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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 88151. |
(A) PCl_(3) is non-polar, but PCl_(5) is polar (R ) PCl_(3) has unsymmetricalstructure, but PCl_(5) is symmetrical |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct explanation of (A) |
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| 88152. |
A patient was suffering from urinary infection. What is the prescribed antibiotic ? |
| Answer» SOLUTION :Chloramphenicol is the prescribed medicine to the PATIENT. It can be given ORALLY to the patient as a tablet. This is because of RAPID absorption by the GASTROINTESTINAL track. | |
| 88153. |
A particular water sample has 131 ppm CaSO_4 . What fraction of the water mustbe evaporated in a container before solid CaSO_4begins to deposit?K_(sp(CaSO_4) =9.0 xx 10^(-6) . |
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Answer» |
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| 88154. |
A particular saturated solution of silver chromate AgCrO_4 has [Ag^+]=5 times 10^-5 and [CrO_4]^(2-)=4.4 times 10^-4M. What is the value of K_(sp) for Ag_2CrO_4? |
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Answer» Solution :`Ag_2CrO_4(s) leftrightarrow 2AG^+(AQ)+CrO_4^(2-) (aq)` `K_(SP)=[Ag^+]^2 [CrO_4^(2-)]` `=(5 times 10^-5)^2 (4.4 times 10^-4)` `=1.1 times 10^-12` |
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| 88155. |
A particular reaction has a rate constant of 1.3xx10^(-2)s^(-1). Find out the ratio of (t_(1//2))/(t_(99.9)) |
| Answer» ANSWER :B | |
| 88156. |
A particular element belongs to group 13 and II period of the periodic table. It is |
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Answer» SOLID, LESS METALLIC |
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| 88157. |
A particle of suspension of radius 1 mm is broken to form colloidal particles of radius 1000 Å. How many times will be the total surface the colloidal particles as sompared to the surface area of the particle of suspension. |
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Answer» Solution :Volume of paticle of suspension of RADIUS 1 mmm `=4/3pi r^(3)=4/3pi (0.1)^(3)cm^(3)=4/3pi xx10^(-3)cm^(3)` Volume of particle of radius `1000Å (10^(-5)cm)=4/3pi (10^(-5))^(3)=4/3pixx10^(-15)cm^(3)` `therefore` NUMBER of colloidal particles formed `=((4//3)pi xx10^(-3))/((4//3)pi xx10^(-15))=10^(12)` Surface area of each colloidal particle `=4 pi r^(2)=4 pi (10^(-5))^(2) cm^(2)=4 pi xx10^(-10)cm^(2)` `therefore` Total surface area of `10^(12)` particles `=(4pi xx10^(-10))xx10^(12)= 4pi xx10^(2)cm^(2)` Surface area of particle of suspension `=4 pi r^(2)=4 pi (0.1)^(2)cm^(2)=4 pi xx10^(-2)cm^(2)` `therefore ("Total surface area of colloidal particles")/("Surface area of particle of suspension")=( 4pi xx10^(2))/(4 pi xx10^(-2))=10^(4)` |
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| 88158. |
A particle having the same charge and 200 times greater mass than that of electron is |
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Answer» Positron |
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| 88159. |
A particle adsorption process process has the following characteristics, (i) It arises due to va der waal's forces and (ii) it is reversible. Identify the correct statement that describes the above adsorption process: |
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Answer» Adsorption is monolayer Physical adsorption USUALLY takes place at low temperature and decrease with increase in temperature. The force of ATTRACTION holding the ADSORBATE are van der waal's forces. Heat of adsorption is low. It is reversible and forms multimolecular layer. It does not acquire any activated energy. |
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| 88160. |
A particle A moving with a certain velocity has a de Broglie wavelength of 1 A. If particle B has mass 25% of that A and velocity 75% of that of A, the de Broglie wavelength of B will be approximately |
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Answer» `1Å` `(lamda_(B))/(lamda_(A))=1/(0.25xx0.75)=5.3` `thereforelamda_(B)=5.3lamda_A=5.3Å` |
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| 88161. |
A partially dried clay mineral contaisn 8% water. The original the partially contained 12% water and 45% silica. The % of silica in the partially dried sample is nearly: |
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Answer» 0.5 Ratio of silica and clay will REMAIN CONSTANT, before and after drying. `therefore (45)/(43)=(x)/(92-x)` `x=47%`. |
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| 88162. |
A partially racemised (+2) 2-Bromooctane on reaction with aq. NaOH in acetone gives an alcolhol with 80% inversion and 20% racemisation . Find out the rate expression of the reaction. |
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Answer» RATE = `K_1[R-X][barOH]` |
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| 88163. |
A part of Ellingham diagram for some metal oxides (Based upon 1mole of O_2) and carbon is shown. In figure A,B,C and D represent curves for metal oxides and a,b,c,d ,e and f are temperatures. Answer the following : (i) Will B oxide reduce metal oxide of A or C or both ? (ii) Which metal can be reduced thermally ? (iii) Will oxide of B be reduced by coke above temperature c or below temperature c ? (iv) Will the formation of CO or CO_2 be preferred above temperature f ? (v) What does temperature 'a' represent ? |
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Answer» SOLUTION :(i) Metal OXIDE of C (ii) Metal oxide of B (iii) Above temperature c (iv) CO (v) The change in STATE (at FUSION or vaporisation) |
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| 88164. |
(A): Paracetamol is widely used as analgesic even it is an antipyretic. (R): It is administered to aspirin sensitive patients. |
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Answer» Both (A) and (R) are true and (R) is the CORRECT EXPLANATION of (A) |
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| 88165. |
A pale yellow inorganic compound K is insoluble in hot and dil. HNO_(3) but dissolves in concentrated ammonia solution and compound L is formed, on treatment with dil. HNO_(3) compound L produces a metal cation which gives white precipitate M with hypo solution. when an aqueous solution of (M) is boiled, a black precipitate of (N) is formd which dissolves in hot dil. HNO_(3) and on adding HCl gives a white precipitate. when the compound (K) is heated with concentrated H_(2)SO_(4) and MnO_(2) brown fumes are observed. Q. Compound (M) and black precipitate of (N) are respectively: |
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Answer» `PbI_(2),PbS` |
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| 88166. |
A pale yellow inorganic compound K is insoluble in hot and dil. HNO_(3) but dissolves in concentrated ammonia solution and compound L is formed, on treatment with dil. HNO_(3) compound L produces a metal cation which gives white precipitate M with hypo solution. when an aqueous solution of (M) is boiled, a black precipitate of (N) is formd which dissolves in hot dil. HNO_(3) and on adding HCl gives a white precipitate. when the compound (K) is heated with concentrated H_(2)SO_(4) and MnO_(2) brown fumes are observed. Q. The compound (K) is: |
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Answer» AgI |
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| 88167. |
A pale yellow crystalline solid insoluble in water but soluble in CS_(2) is allowed to react with nitric oxide to give X and Y.X is a colourless gas with pungent odour. X is further allowed to react in aqueous medium with nitric oxide to yield Z and T. Compounds X,Z and T are- |
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Answer» `SO_(3),H_(2)SO_(3)` |
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| 88168. |
A pale yellow inorganic compound K is insoluble in hot and dil. HNO_(3) but dissolves in concentrated ammonia solution and compound L is formed, on treatment with dil. HNO_(3) compound L produces a metal cation which gives white precipitate M with hypo solution. when an aqueous solution of (M) is boiled, a black precipitate of (N) is formd which dissolves in hot dil. HNO_(3) and on adding HCl gives a white precipitate. when the compound (K) is heated with concentrated H_(2)SO_(4) and MnO_(2) brown fumes are observed. Q. Compound (K) on heating with conc. H_(2)SO_(4) and MnO_(2) gives: |
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Answer» `I_(3)^(-)`<BR>`Br_(2)` 
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| 88169. |
A pale green crystalline inorganic salt (A) dissolves freely in water. It gives a brown precipitate on addition of aqueous NaOH. The solution of (A) also gives a black precipitate on bubbling H_(2)S in alkaline medium. An aqueous solution of (A) decolourises the pink colour of the permanganate solution. The metal in the salt solution is : |
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Answer» Copper |
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| 88170. |
A pair of stereoisomers might be classified in various ways. Which of the followign statement are true with respect to pairs of stereoisomers ? (a) They might be configurational isomers (b) They might be diastereomers (c ) They might be configurational isomers (d) They might be tautomers (e) They might be conformationasl isomer they might be enantiomers (g) they might be positionatal isomers |
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Answer» a,B,c,e |
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| 88171. |
A packing of 8:8 co-ordination crystal is present in which of the following compounds? |
| Answer» ANSWER :C | |
| 88172. |
A pair of diastereomers that differ only in the configuration about a single carbon atom are called |
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Answer» Anomers |
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| 88173. |
Explain the formation of [Co(NH_3)_6] Cl_3 and [Cu(NH_3)_4] SO_4 on the basis of VBT. |
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Answer» IONISATION ISOMERS |
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| 88174. |
A p-type semiconductor is developed by ......... |
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Answer» Increase in TEMPERATURE. |
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| 88175. |
(A) Packing efficiency of hep and CCP are not equal (R) hep, ccp both have ABC ABC type packing |
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Answer» Both (A) and (R) are TRUE and (R) is the CORRECT EXPLANATION of (A) |
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| 88176. |
(A) P_(4)O_(10) is more acidic than N_(2)O_(5) (R ) P_(4)O_(10) is soluble in water where as N_(2)O_(5) is not |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct explanation of (A) |
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| 88177. |
(A) : P_(4) is more reactive than N_(2). (R ) : P-P bonds are relatively weaker than N-=N |
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Answer» Both (A) and (R ) are true and (R ) is the CORRECT EXPLANATION of (A) |
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| 88178. |
A p-type material is electrically |
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Answer» positive |
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| 88179. |
(A): p-Nitrochlorobenzene is more reactive than chlorobenzene in nucleophilic substitution reactions.(R): Electron withdrawing groups like -NO_2, increase the reactivity of haloarenes in nucleophilic substitution. |
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Answer» Both A & R are TRUE, R is the correct EXPLANATION of A |
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| 88180. |
(A) :P-Methoxy benzaldehyde is less reactive than benzaldehyde towers cyanohydrin formation . (R) : +R -effect of the methoxy group increases the electron deficiency of the carbonyl carbon . |
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Answer» Both A & R are TRUE, R is the CORRECT explanation of A |
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| 88181. |
(A) p-chlorobenzoic acid is stronger acid than benzoic acid. (R) Chlorine has electron donating resonance (+R) effect. |
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Answer» Both (A) and (R) are true and (R) is the correct explanation of (A) |
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| 88182. |
(A) Ozone is thermodynamically unstable than oxygen. (R ) Decomosition of ozone into oxygen results in the liberation of heat and an increase in entropy. |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) |
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| 88183. |
(A): Ozone is an allotrope of oxygen. (R): Ozone is better oxidising agent as compared with oxygen. |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) |
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| 88184. |
(A) Ozone is used for bleaching oils, ivory, flour, starch ect. (R ) O _(3) to O _(2) + (O) |
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Answer» Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A) |
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| 88185. |
(A) Ozone is a linear molecule. (R ) In a molecule of ozone, the central oxygen atom is attached with two more oxygen atoms. |
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Answer» Both (A) and (R ) are true and (R ) is the correct EXPLANATION of (A) |
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| 88186. |
(A): Ozone can be used qualitatively to distinguish unsaturated hydrocarbons from saturated (R): Ozonides are formed with unsaturated hydrocarbons |
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Answer» Both (A) and (R ) are true and (R ) is the CORRECT EXPLANATION of (A) |
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| 88187. |
A + Oxygen to underset("Brown paramagnetic")B |
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Answer» `A to NO, B to NO_(2), C to N_(2)O_(4)` |
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| 88188. |
(A) Oxygen is most abundant in earth's atmosphere (R ) Oxygen is the stablest ga present in the air |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) |
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| 88189. |
(A): Oxygen has highest tendency, among chalcogens, to form dinegative ion (R): Electron affinity of oxygen is highest among chacogens |
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Answer» Both (A) and (R ) are true and (R ) is the CORRECT EXPLANATION of (A) |
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| 88190. |
(A) Oxygen is least electron affinity element in 16 ^(th) group (R ) Oxygen does not contain vacant dorbitals. |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct explanation of (A) |
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| 88191. |
(A): Oxygen exhibits positive oxidation states in some of its compounds (R): In binary fluorides, fluorine is always more electronegative |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) |
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| 88192. |
(A) Oxygen does not exhibit oxidation number more than +2 n its compounds. (R ) Oxygen is the highest electronegative element in 16^(th) group. |
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Answer» Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A) |
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| 88193. |
(A) Oxygen belongs to group 16 of the long form of the periodic table (R ) Oxygen has relative atomic mass 16U |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) |
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| 88194. |
(A) Oxidation of toluene & ethyl benzene with acidified KMnO_4 gives benzoic acid & phenyl acetic acid respectively. (R) The oxidation product of alkyl benzene depends on the length of primary alkyl group. S |
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Answer» Both (A) and (R) are true and (R) is the correct explanation of (A) |
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| 88195. |
(A): Oxidation of tertiary alcohols requires strong oxidising agent and elevated temperature. (R): Oxidation of tertiary alcohols involves cleavage of C - C bond. |
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Answer» Both A & Rare true, R is the correct EXPLANATION of A |
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| 88196. |
Anhydroys CrO_(3) is a mild oxidant and it can oxidise |
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Answer» Both (A) and (R) are TRUE and (R) is the correct explanation of (A) |
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| 88197. |
(A): OX^(-) on heating in the presence of OH^(-) gives X^(-) and XO_(3)^(-) (R): Conversion of OX^(-) to X^(-) and XO_(3)^(-), is called disproportionation. |
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Answer» Both A & R are true, R is the correct explanation of A |
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| 88198. |
A) overset("Reduction")underset([H])to Primary amine. The compound A) may be |
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Answer» Alkyl isocyanide |
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| 88199. |
A-overset("Reduction")toBoverset(CHCl_(3)//KOH)toCoverset("Reduction")to |
| Answer» ANSWER :2 | |
| 88200. |
A overset("Reduction")to 1^(0)-amine The compound A may be (1)R-NC (2) R - CN (3) R - CONH_(2) (4)R - NO_(2) |
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Answer» 1,2 |
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