Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In diborane the two H-B-H angles are nearly

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`60^(@), 120^(@)`
`95^(@), 120^(@)`
`95^(@), 150^(@)`
`120^(@), 180^(@)`

SOLUTION :In diborane, `H_(t)-B-H_(t)` and `H_(b)-B-H_(b)` BOND angles are `120^(@)` and `97^(@)` respectively (`H_(t)=` terminal hydrogen atoms, `H_(b)` = BRIDGED hydrogen atoms).
2.

In differential extraction from two layer……layer is above because……

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SOLUTION :SOLVENT, its DENSITY is LESS
3.

In diborane, the number of electronsthat account for bondingin the bridges is

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SIX
TWO
eight
four

Solution :There are fourelectronsin two BRIDGES.
4.

In diborane, the hybridisation of Boron is

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SP
`sp^2`
`sp^3`
`sp^3 d`

ANSWER :C
5.

In diborane , the number of electrons that account for bonding in the bridges is

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six
two
eight
four

Solution :DIBORANE has two 3c-2e BONDS (bridges). Thus there are 4 ELECTRONS for bonding in the bridges.
6.

In diamond lattice, all lattice points and alternate tetrahedral voids are occupied by carbon atoms. If diamond crystallizes in fcc form with edge length 'a' , find out (a)number of next nearest neighbours in diamond lattice (b)distance between the next nearest neighbours.

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Solution :(a)Nearest neighbours are atoms at the LATTICE POINS and tetrahedral voids. Hence, NEXT nearest neighbours are atoms at the lattice POINTS.
`therefore` Number of next nearest neighbours =12 (being fcc lattice )
(B) For fcc, nearest neighbour distance (d)=`a/sqrt2`=0.707 a
7.

In diborane, banana bond is formed between

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2 ELECTRONS, 3 ATOMS
2 electrons, 1 atom
2 electrons, 2 atoms
1 ELECTRON, 2 atoms.

Solution : 2 electrons, 3 atoms
8.

In diammonium phosphate (NH_(4))_(2)HPO_(4), the percentage of P_(2)O_(5) is

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<P>`35.87`
`46.44`
`51.99`
`53.78`

Solution :`%P_(2)O_(5)=(142)/(2xx132)XX100`
9.

In determination by Victor Meyer method, 0.60 g of a volatile substance expelled 123 mL of air measured over water at 20^(@)C and 757.4 mm pressure. Find the molecular mass of the substance. Aqueous tension at 20^(@)C is 17.4 mm.

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SOLUTION :MASS of the organic substance `=0.60 g`
Volume of the displaced air `=123.0 mL`
Temperature at which air is collected `=20^(@)C=(20+273)=293 K`
Pressure at which air is collected `=757.4 mm`
Aqueous tension at `293 K=17.4 mm`
Pressure of the dry air `=757.4-17.4=740 mm`
STEP I. Calculationof the volume of the air displaced (or vapours of the substance) at N.T.P.
`{:("EXPERIMENTAL conditions","N.T.P. conditions"),(V_(1)=123.0 mL,V_(2)=?),(P_(1)=740 mm,P_(2)=760 mm),(T_(1)=293 K,T_(2)=273 K):}`
By applying gas equation :
`(P_(1)V_(1))/T_(1)=(P_(2)V_(2))/T_(2)`
or `V_(2)=(P_(1)V_(1)T_(2))/(T_(1)P_(2))=((740mm)xx(123.0 mL)xx(273 K))/((293K)xx(760 mm))=111.6 mL`
Step II. Calculation of the molecular mass.
111.6 mL of vapours are obtained from subtance = 0.60 g
22400 mL of vapours are obtained from substance `=((0.60g)xx(22400 mL))/((111.6 mL))=120.4 g`
`:.` Molecular mass of the substance `=120.4 g mol^(-1)`.
10.

In detection of halogen what is form by adding AgNO_(3) ? What is its colour?

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Solution :(i) Precipitate of AGX (ii) WHITE precipitate of AGCL (iii) LIGHT yellow precipitate of AgBr (IV) Yellow precipitate of AgI
11.

In dehydrohalogenation, hydrogen and halogen are removed from

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the same CARBON atom
adjacent carbon atoms
isolate carbon atoms
any TWO carbon atoms

Answer :B
12.

In dehalogenation reaction of dihalides to get alkenes, the dihalide to be taken is

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Gem dihalide
Vicinal dihalide
ISOLATED dihalide
Any dihalide

Answer :B
13.

In CuSO_4.5H_2Oall Cu- O bond length are not equal. The total number of shorter Cu - O bonds will be

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4
1
2
3

Answer :A
14.

In curing cement plasters , water is sprinkled from time to time . This helps in

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converting sand into silicic acid
keeping it COOL
developing interlocking needle LIKE crystals of HYDRATED SILICATES
hydrating sand and gravel mixed with cement

Answer :C
15.

In curing cement plasters, water is sprinkled from time to time. This helps in....

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converting sand into silica acid.
KEEPING it cool.
developing interlocking needle like CRYSTALS of HYDRATED silicates.
hydrating sand and GRAVEL mixed with cement.

Answer :C
16.

In curing cement plasters, water is sprinkled from time to time. Which of the following statements are incorrect.

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keeping it cool
converting SAND in to silicic acid
HYDRATED sand gravel mixed with cement
developing interlocking NEDDLE like CRYSTALS of hydrated silicates

Solution :The three resons are not correct.
Reason : developing interlocking needle like cyrstals of hydrated silicates.
17.

In Cu - Zn cell

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Reduction occurs at the copper cathode
Oxidation occurs at the copper cathode
Reduction occurs at the anode
Chemical energy is converted to LIGHT energy

SOLUTION :In Cu-Zu CELL copper ACTS a cathode . So, reduction takes place at copper cathode.
18.

In Cu (At. No. 29)

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13 ELECTRONS have SPIN in one direction and 16 electrons in other direction
14 electrons have spin in one direction and 15 electrons in other direction
one electron can have spin only in the clockwise direction
none of the above is correct.

Solution :`._(29)Cu = [Ar[^(18) 3D^(10) 4s^(1)`
All electrons are paired except `4s^(1)`. Hence, `14E^(-)` have spin one direction and `15 e^(-)` in the other
19.

In crystals of which of thefollowingionic compounds wouldyou expect themaximum distancebetweencentres ofcationsand anions

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`CsF`
`CsI`
`LII`
`LIF`

Solution :Bigger the SIZEOF ions `(CS^(+)` and`I^(-))` longer is thedistancebetweenthe CENTRES oftheirnuclei
20.

In CsCl, if the co-ordination number of Cs^(+) is 8 then co-ordination number of Cl^(-) ion is

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8
16
6
4

Answer :A
21.

In crystal structure of NaCl, total number of Cl^- ions in a unit cell is

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6
4
8
2

Answer :B
22.

In crystal structure ofNaCl, total number ofCl^(-)ionsin a unit cell is

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6
4
8
2

Answer :B
23.

In covalent bond

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TRANSFER of electrons takes place
sharing of electrons takes place
electrons are SHARED by only ONE atom
none of these

Answer :B
24.

In corundum, oxide ions are arranged in hexagonal close packing and aluminium ions occupy two-third of the octahedral voids. What is the formula of corundum ?

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SOLUTION :Suppose oxide ions =n. Then octahedral voids= n. HENCE, `Al^(3+)` ions `=2/3xxn="2n"/3`
`therefore` Ratio `Al^(3+) : O^(2-)="2n"/3:n =2:3` , i.e., FORMULA is `Al_2O_3`
25.

In corrundum, oxide ions are arranged in hexagonal close packing and aluminium ions occupy two-third of the octahedral voids. What is the formula fo corrundum ?

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SOLUTION : SUPPOSE oxideions = n . Then octahedral voids = n Hence,` Al^(3+) " ions"= 2/3 xx n = (2n)/3`
RATIO` Al^(3+): O^(2-)= (2n)/ 3 : n = 2: 3`FORMULA is ` Al_(2)O_(3)` \
26.

In correct statement about the structure of PCl_5

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AXIAL P - CL BONDS have more bondlength than equtorial P -Cl bonds
`d_z^2` orbital is involved in `Sp^3d` hybridization.
The no. of planar ATOMS in `PCl_5` is 4
Phosphorous is in 2nd EXCITED state.

Answer :D
27.

In conversion of limestone to lime, CaCO_(3)(s) to CaO(s) + CO_(2)(g) the values of DeltaH^(@) and DeltaS^(@) are + 179.1 kJ mol^(-1) and 160.2 J/K respectively at 298 K and 1 bar. Assuming that DeltaH^(@) and DeltaS^(@) do not change with temperature, the temperature above which conversion of limestone to lime will be spontaneous is:

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1200 K
845 K
1118 K
1008 K

Solution :`T = (DeltaH^(@))/(DELTAS^(@)) = (179.1 xx 10^(3)J)/(160.0JK^(-1))`
` = 1117.97 = 1118 K`
28.

In contrast with beryllium, which one of the following statements is incorrect -

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it forms `Be_2C`
its salts rarely hydrolysed
its hydride is electron DEFICIENT and polymeric
it is rendered passive by nitric ACID

Solution :Beryllium forms covalent compounds, thus HYDROLYSIS of beryllium compounds occurs readily.
29.

In context with the industrial preparation of hydrogen from water gas (CO+H_(2)), which of the following is the correct statement ?

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CO is oxidising to `CO_(2)` with STEAM in the presence of a catalyst followed by absorption of `CO_(2)` in alkali
`CO and H_(2)` are fractionally separated USING DIFFERENCES in their densities
CO is REMOVED by absorption in aqueous `Cu_(2)Cl_(2)` solution
`H_(2)` is removed through occlusion with Pd

Answer :A
30.

In context with the industrial preparation of hydrogen from water gas (CO + H_2), which of the following is the correct statement ?

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CO is removed by absorption in aqueous `CaCl_2` solution.
`H_2` is removed through occlusion with PD
CO is oxidised to `CO_2` with steam in the PRESENCE of a catalyst followed by absorption of `CO_2` in ALKLI.
CO and `H_2` are fractionally SEPARATED USING differences in their densities.

Answer :C
31.

Which of the following statement is correct?

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CO and `H_2` are fractionally separated using differences in their densities
CO is removed by ABSORPTION in AQUEOUS `Cu_2Cl_2` is solution
`H_2` is removed through occlusion with Pd
CO is oxidised to `CO_2` with steam in the presence of a CATALYST followed by absorption of `CO_2` in alkali

Solution :`underset("steam")(CO + H_2O to CO_2 + H_2)`
32.

In context with beryllium , which one of the following statements is incorrect ?

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It is rendered passive by nitric acid
It FORMS `Be_(2)C`
Its SALTS rarely hydrolyze
Its hydride is electron-deficient and polymeric .

Solution :DUE to small size and HIGH hydration enthalpy Be COMPOUNDS readily hydrolyse .
33.

In context with beryllium, which one of the following statements is incorrect?

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It is RENDERED PASSIVE by nitric acid
It forms `Be_2C`
Its SALTS are rarely hydrolysed
Its hydride is electron deficient and polymeric

Answer :C
34.

In compounds of type ECl_3, where E = B, P, As or Bi, the angles CI-E - CI for different E are in the order

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<P>`B gtP= As = Bi `
` B gtP gtAsgtBi`
`BLT P = As = Bi `
`Blt P LT As LTBI `

Answer :B
35.

In the compound 'X', all the bond angles are exactly 109^(@)28. 'X' may be________.

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CHLOROMETHANE
IODOFORM
CARBON TETRACHLORIDE
chloroform

Answer :C
36.

In compound A, 1.00 g nitrogen unites with 0.57 g oxygen. In compound B, 2.00g nitrogen combines with 2.28 g oxygen. In compound C, 3.00 g nitrogen combines with 5.13 g oxygen. These results obey the following law.

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Law of constant PROPORTION
Law of multiple proportion
Law of reciprocal proportion
Dalton.s law of partial pressure

Solution :`{:(,N_(2),O_(2)),("A",1gm,0.57g),("B",2gm,2.24g),(,1gm,1.12g),("C",3gm,5.11g),(,1gm,1.7g):}`
implies different COMPOUNDS.
37.

Incomplete combustion of petrol in automobile engines can be detected by testing the fuel gases for the presence of

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`NO_(2)`
CO
`CO_(2)`
`CO+ H_(2)O`

SOLUTION :TESTING the fuel GASES in the PRESENCE of .CO.
38.

In comparison to the zeolite process for the removal of permanent hardness, the synthetic resins method is:

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LESS EFFICIENT as it exchanges only anions.
More efficient as it can exchanges only cations.
Less efficient as the RESINS cannot be generated.
More efficient as it can exchange both cations and anions.

Answer :D
39.

In comparison to boron, berylium has :

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(A) LESSER nuclear charge and greater FIRST IONISATION enthalpy
(B) greater nuclear charge and greater first ionisation enthalpy
(C) greater nuclear charge and lesser first ionisation enthalpy
(D) lesser nuclear charge and lesser first ionisation ethalpy.

Solution : lesser nuclear charge and greater first ionisation enthalpy
40.

In commercial electrochemical process for Al extraction, electrolyte used is

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`AL(OH)_(3)` in `NAOH` SOLUTION
An aqueous solution of `Al_(2)(SO_(4))_(3)`
A molten MIXTURE of `Al_(2)O_(3)` and `Na_(3)AlF_(6)`
A molten mixture of `Al(OH)_(3)` and `AlO(OH)`

Solution :Al is extracted commercially by the electrolysis of a molten mixture of `Al_(2)O_(3)` (ALUMINA) and `Na_(2)AlF_(6)` (cryolite).
41.

In commerical reverse osmosis process, the semi permeable membrane used is …………………..

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SOLUTION :CELLULOSE ACETATE
42.

In commercial electro chemical process for Al extraction electrolyte used as

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`AL(OH)_(3)` in NaOH SOLUTION
aq. `Al_(2)(SO_(4))_(3)`
Al MOLTEN mixture of `Al_(2)O_(3)` and `Na_(3)AlF_(6)`
none of the above

Solution :Only .NaOH. because it is basic in nature.
43.

In column chromatography the moving phase consists

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A SUBSTANCE which is to be separated
Mixture of ELUENT and adsorbent
Eluent
Adsorbent

Answer :C
44.

In column chromatography stationary, phase is

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Only SOLID
Only LIQUID
Only GAS
All of these

ANSWER :A
45.

In close vessel the reaction A_((s)) hArr 4B_((g)) + 3C_((g))is in equilibrium. If the partial pressure of C is double then what will be the partial pressure of B?

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SOLUTION :`1/(2SQRT2)` TIMES of ESSENTIAL PRESSURE
46.

In close vessel at 298 K temperature, the water vapour pressure is 25 mm. Then which equilibrium is it ?

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HOMOGENEOUS EQUILIBRIUM
Hetrogeneous equilibrium
Chemical equilibrium
IONIC equilibrium

Answer :B
47.

In Clark's method, the obstance used for the removal of temporary hands of Willer

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`NaOH`
`CaCO_3`
`Ca(OH)_2`
`Ca(HCO_3)_2`

ANSWER :C
48.

In Cl_(2) molecule covalent radius is 99 pm and van-dar-Walls radius is 180 pm what is the distance between two nucleus and distance between two molecules ?

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<P>

SOLUTION :198 PM and 360 p respectvely
49.

In cis and trans, whose dipole moment is more, explain with example ?

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Solution :`CH_(3)CH=CHCH_(3)` has 2 geometrical isomers :
(i) Cis-but-2-ene (ii) Trans-but-2-ene.
Always cis-isomer DIPOLE moment `(mu) gt` Trans-isomers.
Isomers of But-2-ene are shown with its isomers and dipole moment.

Trans-but-2-ene has `2-CH_(3)` group, they are in opposite side therefore dipole moments of `C-CH_(3)` BONDS circle, thus making the trans form non-polar.
Cis isomers are polar because in Cis-but-2-ene has `2-CH_(3)` group and they are on same side of double bond. ELECTRONEGATIVITY of `C_CH_(3)` are added, in which the dipole moment is more. therefore, cis-isomer is polar and trans isomer is non-polar.
50.

In CIF_(3),NF_(3)andBF_(3) molecules the chlorine nitrogen and boron atoms are…

Answer»

`SP^(3)` hybridised
`sp^(3),sp^(3), and sp^(3)` respectivily
`sp^(2)` hybridised
`sp^(3)d,sp^(3)and sp^(2)` hybridiesd respectively

Answer :D