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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
Carbon dioxideis passedthrough asuspension of powderedlimestonein water. Write balancedchemicalequation for the above reaction. |
| Answer» Solution :The limestonedissolves to form calcium BICARBONATE : `CaCO_(3) (s) + CO_(2) (g) + H_(2)O(l) rarr Ca(HCO_(3))_(2) (aq)` | |
| 3. |
Carbon dioxide is found in ......... |
| Answer» SOLUTION :TROPOSPHERE | |
| 4. |
Carbondioxide is isostructural with |
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Answer» `HgCl_(2)` |
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| 5. |
Carbon dioxide contains 27.27% of carbon, carbon disulphide contains 15.79% of carbon and sulphur dioxide contains 50% of sulphur. This data is an agreement with |
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Answer» Law of conservatino of mass Weight of `CO_(2)`= 100 Weight of carbon = 27.27 Weight of oxygen = 72.73 27.27 g of carbon combines with 72.73 g of oxygen 1 g of carbon combines with =`(72.73)/(27.27)` = 2.66` of oxygen `THEREFORE` Ratio of C and O in `CO_(2)` = 1:5.3` If SULPHUR and oxygen were to combine to form `SO_(2)`, according to law of reciprocal proportions. They MUST combine in `5.3:2.66` or `2:1`. In `SO_(2)`,the ratio of `S:O` is `1:1`. thus, the ratio betweente two ratios is `2/1:1/1` = `2:1` Since, the ratio of `S:O` is a simple whole numbers ratio, therefore law of reciprocal is proved. |
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| 6. |
Carbon dioxide and another gas 'X' have their rates of diffusion as 0.299 cc s^-1 and 0.271 cc s^-1 respectively. Find the vapour density of the gas 'X' if the vapour density of carbon dioxide is 22. |
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Answer» |
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| 7. |
Carbon differs from the rest of the family members because of |
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Answer» Number of UNPAIRED electrons in VALENCE shell |
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| 8. |
Carbon-carbon bond order is benzene is 1.5 due to |
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Answer» INDUCTIVE EFFECT |
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| 9. |
Carbon can not expand its valency beyond 4, because |
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Answer» it has only 4 electrons |
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| 10. |
Carbon can form ppi-ppi bond with which kind of elements ? |
| Answer» SOLUTION :CARBON can FORM `ppi-ppi` bond with itself and other ATOMS which have smaller SIZE and high electronegativity. | |
| 11. |
Carbon atoms show sp^(2) hybridisation in compounds A and B. A decolourises alkaline potassium pemanganate solution whereas B cannot decolourise the solution. Then A and B are |
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Answer» PROPENE and Ethene |
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| 12. |
Carbon atoms of graphite possess which type of arrangement ? |
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Answer» TETRAHEDRAL |
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| 13. |
Carbon atoms of diamond possess which type of hybridization ? |
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Answer» SP |
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| 14. |
Carbon atoms in the compound CH_(4)C_(2) are……. |
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Answer» SP HYBRIDIZED 
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| 15. |
Carbon atoms in benzene molecule is inclined at an angle of |
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Answer» `120^(@)` |
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| 16. |
Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment. |
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Answer» Solution :In `CO_2`,carbon atom undergoes sp hybridization. Two sp hybridized orbitals of carbon atom overlap with two .p. orbitals of oxygen atoms to make two sigma bonds while other two electrons of carbon atom are involved in `ppi - ppi` bonding with oxygen atom. This results in its linear SHAPE [with both C-O bonds of EQUAL length (115 pm)]with no dipole MOMENT. Carbon can give double bond with oxygen due to its small size.  Silicon dioxide is a covalent, three dimensional NETWORK solid in which each silicon atom is covalently bonded in a tetrahedral manner to FOUR oxygen atoms. Each oxygen atom in turn covalently bonded to another silicon atoms as shown in diagram. Each corner is shared with another tetrahedron. The entire crystal may be considered as giant molecule in which eight membered rings are formed with alternate silicon and oxygen atoms. Silicon cannot give double bond with oxygen due to large size and less electronegativity. |
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| 17. |
Carbon and silicon have |
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Answer» Same physical properties |
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| 18. |
Carbon and siliconboth belongto thegroup 14, but in spiteof thestoichiometricsimilarit, thedioxides, (i.e, carbon dioxide and silicon dioxide), differ in their structure . Comment. |
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Answer» Solution :Carbonbecauseof its smallsize and higherelectronegatively then silicon forms `ppi-ppi`double BONDS withO-atomsto form `CO_(2)`MOLECULE. These moleculesof `CO_(2)` are heldtogetherby weak van der Waals force ofattraction which can be easily overcome by collisions of the moleculs at roomtemperature. CONSEQUENTLY, `CO_(2)`is a gas. Silicon, on the other hand,because of its bigger size andelectronegativitythan carbonhas little tendencyto form `ppi-ppi`double bondswith O-atoms.Instead, each siliconatom formsfour single covalent bonds with O-atoms which are tetrahedrally arrangedaround itleadingto the formation of a three-dimensionalnetwork structure. T breakthese covalentbonds, a LARGE amount of energyis needed and hence `SiO_(2)`is a highmelting solid. |
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| 19. |
Carbon and oxygen combine to form two oxides, carbon monoxide and carbond dioxide in which the ratioi of the weights of carbon and oxygen is respectively 12:16 and 12:32. these figures illustrate the |
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Answer» LAW of MULTIPLE proportions |
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| 20. |
Carbon and oxygen form two compounds. Carbon content in one of them is 42.9% and in the others is 27.3%. The given data is in agreement with |
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Answer» Solution :In the first compound, the carbon content is 42.9%. This means that 42.9 G of carbon combine with 100 - 42.9 = 57.1 g of oxygen. The amount of oxygen that will combine with a fixed amount say 100 g of carbon `=(57.1)/42.9 xx 100 = 133.1 g` In the first compound, the carbon content is 42.9%. This means that 42.9 g of carbon combine with `100 - 42.9 = 57.1` g of oxygen. The amount of oxygen that will combine with a fixed amount say 100 g of carbon `=(57.1)/(42.9) xx 100 = 133.1 g` In the second compound, the carbon content is 27.3%. This IMPLIES with `100-27.3 = 72.7` g of oxygen. The amount of oxygen that combines with 100 g of carbon =`(72.7)/(27.3) xx 100 = 266.3 g` The ratio in the amounts of oxygen that combine with 100 g of carbon in the two cases is 133.1 : 266.3, i.e., 1 : 2 which is a simple whole NUMBER ratio. Therefore, the data are in agreement with the law of multiple proportions. |
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| 21. |
Carbon and Hydrogen are estimated by |
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Answer» Liebig's method |
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| 22. |
Carbon-60 contains_____pentagons and _____hexagons. |
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Answer» 20,12 |
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| 23. |
Carbon-12 atoms has ______. |
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Answer» 6 ELECTRONS, 6 PROTONS, 6neutrons |
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| 24. |
Carbolic acid is |
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Answer» `C_(6)H_(5)CHO` |
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| 25. |
Carbolic acid |
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Answer» aqeous SOLUTION of phenol |
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| 26. |
Carbogen is used for the artificial respiration to the victims suffering from ....... gas poisoning. |
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Answer» `CO_2` |
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| 27. |
Carbogen is a mixture of O_(2)andCO_(2). It is used for artifical respiration. What is the percentage of CO_(2), in this mixture? |
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Answer» |
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| 28. |
Carbogen is : |
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Answer» PURE FORM of CARBON |
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| 29. |
Carbocations are species in which central carbon carries positive charge. If the charge on the carbocations gets cocentrated or lo-calized the carbocation becomes unstable. The two factors which account for stability of carbocations are inductive effect and hyper conjugation (no bond resonance). Inductive effect is minor factor and hyper conjugation is major factor. Hybridisation of carbon in carbocation is |
| Answer» ANSWER :B | |
| 30. |
Carbocations are species in which central carbon carries positive charge. If the charge on the carbocations gets cocentrated or lo-calized the carbocation becomes unstable. The two factors which account for stability of carbocations are inductive effect and hyper conjugation (no bond resonance). Inductive effect is minor factor and hyper conjugation is major factor. n-propyl carbocation rearranges to isopropyl carbocation by shift of |
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Answer» Proton |
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| 31. |
Carbocations are species in which central carbon carries positive charge. If the charge on the carbocations gets cocentrated or lo-calized the carbocation becomes unstable. The two factors which account for stability of carbocations are inductive effect and hyper conjugation (no bond resonance). Inductive effect is minor factor and hyper conjugation is major factor. Which is most stable carbocation |
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Answer» `OVERSET(+)(C)H_(3)` |
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| 32. |
Carbocation which is most stable is |
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Answer» `CH_(3)CH_(2)^(+)` |
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| 33. |
Carbides are three types, ionic, covalent and interstitial CaC_(2) is one of the commercially important ionic carbide ulX+Coverset(Delta)toCaC_(2)+CO CaC_(2)+Yoverset(1100^(@)C)toulZ+C Z+H_(2)OtoNH_(3)+CaCO_(3) 'Z' is an important nitrogenous fertiliser Y and Z respectively are |
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Answer» `N_(2)OandCa(CN)_(2)` `Y=N_(2),Z=underset("calcium CYNAMIDE")(CaNCN)` |
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| 34. |
Carbene intermediates are produced by the photolysis of diazomethane (CH_2N_2) or kenene (CH_2 = C = O). They are also produced by the reaction of CHX_3 with base or by Simmons-Smith reaction. There are two types of carbenes, singlet and triplet. They are so called due to their spin state. An optically active alkene (I) with lowest molecular mass on hydrogenation gives optically inactive alkene, but on insertion of methylene carbene ( : CH_2) in (I), it gives optically active compound (II). The compounds (I) and (II) are : . |
| Answer» Solution :(C ) In `P` and `Q`, both `(I)` and `(II)` are OPTICALLY active. | |
| 35. |
Capilary action of the liquid ca be explained on the basis of its |
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Answer» RESISTANCE to flow |
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| 36. |
Ca(OH)_2 is ___________ |
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Answer» gypsum |
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| 37. |
CaO is important in construction. It is obtained by heat in, CaCO_3. To get CO_2 why CO_2 is contentiously removed ? |
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Answer» SOLUTION :`CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g))` In this EQUILIBRIUM `CO_2` is GAS. So if `CO_2` is continuously removed than the reaction moves in FORWARD direction. So amount of CaO increases. Hence `CO_2` is removed. |
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| 38. |
CaO and NaCl have the same crystal structure and approximately the same radii. It U is the lattice energy of NaCl, the approximate lattice energy of CaO is |
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Answer» U |
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| 39. |
CaO and NaCl have the same crystal structure and approximately the same radii. IfU is the lattice energy of NaCI. the approximate lattice energy of CaO is ……………. |
| Answer» SOLUTION :`4U` | |
| 40. |
CaO and NaCl has same crystal structure and same radius if lattice enthalpy of NaCl is U than the lattice enthalpy of CaO is ? |
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Answer» `(U)/(2)` Lattice ENERGY = `(q_(1) q_(2))/(l^(2))` where `q_(1) and q_(2)` are charge l = distance between them . In CaO and NaCl ionic distance is same. In `Na^(+) and CL^(-) rarr` charge is 1 In `CA^(2+) and O^(2-) rarr ` charge is 2 So, lattice energy of CuO is 4 times than NaCl. |
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| 42. |
Cannizzaro reaction of C_(6)H_(5)CHO in the presence of NaOH gives |
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Answer» `C_(6)H_(5)COONa+C_(6)H_(5)CH_(2)OH` |
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| 43. |
Cane sugar is water soluble. This is |
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Answer» because SUGAR molecule os polar |
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| 44. |
Candela is the unit of .............. |
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Answer» POLARISATION of light |
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| 45. |
Can you separate a mixture of naphthalene and benzoic acid by subkimation ? |
| Answer» SOLUTION :YES. | |
| 46. |
Can we use potassium in place of sodium for preparing Lassaigne's extract ? |
| Answer» Solution :No, potasium is normally not USED because it is more reactive than sodium and will therefore, REACT violently UPON heating. The HANDLING of the fusion tube will BECOMES difficult. | |
| 47. |
Can we use KCI as electrolyte in the salt bride of the cell Cu (s) | Cu^(2+) (aq)|| ag^(+)(aq)|Ag(s) ? |
| Answer» SOLUTION :KCI cannot be used as electrolyte in the SALT bridge because `CI^(-)` ions will combine with `Ag^(+)` ions to form white precipitate of AGCI | |
| 48. |
Can we use concentrated sulphuric acid and pure zinc in the preparation of dihydrogen? |
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Answer» Solution :Conc. `H_(2)SO_(4)` cannot be USED because it acts as an oxidizing AGENT ALSO and gets reduced to `SO_(2)` `Zn+2H_(2)SO_(4)(Conc.)toZnSO_(4)+2H_(2)O+SO_(2)` Pure Zn is not used because it is non-porous and REACTION will be slow. The impurities in Zn help in constitute of electrochemical couple and speed up reaction. |
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| 49. |
Can we use a copper vessel to store 1 M AgNO_(3) solution ? Given that E_(Cu^(2+)//Ciu)^(@)=+0.34 V and E_(Ag^(+)//Ag)^(@)=+0.80 V |
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Answer» |
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| 50. |
Can we separate two liquids A (b.p. 353 K) and B (b.p. 365 K) present in a mixture by simple distillation ? |
| Answer» Solution :No, the METHOD of simple distillation cannot be used here because the VAPOURS of both the vapours of both the liquids will be formed simultaneously and will CONDENSE together in the receiver. The SEPARATION can be done by FRACTIONAL distillation. | |