Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Classify each of the following as homolysis as homolysis or heterolysis. Identify the reaction intermediates produced , as free radical, carbocation and carbanion.

Answer»

SOLUTION :
Discussion
2.

Classification of hydride according to Lewis structure is ………

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LIH
`CaH_2`
`NH_3`
`NbH_2`

ANSWER :C
Discussion
3.

Classical smog occurs in places of :

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Excess of `NO_2`
WARM dry climate
COOL HUMID climate
All of these

Answer :C
Discussion
4.

Classical smog is otherwise called.........

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SOLUTION : REDUCING SMOG
Discussion
5.

Smog is mainly due to

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Oxidies of SULPHUR & Carbon PARTICLES
Oxidies of Pb
Oxidies of carbon
Oxidies of Chlorine

ANSWER :A
Discussion
6.

Classical smog called London smog contains.............

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SOLUTION :Coal-smoke and FOG
Discussion
7.

Cl_(2)+OH^(-)toClO^(-)+Cl^(-) For this reaction select T(Ture) or F(False). (1) This reaction occurs in basic medium. (2) Oxidation and Reduction occurs for Cl_(2). (3) Products are obtained by dissoication of Cl_(2). (4) In ClO^(-) oxidation number of Cl^(-) is (+1).

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TFTF
FFTT
TFFT
TTFF

Answer :C
Discussion
8.

Cl_(2) gas can be produced in the lab by the reaction, K_(2)Cr_(2)O_(7)+14HCl to 2KCl+2CrCl_(3)+7H_(2)O + 3 Cl_(2) If a 6.13 g sample that is 96% K_(2)Cr_(2)O_(7) is allowed to react with 320 mL of HCl solution density 1.15 g//mL and containing 30% by mass of HCl, what mass of Cl_(2) is generated ?

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SOLUTION :N//A
Discussion
9.

Cl_(2) changes to Cl^( -) and ClO^(-) in cold NaOH. Equivalent mass of Cl_(2) will be.

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Molar mass/2
Molar mass/1
Molar mass/3
`2xx` Molar mass/2

Solution :`Cl_(2) to 2CL^(-) + 2e^(-)`
`Cl_(2) overset(NAOH)(to) 2ClO^(-) + 2e^(-)`
`:.` Equivalent mass=`(" Molar mass")/("No. of electrons lost")=("Molar mass")/2`
Discussion
10.

Cl-P-Cl bond angles in PCl_(5) molecule are

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`120^(@)and90^(@)`
`60^(@)and90^(@)`
`60^(@)AND120^(@)`
`120^(@)AND30^(@)`

ANSWER :A
Discussion
11.

Cl_((g)) + e^(-) rarr Cl_((g))^(-) , E_A = -348 kJ//"mole" at 0 K. then DeltaH for same process at 300K (in kJ) [R=8J/mol/K] [Hint : DeltaH = EA - 5/2 RT].

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`+354`
`+348`
`-354`
ZERO

ANSWER :C
Discussion
12.

Cis-trans isomers have different dipole moments

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ANSWER :t
Discussion
13.

Cis-but-2-ene is polar and trans-but-2-ene is non-polar explain.

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Solution :`CH_(3)CH=CHCH_(3)` has 2 geometrical isomers :
(i) Cis-but-2-ene (ii) TRANS-but-2-ene.
ALWAYS cis-isomer dipole moment `(MU) gt` Trans-isomers.
Isomers of But-2-ene are shown with its isomers and dipole moment.

Trans-but-2-ene has `2-CH_(3)` group, they are in opposite side therefore dipole MOMENTS of `C-CH_(3)` bonds CIRCLE, thus making the trans form non-polar.
Cis isomers are polar because in Cis-but-2-ene has `2-CH_(3)` group and they are on same side of double bond. Electronegativity of `C_CH_(3)` are added, in which the dipole moment is more. therefore, cis-isomer is polar and trans isomer is non-polar.
Discussion
14.

"cis-2-Butene"underset("Addition")overset(Br_2)to"product". Which statemetn about product is correct.

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Product formed by electrophilic addition
Two chiral CENTRE are present in the product
Product CONTAINS a pair of enantiomers
product is a racemic mixture

Solution :Antiaddition takes place Anti addeition of halogen on cis symmetrical alkene gives acemimixture REMEMBER CAR C = cissymmetrical ALKEN A = Antiaddition halogens R = Ramemic mix tune It is eletrophilic addition

Product has two chiral centers Product contains a pair of enantiomus
Produced is a racemic mixture
Discussion
15.

Cis -2- butene and trans -2- butene are

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conformatonal isomers
structural isomers
configuration isomers
optical isomers

Answer :A::C
Discussion
16.

cis-2-butene and trans 2-butene are

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CONFORMATIONAL isomers
structural isomers
configurational isomers
optical isomers

Answer :C
Discussion
17.

cis -2 butene and trans -2- butene are …………….

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CONFORMATION ISOMERS
structural isomers
configuratinoal isomers
OPTICAL isomers

ANSWER :C
Discussion
18.

Cinnamic aldehyde can be converted into cinnamyl alcohol by

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`LiAlH_(4)`
`NaBH_(4)`
`Ni//H_(2)`
Both A and B

Solution :`LiAlH_(4)` attacks a double bond when phenyl group is attached to the `beta`-carbon ATOM of `alpha, beta` unsaturated CARBONYL group. However, under these CONDITIONS `NaBH_(4)` do no attack the double bond.
`underset("Cinnamic ALDEHYDE")(C_(6)H_(5)-CH=CHO+2[H]) overset(NaBH_(4))rarr underset("Cinnamyl ALCOHOL")(C_(6)H_(5)-CH=CH-CH_(2)OH)`
Discussion
19.

CIF_(3)is which type from AB_(3) , AB_(3)E_(2) , AB_(3) E ? How ?

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SOLUTION :It is `AB_(3) E_(2) `type. Because three Cl - F bond with Cl, i.e., `B_(3)` and two nonbonding `e^(-) ` pair on Cl.
Discussion
20.

Cl^(-) ion is more stable than Cl atom - Why?

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Solution :DUE to octet CONFIGURATION, `CI^(-)` ion is more STABLE
Discussion
21.

Chrysobery is a mineral of

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Mg
Ba
Be
Ra

Solution :CHRYSOBERY is a MINERA OFR B.
Discussion
22.

Chromyl chloride test can be given by how many of the following compounds easily?

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SOLUTION :
Discussion
23.

Chromium metal in basic medium is oxidised in air to give chromic tetrahydroxide anion.

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Solution :a) This IONIC skeleton EQUATION is written as
`Cr+O_(2)OVERSET(OH^(-))rarrCr(OH)_(4)^(-)`
b) Writing oxidation numbers
`overset(0)(Cr)+overset(0)(O_(2))rarr[overset(+3)(Cr)(overset-2)(O)overset(+1)(H))_(4)]^(-)`
c) Locating atoms undergoing change in oxidation numbers
`overset(0)(Cr)+overset(0)(O_(2))rarr[overset(+3)(Cr)(overset(-2)(O)H)_(4)]^(-)`
d) Dividing the reaction into two halves andbalancing in acidic medium. separately
Oxidation half - reaction : `Crrarr[Cr(OH)_(4)]^(-)`
Step 1 : Balance oxygen atoms
`Cr+4H_(2)Orarr[Cr(OH)_(4)]^(-)`
Step 2 : Balance hydrogen atoms
`Cr+4H_(2)O+4OH^(-)rarr[Cr(OH)_(4)]^(-)+4H_(2)O`
Step 3 : Balance the CHARGE
`Cr+4H_(2)O+4OH^(-)rarr[Cr(OH)_(4)]^(-)+4H_(2)O+3e^(-)"....(a)"`
Reduction half - reaction : `O_(2)rarr[Cr(OH)_(4)]^(-)`
Step 1 : Balance chromium atoms
`O_(2)+Crrarr [Cr(OH)_(4)]^(-)`
Step 2 : Balance oxygen atoms
`O_(2)+Cr+2H_(2)Orarr[Cr(OH)_(4)]^(-)`
Step 3 : Balance hydrogen atoms
`O_(2)+Cr+2H_(2)rarr[Cr(OH)_(4)]^(-)`
Step 4: Balance charnge
`O_(2)+Cr+2H_(2)O+e^(-)rarr[Cr(OH)_(4)]^(-)"....(b)"`
Step 5 : Equalising the electrons and adding the two half reactions
`"eq (a)"XX1+"eq (b)"xx"3, we get"`
`{:(Cr+4H_(2)O+4OH^(-)rarr),(""[Cr(OH)_(4)]^(-)+4H_(2)O+3e^(-)),(Cr+4H_(2)O+4OH^(-)rarr),(""[Cr(OH)_(4)]^(-)+4H_(2)O+3e^(-)),(3O_(2)+3Cr+6H_(2)O+3e^(-)rarr2[Cr(OH)_(4)]^(-)),(bar(4Cr+3O_(2)+6H_(2)O+4HO^(-)rarr4[Cr(OH)_(4)]^(-))):}`
This is the balnced equation.
Discussion
24.

Chromite ore is processed through the following sequence In this sequence how many species (from A to H) show green colour?

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ANSWER :C
Discussion
25.

Chromic salts (Cr^(3+)) can be reduced to chromous salts (Cr^(2+)) by adding metals(s) to the salt solution acidified with dil. H_(2)SO_(4)

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Sn
Fe
Zn
All the three.

Solution :Such REDUCTIONS were once believed to be DUE to nascent HYDROGEN. But infact it is not so. This reduction can only be CARRIED out with `Zn//H^(+)`.
Discussion
26.

Chromatography technique is used for the separation of :

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SMALL SAMPLES of mixtures
plant pigments
dye stuffs
All the above.

Answer :D
Discussion
27.

Chromatography technique has proved useful for the isolation and detection of (i) amino acids (ii) sugars (iii) plant pigments (iv) nonvolatile liquids

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(i), (ii), (III), (iv)
(i), (ii)
(ii), (iii)
(i), (ii), (iii)

SOLUTION :It is APPLIED to COLORED as well as colorless substances.
Discussion
28.

chromatography is the mathod used to separate and purify compounds when present in small amounts

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ANSWER :t
Discussion
29.

Chromatography is a technique based on

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SOLUBILITIES of solute
ADSORPTION of solute
Chemical adsorption FOLLOWED by dispersion
Differential adsorption of DIFFERENT CONSITITUENTS of a mixture

Answer :D
Discussion
30.

Chromatography is a recent and most effective technique which was used by Tsweff, a botanist for the separation of coloured substances into individual constutients. The name Chromatography means colour writing (In Greek , Chrome = colour, graphy = writing). However, the name as such has lost its significance. The technique can be used to separate constituents from any mixture whether coloured or colourless. (i) What is the basic of Chromatographic separation ? (ii) What is the value associated with it ?

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Solution :(i) CHROMATOGRAPHY is based on selective distribution of the various constituents of a MIXTURE between two PHASES, a stationary phase and a mobile phase. Different constituents migrate at different rates through stationary phase.
(ii) Chromatography is very useful for the separation of constituents and their identification from a mixture available in very SMALL amount (even less than 5 MG or 1 mL). However, other methods of separation are not effective in such cases.
Discussion
31.

Chosse the odd one out

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ETHANE
benzene
ETHENE
ethyne

SOLUTION :(b) Benzene . It isanaromatichydrocarbonwhereasothersare aliphatichydrocarbond.
Discussion
32.

Choose the wrong statements :

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`CO_2` is responsible for greenhouse effect.
`CO_2` can absorb infrared red radiation but does not allow then to pass through
NO is more harmful than `NO_2`
Acidrain contains mainly `HNO_3`

Solution :( c) is WRONG because NO is COLOURLESS and odourless whereas `NO_2` is reddish brown having pungent smell and is suffocating in NATURE
(d) is wrong because acid RAIN contains 60-70% `H_2SO_4` whereas `HNO_3` is 30-40% and least is HCI
Discussion
33.

Choose the weakest acid among the following

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`F_(3)C COOH`
`FCH_(2)COOH`
`CH_(3)COOH`
`(CH_(3))_(2)CHOOH`

ANSWER :D
Discussion
34.

Choose the strongest base among the following:

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SOLUTION :No RESONANCE
Discussion
35.

Choose the reaction which may be used in metallurgical extractions :

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`CaO+P_(4)O_(10)rarr2Ca_(3)(PO_(4))_(2)`
`2Ca(OH)_(2)+2Cl_(2)rarrCaCl_(2)+Ca(Ocl)_(2)+2H_(2)O`
`CaO+SiO_(2)rarrCaSiO_(3)`
`CaCl_(2)+Na_(2)CO_(3)rarrCaCO_(3)+2NaCl`

Solution :N//A
Discussion
36.

Choose the reaction sequence that would best accomplish the preparation of 2-methylcyclohexnol:

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Solution :2-methyl cyclo hexene with BH,THF, hydrolysis.
Discussion
37.

Choose the paramagnetic oxide in the following

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`Na_(2) O `
`MGO `
`BeO `
`KO_(2)`

Solution :` KO_(2)` contains ` O_(2)^(-)` , others CONTAIN ` O^(2 - )`.
Discussion
38.

Choose the pairs of in which IE_(1) of first element is greater than IE_(1) of second element but in case of IE_(2) order is reversed-

Answer»

<P>`P,S`
`F,O`
`Mg,Al`
`N,O`

ANSWER :A::D
Discussion
39.

Choose the odd one out.

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1) Entropy
2) Enthalpy
3) Free energy
4) MOLALITY

Solution :Molality is an intensive PROPERTY while OTHERS are EXTENSIVE property
Discussion
40.

Choose the odd one out

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COPPER
Copper oxide
Copper sulphate
Copper nitrate

Solution :Copper is an ELEMENT WHEREAS OTHERS are COMPOUNDS.
Discussion
41.

Choose the odd one out .

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see -saw
tuh of war
sublimation of camphor
Acid hydrolysis of an ester

Solution :Acid hydrolysis of an ester
Acid hydrolysis of an ester is CHEMICAL equilibrium
`CH_(3)COOCH_(3(aq))+H_(2)O_(aq) overset(H^+) hArr CH_(3)COOH_((aq)) + CH_(3)OH_((aq))`
Whereas a,b,c are EXAMPLES of physical equilibrium.
Discussion
42.

Choose the most appropiate pair of nitrogens that gets protonated in the following structures.

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1 and 3
2 and 4
1 and 4
2 and 3

Answer :C
Discussion
43.

Choose the molecule which has only one pi bond between carbon atoms

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`CH_(2)=CH-CH=CH_(2)`
`CH_(2)=CHCOOH`
`CH_(3)CH=CH_(2)`
`CH=CH`

Answer :C
Discussion
44.

Choose the incorret statement.

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In equilbirium mixture of ice and WATER kept in PERFECTLY in perfectly insuled flask. Mass of ice and water does not change with time
The intensity of red colour increase when oxalic acid is ADDED to a solution containing iron (III) nitrate and potassium thiocyanate
On addition of catalyst the equilibrium constant value is not affected
Equilibrium constant for a reaction with negative `Delta H` value decrease as the timperature increases.

Solution :Oxalate ions of oxalic acid from comples with FERRIC ions thus decrease its concentration thus, concentration of red COMPLEX in product decreases.
Discussion
45.

Choose the incorret pair.

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Acid HYDROLYSIS of an ester : Homogeneous EQUILBRIUM
Synthesis of Ammonia : Homogeneous equilibrium
Decomposition of `CaCO_(3)`:Homogeneous equilbrium
Synthesis of HI : Homogeneous equilibrium

SOLUTION :It is a HETEROGENEOUS equilibrium .
Discussion
46.

Choose the incorrect statement in the following :

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BeO is almost insoluble but `BeSO_(4)` is soluble in water
BAO is soluble but `BaSO_(4)` is insoluble in water
Both Li and Mg form solid hydrogen carbonates
Both LICL and `MgCl_(2)` are DELIQUESCENT

SOLUTION :Both Li and Mg do not form solid hydrogen carbonates .
Discussion
47.

Choose the incorrect statement in the following .

Answer»

Surface TENSION is the force acting perunit length perpendicular to the LINE drawn on the surface of the liquid
Surface tension of a liquid increases with INCREASE in temperature
The SI unit of surface tension in `J m^(-2)`
Viscosity is a measure of resistance for the flow of liquid .

SOLUTION :Surface tension of a liquid decreases with increase of temperature because intermolecular forces of attraction decrease with increase in temperature .
Discussion
48.

Choose the incorrect statement in respect of physisorption

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it is not SPECIFIC in nature
It arises because of vander Waal's forces
it is REVERSIBLE in nature
Enthalpy of adsorption is in the range 80-240 kJ `mol^(-1)`

Solution :The heat EVOLVED in PHYSISORPTION is quite low varing generally between 20-40 kJ `mol^(-1)`.
Discussion
49.

Choose the incorrect statement about the following compounds .

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Compounds (I) and (II) are CONSTITUTIONAL isomers .
Compounds (I) and (III) are resonance structures
Compounds (I) and (IV) are resonance structures
Compounds (II) and (IV) are resonance structures .

Answer :C
Discussion
50.

Choose the incorrect statement.

Answer»

In ortho form of hydrogen molecule, the nuclear spins in the same direction.
The magnetic moment of para hydrogen is twice that of ortho hydrogen.
By PASSING an electric DISCHARGE, para hydrogen can be converted into ortho hydrogen.
As the ortho-form is more STABLE than para-form, the CONVERSION of one isomer into the other is a SLOW process.

Answer :b
Discussion