Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The hydrolysis constant of CH_3 COONais given by

Answer»

` (K_W)/(K_a) `
` (K_W)/(K_b) `
` (K_W)/(K_a.K_b) `
` K_a.K_b`

SOLUTION :`K_h =(K_W)/( K_a.K_b) ` for SALT of WA+WB
Discussion
2.

The hydrogen was warms up during the Joule -Thomson expansion The temperature at which the Joule Thomson coefficeint becomes negative is called Joule-Thomson inversion temperature .

Answer»

Solution :The temperature at which the Joule-Thomson COEFFICEINT BECOMES ZERO is CALLED Joule-Thomson inversion temperature .
Discussion
3.

The hydrogen like species Li^(2+) is in a spherically symmetric state S_(1) with one radial node. Upon absorbing light, the ion undergoes transition to a state S_(2). The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom The orbital angular momentum quantum number of the state S_(2) is

Answer»

0
1
2
3

Solution :As explaine above, `S_(2)` state is 3p
ORBITAL ANGULAR MOMENTUM quantum NUMBER (l) for 3p = 1
Discussion
4.

The hydrogen like species Li^(2+) is in a spherically symmetric state S_(1) with one radial node. Upon absorbing light, the ion undergoes transition to a state S_(2). The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom Energy of the state S_(1) in units of the hydrogen atom ground state energy is

Answer»

0.75
`1.50`
2.25
`4.50`

Solution :Energy in `S_(1)` state (i.e., 2S ORBITAL) of `Li^(2+)` ION
`= - (13.6 XX 3^(2))/(2^(2)) = - 13.6 xx 2.25 eV`
= 2.25 times of `E_(H)`
Discussion
5.

The hydrogen like species Li^(2+) is in a spherically symmetric state S_(1) with one radial node. Upon absorbinf light the ion undergoes transition to a state S_(2) The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom. Energy of the state S_(1) units of the hydrogen atom ground state energy is

Answer»

0.75
`1.50`
2.25
`4.50`

ANSWER :C
Discussion
6.

The hydrogen-like species Li^"2+" is in a spherically symmetric state S_1 with one radial node. Upon absorbing light the ion undergoes transition to a state S_2. The state S_2 has one radial node and its energyis equal to the ground state energyof the hydrogen atom. The state S_1 is

Answer»

2p
2S
1s
3s

Solution :for lower state `(S_1)`
No. of radial NODE = 1=n-l-1
PUT n=2 and l=0 (as HIGHER state `S_2` has n=3)
So, it would be 2s (for `S_1` state)
Discussion
7.

The hydrogen like species Li^(2+) is in a spherically symmetric state S_(1) with one radial node. Upon absorbing light, the ion undergoes transition to a state S_(2). The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom The state S_(1) is

Answer»

1st
2s
2p
3s, 4d

Solution :The state `S_(1)` must be 2s (as it has one RADIAL node)
and it must have jumped to 3P (which again has one radial node and energy equal to that of GROUND state H-atom as `E_(H (Is)) = - 13.6 eV`
`E_(Li^(2+) (3p)) = (-13.6 Z^(2))/(n^(2)) = - (13.6 xx 3^(2))/(3^(2))`
`= -13.6 eV`
Discussion
8.

The hydrogen like species Li^(2+) is in a spherically symmetric state S_(1) with one radial node. Upon absorbinf light the ion undergoes transition to a state S_(2) The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom. The state S_(1) is

Answer»

1s
2s
2p
3s

Answer :B
Discussion
9.

The hydrogen-like species Li^"2+" is in a spherically symmetric state S_1 with one radial node. Upon absorbing light the ion undergoes transition to a state S_2. The state S_2 has one radial node and its energyis equal to the ground state energyof the hydrogen atom. Energy of the state S_1 in units of the hydrogen atom ground state energy is

Answer»

`4.50`
`1.50`
`2.25`
`0.75`

SOLUTION :ENERGY of STATE `S_1 =-13.6(3^2/2^2)` eV/atom =`9/4` (energy of H-atom in GROUND state)
2.25 (energy of H-atom in ground state )
Discussion
10.

The hydrogen-like species Li^(2+) is in a spherically symmetric state S_(1) with one radial node. Upon absorbing light the ion undergoes transition to a state S_(2). The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom. Q. The state S_(1) is:

Answer»

1s
2S
2p
3s

Solution :2s is SYMMETRICAL havig one RADIAL node.
Discussion
11.

The hydrogen ion concentration of a 10^(-8)MHCl aqueous solution at 298 K (K_(w) = 10^(-14)) is

Answer»

`9.525xx10^(-8)M`
`1.0xx10^(-8) M`
`1.0xx10^(-6) M`
`1.0525 xx 10^(-7)M`

Solution :From acid, `[H^(+)]=10^(-8)M`
From `H_(2)O][H^(+)]=[OH^(-)]=x "mol" L^(-1)` (say)
`([H^(+)] or [OH^(-)]!=10^(-7)` M in presence of acid )
Thus, in the solution, `[H^(+)]=(10^(-8)+x) M and [OH^(-)]=XM`
But `[H^(+)] [OH^(-)]=K_(w)=10^(-14)`
`:. (10^(-8)+x)(x)=10^(-14)`
or `x^(2)+10^(-8)x-10^(-14)=0`
`:. x=(-10^(-8)pm sqrt(10^(-16)+4xx10^(-14)))/(2)`
`=9.51xx10^(-8), "i.e.," [OH^(-)]=9.51xx10^(-8)`.
Hence, `[H^(+)]=(10^(-14))/((9.51xx10^(-8)))=1.05xx10^(-7)M`
ALTERNATIVELY, directly, the only CONCENTRATION which will give pH close to 7 but less than7 is (d).
Discussion
12.

The hydrogen ion concentration of 0.2 M CH_3 COOHwhich is 4% ionised is

Answer»

`0.008 N`
` 0.12 N`
` 0.8N`
` 0.08 N`

SOLUTION :` C =0.2 , alpha = 0. 04 ,[H^(+) ] = C alpha = 8 xx 10 ^(-3)`
Discussion
13.

The hydrogen electron de-exites from its 3rd excited state. W hich are tru e and false statem ents for it. Assign T for true and F for the false.(i) It emits the radiation giving the lines in the Lyman Balmer and Paschen series. (ii) It emits radiation of only UV and visible regions and not infrared region. (iii) It em its the ra d ia tio n of sm allest wavelength giving the line in Lyman series. (iv) It will emit the radiation of the highest frequency giving line in Pfund series

Answer»

TFTF
FTFT
TTFF
FFTT

Answer :A
Discussion
14.

The hydrogen bond is strongest in ...... .

Answer»

O - H----S
O - H---N
F - H----F
O - H---O

Answer :C
Discussion
15.

The hydrogen bond is an electrostatic attractive force between covalently bonded hydrogen atom of one molecule and an electronegative atom like (F,O,N) of other molecule. Hydrogen bond is nearly an electrostatic attractive force and not a normal chemical bond. It is very weak (2-10 kcal/mol) as compared to a colvent bond (strength 50-100 kcal/mol). In intramolecular hydrogen bonding, the two or more than two molecules of the same or different substances are linked to form polymeric aggregate. Intermolecular hydrogen bonding increases the boiling point of the compound and also its solubility in water. Intramolecular hydrogen bonding occurs within two atoms of the same molecule. Intramolecular hydrogen bonding is also called chelation, since it involves ring formation. intramolecular hydrogen bonding decreases the boiling point of the compound and also its solubility in water. underset((A))underset(2,4-"pentadione")(CH_(3)-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-)CH_(3)hArrunderset((B))underset(4-"hydroxypent-3-en-2-one")(CH_(3)-overset(OH)overset(|)(C)=CH-overset(O)overset(||)(C)-CH_(3)) Select the correct statement about above tautomers.

Answer»

FORM (A) is more STABLE due to FORMATION of intramolecular hydrogen bond
Form (B) is more stable due to formation of INTERMOLECULAR hydrogen bond
Form (B) is more stable due to the formation of intramolecular hydrogen bond
Form (A) is more stable due to the formation of intermolecular hydrogen bond

ANSWER :C
Discussion
16.

The hydrogen bond is an electrostatic attractive force between covalently bonded hydrogen atom of one molecule and an electronegative atom like (F,O,N) of other molecule. Hydrogen bond is nearly an electrostatic attractive force and not a normal chemical bond. It is very weak (2-10 kcal/mol) as compared to a colvent bond (strength 50-100 kcal/mol). In intramolecular hydrogen bonding, the two or more than two molecules of the same or different substances are linked to form polymeric aggregate. Intermolecular hydrogen bonding increases the boiling point of the compound and also its solubility in water. Intramolecular hydrogen bonding occurs within two atoms of the same molecule. Intramolecular hydrogen bonding is also called chelation, since it involves ring formation. intramolecular hydrogen bonding decreases the boiling point of the compound and also its solubility in water. Which of the following molecules is dimerised when dissolved in non-polar or organic solvent?

Answer»

`R-COOH`
`OVERSET(COOH)UNDERSET(COOH)("|")`
`R-OH`

ANSWER :A
Discussion
17.

The hydrogen bond is an electrostatic attractive force between covalently bonded hydrogen atom of one molecule and an electronegative atom like (F,O,N) of other molecule. Hydrogen bond is nearly an electrostatic attractive force and not a normal chemical bond. It is very weak (2-10 kcal/mol) as compared to a colvent bond (strength 50-100 kcal/mol). In intramolecular hydrogen bonding, the two or more than two molecules of the same or different substances are linked to form polymeric aggregate. Intermolecular hydrogen bonding increases the boiling point of the compound and also its solubility in water. Intramolecular hydrogen bonding occurs within two atoms of the same molecule. Intramolecular hydrogen bonding is also called chelation, since it involves ring formation. intramolecular hydrogen bonding decreases the boiling point of the compound and also its solubility in water. Select the compound which involves intramolecular hydrogen bonding.

Answer»

`HCOOH`
`CH_(3)COOH`
`C_(6)H_(5)COOH`
`CH_(3)COOH`

SOLUTION :Per ACIDS FORM intramolecular hydrogen bond.
Discussion
18.

The hydrogen bond is shortest in

Answer»

`S-H----S`
`N-H----O`
`S-H------O`
`F-H----F`

Solution :o-Nitrophenol is less SOLUBLE in WATER than p- and
m-nitrphenols because o-nitrphenol SHOWS
intramolecular HYDROGEN BONDING .
Discussion
19.

The hydrogen bond is an electrostatic attractive force between covalently bonded hydrogen atom of one molecule and an electronegative atom like (F,O,N) of other molecule. Hydrogen bond is nearly an electrostatic attractive force and not a normal chemical bond. It is very weak (2-10 kcal/mol) as compared to a colvent bond (strength 50-100 kcal/mol). In intramolecular hydrogen bonding, the two or more than two molecules of the same or different substances are linked to form polymeric aggregate. Intermolecular hydrogen bonding increases the boiling point of the compound and also its solubility in water. Intramolecular hydrogen bonding occurs within two atoms of the same molecule. Intramolecular hydrogen bonding is also called chelation, since it involves ring formation. intramolecular hydrogen bonding decreases the boiling point of the compound and also its solubility in water. Which of the following compounds is (are) stabilised by intramolecular hydrogen bonding?

Answer»

`Cl-OVERSET(CI)overset(|)underset(CI)underset(|)(C)-overset(" "OH)overset(|)underset(" "OH)underset(|)(C)-H`

`CH_(3)-overset(OH)overset(|)(C)=CH-overset(O)overset(||)(C)-OC_(2)H_(5)`
`{:(CH_(2)OH),(|),(CH_(2)OH):}`

Answer :A::B::C
Discussion
20.

The hydrocarbon which does not decolourise alkaline KMnO_4 solution and also does not give any precipitate with ammoniacal silver nitrate is

Answer»

BENZENE
acetylene
propyne
butyne-1

SOLUTION :Benzene neither DECOLOURISES alkaline `KMnO_4` solution nor give PPT. with AMMONIACAL `AgNO_3` solution.
Discussion
21.

The hydrocarbon which can react with sodium in liquid ammonia is :1.CH_3CH_2CH_2C -= "CCH"_2CH_2CH_32. CH_3CH_2C -=CH3.CH_3CH = CHCH_34.CH_3CH_2C -= "CCH"_2CH_3

Answer»

`CH_3CH_2CH_2C -= "CCH"_2CH_2CH_3`
`CH_3CH_2C -=CH`
`CH_3CH = CHCH_3`
`CH_3CH_2C -= "CCH"_2CH_3`

ANSWER :B
Discussion
22.

The hydrocarbon which can react with sodium in liquid ammonia is

Answer»

`CH_(3)CH_(2)C-=C CH_(2)CH_(3)`
`CH_(3)CH_(2)CH_(2)C-=C CH_(2)CH_(2)CH_(3)`
`CH_(3)CH_(2)C-=CH`
`CH_(3)CH=CHCH_(3)`

Solution :All terminal ALKYNES acidic react with sodium in liquid AMMONIA to YIELD ionic compounds i.e., sodium alkylides.
Discussion
23.

The hydrocarbon which can react with sodium in liquid ammonia is :

Answer»

`CH_(3)CH_(2)C-=CH`
`CH_(3)CH=CHCH_(3)`
`CH_(3)CH_(2)C-=C CH_(2)CH_(3)`
`CH_(3)CH_(2)CH_(2)C-=C CH_(2)CH_(2)CH_(3)`

ANSWER :A
Discussion
24.

The hydrocarbon that cannot be prepared effectively by Wurtz reaction is

Answer»




ANSWER :B
Discussion
25.

The hydrides of the first elements in groups 15-17, namely NH_(3), H_(2)O and HF respectively show abnormally high values for melting and boiling points. This is due to

Answer»

SMALL SIZE of N,O,F
the ability to form extensive intermolecular H-bonding
the ability to form extensive intramolecular
effective van DER Waals interaction

Answer :B
Discussion
26.

The hydries of first elements in grounp 15 to 17 amely NH_(3) H_(2)Oand HF rectivelyshow abnormally high values for meltin and bolting points this is due to

Answer»

Small size of N, O and F
The ability to FORM EXTENSIVE intermolecular H - BONDING
The ability to form extensive intramolecular H - bonding
Effective van der Waals' interaction

Solution :Abnormalmelting POINTS due to their ability of forming intermolecular H - bonding
Discussion
27.

The hydride ion H^(-) is a stronger base than hydroxide ion. Which of the following reactions will occur if sodium hydride (NaH) is dissolved in water ?

Answer»

`H^(-) (AQ) + H_(2)O(L) to H_(3)O^(+)(aq)`
`H^(-)(aq) + H_(2)O(l) to OH^(-) (aq) + H_(2)(g)`
`H^(-) + H_(2)O to ` No reaction
NONE of these

Answer :B
Discussion
28.

The hydride ion H^-is a stronger base than hydroxide ion. Which of the following reactions will occur if sodium hydride (NaH) is dissolved in water ?

Answer»

`H_((aq))^(-) + H_2O_((L)) to H_3O_((aq))^(+)`
`H_((aq))^(-) + H_2O_((l)) to OH_((aq))^(-) + H_(2(G))`
`H+H_2O to ` No reaction
None of these

Answer :B
Discussion
29.

The hydride H^(-) stronger base than hydroxide ionWhich of the following reaction would occur if NaHdissolved in water

Answer»

`H_(aq)^(-)+H_(2)O_((l)) to H_(3)O_(aq)^(-)`
`H_((aq))+H_(2)O_((l)) overset(O) to OH_((aq))+H_(2)`
`H^(-)+H_(2)O to` No reaction
NONE of the above

Solution :`H^(-)+H_(2)O to O^(-)H+H_(2)`
Discussion
30.

The hydration enthalpies of alkali metal ions decreases in ________ order.

Answer»

`Li^+gtNa^+gtK^+gtRb^+gtCs^+`
`Cs^+gtRb^+gtK^+gtNa^+gtLi`
`Li^+gtRb^+gtK^+gtNa^+gtCs^+`
`Rb^+gtCs^+gtK^+gtNa^+gtLi`

ANSWER :A
Discussion
31.

The hydration energy of Mg^(2+)is greater than that of.....

Answer»

`Al^(3+)`
`Na^(+)`
`Be^(2+)`
`Mg^(3+)`

ANSWER :B
Discussion
32.

The hydration energy of Mg^(2+) is greater than that of

Answer»

`Al^(3+)`
`Na^(+)`
`Be^(2+)`
`MG^(3+)`

Solution :`Na^(+)` has +1 unit charge . `Mg^(2+)` and `Be^(2+)` have +2 unit charge while `Mg^(2+)` and `Al^(3+)` have + 3 unit charge , therefore , hydration energy of `Al^(3+)` and `Mg^(3+)` are expected to be higher than those of `Mg^(2+)`and `Be^(2+)` , which in turn , are expected to be higher than that of `Na^(+)` . Further , the hydration energy of `Be^(2+)` is higher than that of `Mg^(2+)` due to its SMALLER SIZE . In other words , hydration energy of `Mg^(2+)` is expected to be higher than that of `Na^(+)`.
Discussion
33.

The hydration energy of Mg^(2+) is :

Answer»

more than that of `MG^(3+)` ion
more than that of `Mg^(3+)` ion
more than that of `AL^(3+)` ion
more than that of `Be^(2+)` ion

Solution :N//A
Discussion
34.

The hydrated salt Na_(2)CO_(3)x H_(2)O undergoes 63 % loss in mass on heating and becomes anhydrous. What is the value of x ?

Answer»


Solution :MOLECULAR MASS of `Na_(2)CO_(2)X.H_(2)O=106+18x`
Loss in mass due to dehydration = 63 %
`(18x xx 100)/(106+18x)=63or(18x)/((106+18x))=0.63`
`18x=0.63(100+18x)=66.78+11.34x`
`(18 x - 11.34 x)=6.66 x = 66.78`
`x=(66.78)/(6.66)~~10`.
Discussion
35.

The hybridizations of atomic orbitals of nitrogen in NO_(2)^(+), NO_(3)^(-) and NH_(4)^(+)respectively are

Answer»

`SP , sp^(2), sp^(3)`
`sp^(2), sp, sp^(3)`
`sp, sp^(3) , sp^(2)`
`sp^(2) , sp^(3), sp`

Solution :`sp, sp^(2), sp^(3)`
`{:(NO_(2)^(+)= sp , "LINEAR"),(NO_(3)^(+) = sp^(2)," Trigonal PLANAR"),(NH^(+) = sp^(3) , "Tetrahedral" ):}`
Discussion
36.

The hybridization that is not present in 1,2-Butadiene is

Answer»

`SP^(3)`
`sp^(2)`
`sp^(3)d`
`sp`

SOLUTION :Hybridizaion
Discussion
37.

The hybridization of oxygen atom in H_(2)O_(2) is

Answer»

`sp^(3) d `
`sp `
`sp^(2)`
`sp^(3)`

SOLUTION :
Each O-atom has two bond pairs and two lone pairs. HYBRIDISATION of each O-atom is `sp^(3)`.
Discussion
38.

The hybridization of compound 'C' is:

Answer»

`SP^(3)`
`sp^(3)d`
`d^(2)sp^(3)`
`d^(3)s`

ANSWER :D
Discussion
39.

The hybridization of central carbon atom in trimethyl free radical is

Answer»

SP
`sp^(2)`
`sp^(3)`
MAY be `sp^(2)` or sp

Answer :B
Discussion
40.

The hybridizationof C in diamond, graphite and ethyneis in the order

Answer»

`SP^(3), sp , sp^(2)`
`sp^(3), sp^(2)`, sp
sp, `sp^(2), sp^(3)`
`sp^(2), sp^(3), sp`

Solution :`sp^(3)` (DIAMOND), `sp^(2)` (graphite), sp( ethyne).
Discussion
41.

The hybridisation involved in acetylene is

Answer»

`SP`
`sp^(2)`
`sp^(3)`
`DSP^(2)`

ANSWER :D
Discussion
42.

The hybridization involved in acetylene is

Answer»

`SP`
`sp^3`
`sp^3`
`dsp^2`

ANSWER :A
Discussion
43.

The hybridisations of atomic orbitals of nitrogen in NO_(2)^(+),NO_(3)^(-) and NH_(4)^(+) respectively are-

Answer»

`sp^(2),sp^(3) and sp`
`sp,sp^(2) and sp^(3)`
`sp^(2), sp and sp^(3)`
`sp,sp^(3) and sp^(2)`

SOLUTION :`NO_(2)^(o+)(sp)`- linear, `NO_(3)^(-)(sp^(2))to`trigonal PLANAR `NO_(4)^(o+)(sp^(3))-`tetrahedral.
Discussion
44.

The hybridisation type of carbon respectively in methane, ethane, ethene and ethyne is ……,…., …., and ……

Answer»

SOLUTION :`SP^(3), sp^(3), sp^(2) and sp`
Discussion
45.

The hybridisation stateof a carbocation is ………

Answer»

SOLUTION :`SP^(2)`
Discussion
46.

The hybridisation of silicon in SiF_(6)^(2-) is

Answer»

`SP^(3)d^(2)`
`sp^(3)d`
`sp^(3)`
`sp^(3)d^(3)`

ANSWER :A
Discussion
47.

The hybridisation of silicon in SiO_(4)^(4-) is

Answer»

`SP^(2)`
`sp`
`sp^(3)`
`sp^(3)d`

ANSWER :C
Discussion
48.

The hybridisation of oxygen atom is H,O and H, 0, are respectively..........

Answer»

SP and `sp^3 `
sp and sp
sp and sp.
`sp^3and sp^3 `

SOLUTION :`sp^3and sp^3 `
Discussion
49.

The hybridisation of oxygen in OF_(2) molecule is

Answer»

Sodium CHLORIDE
`sp^(2)`
`sp^(3)`
`DSP^(2)`

ANSWER :C
Discussion
50.

The hybridisation of oxygen atom is H_2O and H_2O_2 are, respectively

Answer»

SP and `sp^3
`sp and sp
sp and `sp^2`
`sp^3` and `sp^3`

ANSWER :D
Discussion