94420 + Interview Questions in Chemistry in Class 12 Page 1763 InterviewSolution

88101.	(A) Physisorption is not specific. (R ) Physisorption involves Vanderwaal's forces only between the adsorbent and adsobate, which are non-specific
Answer» Both (A) and (R ) are TRUE and (R ) is the CORRECT explanation of (A) Both (A)and (R ) are true and (R ) is not the correct explanation of (A) (A) is true but (R ) is FALSE Both (A) and (R ) are false ANSWER :A

Discussion

88102.	A physical was performing experiments to study the velociyt and wavelength of the electron. In one case, the electron was accelerated through a potential differences of 1 KV and in second case it was accelerated through a potential difference of 2KV. The value associated with electron n will be
Answer» DOUBLE in the SECOND CASE than in the FIRST case. Double in the first case than in second case 1.4 TIMES in the second case than in the first case 1.4 times in the first case than in the second case. Answer :D

Discussion

88103.	A physician wishes to prepare a buffer solution at pH = 3.58 that efficiently resists changes in pH yet contains only small concentration of the buffering agents. Which of the following weak acids together with its sodium salt would be best to use
Answer» m - chlorobenzoic acid `(pK_(a) = 3.98)` p - chlorocinnamic acid `(pK_(a) = 4.41)` 2, 5-dihydroxy benzoic acid `(pK_(a) = 2.97)` Acetoacetic acid `(pK_(a) = 3.58)` Solution :`pH = pK_(a) + log.(["SALT"])/(["Acid"])`. For HIGHEST buffer CAPACITY `(["Salt"])/(["Acid"]) ~~ 1` `pH = pK_(a) + log_(10)1` `pH = pK_(a)` So, `pK_(a)` should be 3.58.

Discussion

88104.	A physical was performing experiments to study the velociyt and wavelength of the electron. In one case, the electron was accelerated through a potential differences of 1 KV and in second case it was accelerated through a potential difference of 2KV. The velocity acquired by the electron will be
Answer» DOUBLE in the SECOND CASE than in the FIRST case. Four TIMES in the second case than in the first case. Same in both cases. 1.4 times in the second case than in the first case. Answer :D

Discussion

88105.	A physical was performing experiments to study the velociyt and wavelength of the electron. In one case, the electron was accelerated through a potential differences of 1 KV and in second case it was accelerated through a potential difference of 2KV. In order to have half the velocity in the second case than in the first case, the potential applied should be
Answer» 0.5 KV 2 KV 0.25 KV 0.75 KV Answer :C

Discussion

88106.	(A): Physical adsorption and chemical adsorption are distinguished by adsorption isobars (R): Physical adsorption is weak while chemical adsorption is strong
Answer» Both (A) and (R) are true and (R) is the CORRECT EXPLANATION of (A) Both (A) and (R) are true and (R) is not the correct explanation of (A) (A) is true but (R) is false (A) is false but (R) is true Answer :B

Discussion

88107.	A: Phthalimide is less basic than acetamide. R: Acetamide is more basic than ethyl amine.
Answer» If both Assertion & REASON are true and the reason is the correct explanation of the assertion, then MARK (1). If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2) If Assertion is true statement but Reason is false, then mark (3) If both Assertion and Reason are false statements, then mark (4) ANSWER :3

Discussion

88108.	(a) Phthaldeydeoverset(Conc.NaOH)(to) Product (to) Cannizzaro reaction (b) alpha - Methylacylohexanone underset(Delta)overset(NaOH)(to) Product (to) Aldol condensation ( c) Toluene underset(H_(3)O^(+))overset(CrO_(2)Cl_(2)//CS_(2))(to) Product (to) Etard reaction (d)Benzene +CO+HCloverset(AlCl_(3))(to) Product to Gattermann's Koch reaction (e) Benezene +HCN+HCloverset(AlCl_(3))(to) Product to Gattermann's aldehyde synthesisWhich of the following is correct set :
Answer» a,b,C,d a,b,d,E, a,b,c,e a,b,c,d,e Answer :D

Discussion

88109.	A photon of radiationof wavelength 600 nm has an energy E. The wavelength of photon of radiation having energy 0.25 E is
Answer» 600 NM 2400 nm 150 nm 300 nm Solution :`(E_(1))/(E_(2))=(lamda_(2))/(lamda_(1))impliesE/0.25E=(lamda_(2))/600` `:.lamda_(2)=600/0.25=(lamda_(2))/600` `:.lamda_(2)=600/0.25=2400 nm`

Discussion

88110.	A photon of radiation of wavelength 4000 Å has an energy E. The wavelength of photon of radiation having energy 0.5 E will be
Answer» 2000 Å 8000 Å 4000 Å 6000 Å Solution :`E=hv=hc/(lamda),(E_(1))/(E_(2))=(lamda_(2))/(lamda_(1)),E/(0.5E)=(lamda_(2))/4000` or `lamda_(2)=8000Å`

Discussion

88111.	A photon of hard gamma radiation knocks a proton out of ._(12)^(24)Mg nucleus to form
Answer» The isotope of parent nucleus The isobar of parent nucleus The NUCLIDE `._(11)^(230Na` The isobar of `._(11)^(23)Na` Solution :`._(12)^(24)Mg + gamma rarr ._(11)^(23) Na + ._(1)^(1)H`

Discussion

88112.	A photon of hard gamma radiation knocks a. proton out of ""_(12)^(24)Mg nucleus to form :
Answer» the ISOTOPE of PARENT NUCLEUS the isobar of parent nucleus the nucleide `""_(11)^(23)Na` the isobar of `""_(11)^(23)Na` Solution :`""_(12)^(24)Mg+gammato_(11)^(234)Na+_(1)^(1)P`

Discussion

88113.	A photochemical reaction between H_(2(g)) and Cl_(2(g)) is a zero order reaction. Explain.
Answer» Solution :Consider PHOTOCHEMICAL reaction between `H_(2)` and `Cl_(2)` gases. `H_(2(g))+Cl_(2(g))("Diffused")/("Sunlight")2HCl_((g))` In this the rate of the reaction remains constant throughout the progress of the reaction, even if the concentration of the reactants decreases with time, until the reactant has reacted entirely. Hence, by the rate LAW, `R=k[H_(2)]^(0)[Cl_(2)]^(0)=k"(constant)"`. Hence the above reaction is a zero order reaction.

Discussion

88114.	A phosphorus oxide has 43.6% phosphorus(at. mass=31). The empirical formula of the compound is :
Answer» `P_2O_5` `P_2O_3` `P_4O_6` `PO_2` SOLUTION : FORMULA `P_2O_5`

Discussion

88115.	(A): Phosphorus is more reactive element of Group VA (R): N-=N bond is relatively stronger.
Answer» Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A) Both (A) and (R ) are true and (R ) is not the correct explanation of (A) (A) is true but (R ) is false Both (A) and (R ) are false Answer :2

Discussion

88116.	A phenomenon in which a substance is retained partly at the surface and partly enters the bulk is called
Answer» ABSORPTION SORPTION adsorption desorption Solution :sorption

Discussion

88117.	(A): Phenols react with sodium hydroxide but not alcohols. (R) : Phenols are more acidic than alcohols.
Answer» Both A & R are true, R is the correct EXPLANATION of A Both A & R are true, R is not correct explanation of A A is true, R is false A is false, R is true Answer :A

Discussion

88118.	(A) : Phenols are more acidic than alcohols. (R): Phenoxide ion is more stable than alkoxide ion due to resonance.
Answer» Both A & R are TRUE, R is the CORRECT explanation of A Both A & R are true, R is not correct explanation of A A is true, R is false A is false, R is true Answer :A

Discussion

88119.	(A) Phenols are acidic & react with alkalies like NaOH but do not react with Na_2CO_3and NaHCO_3solutions(R) CO_3^(-2) &HCO_3^-ions are less basic than phenoxide ion
Answer» Both (A) and (R) are TRUE and (R) is the CORRECT explanation of (A) Both (A) and (R) are true and (R) is not the correct explanation of (A) (A) is true but (R) is FALSE Both (A) and (R) are false Answer :A

Discussion

88120.	(A) Phenol undergoes Kolbe's reaction but not ethanol.(R) Phenoxide ion is a weaker base than ethoxide ion.
Answer» Both (A) and (R) are TRUE and (R) is the correct explanation of (A) Both (A) and (R) are true and (R) is not the correct explanation of (A) (A) is true but (R) is FALSE Both (A) and (R) are false Answer :B

Discussion

88121.	(A) Phenol and benzoic acid are distinguished with NaHCO_3solution(R) Benzoic acid is more basic than phenol
Answer» Both (A) and (R) are TRUE and (R) is the correct explanation of (A) Both (A) and (R) are true and (R) is not the correct explanation of (A) (A) is true but (R) is FALSE Both (A) and (R) are false Answer :C

Discussion

88122.	A: Phenol is more reactive than benzene towards electrophilic substitution reaction. R: In the case of phenol, the intermediate carbocation is more resonance stabilised.
Answer» a b c d Solution : -OH GROUP shows +M effect and is an activating group, MOREOVER the arenium ion of phenolic SUBSTITUTION is more stable.

Discussion

88123.	(A) Phenetole on cleavage with HI gives phenol & ethyl iodide(R) Phenetole is a mixed aromatic ether
Answer» Both (A) and (R) are true and (R) is the correct explanation of (A) Both (A) and (R) are true and (R) is not the correct explanation of (A) (A) is true but (R) is false Both (A) and (R) are false Answer :B

Discussion

88124.	(A) PH_(3) has the lowest boiling point among the VA group hydrides (R ) PH_(3) explodes in presence of oxidising agent like HNO_(3)
Answer» Both (A) and (R ) are true and (R ) is the CORRECT EXPLANATION of (A) Both (A) and (R ) are true and (R ) is not the correct explanation of (A) (A) is true but (R ) is FALSE Both (A) and (R ) are false ANSWER :2

Discussion

88125.	A petroleum fraction havingboilingrange 70-200^(@)C andcontaining 6-10 carbonatomsper moleculeis called :
Answer» narural GAS gas oil gasoline Kerosene Answer :C

Discussion

88126.	(A) PF_(3) behaves as a Lewis acid (R ) PF_(3) has a pyramidal shape
Answer» Both (A) and (R ) are TRUE and (R ) is the CORRECT explanation of (A) Both (A) and (R ) are true and (R ) is not the correct explanation of (A) (A) is true but (R ) is FALSE Both (A) and (R ) are false Answer :2

Discussion

88127.	A petroleum fraction having boiling range 70-200^@ C and containing 6-10 carbon atoms per molecule is called
Answer» NATURAL gas Gas oil Gasoline kerosene Answer :C

Discussion

88128.	A person requires 2870 kcal of energy to lead normal daily life. If heat of combustion of cane sugar is - 1349 kcal, then his daily consumption of sugar is:
Answer» 728 g 0.728 g 342 g 0.342 g Answer :A

Discussion

88129.	A person requires 2870 kcal of energy to lead normal daily life. If heat of combustion of cane sugar is -1349 kcal//"mol"^(-1), then his daily consumption of sugar is
Answer» 728 G `0.728 g` 342 g `0.342` g ANSWER :A

Discussion

88130.	A person is declared as a diabetic if his/her blood sugar/blood glucose level exceeds 160 mg/dL when tested 2 hours after meals. In some countries, it is reported in the units of m molL^(-1). If a person has blood sugar of 10 m mol L^(-1), is he/she diabetic or not? Explain.
Answer» Answer :Molar mass of glucose `(C_(6)H_(12)O_(6))=180G mol^(-1),i.e., 1 mol=180g` `THEREFORE"1 mmol = 180 mgor1 mmol L"^(-1)=18 ,g//dL` `therefore"10 mmol L"^(-1)=10xx18mg//dL=180mg//dL` Hence, he/she is DIABETIC.

Discussion

88131.	A person living in Shimla observed that cooker takes more time. The reason for this observation is that at high altitude :
Answer» pressure INCREASES TEMPERATURE increases pressure decreases temperature increases Solution :At high ALTITUDES, pressure is low. Hence, boiling TAKES place at lower temperature and therefore, cooking takes more TIME. In pressure cooker, pressure is high and hence boiling point increases.

Discussion

88132.	A person is considered to be suffering from lead poisoning if its concentration in him is more than 15 micrograms of lead per decilitre of blood. Concentration in parts per billion parts is
Answer» 1 0 100 1000 Solution :`10 mu g = 10xx10^(-6)g=10^(-5)g` `"1 decilitre "=0.1 L=100mL` Thus, 100 mL of blood CONTAIN LEAD `=10^(-5)g` `therefore"1 billion "(10^(9))" parts will contain lead"` `=(10^(-5))/(100)xx10^(9)=10^(2)="100 parts"` i.e., concentration = 100 parts per billion parts

Discussion

88133.	A person inhales 640 g of O_(2) per day. If all the O_(2) is used for converting sugar into CO_(2) and H_(2)O , how much sucrose (C_(12)H_(22)O_(11)) is consumed in the body in one day and what is the heat evolved ? DeltaH ( combustion of sucrose) =-5645 " kJ mole"^(-1).
Answer» Solution :MOLES of `O_(2)` inhaled by a person in one day `=(640)/(32)=20` Given that, `C_(12)H_(22)O_(11)+12O_(2) to 12CO_(2)+11H_(2)O,DeltaH=-5645"KJ"` Thus, 12 moles of `O_(2)` consume 1 mole of sucrose or 12 moles of `O_(2)` consume 342 g of sucrose `:. 20` "mole" of `O_(2)` consume `(342)/(12)xx20,i.e., 570g` of sucrose Further, 342g (1 "mole") of sucrose LIBERATES 5645 kJ `:. 570 g` of sucrose should liberate`(5645)/(342)xx570=9408.34"kJ"`.

Discussion

88134.	A person having osteoporosis is suffering from lead poisoning. Ethylene diamine tetraacetic acid (EDTA) is administered for this condition. The best form of EDTA to be used for such administration is:
Answer» EDTA tetrasodium salt disodium salt calcium DIHYDROGEN salt Solution :EDTA should be USED in alkaline medium tetrasodium salt should be used to bind with `Ca^(2+)` .

Discussion

88135.	A person having osteoporosis is suffering from lead poisoning. Ethlene diamine tetra acetic acid(EDTA) is administered for this condition. The best form of EDTA to be used for such administration is -
Answer» EDTA tetrasodium SALT disodium salt calcium DIHYDROGEN salt ANSWER :D

Discussion

88136.	A person has as many notes as number of oxygen atoms in 24.8 g Na_(2)S_(2)O_(3).5H_(2)O (mol. Wt. = 248). A note counting machine counts 48 million notes per day. How many days it would take to count thesenotes?
Answer» `10^(12)` `10^(14)` `10^(16)` `10^(18)` Solution :`24.8g" of" Na_(2)S_(2)O_(3).5H_(2)O=(24.8)/(248)"mole"=0.1 "mole"` `"1 mole of "Na_(2)S_(2)O_(3).5H_(2)O" contains O-atoms = 8 MOLES"` `THEREFORE"0.1 mole of "Na_(2)S_(2)O_(3).5H_(2)O" will contain O-atoms = 0.8 atom"` `=0.8xx6.02xx10^(23)` atoms `=4.816 xx10^(23)` atoms Thus, no. of MASS `=4.816xx10^(23)` `"Days TAKEN"=(4.816xx10^(23))/(48xx10^(6))=10^(16)`.

Discussion

88137.	A person adds 1*71 gram of sugar (C_(12)H_(22)O_(11)) in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar - 342)
Answer» `36xx10^(22)` `72XX10^(21)` `005` `66xx10^(22)` SOLUTION :Moles of sugar added `= (171)/(342) = 5xx10^(-3)` CARBON atoms added `=12xx5xx10^(-3)xx602xx10^(23)` `= 3.61xx10^(22)`

Discussion

88138.	A person accidentally swallow a drop of liquid oxygen, O_(2)(l) which as density 1.2 gm/ml. Assuming drop has volume 0.05 ml. What volume of gas will be produced in person's stomach at a body temperature (27^(@)C) and pressure 1 atm. [Take R=0.08 atm-lit K^(-1) "mol"^(-1)]]
Answer» 40ml 30ml 50ml 45ml Solution :`d=(m)/(V)rArrm_(O_(2)(L))=1.2xx0.005=0.060gm` `n_(O_(2))=(0.06)/(32)` `n_(O_(2))=(NRT)/(P)=(6xx0.08)/(32xx100)xx300` V=45ml

Discussion

88139.	A peroxidase enzyme isolated from human red blood cells was found to contain 0.29% selenium. What is the minimum molecular weight of the enzyme? (Se = 78.96)
Answer» SOLUTION :`2.7 XX 10^4`

Discussion

88140.	(A) Perhalate ions are tetrahedral in shape (R ) Halogens underdo sp^(3) hybridization in perhalates
Answer» Both (A) and (R ) are TRUE and (R ) is the correct explanation of (A) Both (A) and (R ) are true and (R ) is not the correct explanation of (A) (A) is true but (R ) is FALSE Both (A) and (R ) are false Answer :A

Discussion

88141.	A perfectly semipermeable membrane when used to separate a solution from its solvent permits through it the passage of :
Answer» SOLUTE only SOLVENT only BOTH (A) AND (B) None Answer :B

Discussion

88142.	A perfectiges of a given mass is heated first in a small vessel and then in a large vessel, The P-T curves are :
Answer» PARABOLIC with same curvature Parabolic with DIFFERENT curvature Linear with same slope Linear with different slope Answer :D

Discussion

88143.	(A) Peracetic acid is a weaker acid than acetic acid. (R) Acetate ion is stabilized by resonance but peracetate ion is not.
Answer» Both (A) and (R) are TRUE and (R) is the correct EXPLANATION of (A) Both (A) and (R) are true and (R) is not the correct explanation of (A) (A) is true but (R) is false Both (A) and (R) are false Answer :A

Discussion

88144.	A peptide hormone is :
Answer» ESTRONE TESTOSTERONE Insulin Corticoid. Answer :C

Discussion

88145.	A peptide bond is formed between two amino acids by
Answer» a CONDENSATION REACTION FORMING an anhydride. a condensation reaction forming an ester. a condensation reaction forming an amine. a condensation reaction forming an amide. Answer :D

Discussion

88146.	A peptide bond joins two amino acids together. What atoms are linked by this bond in chain ?
Answer» C-0 C-H C-N N-S Answer :C

Discussion

88147.	A peeled egg swells when dipped in water while shrinks in saturated brine solution. Why?
Answer» Solution :Egg in water will swell while egg in MaCl solution will shrink. This is because as a RESULT of osmosis, the net FLOW of solvent is from LESS CONCENTRATED to more concentrated solution.

Discussion

88148.	A+PCl_5 to B B underset("ether")overset("Na")to n-butane. A and B are __________.
Answer» `CH_3OH,CH_3ONa` `C_2H_5OH,C_2H_5Cl` `C_2H_5OH,C_2H_5ONa` `CH_3OH,CH_3Cl` ANSWER :B

Discussion

88149.	(A) PCl_(5) is more covalent than PCl_(3) (R ) Polarising power of P^(5+) is greater than that of P^(3+)
Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) Both (A) and (R ) are true and (R ) is not the correct explanation of (A) (A) is true but (R ) is FALSE Both (A) and (R ) are false ANSWER :1

Discussion

88150.	A : PCl_5 is covalent in gaseous and liquid states but ionic in solid state. R: PCl_5 in solid state consists of tetrahedral PCl_(4)^(+)cation and octahedral PCl_(6)anion.
Answer» <P>a b c d Solution :`PCl_5` is trigonal bipyramidal containing `sp_3d` hybridized P atom in liquid and gaseous states WHEREAS in solid state it consists of tetrahedral `PCL^(4+)` cation and octahedral `PCl^(6-)`anion.

Discussion

Explore topic-wise InterviewSolutions in .

(A) Physisorption is not specific. (R ) Physisorption involves Vanderwaal's forces only between the adsorbent and adsobate, which are non-specific

A physical was performing experiments to study the velociyt and wavelength of the electron. In one case, the electron was accelerated through a potential differences of 1 KV and in second case it was accelerated through a potential difference of 2KV. The value associated with electron n will be

A physician wishes to prepare a buffer solution at pH = 3.58 that efficiently resists changes in pH yet contains only small concentration of the buffering agents. Which of the following weak acids together with its sodium salt would be best to use

A physical was performing experiments to study the velociyt and wavelength of the electron. In one case, the electron was accelerated through a potential differences of 1 KV and in second case it was accelerated through a potential difference of 2KV. The velocity acquired by the electron will be

(A): Physical adsorption and chemical adsorption are distinguished by adsorption isobars (R): Physical adsorption is weak while chemical adsorption is strong

A: Phthalimide is less basic than acetamide. R: Acetamide is more basic than ethyl amine.

A photon of radiationof wavelength 600 nm has an energy E. The wavelength of photon of radiation having energy 0.25 E is

A photon of radiation of wavelength 4000 Å has an energy E. The wavelength of photon of radiation having energy 0.5 E will be

A photon of hard gamma radiation knocks a proton out of ._(12)^(24)Mg nucleus to form

A photon of hard gamma radiation knocks a. proton out of ""_(12)^(24)Mg nucleus to form :

A photochemical reaction between H_(2(g)) and Cl_(2(g)) is a zero order reaction. Explain.

A phosphorus oxide has 43.6% phosphorus(at. mass=31). The empirical formula of the compound is :

(A): Phosphorus is more reactive element of Group VA (R): N-=N bond is relatively stronger.

A phenomenon in which a substance is retained partly at the surface and partly enters the bulk is called

(A): Phenols react with sodium hydroxide but not alcohols. (R) : Phenols are more acidic than alcohols.

(A) : Phenols are more acidic than alcohols. (R): Phenoxide ion is more stable than alkoxide ion due to resonance.

(A) Phenols are acidic & react with alkalies like NaOH but do not react with Na_2CO_3and NaHCO_3solutions(R) CO_3^(-2) &HCO_3^-ions are less basic than phenoxide ion

(A) Phenol undergoes Kolbe's reaction but not ethanol.(R) Phenoxide ion is a weaker base than ethoxide ion.

(A) Phenol and benzoic acid are distinguished with NaHCO_3solution(R) Benzoic acid is more basic than phenol

A: Phenol is more reactive than benzene towards electrophilic substitution reaction. R: In the case of phenol, the intermediate carbocation is more resonance stabilised.

(A) Phenetole on cleavage with HI gives phenol & ethyl iodide(R) Phenetole is a mixed aromatic ether

(A) PH_(3) has the lowest boiling point among the VA group hydrides (R ) PH_(3) explodes in presence of oxidising agent like HNO_(3)

A petroleum fraction havingboilingrange 70-200^(@)C andcontaining 6-10 carbonatomsper moleculeis called :

(A) PF_(3) behaves as a Lewis acid (R ) PF_(3) has a pyramidal shape

A petroleum fraction having boiling range 70-200^@ C and containing 6-10 carbon atoms per molecule is called

A person requires 2870 kcal of energy to lead normal daily life. If heat of combustion of cane sugar is - 1349 kcal, then his daily consumption of sugar is:

A person requires 2870 kcal of energy to lead normal daily life. If heat of combustion of cane sugar is -1349 kcal//"mol"^(-1), then his daily consumption of sugar is

A person is declared as a diabetic if his/her blood sugar/blood glucose level exceeds 160 mg/dL when tested 2 hours after meals. In some countries, it is reported in the units of m molL^(-1). If a person has blood sugar of 10 m mol L^(-1), is he/she diabetic or not? Explain.

A person living in Shimla observed that cooker takes more time. The reason for this observation is that at high altitude :

A person is considered to be suffering from lead poisoning if its concentration in him is more than 15 micrograms of lead per decilitre of blood. Concentration in parts per billion parts is

A person inhales 640 g of O_(2) per day. If all the O_(2) is used for converting sugar into CO_(2) and H_(2)O , how much sucrose (C_(12)H_(22)O_(11)) is consumed in the body in one day and what is the heat evolved ? DeltaH ( combustion of sucrose) =-5645 " kJ mole"^(-1).

A person having osteoporosis is suffering from lead poisoning. Ethylene diamine tetraacetic acid (EDTA) is administered for this condition. The best form of EDTA to be used for such administration is:

A person having osteoporosis is suffering from lead poisoning. Ethlene diamine tetra acetic acid(EDTA) is administered for this condition. The best form of EDTA to be used for such administration is -

A person has as many notes as number of oxygen atoms in 24.8 g Na_(2)S_(2)O_(3).5H_(2)O (mol. Wt. = 248). A note counting machine counts 48 million notes per day. How many days it would take to count thesenotes?

A person adds 1*71 gram of sugar (C_(12)H_(22)O_(11)) in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar - 342)

A person accidentally swallow a drop of liquid oxygen, O_(2)(l) which as density 1.2 gm/ml. Assuming drop has volume 0.05 ml. What volume of gas will be produced in person's stomach at a body temperature (27^(@)C) and pressure 1 atm. [Take R=0.08 atm-lit K^(-1) "mol"^(-1)]]

A peroxidase enzyme isolated from human red blood cells was found to contain 0.29% selenium. What is the minimum molecular weight of the enzyme? (Se = 78.96)

(A) Perhalate ions are tetrahedral in shape (R ) Halogens underdo sp^(3) hybridization in perhalates

A perfectly semipermeable membrane when used to separate a solution from its solvent permits through it the passage of :

A perfectiges of a given mass is heated first in a small vessel and then in a large vessel, The P-T curves are :

(A) Peracetic acid is a weaker acid than acetic acid. (R) Acetate ion is stabilized by resonance but peracetate ion is not.

A peptide hormone is :

A peptide bond is formed between two amino acids by

A peptide bond joins two amino acids together. What atoms are linked by this bond in chain ?

A peeled egg swells when dipped in water while shrinks in saturated brine solution. Why?

A+PCl_5 to B B underset("ether")overset("Na")to n-butane. A and B are __________.

(A) PCl_(5) is more covalent than PCl_(3) (R ) Polarising power of P^(5+) is greater than that of P^(3+)

A : PCl_5 is covalent in gaseous and liquid states but ionic in solid state. R: PCl_5 in solid state consists of tetrahedral PCl_(4)^(+)cation and octahedral PCl_(6)anion.