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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Intramolecular H-bonding is present in___________ |
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Answer» o-nitrophenol |
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| 2. |
Intramolecular dehydration of alcohols is carried out with _______ to give ___ |
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Answer» |
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| 5. |
Internal energy of an ideal gas depends upon |
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Answer» Pressure |
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| 6. |
Internal energy change of a system is the heat absorbed or evolved at constant "…............." whereas enthalpy change is that at constant "…...............". |
| Answer» SOLUTION :VOLUME, PRESSURE | |
| 7. |
Intermolecular hydrogenbonding is strongest in |
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Answer» Methuylamine |
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| 8. |
Intermolecular H-bonding is present in ___________ |
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Answer» HF |
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| 9. |
Intermolecular forces and thermal energy decide physical state of matter. Explain |
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Answer» Solution :Intermolecular forces tend to keep the molecules together but thermal energy of the molecules tends to keept them APART. Three states of matter are the result of balance between intermolecular forces and the thermal energy of the molecules. When molecular interactions are very WEAK, molecules do not cling together to make liquid or SOLID UNLESS thermal energy is reduced by lowering the temperature. Gases do not liquify on compression only, although molecules come very close to each other and intermolecular forces operate to the maximum. However, when thermal energy of molecules is reduced by lowering the temperature, the gases can be very easily liquified. Predominance of thermal energy and the molecular interaction energy of a SUBSTANCE in three states is depicted as follows :  So, we know that all the three states of matter solid, liquid and gas how situated. ..When temperature of gas decreases and decreases thermal energy liquifaction of gas occurs but we can.t obtained state liquid or solid after compressibility of gas we should decrease thermal energy... |
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| 10. |
Intermolecular forces are much stronger in ammonia than in methane. Comment |
| Answer» Solution :Between molecules of methane intermolecular FORCES present are dispersion forces. These are very WEAK. Between molecules of ammonia, inter molecular HYDROGEN is present. These intermolecular forces are relatively strong. | |
| 11. |
Intermediates for both the steps are respectively ? |
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Answer» CARBOCATION & No INTERMEDIATE |
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| 12. |
Intramolecular hydrogen bonding is present in |
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Answer» META nitrophenol |
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| 13. |
Intercoversion takes place in : |
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Answer» ACIDIC medium |
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| 14. |
Inter molecular hydrogen bonding is absent in |
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Answer» `H_(2)O` is non polar |
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| 15. |
Inter molecular forces in solid hydrogen are |
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Answer» Covalent forces |
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| 16. |
Insulin contains 3.4% sulphur. What will be the minimum molecular weigh of insulin? |
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Answer» 94.117 If 3.4 g of S is present, the molecular mass = 100 `THEREFORE` if 32 g of S is present, the molecular mass will be `=(100 xx 32)/(3.4) = 941.176 |
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| 17. |
Inspite of long range order in the arrangement of particles why are the crystals usually not perfect ? |
| Answer» Solution :This is because when crystallisation occurs at a fast or moderate rate, the CONSTITUENT particles may not get sufficient TIME to arrange themselves in a PERFECT order | |
| 18. |
Inspite of longe range order in the arrangement of particles why are the crystals usually not prefect ? |
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Answer» |
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| 19. |
Inspite of being electron deficient, boron halides do not exist as dimers. Explain. |
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Answer» SMALL size of boron ATOM |
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| 20. |
Inside a spherical glass flask 'A' of radius 1 meter containg 300gm of H2, there was another rubber balloon B containing some N2. Inside the balloon B, another rubber balloon 'C containing some O_(2) is present. At 27°C it was found that the balloon B had a radius of 60cm and balloon 'C had a radius of 30cm Calculate the moles of nitrogen in the balloon B |
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Answer» <P>4.123 ATM `r_B = 60 cm ` `r_A = 3282 ` litre `P = (150 xx 0.0821)/(3282) xx 300 = 1.123 atm` 
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| 21. |
Inorganic benzene is |
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Answer» `(BN)_(X)`  `B_(3)N_(3)H_(6)` is called Inorganic BENZENE |
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| 22. |
Inneutral or faintly alkaline solution, 8 moles of permanganate anion quantitatively oxidize thiosulphate anions to produce X moles of a sulphur containing product. The magnitude of X is : |
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Answer» `8MnO_(4)^(-)+3S_(2)O_(3)^(2-)+H_(2)O to 8MnO_(2)+6SO_(4)^(2-)+2OH^(-)` 8 moles of permanganate ion GIVE 6 mols of sulphur CONTAINING product. |
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| 23. |
Initially the reactions in the container a "&" b are at equilibrium when the products & reactants are put together in a container C then at the equilibrium the total number of different compounds are- |
| Answer» SOLUTION :`{:(N_(2),NHD_(2)),(H_(2),NH_(2)D),(D_(2),HD),(NH_(3),),(NO_(3),):}}=8` | |
| 24. |
Initially 0.8 mole of PCl_(5) and 0.2 mole of PCl_(3) are mixed in one litre vessel . At equilibrium 0.4 mole of PCl_(3) is present . The value of K_(C) for the reaction PCl_(5(g)) hArr PCl_(3(g)) + Cl_(2(g))is |
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Answer» 0.13 `MOLL^(-1)`  `K_(c)=([PCl_(3)](Cl_(2)])/([PCl_(3)])=0.13` |
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| 25. |
Initial setting of cement is mainly due to |
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Answer» dehydration and gel FORMATION |
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| 26. |
(i)NH_4^(+)+H_2O hArr NH_3+H_3O^(+)equilibrium constant = K_1 (ii)NH_3 + H_2O hArr NH_4^(+) + OH^- equilibrium constant = K_2 Than write reaction and equilibrium constant obtain by addition of these two reaction. |
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Answer» Solution :(i) + (ii) = `2H_2O hArr H_3O^(+) + OH^(-)` . The EQUILIBRIUM constant of this (i) and (ii)=K `THEREFORE K=(K_1xxK_2)=K_w=1.0xx10^(-14)` |
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| 27. |
Information : The entire system is at eqilibrium at 300 K. The volume of each chamber is 82.1.L. Total pressure in left chamber is 4 atm and in right chamber is 2 atm. NH_(3)(g) and H_(2)S(s) are obtained only form dissociation of NH_(4)HS(s). Based on this information select the correct option : statement-1 : The K_(P) value for the reaction: NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g) is atm^2. statement- 2 : The parrical pressure of He gas in the left chamber is 1 atm. |
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Answer» Statement-1 is TRUE, Statement-2 is True, Statement-2 is a CORRECT EXPLANATION for Statement-1. |
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| 28. |
information : (a) prinicipal qunatum no n is defined as 1,2,3,……….. (b) Azimuthalquantum no .l hdefind as 1 to n +2 inintegral steps . (c ) magntic quantum no m is defindas -(1)/(2)"to " +(1)/(2)(including zero oif any, inin intergral steps). (d)spin quntum no s has six possiblevalues (-2,-1,-(1)/(2),+(1)/(2),+1,+2). (e ) the subshellcorresponding tol=1,2,3,4,5............... designeted as F,GltH,I,J,K.... respectively, (f)the valuesof m forgivenvalues of l give the numberof orbitals in a sub-shell . (g) theprionciple for fillingof E^(-)in theshellsreminsunchanged . the no fo orbitaland maximumnoof e^(-) that canbe filledin aJ- subshell respectivelywill be: |
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Answer» 6,36 `m=-(5)/(2),-(3)/(2) ,-(1)/(2),+(1)/(2) , (3)/(2) ,+(5)/(2)` No. of ORBITALS = 6 No. of `e^(-)= 6xx6=36` |
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| 29. |
information : (a) prinicipal qunatum no n is defined as 1,2,3,……….. (b) Azimuthalquantum no .l hdefind as 1 to n +2 inintegral steps . (c ) magntic quantum no m is defindas -(1)/(2)"to " +(1)/(2)(including zero oif any, inin intergral steps). (d)spin quntum no s has six possiblevalues (-2,-1,-(1)/(2),+(1)/(2),+1,+2). (e ) the subshellcorresponding tol=1,2,3,4,5............... designeted as F,GltH,I,J,K.... respectively, (f)the valuesof m forgivenvalues of l give the numberof orbitals in a sub-shell . (g) theprionciple for fillingof E^(-)in theshellsreminsunchanged . for the elelmenthaving atomicno43last e^(-) emters in: |
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Answer» Solution :`1F,1G ,2F ,1H ` 12+ 18 +12=42 |
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| 30. |
information : (a) prinicipal qunatum no n is defined as 1,2,3,……….. (b) Azimuthalquantum no .l hdefind as 1 to n +2 inintegral steps . (c ) magntic quantum no m is defindas -(1)/(2)"to " +(1)/(2)(including zero oif any, inin intergral steps). (d)spin quntum no s has six possiblevalues (-2,-1,-(1)/(2),+(1)/(2),+1,+2). (e ) the subshellcorresponding tol=1,2,3,4,5............... designeted as F,GltH,I,J,K.... respectively, (f)the valuesof m forgivenvalues of l give the numberof orbitals in a sub-shell . (g) theprionciple for fillingof E^(-)in theshellsreminsunchanged . the 2 nd period would begin with : |
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Answer» Ga |
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| 31. |
Inert pair effect is exhibited by |
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Answer» `PB` |
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| 32. |
Inert gas element which has a different valence shell configuration |
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Answer» Xe |
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| 33. |
What happens when NaH reacts with H_2O :- |
| Answer» | |
| 34. |
Industrial production of NaOH is carried out in ....... cell by electrolysis of NaCl. |
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Answer» Down cell |
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| 35. |
Industrial production of caustic soda involved which reaction ____ |
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Answer» DEHYDRATION of BRINE solution |
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| 36. |
Indusstrially, H_(2)O_(2) is obtainned by the following cyclic process: underset((P))("2-Ethylanthraquinol") underset(H_(2)//Pd)overset(O_(2))hArr underset((Q))("2-Ethylathraquinone")+H_(2)O_(2) Which one of the followin properties is wrong about the mixture of organic solvents inwhich the reaction is carried out? |
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Answer» It must resist oxidation |
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| 37. |
Inductive effect refers to |
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Answer» Electron DISPLACEMENT along a carbon CHAIN through sigma-bonds |
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| 38. |
Inductive effect of which ato is taken as zero to compare inductive effect of other atoms? |
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Answer» Hydrogen |
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| 40. |
Inductive effect involves |
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Answer» DISPLACEMENT off `SIGMA`-ELECTRONS RESULTING in polarisation |
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| 41. |
Inductive effect influences the basic strength as well as acidic strength. -I effect increases acidic strength where as +I effect increases basic strength as they stabilize conjugate base and acid respectively. Which of the following is the strongest acid |
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Answer» HCOOH |
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| 42. |
Inductive effect influences the basic strength as well as acidic strength. -I effect increases acidic strength where as +I effect increases basic strength as they stabilize conjugate base and acid respectively. Identify the strongest base. |
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Answer» `CH_(3)NH_(2)` |
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| 43. |
Inductive effect influences the basic strength as well as acidic strength. -I effect increases acidic strength where as +I effect increases basic strength as they stabilize conjugate base and acid respectively. Which is a stronger acid among the following |
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Answer» `O_(2)NCH_(2)COOH` |
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| 44. |
Indium and thallium of III A group have nearly similar atomic radii due to poor screening effect shown by f-electrons in the |
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Answer» PENULTIMATE shell of THALLIUM |
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| 45. |
Indicators HIn weak acids, Give expression of its equilibrium reaction in water and equilibrium constant. |
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Answer» Solution :`HI n_((aq))+H_2O_((L)) HARR In_((aq))^(-)+ H_3O_((aq))^(+)` `K_c=([H_3O^+][In^-])/"[HIN]"` |
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| 46. |
Indicate which onefrom O_(2)^(+) and O_(2)^(2-)may exhibit paramagnetism ? |
| Answer» Solution :`O_(2)^(-)`shows paramagnetic because it contains ONE UNPAIRED electron. | |
| 47. |
Indicate whether the following statements is TRUE of FALSE. Jusitfy your answer in not more than three lines : The dipole moment of CH_(3)F is greater than that of CH_(3) Cl |
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Answer» Solution :FALSE because no DOUBLE C-F bond is morepolar than C-CL bond DUE to greater ELECTRONEGATIVITY of F than Cl but C - F bond length is much smaller than C-Cl bond length . |
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| 48. |
Indicate whether the following statement is true or false. Justify your answer : |
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Answer» |
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| 49. |
Indicate the wrongly named compound. |
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Answer» `underset(("4-Methyl-1-pentanal"))(CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(2))-CH_(2)-CHO` |
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