II). | |
| 26. |
Can oxidation number of metals be negative? ? |
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Answer» The\xa0metals\xa0always have\xa0oxidation number\xa0in positive and non\xa0metal\xa0in\xa0negative\xa0when present together in ionic compounds. Generally to positive he hote h... Lekin transition metals negative Ho skte h... |
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| 27. |
Oxidation of Oxygen? |
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Answer» Shi h... All the best .. Ab* Exam kaisa gya. ?? An next chemistry ka h kya. ? Oxidation number* |
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| 28. |
Calculate the mass percent of sodium 2Na |
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Answer» Pls explain 200 |
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| 29. |
$$what is bond order$$ |
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Answer» $$\\frac{y7656}{6657}$s [tex] Mercury \\: Venus \\: Earth \\: Mars [/tex][tex] $$Mercury \\: Venus \\: Earth \\: Mars $$ The iron oxide has 69.9% iron and\xa030.1% dioxygen by mass.Thus, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen.The number of moles of iron present in 100 g of iron oxide are\xa0$$55.8/69.9\u200b=1.25$$.The number of moles of dioxygen present in 100 g of iron oxide are\xa0$$32/30.1\u200b=0.94$$.The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is\xa0$$1.252×0.94\u200b=1.5:1=3:2$$.Hence, the formula of the iron oxide is\xa0$$Fe2O3$$ Called* The number of bonds between two atoms in a molecule is call bond order. |
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| 30. |
Chemical bond? |
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Answer» Chemical bonding is a attraction b\\w atoms and molecule and formed a chemical compound.. Is form due to electrostatic force of attraction between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds. Mai aa gya |
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| 31. |
Define viscosity...?? ✍✍✍✍✍✍✍ |
| Answer» Viscosity\xa0is a measure of a fluid\'s resistance to flow.It describes the internal friction of a moving fluid. A fluid with large\xa0viscosity\xa0resists motion because its molecular makeup gives it a lot of internal friction.\xa0The SI\xa0unit\xa0for dynamic\xa0viscosity\xa0η is the Pascal-second (Pa-s), which corresponds to the force (N) per\xa0unit\xa0area (m2) divided by the rate of shear (s-1). | |
| 32. |
Define hydrogen paraoxide✍✍✍✍✍ |
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Answer» Aaj kl maherbaan h pta n kyu.. ?? Match dekh rhe Ho. ..? Aaj bhi aapka network Accha h.. Sirf mera he Kharab chlta h ? Ha.. Dhakka... ??? Dhakaa de k..\xa0? |
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| 33. |
How will you describe the deviation of ionisation enthalpy in group 13 element? |
| Answer» | |
| 34. |
Reducing agents? |
| Answer» | |
| 35. |
Oxidizing agents? |
| Answer» Gazab ???? 2nd book start ho gaya aapka ?? | |
| 36. |
Oxidation number of hydrogen? |
| Answer» | |
| 37. |
Oxidation number of oxygen in Ozonide form? |
| Answer» | |
| 38. |
Can oxidation number of Oxygen be positive? |
| Answer» | |
| 39. |
Why sp4 and sp5 hybridization isn\'t possible? ? |
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Answer» Oh! to app 6 baje soti ho , or 3 baje uthti ho ?? $$\\textsf{Vese aap itna kyo jagti ho, this is not a good way to study }$$ $$\\texttt{scroll to see, full }$$$$\\textfrak{*sp_{3} }$$ $$\\mathfrak{Because\\ \'p\' \\ subshell \\ has\\ only \\ 3\\ orbital\\ which\\ get\\ completed \\ in \\sp-{3}\\ hybridization\\. }$$ |
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| 40. |
Which is more polar - CO2 or N2O....???...?Give reason.....✍️ |
| Answer» N2\u200bO\xa0is more polar than\xa0CO2\u200b.\xa0This is because\xa0CO2\u200b\xa0is linear and symmetrical. Its net dipole moment is zero\xa0(O=←C=→O).N2\u200bO\xa0is linear but symmetrical. It is considered as a resonance hybrid of the following two structures:N..−=N+=O:..↔:N≡N+=..O:..\u200b−\u200bIt has a net dipole moment of\xa00.116D. | |
| 41. |
P4+NO3 -1--->PO4*-3 +NO2Balance the rxn by half rxn method |
| Answer» solve equation by oxidation number method : p4 + no3^-1 gives po4^-3 + no2oxidation no of p4 is 0, no3^-1 is 5, po4^-3 is 5 & no2 is 4oxidation: p4 gives 4po4^-3 increases by 20 × 1reduction :no3^-1 gives no2 decreases by 1 × 20p4 gives 4po4^-3 20no3^-1 gives 20no2p4 + 16h2o gives 4po4^-3 20no3^-1 gives 20no2 + 20h2obalanced equation is p4 + 20no3^-1 + 8h+ gives 4po4^-3 + 20no2 + 4h2o | |
| 42. |
VSEPR theory? |
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Answer» $$VESPR- theory \\ says\\ that\\ the \\electrons\\ arrange\\ themselves\\ at\\ minimum\\ repulsion\\ $$ $$lone- pair-lone- pair. repulsion > lone -pair- electron- pair .repulsion> electron -pair- electron- pair. repulsion$$ The Valence Shell Electron Pair Repulsion Theory abbreviated as VSEPR theory is based on the premise that there is a repulsion between the pairs of\xa0valence electrons\xa0in all atoms, and the atoms will always tend to arrange themselves in a manner in which this electron pair repulsion is minimalized. This arrangement of the atom determines the geometry of the resulting molecule.The different geometries that molecules can assume keeping with VSEPR theory can be seen in the illustration provided below.VSEPR Theory – Different Geometries that Molecules can Assume |
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| 43. |
What is functional groups?? |
| Answer» Functional group is a function of a group - f(x) | |
| 44. |
What is silicate |
| Answer» Silicate are mineral that contain silicon and oxygen and one or more other elements.Quartz is the silicates and is the most common mineral. Silicon and oxygen are the basic building blocks for most of the minerals on the Earth\'s crust and mantle. | |
| 45. |
How many quantum numbers are required to specify an orbital...? |
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Answer» Hello bhai? kaise ho?? Yrr kaha tum bhi in faltu ke bakwas me phass jate ho...waise kal maine bahot miss kiya tumhe.....bhai jara apna syllabus batana for 1 st terminal. 3 orbitals are required 4 quantum numbers are there .Principal quantum number : Denoted by n ,gives the number of shellAzimuthal quantum number : Denoted by l, gives the account of subshell or orbitalMagnetic quantum number : Denoted by ml , states the sub -orbitalMagnetic quantum number : Denoted by ms, states the spin of electron To designate an orbital n,l and m quantum numbers are required and s represents the (spin ) of the electron present in the orbital. |
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| 46. |
Find the position of elements having atomic number 17 in periodic table |
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Answer» 3 period 17 group Chlorine has an atomic number 17 in the periodic table |
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| 47. |
Why this structure is unstable ? |
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Answer» ∮xixfF→.dx→ Since lone pairs are placed at equitorial position so this structure is unstable because according to the bent\'s rule the electronegative elements must placed at equitorial position in compound with Trigonal bypriamidal geometry not the lone pairs. |
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| 48. |
What is exchange energy ? |
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Answer» ??? Hahajaja? Thanks mam and you are elder so plz dont be sorry It can be defined as the electrons which are there in degenerate orbitals have a parallel spin and tend to exchange their position. The exchange energy is the energy released when two or more electrons with the same spin-exchange their positions in the degenerate orbitals of a subshell. Exchange energy is nothing but the energy released during this process. When the orbitals are half-filled or completely filled then the number of exchanges is maximum. Therefore, its stability is maximum. |
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| 49. |
Why $$\\Psi$$ has no significance but $$\\Psi^2$$ has ? |
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Answer» −b±b2−4ac2a −b±b2−4ac−−−−−−−√2a−b±b2−4ac2a The wave function (psi)for a moving object is not a observable quantity but psi square has a physical significance which tells about the area in which the probability of getting electrons is 90 percent |
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| 50. |
What are the methods for balancing the redox reaction |
| Answer» There are two ways of balancing Redox reactions:\tOxidation number method\tHalf equation methodOxidation method: The steps to be followed-\tWrite the skeletal equation of reactants and products.\tIndicate the oxidation number of all the elements involved in the reaction.\tCalculate the increase or decrease in oxidation number per atom. Also, identify the oxidizing and reducing agents.\tMultiply the formula of oxidizing agent and reducing agent by suitable integers, so as to equalize the total increase or decrease in oxidation number as calculated in step c.\tBalance all atoms other than H and O.\tFinally balance H and O atoms by adding water molecules using hit and trial method.\tIn case of Ionic reactions:\tFor acidic medium\tFirst balance O atoms by adding water molecules to the deficient side.\tBalance H+ ions to the side deficient in H atoms.\tFor Basic medium\tFirst balance oxygen atom by adding water molecules to the deficient side.\tThen to balance hydrogen, add water molecules equal to the number of deficiency of H atoms.\tAlso add equal number of OH-\xa0ions to opposite side of the equation.Example: Permagnate ion reacts with bromide ion in basic medium to give manganese dioxide and Bromate ion .Step1: the skeletal ionic equation is :MnO4-\xa0(aq) +Br-\xa0(aq) ---> MnO2\xa0+BrO3-Step 2: assign oxidation numbers for Mn and BrStep3: calculate the increase and decrease in oxidation number and make the change equal :Step: 4 as the reaction occurs in basic medium, and the ionic charges are not equal on both sides, add 2OH-\xa0ions on the right to make it equal.Step5: finally count the hydrogen atoms and add appropriate number of water molecules on the left side to achieve balanced Redox reaction.Half reaction method or Ion electron method\tWrite the skeletal equation and indicate the oxidation number of all the elements which occur in skeletal equation\tFind out the species that are oxidized and reduced.\tSplit the skeletal equation into two half reactions: oxidation half reaction and reduction half reaction\tBalance the two-half equation separately by rules described below:\tIn each half reaction first balance the atoms of element that has undergone a change in oxidation number.\tAdd electrons to whatever side is necessary to make up the difference in oxidation number in each half reaction.\tBalance the charge by adding H+\xa0ions, if the reaction occurs in acidic medium .For basic medium, add OH-\xa0ions if the reaction occurs in basic medium.\tBalance oxygen atoms by adding required number of water molecules to the side deficient in oxygen atoms\tIn the acidic medium, H atoms are balanced by adding H\xa0+\xa0ions to the side deficient in H atoms.\tHowever, in the basic medium H atoms are balanced by adding water molecules equal to number to H atoms deficient.\tAdd equal number of OH-\xa0ions to opposite side of equation.\tThe two half reactions are then multiplied by suitable integers .so that the total number of electrons gained in half reaction becomes equal to total number of electrons lost in another half reaction.\tThen the two half reactions are added up.\tTo verify the balancing, check whether the total charge on either is equal or not.Example: Let us consider the skeletal equation:Fe2+\xa0+ Cr2O72-\xa0--> Fe3+\xa0+Cr3+Step 1: Separate the equation in to two halves:Oxidation half reaction: Fe2\xa0-->\xa0Fe3+\xa0Reduction half reaction: Cr2O72-\xa0\xa0--> Cr3+Step 2: Balance the atoms other than hydrogen and oxygen in each half reaction individually. Here the oxidation half reaction is already balanced with respect to Fe atoms .For the reduction half reaction, we multiply the Cr3+\xa0by 2 to balance Cr atoms.Step 3: For reactions occurring in acidic medium, add water molecules to balance oxygen atoms and hydrogen ions are balanced by adding H atoms. Thus, we get:Cr2O72-\xa0+\xa014 H+ + 6e-\xa0--> 2 Cr3+\xa0+ 7H2OStep 4: Add electrons to one side of the half reaction to balance the charges .if needed make the number of electrons equal in two half reactions by multiplying one or both half reaction by suitable coefficient.The oxidation half reaction is thus written again to balance the charge .Now in the reduction half reaction there are 12 positive charges on the left hand side and only 6 positive charge on right hand side .Therefore, we add six electrons to left hand side .Cr2O72-\xa0+\xa014 H+ + 6e-\xa0--> 2 Cr3+\xa0+ 7H2OTo equalize the number of electrons in both reactions, we multiply oxidation half reaction by 6 and write as:6Fe2+ --> 6Fe3+\xa0+6e-Step 5: We add the two half reactions to achieve the overall reaction and cancel the electrons on each side .This give us net ionic equation:6Fe2+ + Cr2O72-\xa0+ 14 H+\xa0--> 2Cr3++6Fe3+\xa0+7H2OStep6: Verify that the equation contains the same type and number of atoms and the same charges on both sides of the equation. This last check reveals that the equation is fully balanced with respect to number atoms and the charges. | |