InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 88251. |
(A) Number of moles of H_(2) in 0.224 L of H_(2) is 0.001 mol. (R) 22.4 litres of H_(2) at STP contains 6.023xx10^(23) mol. |
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Answer» If both (A) and (R) are CORRECT and (R) is the correct EXPLANATION of (A). |
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| 88252. |
A number of ionic compounds are insoluble in water. This is because |
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Answer» Ionic COMPOUNDS do not dissolve in water |
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| 88253. |
A number of factors such as temperature, concentration of reactants, ____________, affect the rate of reaction. |
| Answer» SOLUTION :CATALYST | |
| 88254. |
A number of elements are available in earth's crust but most abundant elements are |
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Answer» `AL and FE` |
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| 88255. |
A number ofelecments areavailablein earth'scrustbut mostabundantelementsare |
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Answer» AL ANDFE |
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| 88256. |
A number of elements are available in earth's crust but most abundant elements are………. |
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Answer» AL and Fe |
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| 88257. |
A number of elements are available in earth's crust but most abundant elements are : |
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Answer» Al and Fe |
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| 88258. |
A nuclide of an alkaline earth metal undergoes radioactive decay by emissio of the alpha-particles in succession. The group of the periodic table to which the resulting daughter element would belong is |
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Answer» `Gr.14` |
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| 88259. |
A nuclide has mass number (A) and atomic number (Z). During a radioactive process if: (A) both A and Z decrease, the process is called alpha-decay (B)A remains unchanged and Z decreases by one, the process is called beta^(+) or positron decay of K-electron capture (C ) both A and Z remain unchanged the process is called gamma-decay (D)both A and Z increase, the process is called nuclear isomerism. The correct answer is: |
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Answer» 1,2 and 3 |
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| 88260. |
A nucleotide consists of three parts : a phosphate unit, a sugar and a..............or ............... |
| Answer» SOLUTION :PURINE , PYRIMIDINE | |
| 88261. |
A nucleotide consist of …….. . |
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Answer» baseand SUGARE |
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| 88262. |
A nucleoside on hydrolysis gives |
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Answer» an aldopentose and a NITROGENOUS BASE |
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| 88263. |
A nucleophilic reagent would readily attack: |
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Answer» CARBONIUM ion |
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| 88264. |
A nucleophile is: |
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Answer» LEWIS ACID |
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| 88265. |
A nucleophile should possess_________. |
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Answer» an overall negative charge |
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| 88266. |
A nucleophile is a : |
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Answer» LEWIS ACID |
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| 88267. |
A nucleide of an alkaline earth metal undergoes radioactive decay by emission of three a-particles in succession. The group of the periodic table to which the resulting daughter element would belong is: |
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Answer» GROUP 4 |
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| 88268. |
A nuclear reaction is accompanied by loss of mass equivalent to 0.01864 amu. Energy liberated is: |
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Answer» 931 MEV `= 0.01864 xx 931 = 17.36 MeV` |
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| 88269. |
A nuclear reaction is accompanied by a loss of mass equivalent to 0.01864 amu. The energy liberated is |
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Answer» 17.34 MeV |
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| 88270. |
(A) Nuclear isomers have same atomic number and same mass number but with different radioactive properties. U_((A)) and U_((Z)) are nuclear isomers. |
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Answer» If both (A) and (R ) are CORRECT and (R ) is the correct EXPLANATION for (A). |
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| 88271. |
A non-volatile solute (A) is dissolved in a volatile solvent (B). The vapour pressure of the resultant solution is P_(s^(*)). The vapour pressure of pure solvent is P_(B)^(@). If X_(B) is the mole fraction of the solvent, which of the following is correct? |
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Answer» `P_(S)=P_(B)^(0).X_(A)` |
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| 88272. |
A non -volatile solute.'A' tetramerises in water to the extent of 80% .2.5 g of 'A' in 100 g of water .lower the freezing point by 0.3 ""^(@)C.The molar mass of Å in mol 4^(-1) is (K_(T)For water =1.86 K kg mol^(-1)) |
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Answer» 62 `:. ALPHA =(l=i) (n)/(n-1) alpha = 80%` (given) 0.8 = (l-i) `4/3 rArr i=0.4` `Delta T_(f) = iK_(f)m` `0.3=0.4xx1.86xx (2.5)/("Molar mass") xx (1000)/(100)` Molar mass `= (0.4xx1.86xx2.5xx10)/(0.3)` = 62 g/mol Note: Read mole `L^(-1)` as g `mol^(-1)` in question. |
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| 88273. |
A non-volatile hydrocarbon has 5.6% hydrogen. Determine the molecular formula of the non-volatile hydrocarbon (Molecular mass of benzene is 78 a.m.u.) |
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Answer» in hydrocarbon, H=5.6% , C=100-5.6= 94.4 %  Empirical formula of hydrocarbon `=C_(7)H_(5)` `"Empirical formula mass of hydrocarbon"=7xx12+5xx1=89" amu"=89 g` Step II. Calculation of molecular mass of the hydrocarbon. According to Raoult's law, `(P_(A)^(@)-P_(S))/(P_(A)^(@))=X_(B)=n_(B)/n_(A)` `(P_(A)^(@)-P_(S))/(P_(A)^(@))=1.306xx10^(-2),W_(B)=3g, W_(A)=100g, M_(A)=78" amu"=78" g mol"^(-1)` `1.306xx10^(-2)=(W_(B)//M_(B))/(W_(A)//M_(A))=((3g)//M_(B))/((100g)//(78" g mol"^(-1)))=(3xx78(g//mol^(-1)))/(100xx(M_(B)))` `M_(B)=(378(g//mol^(-1)))/(100xx(1.306xx10^(-2)))=179.17("GMOL"^(-1)).` Step III. Calculation of molecular formula of the hydrocarbon. `n=("Molecular mass of hydrocarbon")/("Empirical formula mass of hydrocarbon")=(179.17)/(89.0)~~2. `"Molecular formula"=nxx"Empirical formula"=2C_(7)H_(5)=C_(14)H_(10).` |
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| 88274. |
A non-reacting gaseous mixture contains SO_2 and SO_3 in the mass ratio of 1 : 5. Find the ratio of the number of molecules |
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Answer» ` 1 : 1` |
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| 88275. |
(A) Non-competitive inhibitors occupy allosteric site so that the substrate cannot attach at active site. (R) Non-competitive inhibitors change the shape of active site of enzyme after binding at allosteric site. |
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Answer» Both (A) and (R) are TRUE and (R) is the CORRECT EXPLANATION of (A) |
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| 88276. |
(A): Noble gases are springly soluble in water (R): Neon has high positive electron gain enthalpy. |
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Answer» Both (A) and (R) are true and (R) is the correct EXPLANATION of (A) |
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| 88277. |
(A) Noble gases have very high ionization enthalpies in periodic table (R) All noble gases have stable octet configuration in their valence shell |
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Answer» Both (A) and (R) are TRUE and (R) is the CORRECT EXPLANATION of (A) |
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| 88278. |
A noble gas has the property to diffuse through rubber. Name the noble gas. |
| Answer» SOLUTION :HELIUM has PROPERTY to DIFFUSE through RUBBER. | |
| 88279. |
A noble gas which is not adsorbed by coconut charcoal is |
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Answer» He |
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| 88280. |
(A): Noble gases are lower melting points and boiling points (R): Noble gases posses weak dispersion forces. |
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Answer» Both (A) and (R) are true and (R) is the CORRECT EXPLANATION of (A) |
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| 88281. |
(A) Noble gas elements have very low melting and boiling points(R) The interatomic attractions in noble gas elements are weak dispersion forces. |
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Answer» Both (A) and (R) are TRUE and (R) is the correct EXPLANATION of (A) |
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| 88282. |
(A): NO_(3)^(-) and CO_(3)^(-2) ions are isoelectronic. (R): Nitrate ion is planar |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) |
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| 88283. |
(a) NO_(2)^(-) interface in the Ring Test of NO_(3)^(-) Suggest a chemical method for removal of NO_(2)^(-).(b)I interface in the Ring of NO_(3)^(-). Suggested chemical reagent that can remove I |
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Answer» Solution :By bolling the mixture with `NH_(4)CL,NO_(2)^(-)` is decomposed as `N_(2)` `NaNO_(2)+NH_(4)OVERSET(Delta)toNaCl+N_(2)uarr+2H_(2)O` `HgCl_(2)`removes l as Hg`l_(2)` `Hgl_(2)toHgl_(2)darr+2Cl` |
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| 88284. |
(A): Nitrous oxide is called laughing gas. (R): Nitrous oxide is a linear molecule. |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) |
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| 88285. |
A nitrogen containing compound on heating with CHCl_3 and alcoholic KOH evolved an unpleasant smelling vapour. The compound could be |
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Answer» NITROBENZENE |
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| 88286. |
(A) Nitromethane can give aldol condensation. (R) alpha hydrogen of nitromethane is acidic. |
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Answer» If both (A) and (R) are CORRECT and (R) is the CORECT explanation of (A) |
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| 88287. |
A nitrogenous substance X is treated with HNO_(2) and the product so formed is further treated with NaOH solution, which produces blue colouration. Which of the following can X be ? |
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Answer» `CH_(3)CH_(2)NH_(2)` |
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| 88288. |
A nitrogenous subsatnce X is treated with HNO_2 and the product so formed is further treated with NaOH solution , which produces blue colouration X can be : |
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Answer» `CH_3CH_2NH_2` |
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| 88289. |
A nitrogenous substamnce (X ) is treated withHNO_2 and the product so formed is further treate withNaOH solution , which produces blue coloruation . Whichof the following can (X ) be ? |
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Answer» `CH_3CH_2NH_2`  .
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| 88290. |
A nitrogenouscompoundis treatedwithnitrousacidand the prodructsofromedinfurthertreatedwith NaOHsoluitonwhichproduces bluecolouration . The nitrogenouscompoudis |
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Answer» `CH_(3) - CH_(2) - CH_(2) - NH_(2)` |
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| 88291. |
A nitrogenous compound is treated with HNO_(2) and the product so formed is further treated with NaOH solutoin which produces blue colouration. The nitrogenous compound is: |
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Answer» `CH_(3)CH_(2)NH_(2)` |
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| 88292. |
(A): Nitrogen is unable to show a valency more than three. (R): Nitrogen does not have vacant d-orbitals in its valence shell. |
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Answer» Both (A) and (R ) are true and (R ) is the CORRECT explanation of (A) |
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| 88293. |
(A) :Nitrogen is a non metal where as Bismuth is a typical metal (R ) Oxides of Nitrogen are acidic where as Bi_(2)O_(3) is a basic oxide |
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Answer» Both (A) and (R ) are true and (R ) is the CORRECT EXPLANATION of (A) |
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| 88294. |
(A)Nitrogen is a gas, where as phosphorus is a solid (R ) Nitrogen can form (P-P) pi bonds in effective manner when compared to phosphorus |
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Answer» Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A) |
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| 88295. |
(A) : Nitrogen has higher ionization energy than that of oxygen. (R ) : Nitrogen atom has smaller atomic size than that of oxygen. |
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Answer» Both (A) and (R ) are true and (R ) is the CORRECT explanation of (A) |
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| 88296. |
a) Nitrogen dioxide (NO_(2)) dissociates into nitric oxide (NO) and oxygen (O_(2)) as follows: Write the rate of reaction in terms of (i) rate of disappearance of NO_(2) ii) rate of formation of NO and iii) rate of formation of O_(2). Equate the three rates of reaction. b) If the rate of decreases of concentration of NO_(2) is 6.0 xx 10^(-12) mol L^(-1)s^(-1), calculate the rate of increase of concentration of NO and O_(2) |
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Answer» B) Solved in the text PORTION |
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| 88297. |
A nitrogen containing organic compound gave an oily liquid on heating with bromine and potassium hydroxide solution. On shaking the product with acetic anhydride, an antipyretic drug was obtained. The reactions indicate that the starting compound is |
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Answer» ANILINE 
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| 88298. |
A nitrogen -containing aromatic compound A reacts with Sn/HCl, followed by HNO_(2) to give an unstable compound B. B on treatment with phenol, forms a beautiful coloured compound C with the molecular formula C_(12)H_(10)N_(2)O. The structure of compound A- |
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Answer»
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| 88299. |
A nitrogen containing compound dissolves in 10% aq. sulfuric acid. The Hinsberg test (C_(6)H_(5)SO_(2)Cl in base) gives a solid product that is not soluble in 10% aq. NaOH. Which of the following would best fit these facts? |
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Answer» N,N-Dimethylaniline, `C_(6)H_(5)N(CH_(3))_(2)`. |
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| 88300. |
(A): Nitrogen can form pentahalides (R): Nitrogen does not possess vacant d-orbitals in the valance shell |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) |
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