Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

When dissolved in dilute sulphuric acid, 0.275 g of a metal evolved 119.7 mL of hydrogen at 20°C and 763 mm pressure. What is the equivalent mass of the metal ?

Answer»

<P>

Solution :In the PRESENT case,
`P_1 = 763 mm, V_(1) = 119.7 ML, T_2 = 20°C = 293` K, MASS of metal = 0.275 g
If the volume of hydrogen at N.T.P is `V_2`, we have from gas equation
`(P_(1)V_(1))/T_(1) = (P_(2)V_(2))/T_(2)`
or `(763 xx 119.7)/293 = (760 xx V_(2))/273`
`therefore V_(2)=(793 xx 119.7 xx 273)/(760 xx 293) = 111.97` mL
Mass of 111.97 mL of `H_2` at S.T.P.
`=2/(22400) xx 111.97 = 0.011` g
Hence, Equivalent weight of the metal
`=("Mass of the metal")/("Mass of "H_(2) "evolved at S.T.P") = 0.275/0.011 = 25`
2.

Write the structure of pyrophosphoric aicd.

Answer»

<P>

Solution :`HO-underset(|)overset(||)P-O-underset(|)overset(||)P-OH` Pyrophosphoric `(H_(4)P_(2)O_(7))` ACID
3.

W/V percentage of 1 M H_2O_2solution is

Answer»

3.03
3.4
6.8
1.7

Answer :B
4.

Write formulas for the following compounds : Mercury (II) chloride

Answer»

SOLUTION :`HgCl_(2)`
5.

The total number of reagents(s) which give white precipitate with solution of sodium oxalates. (MnO_(2)+H_(2)SO_(4)),CaCI_(2),AgNO_(3),BaCI_(2),KMnO_(4),(K_(2)Cr_(2)O_(7)+H_(2)SO_(4))

Answer»


SOLUTION :`CaCI_(2),AgNO_(3),BaCI_(2)`
6.

What do you mean by dihedral angle or torsional angel ?

Answer»

SOLUTION :Magnitude of torsional strain depends upon the angle of rotation about C-C BOND. This angle is also CALLED DIHEDRAL angle or torsional angle.
7.

Three reactions involving H_(2)PO_(4)^(-) are given below : (i) H_(3)PO_(4) + H_(2)O rarrH+_(3)O^(+) + H_(2)PO_(4)^(-) (ii) H_(2)PO_(4)^(-) + H_(2)O rarr HPO_(4)^(2-) + H_(3)O^(+) (iii) H_(2)PO_(4)^(-) + OH^( -) rarr H_(3)PO_(4) + O^(2-) In which of theabove does H_(2)PO_(4)^(-) act as an acid ?

Answer»

(iii)only
(i) only
(ii) ony
(i) and (ii)

SOLUTION :In (i), in the reverse REACTION, `H_(2)PO_(4)^(-)` is accepting a proton. Hence,it is a base
(ii), `H_(2)PO_(4)^(-)` is donating a proton which is ACCEPTED by `H_(2)O`. Hence it is an acid.
In (iii) , `H_(2)PO_(4)^(-)` is accepting a proton. Hence it is a base
Thus, only in (ii), `H_(2)PO_(4)^(-)` acts an acid.
8.

The solution of salt of (HCl + NH_4OH) is ____

Answer»

Acidic
Basic
Neutral
Protic

Answer :A
9.

Which of the following is a poisonous gas ?

Answer»

OXYGEN
Nitrogen
Chlorine
Ozone

Answer :C
10.

Why can dilute solutions of hydrogen peroxide not be concentrated by heating ? How can a concentrated solution of hydrogen peroxide be obtained ?

Answer»

Solution :`H_2O_2` cannot be CONCENTRATED by heating because it decomposes much below its boiling point to GIVE `H_2O` and `O_2`.
`2H_2O_2 to 2H_2O+ O_2`
Therefore, concentrated of `H_2O_2` is carried out in a number of STAGE (i) The `H_2O_2` formed (about 1%) is EXTRACTED with water and the aqucous solution is concentrated by distillation under REDUCED pressure. to give 30% `H_2O_2` solution.
11.

What are the products in the following sequence of reaction Poly (F) is:

Answer»

Nylon-6,6
Nylon-6,10
Nylon-6
Nylon-5

Answer :A
12.

What is electronic configuration ?

Answer»

Solution :Distribution of ELECTRONS in an ATOMS is known as ELECTRONIC configuration.
13.

The varous types of hydrides and examples of each type are given below : {:(,"Hydride type",,"Compound"),((A),"Electron deficient",(i),LiH),((B),"Saline",(ii),CH_(4)),((C ),"Electron-precise",(iii),NH_(3)),((D),"Interstitial",(iv),B_(2)H_(6)),((E ),"Electron rich",(v),CrH):} Choose the correct matching from the codes given below :

Answer»

(A) - (ii), (B) - (iv), (C )-(v), (D)-(iii), (E )-(i)
(A) - (iv), (B)-(i), (C )-(ii), (D)-(v), (E )-(iii)
(A) -(iv), (B) - (iii), (C )-(v), (D)-(ii), (E )-(i)
(A)-(v), (B)-(iii), (C )-(iv), (D )-(ii), (E )-(i)

Solution :Electron deficient `- B_(2)H_(6)`
Saline - LiH
Electron precise `- CH_(4)`
Interstitial - CRH
Electron rich `- NH_(3)`
14.

The type of hybrid orbitals employed in the formation of SF_(6) molecules is

Answer»

`SP^(3)d`
`sp^(3)`
`sp^(3)d^(2)`
`d^(2)sp^(3)`

ANSWER :C
15.

The solubility of H_2O_2 is 48 gm in 500 ml calculate volume strength and %w/v.

Answer»

34.62,19.2
31.62,19.2
31.62,9.6
30.2,9.6

Solution :MOLARITY=`"Weight of solute gm"/"MOLECULAR X Volume of solution"`
`=48/(34xx0.5)=2.82 M H_2O_2`
%w/v = `(Mxx34)/10 = (2.82xx34)/10`=9.6
V=M x 11.2 = 2.82 x 11.2 = 31.58
16.

Which of the following statement (s) is/are true about the following eliminations ?

Answer»

HOFFMANN PRODUCT is MAJOR product in I
Saytzeff product is major product in I
Hoffmann product is major product in II
Saytzeff product is major product in II

Answer :A::D
17.

Which of the following properties of lithium cannot be attributed to its anomalous properties

Answer»

Lithium chloride crystallizes as hydrated lithium chloride .
Lithium cannot crystallizes as hydrated lithium chloride.
Lithium dissolves in ammonia to form BLUE coloured paramegnetic SOLUTION .
Lithium bicarbonate EXISTS only in solution.

Answer :C
18.

Which is the most reactive alkane towards bromination in presence of sunlight ?

Answer»

`CH_3CH_3`
`CH_4`
`CH_3CH_2CH_3`
`CH_3-undersetunderset(CH_3)(|)CH-CH_3`

ANSWER :D
19.

Which of the following molecules represents the order of hybridization sp^(2), sp^(2), sp, sp from left to right atoms ?

Answer»

`HC -= C-C-=CH`
`CH_(2)=CH-C-=CH`
`CH_(2)=CH-CH=CH_(2)`
`CH_(3)-CH=CH-CH_(3)`

SOLUTION :`overset(SP^(2))(CH_(2))=overset(sp^(2))(CH)-overset(sp)(C)-=overset(sp)(CH)`
20.

What iselectromagneticradiation ?

Answer»

SOLUTION :JamesMaxwellwas the FIRST to GIVE acomprehensiveexplanationabout theinteractionbetweenthe chargebodiesand thebehavior of ELECTRICAL andmagneticfields.
Whenelectrically chargedparticlemovesunderaccelerationaltermatingelectricalandmagneticfieldareproduced andtransmitted .
thesefieldare transmittedin the formsofwaves calledelectromagneticwavesofelectromagneticradiation.
21.

Which one of the following is an incorrect statement for physiosorption ?

Answer»

It is reversible process
It REQUIRES less HEAT of adsorption
It requires ACTIVATION ENERGY
It takes place at low temperature

Solution :Physiosorption does not require any activation energy
22.

which salt can be produced by the reaction of carbon monoxide and caustic soda (NaOH)?

Answer»

`CH_(3)COOH`
`C_(2)H_(2)O_(4)`
`HCOONa`
`HCHO`

Solution :`CO + NaOH overset("Pressure")RARR HCOONa`
23.

What are Cabanions ?

Answer»

Solution :Let us consider the heterolytic fission of the bond C-X present in a ORGANIC molecules . If the carbon atom FORMER takes away the bonding electron PAIR and ACQUIRES a negative charge . The resulting carbon anion is known as Carbanion .
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24.

Which one of the metal is used to convert para hydrogen into ortho hydrogen?

Answer»

 COPPER
Aluminium
Sodium
PLATINUM

ANSWER :d
25.

Which of the following gases is not a greenhouse gas ?

Answer»

CO
`O_3`
`CH_4`
`H_2O` vapour

Solution :CO is not a GREEN HOUSE GAS
26.

The redispersal of a freshly precipitated substance into a sol by the addition of an electrolyte in common is known as

Answer»

Aggregation
Condensation
Coagulation
Peptization

Answer :D
27.

Whichone (atom//ion )in the followingpairshas highestelectrongainenthalpy ? (i)O^(-)S(ii) O, S^(-)(iii) O^(-), S^(-)(iv)N^(-)P

Answer»

<P>

Solution :(i) Dueto repulsionsbetweenthe ELECTRONSON `O^(-)` and theadditional incomingelectron , theelectron gainenthalpy of `O^(-)` is positivewhilethat O a -ve
(ii) Onsimilargroundsthe electron gainenthalpyof `S^(-)` is+ vewhilethat OFO is - ve
(iii) dueto smallsizerepulsionsbetween `O^(-)` and theincomingelectron is muchmore thanin `S^(-)` .thereforeelectron gainenthalpyof `O^(-)` is more+ vethanthatof `S^(-)`
(iv) DUE torepulsion between`N^(-)` and theincomingelectron gainenthalpyof `N^(-)` positivewhilethat P is -ve
28.

What is difference between barometer and nanometer ?

Answer»

SOLUTION :Barometer is USED for measurement of pressure of atmosphere and nanometer is used for measurement of pressure of gases.
Example : Pressure of barometer is 740 mm of Hg and difference between two end of nanometer is 2.1 CM. Then calculate pressure of Gas ?
Pressure of Gas = Pressure of barometer - Difference between two end
`= 740-(2.1xx10) [because 2.1 cm = 2.1xx10 mm]`
= 719 mm Hg.
29.

Which of the following is less than zero during adsorption?

Answer»

`DELTAG`
`DELTAS`
`DELTAH`
All the above

Answer :D
30.

Which of the following cations is not hydrolyzed in aqueous solution ? (i) Ba^(2+),(ii) Ca^(2+) (iii) Na^(+),(iv) K^(+)

Answer»

(i), (ii)
(iii), (iv)
(i), (ii), (iii), (iv)
(i), (ii), (iii)

Solution :Salts formed by the REACTIONS between acids and bases (in denfinite proporties) undergo dissociation in water. The cation/anions formed on dissociation of salts either exist as hydrated ions in aqueous solutions or interact with water to reform the corresponding acids/bases depending upon the nature of salts. The latter process of interaction between water and cations/anions or both of salts is called hydrolysis. The pH of the solution GETS a AFFECTED by this interaction. The cations of strong bases such as `Na^(+), K^(+), Ca^(2+)`, and `Ba^(2+)` SIMPLY get hydrated but do not HYDROLYZE.
31.

What is [H^(+)] in mol/L of a solution that is 0.20 M in CH_(3)CO ON aand 0.10M in CH_(3)CO OH ? K_(a) for CH_(3)CO OH = 1.8 xx 10^(-5).

Answer»

`9.0xx10^(-6)`
`3.5xx10^(-4)`
`1.1xx 10^(-5)`
`1.8xx10^(-5)`

Solution :The given solution is an acidic buffer. Hence, its pH will be
`pH = pK_(a) +log. (["SALT"])/(["ACID"])`
`=-log.(1.8xx10^(-5))+log.(0.20)/(0.10)`
or `-log(h^(+)]=log.(2)/(1.8xx10^(-5))`
or `log.(1)/([H^(+)])=log.(2)/(1.8xx10^(-5))`
or `[H^(+)]=(1.8xx10^(-5))/(2) = 0.9xx10^(-5)M`
`=9xx10^(-6)M`
32.

Which set of quantum numberis notpossible

Answer»


ANSWER :D
33.

Which is the correct Lewis structure of N_(2) ?

Answer»




Solution :
In `N_(2)` TOTAL valence ELECTRON = 5 + 5 = 10
Only OPTION (A) is correct for no. of electrons.
34.

Which of the following is a stronger base? Give reason to justify your answer. {:(CH_(2)=CH-NJ_(2)""CH_(2)=N-CH_(3)),(""I""II):}

Answer»


ANSWER :I is less basic than II because, in COMPOUND (I) the LONE pair of electrons is involved in RESONANCE but not in II.
35.

The tendency of BF_(3),BCl_(3) and BBr_(3) to have as Lewisacid decreases in the sequence

Answer»

`BF_(3) lt BCl_(3) gt BBr_(3)`
`BCl_(3) gt BF_(3) gt BBr_(3)`
`BBr_(3) gt BCl_(3)gt BF_(3)`
`BBr_(3) gt BF_(3) gt BCl_(3)`

Solution :As the extent of `ppi-ppi` back bonding decreases with increase in the SIZE of the halogen, electron-deficiencyincreases , i.e., OPTION (c ) is correct.
36.

which of the following is not matched correctly with its use?

Answer»

PIEZOELECTRIC MATERIAL - Quartz
Ion - exchanges - Graphite
Filtration plants - Silica
Electrical insulators - Silicones

Solution :Zeolites are USED as ion-exchangers in softening of hard water
37.

What would be the pH of a solution obtained by mixing 10 g of acetic acid and 15 g of sodium acetate and making the volume equal to 1L. Dissociation constant of acetic acid at 25^(@)C is1.75xx10^(-5).

Answer»

Solution :`pH=pK_(a) + log. (["Salt"])/(["Acid"])=pK_(a) + log. ([CH_(3)CO ON a])/([CH_(3)CO OH])`
`[CH_(3)CO OH]=(10)/(60) "mol L"^(-1)` (molar MASS of `CH_(3)CO OH = 60 g "mol"^(-1)`)
`[CH_(3)CO Ona]=(15)/(82) "mol" L^(-1)` (molar mass of `CH_(3)CO Ona = 82 g "mol" ^(-1)`)
`pK_(a)=-log K_(a)=-log(1.75xx10^(-5))=5-0.2430 = 4.757`
`:. pH = 4.757 + log(15//82)/(10//60) = 4.757+ log. ((15)/(82)xx(60)/(10))`
`=4.757 + log 1.098 = 4.757 + 0.0406 = 4.80`
38.

The reagent(s) used for softening the temporary hardnes of water is(are):

Answer»

`Ca_(3)(PO_(4))_(2)`
`CA(OH)_(2)`
`Na_(2)CO_(3)`
`Na_(2)CO_(3)`.

Solution :(B,c) Both `Ca(OH)_(2) and Na_(2)CO_(3)` can remove temporary HARDNESS from WATER.
39.

Which of the following contain same number of carbon atoms as in 6 g of carbon-12?

Answer»

7.5 G ethane
8 g METHANE
both (a) and (b)
none of these

Solution :No. of moles of CARBON present in 6 g of C-12 = Mass / Molar mass
= 6/12 = 0.5 moles = `0.5 xx 6.022 xx 10^(23)` carbon atoms.
No. of moles in 8 g of methane = 8 /16 = 0.5 moles
` = 0.5 xx 6.022 xx 10^(23)` carbon atoms.
No. of moles in 7.5 g of ethane = 7.5 / 16 - 0.25 moles = `2 xx 0.25 xx 6.022 xx 10^(23)` carbon atoms
40.

The volume of the nucleus of an atom when compared to the extra nuclear part is ______.

Answer»

heavier
Smaller
Same size
Unpredictable

Answer :B
41.

Which one of the following is s-butylphenylvinyl methane ?

Answer»




SOLUTION :OPTION (C) REPRESENTS s-butylphenylvinylmethane.
42.

Which of the following gases is not a green house gas ?

Answer»

CO
`O_3`
`CH_4`
`H_2 O` vapour

Solution :NEAR the earth.s surface the solar energy absorb by the gases and then radiate it back to the earth are KNOWN as GREENHOUSE gases. `CO_2`, water vapour, `CH_4, O_3`, oxides of nitrogen, chlorofluoro carbons etc. are GREEN house gases. CO is not a green house gas.
43.

The splitting of spectral lines by a magnetic field is called the zeeman effect after the Dutch physicist Pieter Zeeman. The Zeeman effect is a vivid confirmation of of space quantization. Magnetic quantum number 'm' was introduced during the study of zeeman effect. 'm' can have the (2l+1) values (-l,0,+l). Magnetic quantum number represents the orientation of atomic orbitals in three-dimensional space. the normal zeeman effect consists of the splitting of a spectral line of frequency v_(0) into three components i.e., v_(1)=v_(0)-(e)/(4pim)B,v_(2)=v_(0),V_(3)=v_(0)+(e)/(4pim)B Here, B is magnetic field. Q. Which of the following statements is incorrect with reference to the Zeeman effect?

Answer»

In a MAGNETIC field, the energy of a paritcular ATOMIC state depends on the values of 'm' and 'n'
Zeeman effect is used to CALCULATE the e/m ratio for an electron
Individual spectral lines split into separate lines. The DISTANCE between them is independent of the MAGNITUDE of the magnetic field.
Individual spectral lines split into seprate lines. The distnace between them is independent of the magnitudeof the magnetic field

Answer :B
44.

The splitting of spectral lines by a magnetic field is called the zeeman effect after the Dutch physicist Pieter Zeeman. The Zeeman effect is a vivid confirmation of of space quantization. Magnetic quantum number 'm' was introduced during the study of zeeman effect. 'm' can have the (2l+1) values (-l,0,+l). Magnetic quantum number represents the orientation of atomic orbitals in three-dimensional space. the normal zeeman effect consists of the splitting of a spectral line of frequency v_(0) into three components i.e., v_(1)=v_(0)-(e)/(4pim)B,v_(2)=v_(0),V_(3)=v_(0)+(e)/(4pim)B Here, B is magnetic field. Q. A d-subshell in an atom in the presence and absence of magnetic field is:

Answer»

five-fold DEGENERATE, non-degenerate
seven-fold degenerate, non-degenerate
five-fold degenerate,five-fold degenerate
non-degenerate, five-fold degenerate.

Answer :D
45.

The splitting of spectral lines by a magnetic field is called the zeeman effect after the Dutch physicist Pieter Zeeman. The Zeeman effect is a vivid confirmation of of space quantization. Magnetic quantum number 'm' was introduced during the study of zeeman effect. 'm' can have the (2l+1) values (-l,0,+l). Magnetic quantum number represents the orientation of atomic orbitals in three-dimensional space. the normal zeeman effect consists of the splitting of a spectral line of frequency v_(0) into three components i.e., v_(1)=v_(0)-(e)/(4pim)B,v_(2)=v_(0),V_(3)=v_(0)+(e)/(4pim)B Here, B is magnetic field. Q. Which among the following is/are correct about the orientation of atomic orbitals in space?

Answer»

s-orbitals has single orientation
d-subshell orbitals have three orientations along x,y and Z directions
f-subshell have SEVEN orientations in their orbitals
None of the above

Answer :A::C
46.

The splitting of spectral lines by a magnetic field is called the zeeman effect after the Dutch physicist Pieter Zeeman. The Zeeman effect is a vivid confirmation of of space quantization. Magnetic quantum number 'm' was introduced during the study of zeeman effect. 'm' can have the (2l+1) values (-l,0,+l). Magnetic quantum number represents the orientation of atomic orbitals in three-dimensional space. the normal zeeman effect consists of the splitting of a spectral line of frequency v_(0) into three components i.e., v_(1)=v_(0)-(e)/(4pim)B,v_(2)=v_(0),V_(3)=v_(0)+(e)/(4pim)B Here, B is magnetic field. Q. In presence of magnetic field, d-suborbit is:

Answer»

five-fold degenerate
three-fold degenerate
seven-fold degenerate
non-degenerate

Answer :D
47.

The splitting of spectral lines by a magnetic field is called the zeeman effect after the Dutch physicist Pieter Zeeman. The Zeeman effect is a vivid confirmation of of space quantization. Magnetic quantum number 'm' was introduced during the study of zeeman effect. 'm' can have the (2l+1) values (-l,0,+l). Magnetic quantum number represents the orientation of atomic orbitals in three-dimensional space. the normal zeeman effect consists of the splitting of a spectral line of frequency v_(0) into three components i.e., v_(1)=v_(0)-(e)/(4pim)B,v_(2)=v_(0),V_(3)=v_(0)+(e)/(4pim)B Here, B is magnetic field. Q. Zeeman effect explains splitting of spectral lines is:

Answer»

MAGNETIC field
electric field
both (a) and (B)
NONE of these

Answer :A
48.

Which of the following property increases as we go down the group in the periodic property?

Answer»

IONIZATION energy
Electronegativity
Atomic radius
Electron affinity

Answer :C
49.

What is the colour of the flame obtained on burning the vapours of ethyl borate?

Answer»

SOLUTION :GREEN EDGED FLAME
50.

Which one is pesticides?

Answer»

INSECTICIDES
Fungicides
Herbicides
All of these

SOLUTION :All of these