Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The hybridisation of orbitals of N atom in NO_(3)^(-), NO_(2)^(+) and NH_(4)^(+) are respectively ……………………..

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SOLUTION :`SP^(2), sp, sp^(3)`
2.

The hybridisation of carbons of C-C single bond of HC-=C-CH=CH_(2) is

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`sp^(3)-sp^(3)`
`sp-sp^(2)`
`sp^(3)-sp`
`sp^(2)-sp^(3)`

SOLUTION :`H_(2)OVERSET(sp^(2))(C)=overset(sp^(2))(CH)-overset(sp)(C)-=overset(sp)(C)H`
3.

The hybridisation of carbons in benzene is

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`SP & sp^2`
`sp^2 & sp^3`
`sp & sp^3`
`sp^2` only 

ANSWER :D
4.

The hybridisation of carbon in methyl cation is…..

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`SP^(3)`
`sp^(2)`
sp
`DSP^(3)`

Answer :B
5.

The hybridisation of carbon in alkane serise is which type?

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`SP^(2)`
`sp^(3)`
sp
`dsp^(2)`

ANSWER :B
6.

The hybridisation of carbon atoms in C-C single bond H-C equiv CH=CH_(2) is

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`SP^(3)-sp^(3)`
`sp^(2) - sp^(3)`
`sp-sp^(3)`
`sp-sp^(2)`

SOLUTION :`sp-sp^(2)`
7.

The hybridisation of carbon atoms in C-C single bond H-C equiv C-CH_(3) is

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`SP^(3)-SP3`
`sp2-sp3`
`sp-sp3`
`sp-sp3`

ANSWER :D
8.

The hybridisation of C in diamond, graphite and ethyne is in the order

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`SP^(3),sp,sp^(2)`
`sp^(3),sp^(2),sp`
`sp,sp^(2),sp^(3)`
`sp^(2),sp^(3),sp`

ANSWER :B
9.

The hybridisation of boron in ortho boric acid is

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SP
`sp^2`
`sp^3`
`sp^3 d`

ANSWER :B
10.

The hybridisation of boron and oxygen atoms in a molecule of boric acid are respectively

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`sp^3 and sp^2`
`sp^2 and sp^3`
`sp^2 and sp^2`
`sp^3 and sp^3`

ANSWER :B
11.

Calculate the hybridisation of BF_(3)

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SOLUTION :`SP^(2)`
12.

The hybridisation of atomic orbitals of nitrogen inNO_(2)^(+), NO_(3)^(-) and NH_(4)^(+) are

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`sp , sp^(3) andsp^(2)` RESPECTIVELY
`sp,sp^(2) and sp^(3)` respectivly
`sp^(2), sp and sp^(3)`respectively
`sp^(2), sp^(3) and sp^(3)` respectively.

ANSWER :B
13.

The hybridisation of Ag in the complex [Ag(NH_(3))_(2)]^(+) is

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SP
`sp^(2)`
`sp^(3)`
`DSP^(2)`

ANSWER :A
14.

The hybridisation of 1st and 2nd carbon atoms in propadiene respectively

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`SP, sp^(2)`
`sp^(2), sp`
`sp^(2), sp^(2)`
sp, sp

Answer :B
15.

The hybridisation in methane, ethene and Ethyne respectively is……

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`SP^(3), sp^(2) and sp`
`sp^(3), sp, sp^(2)`
`sp^(2), sp^(3) and sp`
`sp, sp^(2), sp^(3)`

ANSWER :A
16.

The hybrididsation of S in SO_(2)is

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`SP`
`sp^(2)`
`sp^(3)`
NONE of these

ANSWER :d
17.

The hybrid state of carbon, to which phenolic group is attached in phenol is

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SP
`sp^(2)`
`sp^(3)`
`DSP^(2)`

SOLUTION :`sp^(2)`
18.

The hybrid state of carbon in acetylene is the same as that of carbon in

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Benzene
Carbondioxide
Graphite
Ethylene

ANSWER :B
19.

The hybrid state of Carbon in Acetylene is same as that of …..

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GRAPHITE
`BeH_(2)`
Benzene
Diamond

Answer :B
20.

The hybrid state of 1 and 3 carbon atoms in CH_(2)=C=CH_(2)

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`SP^(3)`
`sp^(2)`
`sp`
`sp^(3)d`

ANSWER :B
21.

The hybrid orbitals with 33.33% s-character are involved in the bonding of one of the crystalline allotropes of carbon. The allotrope is

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CARBON BLACK 
Graphite 
DIAMOND 
Gas carbon 

Answer :B
22.

The hybrid orbitals have a bond angle ofk 109.5^(@). The percentage of p-character in the hybrid orbital in nearly

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0.25
0.33
0.5
0.75

Answer :D
23.

The hybrid orbitals have bond angle of 109^(@)28. The ratio ot percentage of 's' and 'p' characters is

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`1:1`
`1:2`
`1:3`
`2:3`

ANSWER :C
24.

The human eye is sensitive to colour differences of indicator only when the ratio [In^(-) ] // [Hin] is greater then 10 (or)smaller than 0.1. What should be the minimum change in the pH of solution of observe a complete colour change . (pK_(In) =5).

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`1.2`
` 1.4`
` 1`
`2`

SOLUTION :`pH " RANGE"=[PK_(I_n) -1, pK_(I_n) +1]`
` THEREFORE `change =2
25.

The hottest region of Bunsen flame shown in the figure below is:

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2
1
4
3

Answer :A
26.

The hottest region of Bunsen flame shown in the figure below is :

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REGION 2
region 3
region 4
region 1

Solution :COMBUSTION is COMPLETE in this region
27.

The hottest region of Bunsen flame showin in the figure below

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Region2
Region3
Region4
Region1

Solution :
28.

The horizontal bonds in Fischer projection respresents the bond in the three dimension for

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Both below the plane of paper
Both above the plane of paper
Both on the plane of paper
One above and another below the plane of paper

Solution :In FISCHER projection the horizontal line represents GROUPS coming above the plane and VERTICAL line REPRESENT groups below plane.
29.

The homologue of ethyne is

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`C_(2)H_(4)`
`C_(2)H_(6)`
`C_(3)H_(2)`
`C_(3)H_(4)`

Answer :D
30.

The HNH angle value is higher than HPH, HAsH and HSbH angles. Why ?

Answer»

<P>

Solution :In all the hydrides of group 15 elements, the CENTRAL atom is `sp^(3)`-hybridized. There of the four `sp^(3)`-orbitals FORM three E-H, `sigma-"bonds"` while the fourth CONTAINS the lone pair of electrons as shown below :
Since the lone pair-bond pair repulsions are stronger than the bond pair-bond pair repulsions, therefore, in `NH_(3)` the bond angle decreases from `109^(@)-28` to `107.8^(@)`. As we move from N to P to As to Sb, the electronegativity of the central atom goes on decreasing. As a result, bond pairs of electrons, LIE electrons, lie away and away from the central atom. In other words, force of repulsion between the adjacent bond pairs goes on decreasing and consequently the bond angles keep on decreasing from `NH_(3)"to"SbH_(3)`. In other words, HNH bond angle is maximum `(107.8^(@))` followed by HPH `(93.6^(@))`, followed by HAsH`(91.3^(@))`.
31.

The highly water soluble alkaline earth metal fluoride is

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`CaF_(2)`
`BaF_(2)`
`MgF_(2)`
`BeF_(2)`

ANSWER :4
32.

Thehighly metallicwill havethe configurationof

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`2,8,7 `
2,8,8,5
2,8,81
2,8,2

Solution :NA
33.

The highly metallic element will have the configuration of....

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`2, 8, 7`
`2, 8 , 8, 5`
`2, 8, 8, 1`
`2, 8, 2`

Answer :c
34.

The highest yield of m product is possible by the electrophilic substitution of the following:

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`C_6H_5CH_3`
`C_6H_5CH_2COOC_2H_5`
`C_6H_5CH(COOC_2H_5)_2`
`C_6H_5C(COOC_2H_5)_3`

SOLUTION :`C_6H_5C(COOC_2H_5)_3`
35.

The highest temperature at which vapour pressure of any liquids can be measured is

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CRITICAL temperature
BOYLE's temperature
Boiling POINT of the LIQUID
KRAFT temperature

Answer :C
36.

The highest temperature at which vapour pressure of a liquid can be measured is :

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CRITICAL temperature
inversion temperature
critical SOLU. Temperature
b.pt of liquid

Answer :D
37.

What are the highest oxidation states shown by s-block elements ?

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SOLUTION :GROUP NUMBER
38.

The highest ionization energy is exhibited by………

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Halogens
Noble gases
ALKALINE EARTH METALS
Transition metals

Solution :alkaline earth metals
39.

The highest electron affinity is shown by

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`O^(-)`
`F^(-)`
`Cl_(2)`
`F_(2)`

Solution :The molecuels of `F_(2)` and `Cl_(2)` and the anion F, All have stable NOBLE gas CONFIGURATION. Therefore, their EA is ALMOST ZERO. However,`O^(-)` has one ELECTRON less than the noble gas configuration, therefore, `O^(-)` has the highest EA.
40.

Thehighestelectronaffinityis shownby

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`O^(-)`
`F^(-)`
`C1_(2)`
`F_(2)`

SOLUTION :The MOLECULESOF `F_(2) ,C1_(2)`and theanion `F^(-)` , all havestablenoble gasconfiguration. Thereforetheir`Delta_(EG)H_(1) ` isalmostzero.However , `O^(-)` has oneelectronless thanthe noblegas configurationtherefore`O^(-)`has thehighest`Delta_(eg) H_(1)`.
41.

The highest dipolemoment is of

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`CF_4`
`CH_3OH`
`CO_2`
`CH_3 F`

ANSWER :B
42.

The highest bond energy is for

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`UNDERSET(SP)(C ) -H`
`underset(sp^2)(C ) - H`
`underset(sp^3)(C ) - H`
all have EQUAL energy

Answer :A
43.

The highest boiling point is expected for…..

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iso-octane
n-octane
2, 2, 3, 3-tetramethyl butane
n-butane

Solution :More no. of C -ATOMS in linear structure WITHOUT branches
44.

The higher density of water than that of ice is due to ..............

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DIPOLE-dipole interaction
dipole-induced dipole interaction
HYDROGEN BONDING
all of above

Solution :hydrogen bonding
45.

The high poisonous nature of CO is due to its

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NEUTRAL nature
Complex FORMING ability
Reducing nature
Oxidising nature

Answer :B
46.

The high density of water compared to ice is due to

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HYDROGEN BONDING INTERACTIONS
DIPOLE - dipole interactions
Dipole - INDUCED dipole interactions
Induced dipole - induced dipole interactions

Answer :A
47.

The high density of water as compared to ice isdue to ……

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HYDROGEN BONDING interactions
DIPOLE-dipole interactions
Dipole-INDUCED dipole interactions
Induced dipole induced dipole interactions

Answer :A
48.

The high boiling points of carboxylic acids are due to

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their dimerisation
their trimerisation
their ABILITY to FORM inter-molecular H-bond
Both A and C

Solution :FACTUAL QUESTION
49.

The heterolytic cleavage of C-H bonds results in the formation of __________

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CARBANION
CARBOCATION
Hydri
Hydronium

Solution :N/A
50.

The hetero elements in organic compound are nitrogen, halogen, sulphur and phosphorousd, Nitrogen is estimated by Duma's method (or) Kjeldahl's method. The other hetero elements are estimated using Carius method.The substance used in the estimation of phosphorous is

Answer»

Conc. `H_(2)SO_(4)`
fuming sulphuric ACID and `MgCl_(2)`
Conc. `HNO_(3).NaOH`
fuming nitric acid and magnesia mixture

SOLUTION :Phosphorous is precipitated as `Mg_(2)P_(2)O_(7)` by heating the organic COMPOUND with fuming `HNO_(3)` and magnesia mixture.