Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The number of unpaired electrons in Fe^3+ (Z=26) are

Answer»

0
1
2
3

Solution :Number of -OH GROUP in `H_(3)PO_(3)` is 2 and HENCE it is diabasic in nature.
Discussion
2.

The number of 3 centered, 2 electron bonds in doborane is

Answer»

2
4
3
6

Solution :The number of 3 CENTERED , 2 ELECTRON bonds in DIBORANE is 2
Discussion
3.

The number of 2p electrons having spin quantum number s = -1//2 are

Answer»

6
0
2
3

Answer :D
Discussion
4.

The number of three centred, 2 electron bonds in diborane is

Answer»

2
4
3
6

Solution :ALUMS have SIMILAR CRYSTAL STRUCTURE
Discussion
5.

The number of 2-centre-2-electron and 3-centre-2-electron bonds in B_2H_6, respectively, are.....

Answer»

2 and 4
2 and 2
2 and 1
4 and 2

SOLUTION :
Discussion
6.

The number if electron deficient bonds in Al_(2)Cl_(6) is :

Answer»


ANSWER :0
Discussion
7.

The number and types of bonds between two carbon atoms in calcium carbide are

Answer»

one SIGMA , one pi
one sigma , two pi
two sigma, one pi

Solution :`CaC_(2)`is `Ca^(2+)underset(C^(-))OVERSET(C^(-))|||` . Thus , ITHAS one sigma and two po bonds.
Discussion
8.

The number and type of bonds between two carbon atoms in CaC_(2) are

Answer»

one `SIGMA` and one `PI` BOND
one `sigma` and two `sigma` BONDS
one `sigma` bond
one `pi` bond

Solution : one `sigma` and two `pi` bonds.
Discussion
9.

The num ber of protons in nucleus of an elem ent having maximum unpaired electrons in 2p sub-shell are .............

Answer»

7
5
14
6

Solution :N is the ELEM ENT, having m axim um 3 UNPAIRED electron in its 2p sub-shell
N (He) `2p^(3)` OR [He]

N(Z=7) its has protons =7
ELECTRONS =7
Discussion
10.

The nucleus of tritium consists of

Answer»

1 PROTON +1 neutron
1 proton +3 neutron
1 proton + ZERO neutron
1 proton +2 neutron

Answer :D
Discussion
11.

the nucleus of an element contain9protons itsvalencywould be

Answer»

`-1`
3
2
5

Solution :Sinceitsnucleuscontain9protonso itsatomicnumber is 9AND itselectronicconfigurationis 27. so itrequireone moreelectronto completeitsocter. Henceitsvalencyis -1
Discussion
12.

The nucleus of an atom is located at x = y = z = 0. If the probability of finding an s orbital electron in a tiny volume around x=a, y=z=0 is 1. xx 10^(-5), choose the correct statements(s) regarding the probability of electron

Answer»

The probability of finding the electron in the same-sized VOLUME AROUND x = Z=0, y=a is the same i.e., `1 XX 10^(-5)`
The probability of finding the electron in the same -sized vlume around x=y=0, z=a is zero
The probability at the second site if the electron were in a `P_(z)` obital is zero.
The probability at the second site if the electron were in a `P_(z)` orbital is the same i.e., `1.0 xx 10^(-5)`

Answer :A::C
Discussion
13.

The nucleus of an atom contains

Answer»

ELECTRONS and protons
Protons and neutrons
Electrons and BETA particles
Protons and ALPHA particles

Answer :B
Discussion
14.

The nucleus of an atom can be assumed to be spherical. The radius of the nucleus of mass number A is given by 1.25xx10^(-13) xx A^(1//3) cm Radius of atom is one Å. If the mass number is 64, Then the fraction of the atomic volume that is occupied by the nucleus is

Answer»

`1.0xx10^(-3)`
`5.0xx10^(-5)`
`2.5xx10^(-2)`
`1.25xx10^(-13)`

Solution :Radius of nucleus = `1.25xx10^(-13) XXA^(1//3) cm`
`=1.25xx10^(-13) xx 64^(1//3) =5xx10^(-13)` cm
Radius of ATOM =1Å=`10^(-8)` cm
`"Volume of nucleus"/"Volume of atom"=((4//3)pi(5xx10^(-13))^3)/((4//3)pi(10^(-8))^3)`
`=1.25xx10^(-13)`
Discussion
15.

The nucles of an atom contains:

Answer»

ELECTRONS and PROTONS
NEUTRONS and protons
Electrons, protons and neutrons
Neutrons and electrons

ANSWER :B
Discussion
16.

The nucleophile is not

Answer»

Lewis BASE
Lewis ACID
`H_(2)O`
Carbanion

Solution :N/A
Discussion
17.

The nuclear radius is of the order of 10^(-13) cm while atomic radius is of the order 10^(-8) cm. Assuming the nucleus and the atom to be spherical, what fraction of the atomic volume occupied by the nucleus ?

Answer»

Solution :The volume of a sphere `= 4pi r^(3)//3` where r is the RADIUS of the sphere
`:.` Volume of the NUCLEUS `= 4pi r^(3)//3 = 4pi (10^(-13))^(3)//3 cm^(3)`
SIMILARLY, Volume of the atom `= 4pi r^(3)//3 = 4pi (10^(-8))^(3)//3 cm^(3)`
`:.` Fraction of the volume of atom occupied by the nucleus `= (4pi (10^(-13))^(3)//3 cm^(3))/(4pi (10^(-8))^(3)//3) cm^(3) = 10^(-15)`
Discussion
18.

The nuclei of tworadioactive isotopes of same substanceA^(236) and B^(234) are present in the ratio of 4:1 in an ore obtained form some other planet. Their half-lives are 30 and60 minutes respectibvely. Both isotopes are alpha emitters and acitity of isotopeA^(236) si 1 rutherford(10^(6) dps). Calcualte: (a) After how much time their activities will becomes identical? (b) The time required tobring the ratio of their atoms to 1:1

Answer»


ANSWER :(a) `180` MIN., (B) `120` min
Discussion
19.

The normality of the mixture of HCl and H_(2)SO_(4) solution is N//5 . 0.287 g of AgCl is obtained when 20 mL of this solution is treated with excess of AgNO_(3). Calculate the percentage of both the acids in the mixture.

Answer»


SOLUTION :N//A
Discussion
20.

The nuclear cross section is measured in barn'. It is equal to

Answer»

`10^(-20)m^(2)`
`10^(-30)m^(2)`
`10^(-28)m^(2)`
`10^(-14)m^(2)`

Answer :C
Discussion
21.

The normality of aqueous solution of 1 M H_(3)PO_(4)is ...........

Answer»

1.5 N
3 N
0.5 N
2 N

Solution :Normality `= "Molarity" xx "Basicity"`
`= 1 xx 3 = 3N`
Discussion
22.

The normality of a 26 % "mass"//"volume" solution of ammonia (density 0.885 g//mL) is approximately :

Answer»

1.5
4
0.4
15.3

Solution :N//A
Discussion
23.

The normality of 2.24 vol H_2O_2 is

Answer»

1.786
4
0.4
0.285

Answer :C
Discussion
24.

The normality of 10 volume H_(2)O_(2) is :

Answer»

0.176
0.88
1.78
3.52

Solution :N//A
Discussion
25.

The normality of 10 % ("mass"//"volume") acetic acid is :

Answer»

1 N
10 N
1.7 N
0.83 N

Solution :N//A
Discussion
26.

The normality of 0.3 M phosphorous acid (H_(3) PO_(3)) is

Answer»

0.1
0.9
0.3
0.6

Solution :Phosphorus ACIDIS a DIBASIC acid.Hence,its EQ. MASS `=("Mol. Mass")/2`
Discussion
27.

The normality of 0.3 M phosphorous acid (H_(3)PO_(3)) is :

Answer»

0.1
0.9
0.3
0.6

Solution :N//A
Discussion
28.

The normality of 0.3 H_3PO_3 is

Answer»

0.1
0.9
0.3
0.6

Solution :`HO-UNDERSET(H)underset(|)OVERSET(OH)overset(|)P=O`
n = 2 , `N = M xx n = 0.3 xx 2 = 0.6`
Discussion
29.

The normalitiy of 10 % ( weight / volume )( acetic and is

Answer»

1N
10 N
1.7 N
0.83 N

ANSWER :C
Discussion
30.

The normal boiling point of the liquid is approximately

Answer»

1.55 TIMES of its CRITICAL temperture
TWO -THIRD of its critical TEMPERATURE
half of its critical temperature
one third of its critical temperature

Solution :Two third of critical temperature
Discussion
31.

The normal boiling point of a liquid 'A' is 350K. DeltaH_("vap") at normal boiling point is 35 kJ/mole. Pick out the correct statement(s). (Assume DeltaH_("vap") to be independent of pressure)

Answer»

`Delta S_("VAPORISATION") gt 100 J//K` mole at 350K and 0.5atm
`Delta S_("vaporisation") lt 100 J//K` mole at 350K and 0.5 atm
`Delta S_("vaporisation") lt 100 J//K` mole at 350K and 2 atm
`Delta S_("vaporisation") = 100 J//K` mole at 350K and 2 atm

SOLUTION :`Delta S = (Delta H)/(BP) = (35 xx 1000)/(350) = 100J//K` mole at 1 atm if `P DARR Delta S uarr`
Discussion
32.

The no.of intermediate formed in the following conversion is

Answer»


SOLUTION :
Discussion
33.

The non-viable particulate is among the following is

Answer»

DUST
BACTERIA
MOULDS
Fungi

Solution :Dust
Discussion
34.

The non metal which occur only in the oxidised form in nature is

Answer»

carbon
nitrogen
chlorine
None of these.

Answer :A
Discussion
35.

The non planar molecule among the following is

Answer»

`B_2 H_6`
`C_2 H_4`
`C_6 H_6`
`BCl_3`

ANSWER :A
Discussion
36.

The non metal which is generally occur in the oxidised form in nature is

Answer»

C
N
S
None of these.

Answer :D
Discussion
37.

The non existing compound is

Answer»

`KO`
`KO_(2)`
`K_(2)O`
`K_(2)O_(2)`

ANSWER :A
Discussion
38.

The non-existence of PbI_(4) is due to

Answer»

HIGHLY oxidising NATURE of `Pb^(4+)`
highly reducing nature of `Pb^(4+)`
sufficientlylarge covalent character
highly reducing nature of `I_(4)^(-)` IONS

Solution :Highly oxidising natureof `Pb^(+4)` , highly reducing nature of `I^(-)` ions
Discussion
39.

The non aromatic compound among the following is -

Answer»




ANSWER :D
Discussion
40.

The non aromatic compound among the following is :

Answer»




ANSWER :D
Discussion
41.

The non-aromatic compound among the following

Answer»




Solution :CYCLOPENTADIENE , i.e., option (a) CONTAINS only 4 `pi`-electrons and is also NON-planar , therefore, it is non aromatic.
Discussion
42.

The nodal plane in the pi-bond of ethene is located in

Answer»

the MOLECULAR plane
a plane parallel to the molecular plane
a plane PERPENDICULAR to the molecular plane
which bisects the carbon-carbon `sigma`-BOND at
right angle.
a plane perpendicular to the molecular plane
which contains the carbon-carbon `sigma `-bond

Solution : The molecular plane does not have any have `pi` electron DENSITY.
Discussion
43.

The non-aromatic compound among the following is

Answer»




SOLUTION :CYCLO pentadiene contains only ` 4 pi ` -electrons and is ALSO NON planer therefore it is non aromatic.
Discussion
44.

The nodal plane in the -bond of ethene is located in

Answer»

The molecular PLANE
A plane PARALLEL to the molecular plane
A plane perpendicular to the molecular plane which BISECTS the carbon-carbon SIGMA bond at right angle
A plane perpendicular to the molecular plane which contains the carbon-carbon o-bond

Answer :A
Discussion
45.

The noble gases are stable due to their __________ outer shell electronic configuration .

Answer»

pantly FILLED
partialy filled
COMPLETELY filled
zero

ANSWER :C
Discussion
46.

The -NO_(2) group in nitrobenzene: (i) In resonance act as a electron donating and in inductive effect it act as an electron attracting. (ii) It acts as an electron donating in resonance as well as inductive effect. (iii) It acts as an electron attractive in resonance as well as inductive effect. (iv) It acts as an electron attracting in resonance and electron donating in inductive effect

Answer»

SOLUTION :(i-F),(ii-F), (iii-T), (iv-F)
Discussion
47.

The no. of possible isomers of C_(4)H_(10)O is….

Answer»

7
6
4
3

Solution :(i) `underset("methoxy PROPANE")(CH_(3)-O-CH_(2)-CH_(2)-CH_(3))`
(ii) `underset("ethoxy ethane")(CH_(3)-CH_(2)-O-CH_(2)-CH_(3))`
(iii) `underset("methyl isopropyl ether")((CH_(3))_(2) -CH-O-CH_(3))`
(IV) `underset("1-butanol")(CH_(3)-CH_(2)-CH_(2)-CH_(2)-OH)`
(v) `underset("2-butanol")(CH_(3)-CH_(2)- underset(underset(OH)(|))(CH)-CH_(3))`
(VI) `underset("2-methyl-propanol")(CH_(3)-underset(underset(CH_(3))(|))(CH)-CH_(2)-OH)`
(VII) `underset("2-methyl 2-propaol")(CH_(3)-underset(underset(CH_(3))(|))overset(overset(CH_(3))(|))(C )-CH_(3))`
Discussion
48.

The no of mono substituted derivatives of pyridine is ________

Answer»


SOLUTION :
Discussion
49.

The no of moles of CO_2, formed during the oxidation of CH_2 = CH - CH = CH_2 with acidified KMnO_4 is

Answer»


SOLUTION :TWO MOLES of `CO_2` are FORMED
Discussion
50.

The no. of isomers for the compound with molecular formula C_(2)BrClFl is…..

Answer»

3
4
5
6

Solution :
Discussion