Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The charge on colloidal particles is due to the ___________.

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adsorption of CHARGED species by disperse phase
formation of aggregates
collisions of disperse phase particles with MOLECULES of DISPERSION medium
VISCOSITY of the medium

Answer :A
2.

The charge on cobalt in [Co(CN)_6]^(3-) is

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`-6`
`+3`
`-3`
`+6`

SOLUTION :`[CO(CN)_6]^(3-),x-6 =-3,x+3`
3.

The charge on a cation 'M' is +2 and anion 'A' is -3. The compound formed has the formula

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`MA_(2)`
`M_(3)A_(2)`
`M_(2)A_(3)`
`M_(2)A`

ANSWER :B
4.

The charge on cation M is +2 and anion A is -3. The compound formed has the formula

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`MA_(2)`
`M_(3)A_(2)`
`M_(2)A_(3)`
`M_(2)A`

ANSWER :B
5.

The charge of an electron is 1.6xx10^(-19) coulombs. What will be the value of charge on Na^(+) ion

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`1.6xx10^(-19)C`
`3.2xx10^(-19)C`
`2.4xx10^(-19)C`
`11xx1.6xx10^(-19)C`

ANSWER :A
6.

the chargeof anelectronis -1.6 xx 10^(19) C.the valueof freechargeon Li^(+) ion will be

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`3.6 XX 10^(19) C`
`1XX 10^(19) C`
`1.6 xx 10^(19) C`
`2.6 xx 10^(19)C`

ANSWER :C
7.

The charge balance equation of species in 0.100 M acetic acid solution is given by

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`[H^(+)]=[OH^(-)]`
`[H^(+)]=[CH_(3)CO O^(-)]`
`[H^(+)]=[OH^(-)]+[CH_(3)CO O^(-)]`
`2 [H^(+)]=[OH^(-)]+[CH_(3)CO O^(-)]`

Solution :Solution will contain `H^(+), CH_(3)CO O^(-) and OH^(-)` IONS (from `H_(2)O`) . As solution as a whole is electricallyneutral, `[H^(+)]=[OH^(-)]+ [CH_(3)CO O^(-)]`.
8.

The charge and mass of the electron are....coulombs and kg respectively

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SOLUTION :`1.60 XX 10^(-19), 9.11 xx 10^(-31)`
9.

The characteristic temperature of a ferromagnetic substance above which it shows no ferromagnetism is known as ______

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ANSWER :CURIE TEMPERATURE
10.

The characteristic properties of transition elements are due to

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UNPAIRED electron in d-subshell
d-orbital have FIVE FOLD degeneracy
Presence of 2 nodal planes for d-orbital
Because they belong to d-block

Answer :A
11.

The characteristic not related to alkali metals is

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their ions are isoelectronic with noble GASES
LOW melting point
low electronegativity
HIGH IONIZATION energy

ANSWER :d
12.

The characteristic group of secondary alcohol is :

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`-CH_(2)OH`
`-underset(|)overset(|)(C)-OH`
`GT CHOH`
`gt C(OH)_(2)`

SOLUTION :`gt overset(2^(@))(C)H-OH`
13.

The characteristic feature of orderly arrangement of molecules belongs to

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SOLIDS
LIQUID
GASES
NONE of these

Answer :D
14.

The change of energy on freezing 1.00 kg of liquidwater at 0^(@)C and1 atmis

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`236 .7 kJ KG^(-1)`
` 333.4kJ kg^(-1)`
` - 333.4kJ kg^(-1)`
`- 236 .7 kJ kg^(-1)`

SOLUTION :Enthalpy of fusion of ice `= 6.03 kJ mol^(-1)` at `0^(@)C`
`:.`Enthalpy of freezing of water `= - 6.03 kJmol^(-1) `at`0^(@)C`
i.e.,.Enthalpy change on freezing of 18 g ofwater at `0^(@)C =- 6.03 kJ`
`:.`ENTHALPYCHANGE on freezing1000 g ofwter.
`= - ( 6.03)/( 18) xx 1000 =- 335 kJ `
15.

The change in velocity when electron jumps from the first orbit to the second orbit is

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Half its ORIGINAL VELOCITY
TWICE its original velocity
One FOURTH its original velocity
Equal to its original velocity

Solution :`V = 2.18 XX 10^6 xx Z/n`
16.

The change in Gibbs free energy of the system along provides a criterion for the spontaneity of a process at constant temperature and pressure. A change in the free energy of a sytem at constant temperature and pressure will be: DeltaG_("system") = DeltaH_("system") - T DeltaS_("system") The free energy for a reaction having Delta H= 31400 cal, DeltaS= 32 cal K^(-1) mol^(-1) at 1000^(@)C is

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`-9336` CAL
`-7386` cal
`-1936` cal
`+9336` cal

Solution :`DELTA G = Delta H- T Delta S`
`= 31400 - 32 (1273) = - 9336` cal
17.

For a system in equilibrium Delta G= 0 under conditions of constant:

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temperature and pressure
temperature and volume
pressure and volume
energy and volume

Solution :`(DELTA G)_(T,P) = 0` for EQUILIBRIUM
18.

The change in free energy during working of pencil cell is -1372.58 cal. Calculate the equilibrium constant of the cell under standard condition (R=2 "cal mol"^(-1) K^(-1) )

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`1.00 XX 10^(5)`
`1.00 xx 10^(2)`
`1.00 xx 10^(10)`
`1.00 xx 10^(1)`

ANSWER :B
19.

The change in enthalpy when one mole ofC_("diamond") " to " C _("graphite")is called ………..

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MOLAR heat of VAPORISATION
Molar heat of sublimation
Molar heat of TRANSITION
Molar heat of FUSION

ANSWER :C
20.

The change in enthalpy of NaOH+HClrarrNaCl+H_(2)Ois called ………

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Heat of REACTION
Heat of NEUTRALIZATION
Heat of FORMATION
Heat of liquid

Answer :B
21.

The chair form is ___________ stabole than boat form by potential energy _______kJ//mol.

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More, `44 kJ//mol`
LESS, `44 kJ//mol`
More, `12.55 kJ//mol`
Less, `4 kJ//mol`

ANSWER :A::D
22.

The CGS unit of dipolemoment is …………. Whereas its SIunit is …………..

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SOLUTION :DEBYE, COULOMB METRE (C m)
23.

The centre of the Sun consists of gases whose average molecular weight is 2 . If the density of the gases is 2.73 xx 10^(3) kg/ m^(3) at a pressure of 1.12 xx 10^(9) atm , the temperature at the centre of the Sun is (assuming ideal behaviour)

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`10^(8) K`
`10^(6) C`
`10^(7) K`
`10^(9) K`

Answer :D
24.

The central carbon atom in dichlorocarbene contains_______valence electrons.

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6
8
4
2

Answer :A
25.

The central C-atom of a carbanion possesses

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sectet of electrons
octet of electrons
duplet of electrons
none of these

Answer :B
26.

the central atoms of ch_2=c=ch_2is hybridized

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ANSWER :SP
27.

The cell constant of a given cell is 0.47 cm^(-1) . The resistance of a solution placed in this cell is measured to be 3.16 ohm . The conductivity of the solution (inA cm^(-1) where S has usual meaning ) is

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0.15
1.5
0.015
150

Solution :`K=(1)/(R)xx` Cell CONSTANT `=(0.47)/(316)=0.01487`
28.

The C—C bond length is maximum in :(a)C_(60)(b)diamond(c)C_(70)(d)All of these

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`C_(60)`
DIAMOND
`C_(70)`
All of these

Solution :diamond
29.

The cause of permanent hardness of water is due to

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`Ca(HCO_(3))_(2)`
`Mg(HCO_(3))_(2)`
`CaCI_(2)`
`MgCO_(3)`

SOLUTION :Permanent HARDNESS if water is due to the presence of the CHLORIDES, nitrates and SULPHATES `Ca^(2+)` and `Mg^(2+)` ions.
30.

The cause of cis-trans isomerism is

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strength of the double bond
stability of the double bond
vibration of the double bond
LACK of rotation about the double bond

Solution :Double bond don.t UNDERGO FREE rotation
31.

The cause of Brownian movement is

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heat changes in liquid state
convectional currents
the impact of molecules of the DISPERSION MEDIUM on the colloidal particle
Attractive forces between the colloidal PARTICLES and molecules of dispersion medium

Answer :C
32.

The cation which gives a yellow precipitate with potassium chromate is

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`NH_(4)^(+)`
`Ba^(2+)`
`CA^(2+)`
`Na^(+)`

Solution :Barium gives a YELLOW ppt of barium chromate with potassium chromate
`K_(2)CrO_(4) +Ba^(2+) to BaCrO_(4) +2K^(+)`
33.

Thecationis …….. And theanionis ………. Thanthe atom.

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SOLUTION :SMALLER BIGGER
34.

The cathode in middle compartment of Castner-Kellner process is

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Graphite
Mercury
Iron
Steel

Answer :C
35.

The catalytic hydrogentaion more easier in case of which alkene?

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SOLUTION :STERIC HINDRANCE
36.

The catalytic hydrogenation is more easier in case of which alkene?

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ANSWER :B
37.

The catalyst used in the preparation of C Cl_2F_2 from C Cl_4 and HF is ……………….. .

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SOLUTION :`SbCl_5`
38.

The catalyst used in the preparation of chlorobenzene from benzene is …………….. .

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SOLUTION :`FeCl_3`
39.

The catalyst used in the manufacture of methanol from water gas is:-

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`V_(2)O_(5)`
`Ni+MO`
`ZnO+Cr_(2)O_(3)`
`Pt+W`

Solution :`[CO+H_(2)]+H_(2)overset(ZnO+Cr_(2)O_(3))toCH_(3)OH`.
40.

The catalyst used in Fisher-Tropsch process is

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Nickel
Cobalt
IRON
`ZNO. CrO_3`

ANSWER :B
41.

The catalyst used in Darzen halogenation of alcohol is …………………… .

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SOLUTION :PYRIDINE
42.

The catalyst used for obtaining carbonyl compound from alkyne during hydration is …..

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HCN
`HgSO_(4)`
`HgCl_(2)`
Pt

Answer :B
43.

The carboxyl functional group (-COOH) is present in

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PICRIC acid
barbituric acid
ascorbic acid
aspirin

Answer :D
44.

The carbonate which decomposes on heating is

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`Na_(2)CO_(3)`
`K_(2)CO_(3)`
`MgCO_(3)`
`Cs_(2)CO_(3)`

Answer :C
45.

The carbonate that will not decompose on heating is

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`Na_(2)CO_(3)`
`CaCO_(3)`
`BaCO_(3)`
`SrCO_(3)`

SOLUTION :ALKALI metal carbonates (i.e., `Na_(2)CO_(3), K_(2)CO_(3)`, etc.) except `Li_(2)CO_(3)` do not DECOMPOSE on heating.
46.

The carbonate having high decomposition temperature among the following is

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`MgCO_(3)`
`BeCO_(3)`
`CaCO_(3)`
`BaCO_(3)`

ANSWER :D
47.

The carbon-hydrogen bonds in benzene are

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`SIGMA SP^2 - s` 
`sigma sp^3 - s`
`Both sigma sp^2 – s & sigma sp^3 – s`
`sigma sp - s` 

ANSWER :A
48.

Convert : Carbon to acetylene

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SOLUTION :`SIGMA, PI`
49.

The carbon-carbon bonds in benzene are

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`SIGMA SP^3 - sp`
`sigma sp^2 - sp^2`
`sigma sp^3 - sp^2`
`sigma sp^2 - sp`

ANSWER :B
50.

The carbon-carbon bond length in benzene is 0.139 xx 10^(x) Pm, the value of x is

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Solution :`C-C = 139 PM = 0.139 XX 10^(3)`