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87801.

A reaction is A+BhArrC+D. Initially we start with equal concentration of A and B. At equlibrium we find the moles of C is two times of A. What is the equilibrium constant of the reaction

Answer»

4
2
`1//4`
`1//2`

SOLUTION :`A+BhArrC+D`
at EQULIBRIUM AA 2a 2a
`K=(2axx2a)/(axxa)=4`
Discussion
87802.

A reaction is a first order when

Answer»

the amount of product formed increases linearly with time
the amount of product formed increases linearly with time
the rate is Jinearly RELATED to the CONCENTRATION of the reactant
the concentration of the reactant decreases linearly with time

SOLUTION :For a 1st order reaction , rate `prop` CONC.
Discussion
87803.

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What the order of the reaction?

Answer»

Solution :It is FIRST ORDER. In first order REACTIONS, `t_(75%)=2t_(50%)`.
Discussion
87804.

A reaction is 50% completed in 2 hours and 75% completed in 4 hours. Then the order of the reaction is ...............

Answer»

FIRST ORDER
ZERO order
second order
THIRDORDER

ANSWER :A
Discussion
87805.

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What is the order of reaction ?

Answer»

Solution :`t_(1//2)=2` hours. As `75%` COMPLETION takes two HALF lives, this shows that `t_(1//2)` is independent of initial CONCENTRATION. HENCE, it is a reaction of first order.
Discussion
87806.

A reaction is 50% complete in 2 hours and 75% complete in 4 hours . The order of reaction is

Answer»

1
2
3
0

Solution :For a first order reaction ,
`t_(75%) = 2 XX t_(50%)`
Discussion
87807.

A reaction is 50% complete in 10 minutes. It is allowed to proceed another5 minutes. How much of the reaction would be complete at the end of these 15 minutes if the reaction follows zero-order kinetics?

Answer»


ANSWER :0.75
Discussion
87808.

A reaction involving two different reactants can never be:

Answer»

UNIMOLECULAR reaction
first ORDER reaction
second order reaction
bimolecular reaction

Answer :A
Discussion
87809.

A reaction involving two different reactants can never be

Answer»

bimolecular REACTION
second order reaction
first order reaction
UNIMOLECULAR reaction

Solution :The molecularity of a reaction is the number of REACTANT MOLECULES TAKING part in a single step of the reaction. Thus the reaction involving two different reactant can never be unimolecular.
Discussion
87810.

A reaction involving two different reactants…

Answer»

can never be a second ORDER reaction
can never be a UNIMOLECULAR reaction
can never be a molecular reaction
can never be a first order reaction

Answer :B
Discussion
87811.

A reaction involving an aromaticnucleas is usually initiated by:

Answer»

FREE radicals
Molecules POSSESSING a LONE PAIR of electrons
Nucelphiles
Eletrophiles

Solution :NA
Discussion
87812.

A reaction involves two reactants. The rate of reaction is directly proportional to the concentration of one of them and inverselyproportional to the concentration of the other. The overall order of the reaction will be

Answer»

ONE
TWO
ZERO
None of these

Answer :C
Discussion
87813.

A reaction involves two reactants. The rate of reaction is directly proportional to the concentration of one of them and inversely proportional to the concentration of the other. The overall order of reaction will be

Answer»

ONE
TWO
Zero
fractional

Answer :C
Discussion
87814.

A reaction in which rate is independent of the the concentration of the reactant over a wide range ofconcentration is called............

Answer»

SOLUTION :ZERO ORDER REACTION
Discussion
87815.

A reaction in which an increase in pressure will increase the yield of a products is

Answer»

`CO(G) +3H_(2)(g) hArr CH_(4)(g)+H_(2)(g)`
`NO(g)hArr(1)/(2)(g) + (1)/(2) O_(2)(g)`
`H_(2)O+ C(s)hArr CO(g)+ H_(2)(g)`
`ZN(s) + Cu^(2+)(aq.)hArr Cu(s) + Zn^(2+)(aq.)`

Answer :A
Discussion
87816.

A reaction having equal activation energies for forward and reverse reaction that

Answer»

`DELTA H = 0`
`Delta S = 0`
Zero ORDER
None of these

Answer :a
Discussion
87817.

A reactionhas rateconstants1.73 xx 10^(-3) min^(-1)and 4.86 xx 10^(-3)min^(-1)at 300 K and 300 K respectively. Calculate The energyof activation of thereaction(R= 8.314 JK^(-1)mol^(-1))

Answer»

SOLUTION :Activation ENERGY`=E_(a)= 28. 35 kJ`
Discussion
87818.

A reaction has DeltaH=-33kJ and DeltaS=-58J//K. This reaction would be:

Answer»

SPONTANEOUS at all temperatures
NON - spontaneous at all temperatures
Spontaneous above a CERTAIN temperature
Spontaneous below a certain temperature

Answer :D
Discussion
87819.

A reaction has DeltaH=-33 KJ and DeltaS J//k . This reaction would be:

Answer»

spontaneous at all temperatures
non- spontaneous at all temperatures
spontaneous above a CERTAIN temperature
Spontaneous below a certain temperature

Solution : `DELTAG = underset(-"ve")underset(darr)((DeltaH))-underset(-"ve")underset(darr)(T(DeltaS))`
since both are `-"ve"` , the REACTION would have a `-"ve" DeltaG` below a TEMPERATUREOF `(33000)/(58) K (=569K)`
Discussion
87820.

A reaction hos both Delta H and Delta S - ve. The rate of reaction

Answer»

CANNOTBE predictedfor changein temperature
increases with INCREASE in temperature
increases with decreases in temperature
remains unaffectedby CHANGE in temperature

Answer :C
Discussion
87821.

A reaction has both DeltaH and DeltaS negative. The rate of reaction

Answer»

increses with increase of TEMPERATURE
increases with decrease of temperature
ramains unaffected by change of temperature
cannot be predicated for change in tempeature

Solution :`DeltaG=DeltaH-TDeltaS`
Negative `DeltaH` favours the PROCESS. Negative `DELTAS` opposes the process. If temperature is decreased, OPPOSING factor decreases. Hence , RATE of reaction increases.
Discussion
87822.

A reaction completes 50% in 2 hours and 75% in 4 hours. What is the order of the reaction. Give reason.

Answer»

Solution :` t_(3//4) = 2 xx t_(1/2)` Half life period is INDEPENDENT of initial concentration. HENCE it is a FIRST order reaction.
Discussion
87823.

A reaction cannot take place spontaneously at any temperature where

Answer»

both `DELTA H and Delta S` are POSITIVE
both `Delta H and Delta S` are NEGATIVE
`Delta H` is negative and `Delta S` is positive
`Delta H` is positive and `Delta S` is negative

Answer :D
Discussion
87824.

A reaction can take place by two paths, k_1 and k_2 are rate constants for the two paths & E_1 and E_2 are their respective activation energies. At temperature T_a: k_1gtk_2, E_1ltE_2. if temperature is raised to T_b, the rate constants change to k_1 & k_2 Which relation is correct between k_1,k_2,k_1 & k_2 (considering activation energy does not change with temperature )

Answer»

`k_1/k_1gtk_2/k_2`
`k_1/k_1=k_2/k_2`
`k_1/k_1ltk_2/k_2`
`k_1/k_2gtk_1/k_2`

Solution :`k_1=Ae^((-E_(1))/(RT_a)) "" k_2=Ae^((-E_2)/(RT_a)) " " IMPLIES (k'_(1))=Ae^((-E_1)/(RT_b)) " " k'_2=Ae^((-E_2)/(RT_b))`
`k_1/k_1'=(Ae^((-E_1)/(RT_a)))/(Ae^((-E_1)/(RT_b))) "" k_1/k_1'=E^((-E_1)/R(1/T_a-1/T_b))`
`(k_1')/k_1=e^((E_1)/R(1/T_a-1/T_b))`
Similarly
`(k_2')/k_2=e^((E_2)/R(1/T_a-1/T_b))`
`E_1ltE_2 implies e^((E_1)/R(1/T_a-1/T_b)) " " lt e^((E_2)/R(1/T_a-1/T_b))`
`implies k_1^'/k_1ltk_2^'/k_2`
Discussion
87825.

A reaction between methyl magnesium bromide and ethyl alcohol gives

Answer»

METANE
Ethane
Propane
Butane

Solution :
Discussion
87826.

A reaction between copper and hot concntratd sulphuric acid produces :

Answer»

`SO_2`
`SO_3`
`H_2O`
`CU^+` IONS

ANSWER :A
Discussion
87827.

A reaction between ammonia and boron trifluoride is given below overset(..)NH_(3)+BF_(3)rarr H_(3)N:BF_(3).Identify the acid and base in the reaction. Which theory explain it ?

Answer»


Solution :`overset(..)NH_(3)+BF_(3)RARR H_(3)N:BF_(3)`
(i) In the above reaction `BF_(3)` is an acid and `NH_(3)` is the base.
(ii) Lewis concept explain it as follows:

(iii) A Lewis acid is an electron deficient molecule and capable of ACCEPTING a pair of electron and a Lewis base is electron RICH moleculeand capable of donating a pair of ELECTRONS.
Discussion
87828.

A reaction between ammonia and boron trifluoride is given below NH_3+BF_3 to H_3N,BF_3 Identify the acid and base in the reactions. Which theory explain it?

Answer»

SOLUTION :`NH_3+BF_3 to N,BF_3`
(i) In the above reaction `BF_3` is an acid and `NH_3` is the base.
(ii) LEWIS CONCEPT explain it as follows:

(iii) A lewis acid is an ELECTRON deficient molecule and capable of ACCEPTING a pair of electrons and a lewis base is electron rich molecule and capable of donating a pair of electrons.
Discussion
87829.

A reaction, A(g)+2B(g)hArr 2C(g)+D(g) was studied using an initial concentraction of A and B were found to be equal. The value of K_(P) for the equilibrium is

Answer»

4
6
8
12

Answer :A
Discussion
87830.

A reaction A+BtoD+E takes place as A+Boverset(k_(1))to2C C+Boverset(k_(2))to2D C+Aoverset(k_(3))to2E The rate of disappearance of C is given by

Answer»

`-(d[C])/(dt)=k_(2)[B][C]+k_(3)[A][C]-k_(1)[A][B]`
`-(d[C])/(dt)=k_(2)[B][C]+k_(3)[A][C]`
`-(d[C])/(dt)=k_(2)[D]+k_(3)[E]-k_(1)[C]`
`-(d[C])/(dt)=k_(2)*k_(3)[D][E]`

Answer :A
Discussion
87831.

A reaction : A + B rarr C follows the rate law as shown : R=10^(-2) [A] [B] M/sec. Calculate time required for concentration of [B] to reduce to one fourth of its original value if initially A and B are taken at 3 M and 3.2 M respectively.

Answer»

`("LN"(5)/(4))XX(1)/(2xx10^(-3))SEC`
`("ln 5")xx(1)/(2)sec`
`"ln 4"xx(1)/(2xx10^(-3))sec`
`"ln 5"xx(1)/(2xx10^(-2))sec`

ANSWER :A
Discussion
87832.

A reaction A+B rarr C is second order with respect to A and independent of B .The rate expression for the reaction is :

Answer»

RATE= K[A] [B]
rate = k `[A]^(2) [B]`
rate = `k[A]^(2)[B]^(2)`
rate = `k[A]^(2)`

ANSWER :D
Discussion
87833.

A reactant (A) froms two products, Aoverset(k_(1))toB, Activation Energy E_(a_(1)) Aoverset(k_(2))toB, Activation Energy E_(a_(2)) If E_(a_(1))=2E_(a_(2)), then k_(1) and k_(2) are related as:

Answer»

`k_(2)=k_(1)e^((E_(a_(1)))/(RT))`
`k_(2)=k_(1)e^((E_(a_(2)))/(RT))`
`k_(1)=Ak_(2)e^((E_(a_(1)))/(RT))`
`k_(1)=2k_(2)e^((E_(a_(1)))/(RT))`

SOLUTION :`k_(1)=A_(1)e^(-E_(a_(1)))/(RT)`….(i)
`k_(2)=A_(2)e^(-E_(a_(2)))/(RT)`….(ii)
On dividing EQN(i) from eqn(ii)
`(k_(1))/(k_(2))=(A_(1))/(A_(2))(E_(a_(1))-E_(a_(2)))/(RT)`… (iii)
Given `E_(a_(1))=E_(a_(2))`
On substituting this value in eqn. (iii)
`K_(1)=K_(2)Atimese^(E_(a_(1)))/(RT)`
Discussion
87834.

A reaction 2A+Boverset(k)rarrC+D is first order with respect to A and 2nd order with respect to B. Initial conc. (t = 0) of A is C_(0) while that of B is 2C_(0). If at t = 30 minutes the conc. Of C is (C_(0))/(4) then rate expression at t = 30 minutes is :

Answer»

`R=7C_(0)^(3)(k)/(16)`
`R=27C_(0)^(3)(k)/(32)`
`R=247C_(0)^(3)(k)/(64)`
`R=49C_(0)^(3)(k)/(32)`

ANSWER :D
Discussion
87835.

A reactant (A) forms two products : Aoverset(k_(1))(to)B activation energy E_(a_(1)) A overset(k_(2))(to)C activation energy E_(a_(2)) If E_(a_(2))=2E_(a_(1)), then k_(1) and k_(2) will be related as

Answer»

`k_(2)=k_(1)E^(E_(a_(1))//RT)`
`k_(2)=k_(1)e^(E_(a_(2))//RT)`
`k_(1)=Ak_(2)e^(E_(a_(1))//RT)`
`k_(1)=2k_(2)e^(E_(a_(2))//RT)`

ANSWER :A
Discussion
87836.

A reactant (A) forms two products : A overset(k_(1))to B, Activation Energy E_(a_(1)) A overset(k_(2))to C, Activation Energy E_(a_(2)) If E_(a_(2))=2E_(a_(1)), then k_(1) and k_(2) are related as

Answer»

`k_(1)=2k_(2)e^(Ea_(2)//RT)`
`k_(2)=k_(1)e^(Ea_(1)//RT)`
`k_(2)=k_(1)e^(Ea_(2)//RT)`
`k_(1)=A" K"_(2)e^(Ea_(1)//RT)`

Solution :`k_1=A_1e^(-E_(A1)//RT), k_2=A_2e^(-E_(a2)//RT)`
`:.""k_1/k_2=A_1/A_2e^((E_(a_2)-E_(a1))//RT)=A_1/A_2e^((2E_(a_1)-E_(a_(1))))`
`(because E_(a2)=2E_(a_1))`
or `k_1=k_2Ae^(E_(a1)//RT)`
Discussion
87837.

A reacation takes place in three steps with actiation energy E_(a_(1))=180 KJ/mol , E_(a_(2)) =80 KJ/mol , E_(a_(3))=50 KJ/mol respectively overall rate constant of the reaction is k=[(k_(1)k_(2))/(k_(3))]^(2//3) the overallactivation energy of reaction will be (Here k_(1),k_(2) a"and k_(3) are rate constant of first, second and third step respectively.):

Answer»

140 KJ/mol
150 KJ/mol
43.44 KJ/mol
100 KJ/mol

Answer :A
Discussion
87838.

(A) RCOCl,(RCO)_(2)O and RCOOR' all react with Grignard reagent to form 3^(@) alcohols. (R ) RCOCl reacts with R_(2)Cd to form ketones but (RCO)_(2)O and RCOOR' do not react at all.

Answer»

If both (A) and (R ) are correct and (R ) is correct EXPLANATION of (A ).
If both (A ) and (R ) are correct but (R ) is not correct explanation of (A ).
If (A) is correct but (R ) is incorrect
If (A) is incorrect but (R ) is correct.

ANSWER :B
Discussion
87839.

(A) RCOCL (RCO)_(2)O and R-overset(O)overset(||)C-OR' a react with Grignard reagent to form tertiary alcohol. (R) RCOCl reacts with dialkyl cadmium R_(2)Cd to form ketone but (RCO)_(2) O and RCOOR' do not react with dialkyl cadmium.

Answer»

If both (A) and ( R) are CORRECT and ( R) is the correct EXPLANATION of (A).
If both (A) and (R) are correct but (R) is not correct explanation of (A).
If (A) is correct but ( R) is INCORRECT.
If (A) is incorrect but ( R) is correct.

ANSWER :B
Discussion
87840.

A reactant (A) forms two products : A overset(k_(1))(rarr)BActivation Energy E_(a_(1)) A overset(k_(2))(rarr)CActivation Energy E_(a_(2)) If E_(a_(1)) then k_(1) and k_(2) are related as :

Answer»

`k_(2)=k_(1)E^(E_(a_(1))//RT)`
`k_(1)=k_(2)e^(E_(a_(1))//RT)`
`k_(1)=Ak_(2)e^(E_(a_(1))//RT)`
`k_(1)=2k_(2)e^(E_(a_(2))//RT)`

Solution :( C) `k_(1) =A_(1)e^(-E_(a1)//RT)`
`k_(2) = A_(2)e^(-E_(a2)//RT)`
`(k_(2))/(k_(2))=((A_(1))/(A_(2))) e^((-E_(a1)+E_(a_(2)))/(RT)`
Now `(A_(1))/(A_(2))` = CONSTANT and `E_(a2)= 2E_(a1)`
`(k_(1))/(k_(2))=Ae^(E_(a1)//RT)`
`K_(1)= Ak_(2)e^(E_(a1)//RT)`
Discussion
87841.

A reactant (A) forms two products A overset (k_(1))rarr B, Activation energy E_(a1) A overset (k_(2))rarr C, Activation energy E_(a2) If E_(a_(2)) = 2E_(a_(1)) then k_(1) and k_(2) are related as

Answer»

`k_(2)=k_(1)e^((-E_(a_(1)))/(RT))`
`k_(2)=k_(1)e^((E_(a_(2)))/(RT))`
`k_(1)=Ak_(2)e^((E_(a_(2)))/(RT))`
`k_(1)=2k_(2)e^((E_(a_(2)))/(RT))`

ANSWER :A
Discussion
87842.

A raw material used in making nylon is butadiene. True or False?

Answer»

SOLUTION :adipic ACID is a raw MATERIAL of nylon.
Discussion
87843.

A raw material used in making nylon is

Answer»

ADIPIC ACID
butadiene
ethylene
methyl methacrylate

Solution :adipic acid
Discussion
87844.

A raw material used in making nylon-6,6 is:

Answer»

ADIPIC acid
Butadiene
Ethylene
Methyl methacrylate

Answer :A
Discussion
87845.

A rawmaterial used in making nylon-66is

Answer»

ethylene
butadiene
adipic ACID
METHANOL

Answer :C
Discussion
87846.

A raw mango placed in concentrated salt solution loses water via____and shrivelsinto pickle.

Answer»

SOLUTION :OSMOSIS
Discussion
87847.

A ratherinteresting example of the Wolff rearrangement with 2-diazocyclohexanone in methanol is gives below. Identify the major product :

Answer»




SOLUTION :(a)
INTRAMOLECULAR Wolff REARRANGEMENT REACTION.
Discussion
87848.

A : Rate of reaction of alkyl halide in Williamson's synthesis reaction is 1^(@)R X gt 2^(@)R X gt 3^(@)R XR : If is a type of bimolecular sustitution reaction [SN^(2)]

Answer»

Assertion and REASON both are correct and reason is correct explanation of assertion.
Assertion and reason both are WRONG statements.
Assertion is correct but reason is wrong statement.
Assertion is wrong but reason is correct statement.

Solution :Williamson.s SYNTHESIS OCCURS by `SN^(2)` mechanism and primary alkyl halides are most reactive in `S_(N)2` reactions.
Discussion
87849.

(A) Rate of reaction increases with increase in temperature. (R ) Number of collisions increases with increase in temperature.

Answer»

Both (A) and (R ) are true and (R ) is the correct EXPLANATION of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is false
Both (A) and (R ) are false

Answer :B
Discussion
87850.

A: Rate of reaction increases with increasse in concentration of reactants. R: Number of effective collisions increases with increase in concentration of reactants.

Answer»

Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is false
Both (A) and (R ) are false

Answer :A
Discussion