Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What is the empirical formula of the following? (i) Fructose (C_(6)H_(12)O_(6) ) found in honey (ii) Caffeine (C_(8)H_(10)N_(4)O_(2)) a substance found in tea and coffee.

Answer»

Solution :FRUCTOSE (`C_(6)H_(12)O_(6)`)
Empirical FORMULA is the simplest formula. So it is DIVIDED by 6 and so empirical formula is `CH_(2)O`.
Caffeine (`C_(8)H_(10)N_(4)O_(2)`)
Simplified formula = `("molecular formula")/2`
Empirical formula = `C_(4)H_(5)N_(2)O`.
Discussion
2.

What are the various methods you suggest to protect our environment from pollution?

Answer»

Solution :Methods to control environmental pollution
(i) Waste MANAGEMENT: Environmental pollution can be controlled by proper disposal of wastes.
(ii) Recycling: A large amount of disposed waste materials can be reused by recycling the waste, THUS it reduces the landfill.
(iii) Bysubstitution of less toxic SOLVENTS for highly toxic ones are used in industrial PROCESSES.
(IV) By growing more trees.
(v) By using fuels with lower sulphur content.
(vi) By control measures in vehicle emissions which are adequate.
Discussion
3.

Which is the best description of the behavior of bromine in the reaction given below ? H_(2)O+Br_(2)toHOBr+HBr

Answer»

PROTON ACCEPTOR only
Both OXIDIZED and reduced
Oxidized only
Reduced only

Answer :B
Discussion
4.

Which one of the following statements is false ?

Answer»

Raolt's law states that vapour pressure of a component over a SOLUTION is proportional to mole fraction.
The OSMOTIC pressure `(pi)` of a solution is given by the reation `pi = MRT` where M is molarity of the solution
The correct order of osmotic pressure of 0.01 M aqueous solution of each component is :
`BaCl_(2)gtKClgtCH_(3)COOHgt "SUCROSE"`
Two sucrose solutions of same molality prepared in different solvents will have the same FREEZING point depression.

Answer :D
Discussion
5.

Which of the following is an acidic salt that can form an alkaline solution ?

Answer»

`NaHSO_4`
` NA HCO_3`
` Na_2HPO_3`
` NaCN`

Solution :` NaHSO_4 and NaHCO_3`are acidic SALTS pH of ` NaHSO_4 lt 7 pH"of"NaHCO_3gt 7`DUE to anionhydrolysis
Discussion
6.

Which mixture is used as Lindlar's catalyst ?

Answer»

Pt+Charcoal
Pd+Halogen
Pt+Halogen
Pd+Charcoal

Answer :D
Discussion
7.

What happens when alcoholic KOH is treated with (i) Ethylidene dichloride (ii) Ethylene dichloride?

Answer»

Solution :(i) Gem-DIHALIDES and vicinal dihalides both on treatment with alcoholic KOH GIVE ALKYNES.
(II) `H-underset(H)underset(|)overset(H)overset(|)C -underset(H)underset(|)overset(H)overset(|) - H + 2KOH underset(Delta)overset("ETHANOL")to underset("Acetylene")(HC-=CH) + 2KCl + H_2O`
(iii) `H - underset(H)underset(|)overset(Cl)overset(|)C - underset(Cl)underset(|)overset(H)overset(|)C - H + 2KOH underset(Delta)overset("Ethanol")to underset("Acetylene")(HC-=CH) + 2KCl + H_2O`
Discussion
8.

What transition in the hydrogen spectrum would have thesamewavelength as the Balmer transition n=4 to n=2 of He^(+) spectrum ?

Answer»

`n=4` to n=1
n=3 to n=2
n=3 to n=1
n=2 to n=1

Answer :D
Discussion
9.

What is the conclusion of alpha-ray scattering experiment?

Answer»

Solution :The conclusion of `alpha` -ray scattering experiment is atoms inside gold are closely packed, `alpha` particles must have PASSED through the atoms.
(a) Since most of the `alpha` - particles SIMPLY passed through, most part of the atom should be empty space.
(b) Since a few of the`alpha` particles got DEFLECTED by small angles, they must have COME across a positive part which would repel them.
(c) Since only one out of 20000 `alpha` particles retracted then path, the size of the positive part in the atom should be extremely small, only those particles which MADE a head on collision with the nucleus would retrace their path.
Discussion
10.

Which of the following are analgesics ?

Answer»

Diclofen
Phenacetin
Naproxen
Furacin

Answer :A::C
Discussion
11.

Which of the following methods is used for obtaining Aluminium metal ?

Answer»

ELECTROLYSIS of food `Al_(2)O_3` and cryolite
By heating alumina with CARBON
By heating alumina in Muffle furnace
By a PROCESS CALLED pyrometallurgy

Solution :N//A
Discussion
12.

What is the percentage of H in CH_(3)COOH ?

Answer»

40
6.66
10
15

Solution :Molecular MASS of `CH_(3)COOH=60 " G mole"^(-1)`
`% H = (4xx100)/(60) = 6.66`
Discussion
13.

Which one of the following is used to remove silicon dioxide in the Serpeck's process of purification of bauxite ?

Answer»

CAO
`Na_(2)CO_(3)`
Coke
Nickel

Solution :`SiO_(2)+2C rarr Si UARR + 2CO uarr`

In Serpeck's process of purification of bauxite `SiO_(2)` is removed by carbon as volatile PRODUCTS.
Discussion
14.

The volume of 40 vol. H_(2)O_(2) solution required to prepare 2L. of O_(2) at STP is

Answer»

40 m.L
50 m.L.
25 m.L.
500 m.L.

Answer :B
Discussion
15.

The types of hybrid orbitals of nitrogen in NO_(2)^(+) , NO_(3)^(-) and NH_(4)^(+)respectively are expected to be

Answer»

`sp, sp^(3) and sp^(2)`
`sp, sp^(2) and sp^(3)`
`sp^(2), sp and sp^(3)`
`sp^(2), sp^(3) and sp`

Solution :`sp, sp^(2) and sp^(3)`
The type of HYBRID orbitals of nitrogen can be calculated by using VSEPR THEORY counting bp and as Ip in
`NO_(2)^(+) `= 2bp + 0lp= linear = sp hybridised
`NO_(2)^(-) ` = 3bp + 0lp `rArr` linear `sp^(2)` hybridised
`NH_(4)^(+)` = 4dp + 0lp `rArr` linear `hsp^(3)` hybridised
Discussion
16.

When Lithium vapour is taken in a discharge tube and the potential difference between the electrodes is 5.4 ev, there is a sudden increase in the flow of current. The ionisation energy of Lithium is

Answer»

54 EV
`520 KJ mol^(-1)`
`54 kJ "ATOM"^(-1)`
`5.4 ev "atom"^(-1)`

Answer :D
Discussion
17.

Which one of the following is the strongest base in aqueous solution ?

Answer»

Dimethylamine
Methylamine
Trimethylamine
Aniline

Answer :A
Discussion
18.

Which element of every group shows anomalous properties?

Answer»

First
Last
Second
Third

Answer :A
Discussion
19.

The salt of an alkali metal gives yellow colour in the flame test . Also its aqueous solution gives an insolublewhite precipitate with barium chloride in acid medium . The salt is

Answer»

NACL
`K_(2)SO_(4)`
`Na_(2)SO_(4)`
`Li_(2)SO_(4)`

Solution :SINCE the alkali METAL salt gives a yellow colour in the flame , it must be sodium salt . Further , since the salt gives an insoluble white ppt. with `BaCl_(2)` in acidic MEDIUM , it must be sodium sulphate , `Na_(2)SO_(4)`.
`Na_(2)SO_(4) + BaCl_(2) to underset("White ppt.")(BaSO_(4)) darr + 2 NaCl`
Discussion
20.

Out of O_(2) and O_(3), which is paramagnetic ?

Answer»

SOLUTION :`O_(2)^(-)` is PARAMAGNETIC and `O^(2)^(2-)` is DIAMAGNETIC
Discussion
21.

Which alkene on ozonolysis gives CH_(3)CH_(2)CHO and CH_(3)COCH_(3)?

Answer»


`CH_(3)CH_(2)CH=CHCH_(2)CH_(3)`
`CH_(3)CH_(2)CH=CHCH_(3)`
`CH_(3)UNDERSET(CH_(3))underset(|)C=CHCH_(3)`

SOLUTION :
Discussion
22.

What is screening effect ?

Answer»

Solution :The repulsive FORCE between INNER shell electrons and the valence electrons leads to a decreases in theelectrostatic attractive forces acting on the valence electrons ACTS as a shield between the nucleus and the valence electrons
Pauling 's scale :
(i) Electronegativity is the relative tendency of an element present in a covalently bonded molecule to attract the shared pair of electrons towards itself.
(ii)Pauling assigned arbitrary value of electro negativities for hydrogen and fluorine as 2.2 and 4 respectively .
(iii)Based on this the electro negativity values for other ELEMENTS can be calculated using the following expression .
`(X_(A)-X_(B))=0.182sqrt(E_(AB)-(E_(A A)xxE_(BB))^(1//2))`
Where`E_(AB),E_(aa)andE_(bb)`are the bond dissociation energies of `AB,A_(2)andB_(2)` molecule respectively`X_(A)andX_(B)`are elctro negativity values of A and B.
Discussion
23.

Which of the following is an electrophilic substitution reaction?

Answer»




Solution :(A). Is electrophilic substitution reaction i.e., sulphonation because `-SO_(3)` in an electrophile.
(C). Is electrophilic substitution reaction because `overset(o+)(N)O_(2)` is an electrophile.
(D). Is friedel-crafts ALKYLATION i.e., electrophilic substitutio reactionb ecause `CH_(3)-overset(o+)(CH)-CH_(3)` is an electrophile.
(B) is a free RADICAL ADDITION reaction..
Discussion
24.

Whichof thefollowingisCORRECTregardinghumanbloodplas,a ?

Answer»

Highconcentrationof`K^(+)`
Lowconcentration of `K^(+)`
Lowconcentrationof`K^(+)`
NONEOF these

ANSWER :B
Discussion
25.

Write the formal charges on atoms in (i) and carbonate ion (ii) nitrite ion.

Answer»

Solution : (i) Lewis structure of ` CO_(3)""^(2-)` ions is
Formal charge on C atom ` = 4 - 0 - (1)/(2) (8) = 0 ` , formal charge on double BONDED O atom = ` 6 - 4 - (1)/(2) (4) = 0 `
Formal charge on single bonded O atom ` = 6 - 6 - (1)/(2) (2) = - `
(ii) Lewis structure of ` NO_(2)^(-)`ions is
Formal charge on N atom = ` 5 - 2 - (1)/(2) (6) = 0 ` , Formal charge on double bonded O atom ` = 6 - 4 - (1)/(2) (4) = 0 `
Formal charge on single bonded O atom `= 6 - 6 - (1)/(2)= - 1 `
Singnificance of formalcharge . The MAIN advantage of the calculation of formal charges is that it helps to
select the most stable structure, i.e., the one with least energy out of the different POSSIBILE Lewis structure. The
most stable is the one which has the SMALLEST formal charges on the atoms.
Discussion
26.

Which of the following pairs of species have the same bond order?

Answer»

`CN^(-)` and `CN^(+)`
`O_(2)^(-) ` and `CN^(-)`
`NO^(+)` and `CN^(-)`
`CN^(-)` and `NO^(-)`

ANSWER :C
Discussion
27.

Write formulas for the following compounds: a) Mercury (II) chloride

Answer»

SOLUTION :HG (II) `Cl_2`
Discussion
28.

When a standard solution of NaOH is left in air for a few hours

Answer»

A PRECIPITATE will form
Strength will decrease
Strength will increase
The concentrationof Na+ ions will REMAIN constant

Solution :`2NaOH+CO_(2)rarrNa_(2)CO_(3)+H_(2)O`
Discussion
29.

Which of the following compound used for metal cleaning solvent?

Answer»

METHYLENE chloride
Methyl chloride
Chloroform
 Ethane

Answer :a
Discussion
30.

Which of the following has higher mass

Answer»

electrons
silver
rombic
chloroform

Answer :C
Discussion
31.

What will be the number of hydrogen atoms (Y) replaced by D on prolonged treatment with D^(o+)//D_(2)O ?

Answer»


SOLUTION :N//A
Discussion
32.

Which of the following is an intermediate in the reaction of benzene with Br_2 and AlBr_3 ?

Answer»

<BR>

Solution :The bromine MOLECULE reacts with the aluminum BROMIDE to form the bromonium ion Br+ and this cation attacks the benzene RING to form the INTERMEDIATE shown.
Discussion
33.

Which pairs of the salts should have identical solubilities in methanol?

Answer»

P and D
P and R
P and Q
Q and S

Solution :P and S are ENANTIOMERS, enantiomers have identical SOLUBILITY.
Discussion
34.

Which of the following species is not stable?

Answer»

`[SN (OH)_6]^(2-)`
`[SiCl_6]^(2-)`
`[SiF_6]^(2-)`
`[GeCl_6]^(2-)`

SOLUTION :`[SiCl_6]^(2-)`
Discussion
35.

What are hybridisation states of each carbon atom in the following compounds? CH_2 = C = O, CH_3CH=CH_2(CH_3)_2CO, CH_2= CHCN, C_6H_6

Answer»


ANSWER :`(##ANE_PKE_CHE_0XI_C12_E02_001_S01##)`
Discussion
36.

Which gas has contribution of 8% in globl warming ?

Answer»

CFC
`N_2 O`
`O_3`
`H_2 O`

SOLUTION :`O_3`
Discussion
37.

What are the oxidation numbers of : (a) S in H_(2)SO_(4), (b) Mn in MnO_(4)^(-) (c) N in NH_(4)^(+) and (d) Al in A1O_(2)^(-) (e) Mn in MnO_(4)^(-2)

Answer»

Solution :(a) 2 (Oxidation number of H)+(Oxidation number of S)+ 4(-2)=0
Oxidation number of S=-2+8=+6
(b) (Oxidation number of Mn)+4(-2)=-1
Oxidation number of Mn =-1+8=+7
(c ) (Oxidation number of N) +4(+1)=+1
Oxidation number of N =+1-4=-3
(d) (Oxidation number of AL)+2(-2)=-1
Oxidation number of Al =-1+4=+3.
(E) (Oxidation number of Mn) +4(oxidation number of oxygem)=-2
Oxidation number of Mn=-2+8=+6
Discussion
38.

Write the cell reaction for each of the following cells. Ni(s)|Ni^(2+)(aq)||Cu^(2+)(aq)|Cu(s).

Answer»

Solution :`NI(s)+CU^(2+)(AQ)TONI^(2+)(aq)+Cu(s)`
Discussion
39.

Which acid will not form hydrocarbon on soda lime decarboxylation ?

Answer»

Cinnamic acid
Salicylic acid
Phthalic acid
Benzoic acid

Solution :
Discussion
40.

Which of the following species contains three bond pairs and one lone pair around the central atom-

Answer»

`H_(2)O`
`BF_(3)`
`NH_(2)^(-)`
`PC l_(3)`

SOLUTION :
Discussion
41.

Write the significance/applications of dipole moment.

Answer»

Solution :In determining the POLARITY of bond As `mu = a xx d` obviously greater the magnitude of dipole moment the polarity of bond will be more. For one polar bond A - B TYPE molecule. H - F `gt H - Cl gt H - Br gt H - I and " if" mu = 0 ` then `mu= 1.78` D, HCL `mu` = 1.07 , H - Br = 13.79 D, H- I = 0.38 D molecule is non polar. e.g. `O_(2), N_(2), F_(2),Cl_(2), Br_(2), Z_(1), H_(1) ` etc.
`BeF_(2) , CO_(2), BeCl_(2)` forsuch molecule `mu` = 0 so they are linear do, but `H_(2)`O. `SO_(2) mu ne 0` So they must have angular shapeSimilarly `BF_(3), CH_(4), "CCl"_(4)` non polar but `NF_(3),NH_(3), CH_(3)Cl` are polar so their shape can be determine.
In CALCULATION of ionic or covalent characters : Ionic character`prop` Difference of electronegativity.
ln HI, HBr, HCl, HF ionic character increase by using felon rules ionic character can be calculated.
To distinguish between cis & trans isomers for cis isomers `mu ne 0` for trans isomer `mu = 0 `.
To distinguish between ortho, META and para isomers for paraisomers `mu` = 0 and dipole moment of ortho is greater than meta.
Discussion
42.

Which of the following options reprsents the correct bond order ?

Answer»

`O_(2)^(-) GT O_(2) LT O_(2)^(+)`
`O_(2)^(-) lt O_(2) gt O_(2)^(+)`
`O_(2)^(-) gt O_(2) gt O_(2)^(+)`
`O_(2)^(-) lt O_(2) lt O _(2)^(+)`

SOLUTION :`{:("",O_(2)^(-) ,lt O_(2) , lt O_(2)^(2+)),("B.O.",:1.5 ,2.0 ,2.5):}`
Discussion
43.

What are conformers

Answer»

SOLUTION :Therotationabout L `C-C` singlebondaxisyielding severalarrangementsof ahydrocacalledconformers.
Discussion
44.

Which will be the least stable resonating structure ?

Answer»

`CH_(2) = CH - overset(OPLUS)CH - overset(Theta)CH-NH_(2)`
`CH_(2) - underset(oplus)CH-CH=CH-NH_(2)`
`overset(oplus)CH_(2)-CH=CH-CH=overset(oplus)NH_(2)`
`CH_(2) = CH - overset(Theta)CH - CH = overset(oplus)NH_(2)`

Solution :In Structure ONE the opposite charges are PRESENT on adjacement atoms and both are in conjugation
Discussion
45.

Which of the following statement is incorrect regarding the complete hydrolu=ysis of Marshall's acid?

Answer»

CARO's acid is an intermediate product
Two molecules of `H_(2)SO_(4)` and one molecule of `H_(2)O_(2)` are the final product
Hybridisation and oxidation state of CENTRAL atom remain unchanged in the final product
Both final products can ACT as oxidising as WELL as reducing agent

Answer :D
Discussion
46.

Which of the following acts as reducing as well as oxidising agent ?

Answer»

`NaNO_(3)`
`Na_(2)O`
`Na_(2)O_(2)`
`KNO_(3)`

Solution :`O_(2)^(-)` (peroxide ION) can be oxidised to `O_(2)` and can be reduced to oxide ion , `O_(2)^(-)` . THUS , `Na_(2)O_(2)` ACTS both a reducing as well as an oxidising agent .
Discussion
47.

The total number of compounds having atleast one bridging oxo group among the molecules given below is ……….. . N_(2)O_(5),N_(2)O_(3),P_(4)O_(6),P_(4)O_(7),H_(4),P_(2),O_(5),H_(5)P_(3)O_(10),H_(2)S_(2)O_(3),H_(2)S_(2)O_(5)

Answer»


SOLUTION :These are `N_(2)O_(5)` , `P_(4)O_(6)` , `P_(4)O_(7)` (one P=O in `P_(4)O_(6)`), `H_(4)P_(2)O_(5)` , `H_(5)P_(3)O_(10)`

If `N_(2)O_(3)` is ALSO INCLUDED, then total number of compounds is
Discussion
48.

What is the vapour pressure of water at 373 K ?

Answer»

SOLUTION :373 K is the boiling point of water.
At the boiling point, the vapour pressure of any liquid is EQUAL to the ATMOSPHERIC pressure.
The vapour pressure of water at 373 K is 760 mm Hg.
Discussion
49.

Which of the following statement is incorrect for compounds of graup 2 meters?

Answer»

The number of MOLECULES of water of crystllistoion INCREASES with size of the metal IONS.
The number of molecules of water of crystllistion increases asthe size of the metal ions DECREASES.
the number of molecules of water of crystallistion decreases as the size of the metal ions increses.
all the above

Answer :1
Discussion
50.

What is effect of temperature on value of K_w and pH ?

Answer»

SOLUTION :The ionic PRODUCT of WATER `(K_w)` increases with increase of temperature the effect of TEMP. on value of pH is niglible.
Discussion