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88001.

a. Prepare the following ethers via Willamson's syntesis. I. Di-n- propyl ether (A0) II. Benzyl methyl ether (B) III. Phenylethyl ehter (C) IV. t- Butyl ethyl ether (D) b. Which compound in the above problem, can be prepared by alternative Williamson's reaction? c. Explain teh inabiliity of (A),(C), (D) in the above problem to be preaparedvia alternate Williamson's syntesis. d. Give six typesof ethers that cannot be syntesised by the typicalwilliamson's synthesis. e. Rank the following alkyl halides in the decreasing order of reactivity in Willamson's reaction. (CH_(3))C - CH_(2) Br (A), ClCH_(2) CH + CH_(2) (B), ClCH_(2) CH_(2) (C), Br CH_(2) CH_(2) CH_(3)(D)

Answer»

Solution :a.
I. `n-PrOH overset(Na)(rarr) n-PrO overset(n-PrBr)(rarr)PROPR (A)`
IIgt `MeOH overset(Na)(rarr) MeO overset(PhCH_(2)Br)(rarr)PhCH_(2) OMe (B)`
III. `PHOH overset(NAOH)(rarr) PhO overset(ErBr)(rarr) PhOEt (C)`
IV. `t- BuOH overset(Na)(rarr) t-BuOoverset(EtBr)(rarr) t-Bu - OEt (D)`
b. Only (B): `PhCH_(2) OH overset(Na)(rarr) PhCH_(2)O`
`overset(MeBr)(rarr) Ph-CH_(2)OMe (B)`
c. I.`(A)` is a simple ether.
III. Aryl halides do not undergo nuclephilicdisplacement`(SN)` reaction.
III. `ErO` is a strong base as well as a nucleophile and dehydohalogenates `t-` butylchloride in completing `E2` reaction, givingalkeneand littleor no ether.
d. i. `R_(2) CH - O - CHR_(2)`, both `C` atoms are `2^(@)`.
ii. `R_(2)CH - O - CR_(3)`, one `C` is `2^(@)` and one is `3^(@)`.
iii. `R_(3)C - O - CR_(3)`, both `C` atoms are `3^(@)`.
iv. `Ar-O-Ar`, both diarly ethers.
v. `R-CH=CH-O-CH=CH-R'`: vinyl halides do not undergo `SN` reaction
vi. `R - underset(R) underset(||)overset(R) overset(|)(C) - CH_(2) - O - CH_(2) - underset(R') underset(|)overset(R')overset(|)(C) - R'`
e. `(B) gt (D) gt (C) gt (A)`. Alliylic gt bromidic gt chloride gt neopentyl (too hindered).
Discussion
88002.

A prefix penta is used in naming the complex

Answer»

`CrCl_3. 6NH_3`
`CrCl_3. 5NH_3`
`CrCl_3. 4NH_3`
`CrCl_3. 3NH_3`

ANSWER :B
Discussion
88003.

a. Predict the products (i) CH_(3)COCH_(3)underset("Conc."HCl)overset(Zn-Hg)(to) (ii)CH_(3)CoCl+H_(2)overset(Pd-BaSO_(4))(to) B. Which acid of each pair shown here would you expect to be stronger? (i) F-CH_(2)-COOH or Cl-CH_(2)-COOH ORCH_3 COOH

Answer»

Solution :a. (i)
`CH_(3)-overset(O)overset(||)(C)-CH_(3)underset("Conc"HCl)overset(Zn-Hg)(to)CH_(3)CH_(2)CH_(3)+H_(2)O`
(ii) `CH_(3)-overset(O)overset(||)(C)-Cl+H_(2)overset(Pd-BaSO_(4))(to) CH_(3)-overset(O)overset(||)(C)-H+HCl`

b. (i) `F-CH_(2)-COOH` is stronger acid DUE to higher -I-effect.
(ii) Phenol ismore ACIDIC than acetic acid.
Discussion
88004.

A precipitate of ……wouldbe obtained on addingHCI to a solution of Sns in yellowammoniumsalphide

Answer»

SnS
`Sn_(2)S_(3)`
`SnS_(2)`
`(NH_(4))_(2)SnS_(2)`

Answer :c
Discussion
88005.

A precipitate of ____would be obtained on adding HCl to a solution of (Sb_(2)S_(3)) in yellow ammonium sulphide

Answer»

`Sb_(2)S_(3)`
`Sb_(2)S_(3)`
`SbS`
`SbS_(2)`

Solution :`Sb_(2)S_(3)+2(NH_(4))_(2)S_(2) to 2(NH_(4))_(2)S+Sb_(2)S_(5)`
Discussion
88006.

A precipitate of ……wouldbe obtained on addingHCI to a solution of As_(2)S_(3) in yellowammoniumsalphide

Answer»

`As_(2)S_(3)`
`As_(2)S_(3)`
`ASS`
`AsS_(2)`

ANSWER :B
Discussion
88007.

A precipitate of the following would be obtained when HCl is added to a solution of stannous sulphide (SnS) in yellow ammonium sulphide

Answer»

`SNS`
`SnS_2`
`Sn_2S_2`
`(NH_4)_2SnS_3`

ANSWER :B
Discussion
88008.

A precipitate of AgCl is formed when equal volumes of the following are mixed. [K_(sp) for AgCl = 10^(-10]

Answer»

`10^(-4)MAgNO_(3)AND10^(-7)M HCI`
`10^(-5)MAgNO_(3)and10^(-6)M HCI`
`10^(-5)MAgNO_(3)and10^(-4)M HCI`
`10^(-6)MAgNO_(3)and10^(-6)M HCI`

Solution :For the precipitation of an electrolyte, it is necessary that the ionic product must exceed its solubility product
Discussion
88009.

A precipitate of calcium oxalate will not dissolve in

Answer»

HCL
`HNO_(3)`
Aqua-regia
ACETIC acid

Solution :CALCIUM oxalate will not dissolve in acetic acid (Weak acid) but dissolve only in strong acid.
Discussion
88010.

A precipitate of AgCl and AgBr weighs 0.4066 g. On heating in a current of chlroine, the AgBr is converted to AgCl and the mixture loses 0.0725 g in weight. Calculate the % of Cl in the original mixture (Atomic mass of Ag = 108, Cl = 35.5, Br = 80).

Answer»

Solution :Suppose the precipitate contains 'a' g of AgCl and 'b' g of AgBr. Then
`a+b=0.4066g`
On heating the mixture in a current of `Cl_(2),AgBr` changes to `AgCl` according to the reaction
`underset(188g)(AgBr)overset(Cl_(2))rarr underset(143.5g)(AgCl)`
Thus, 188g AgBr gives AgCl = 143.5g
`THEREFORE"b g AgBr will give AgCl"=(143.5)/(188)xxbg`
As AgCl remians as such (= a g), therefore total MASS of the mixture now `=a+(143.5)/(188)xxb`
`therefore""(a+b)-(a+(143.5)/(188)b)=0.0725"(GIVEN VALUE of loss in mass)"`
`"or"b(1-(143.5)/(188))=0.0725"or"bxx(44.5)/(188)=0.0725`
`"or"b=0.0725 xx(188)/(44.5)=0.3063"g (mass of AgBr)"`
`therefore"Mass of agCl"=0.4066-0.3063=0.1003g`
Mass of Cl in 0.1003 g of `AgCl =(35.5)/(143.5)xx0.1003=0.025g`
`therefore %" of Cl in the mixture "=(0.025)/(0.4066)xx100=6.15%`
Discussion
88011.

A pre-weighes vessel was filled with oxygen at N.T.P. and weighed. It was then evacuated, filled with SO_(2) at the same temperature and pressure, and again weighted. The weight of oxygen will be

Answer»

The same as that of `SO_(20`
`(1)/(2)` that of `SO_(2)`
TWICE that of `SO_(2)`
One fourth that of `SO_(2)`

Solution :`("M. wt. of " O_(2))/("M.wt . of "SO_(2))implies (M_(1))/(M_(2))implies(32)/(64)=(1)/(2)`
The weight of oxygen will be `(1)/(2)` that of `SO_(2)`
Discussion
88012.

A precipitate of AgCl is formed when equal volumes of the following are mixed. [K_(sp) for AgCl = 10^(-10)]

Answer»

`10^(-4) M AgNO_(3)` and `10^(-7) M HCL`
`10^(-5) M AgNO_(3)` and `10^(-6) M HCl`
`10^(-5) M AgNO_(3)` and `10^(-4) M HCl`
`10^(-6) M AgNO_(3)` and `10^(-6) M HCl`

Solution :For the precipitation of an electrolyte, it is NECESSARY that the IONIC product must exceed its solubility product.
Discussion
88013.

A pre-weighed vessel was filled with oxygen at NTP and weighed , It was then evacuated, filled with SO_2 at the same temperature and pressure and again weighed. The weight of oxygen is:

Answer»

The same as that of `SO_2`
1/2 that of`SO_2`
TWICE that of `SO_2`
1/4 that of `SO_2`

ANSWER :B
Discussion
88014.

A power company burns approximately 500 tons of coal per day to produce electricity. If the sulphur content of the coal is 1.20% by weight, how many tons SO_(2) are dumped into the atmosphere each day ?

Answer»


ANSWER :12
Discussion
88015.

A Powerful sedative made from acetaldehyde is:

Answer»

ACETIC anhydride
Paraldehyde
Acetic acid
Acetamide

Answer :B
Discussion
88016.

A powerful oxidatn among the following is

Answer»

HYPOCHLORITE ion
Chlorite ion
Chlorate ion
Perchlorate ion

Answer :A
Discussion
88017.

A potter wishes to make a deep blue glaze . Which one of these available chemicals should be mix:

Answer»

IRON oxide
Cuprous oxide
Cobalt oxide
Nickel oxide

Answer :C
Discussion
88018.

A potential difference of 20 volts applied to the ends of a column of M/10 AgNO_(3) solution, 4 cm in diameter and 12 cm in length gave a current of 0.20 ampere. Calculate the specific and molar conductivities of the solution.

Answer»


Solution :By OHM's LAW, `R=(E)/(I)=(20V)/(0.20A)=100VA^(-1)=100Omega`
Discussion
88019.

A possible mechanism for hydrogenation of ethylene, in presence of mercury vapour, is C_(2)H_(2)+ H_(2) rarr C_(2) H_(2)("overall") Steps :Hg + H_(2) overset(K_1)(rarr) Hg + 2H H + C_(2)H_(4) overset(K_(2))(rarr) C_(2)H_(2) C_(2)H_(2) + H_(2) overset(K_(3))(rarr)C_(2)H_(6)+H_(-) H+ H overset(K_(4))(rarr) H_(2) Determine the rate of formation of C_(2) H_(2) in terms of rate constants and the concentrations [Hg], [H_(2)] and [C_(2)H_(4)] Assume that H and C_(2)H_(5) reach steady state concentration.

Answer»


Answer :`(d[C_(2)H_(6)])/dt = k_(2) (k_(1)/k_(2) )^(1//2) [C_(2)H_(4)][Hg]^(1//2)[H_(2)]^(1//2)`
Discussion
88020.

(A) Potassium dichromate is used as a primary standard in volumetric analysis. (R) K_(2)Cr_(2)O_(7) is strong reducing agent

Answer»

Both (A) and (R) are TRUE and (R) is the CORRECT EXPLANATION of (A)
Both (A) and (R) are true and (R) is not the correct explanation of (A)
(A) is true but (R) is FALSE
Both (A) and (R) are false

Solution : (A) is true but (R) is false
Discussion
88021.

(A) Potassium ferrocyanide and potassium ferricyanide both are paramagnetic. (R) Both have unpaired electrons

Answer»

Both (A) and (R) are TRUE and (R) is the CORRECT EXPLANATION of (A)
Both (A) and (R) are true and (R) is not the correct explanation of (A)
(A) is true but (R) is FALSE
Both (A) and (R) are false

Solution :Both (A) and (R) are false
Discussion
88022.

A postersugeststhe followinglife styleon the partof families/ individuals (i) Whichenvironmentalvaluesare promoted throughtheselifestyle ? (ii) Suggestoneadditionallife styleactionfor promotion of greenchemistry. (iii) Givereasonfor te bleachingactionof KMnO_(4)

Answer»

SOLUTION :(i) Enviromentalconservation
(ii) usejutebagsor clothbagsin PLACE of polythenebags.
(iii) `KMnO_(4)` actsas a strongoxidising AGENT.
Discussion
88023.

A possible material for use in the nuclear reactors as a fuel is

Answer»

Thorium
Zirconium
Beryllium
PLUTONIUM

Solution :URANIUM or Plutonium is ATOMIC FUEL
Discussion
88024.

A positron is emitted from ""^(23)Na. The ratio of atomic mass and atomic number of the resulting nucleide is :

Answer»

`22//10`
`22//11`
`23//10`
`23//12`

Solution :`""_(11)^(23)Nato_(10)^(23)NE+""_(+)overset(0)1e`
Ratio =`23/10`
Discussion
88025.

A positron is emitted from ._(11)^(23)Na. The ratio of the atomic mass and atomic number of the resulting nuclide is

Answer»

22/10
22/11
23/10
23/12

Solution :`._(11)^(23)NA RARR._(10)^(23)X + ._(1)^(0)beta`
Discussion
88026.

A positron is emitted from ""_(11)^(23)Na. The ratio of the atomic mass and atomic number of the resulting nuclide is

Answer»

`22/10`
`22/11`
`23/10`
`23/12`

ANSWER :C
Discussion
88027.

A positron is emitted from ._(11)Na^(23) . The ratio of the atomic mass and atomic number of the resulting nuclide is

Answer»

22/10
22/11
23/10
23/12

Solution :`._(11)^(23) Na rarr ._(10)Ne^(23) +. _(+1) E^(0)`
RATE of ATOMIC mass and atomic number `=(23)/(10)`
Discussion
88028.

A positron has a charge equal to that of

Answer»

a proton
an electron
an `ALPHA`-PARTICLE
a neutron.

Answer :D
Discussion
88029.

A positive reaction of n–butane is possible with the reagent -

Answer»

`F_(2)` in the DARK
`Cl_(2)` in the dark
`Br_(2)` in the dark
IODINE in the dark

Answer :A
Discussion
88030.

A positive potential implies that the species under study has _____reduction tendency than that of _____into H_(2)(g).

Answer»


ANSWER :more, `H^(+)(AQ).
Discussion
88031.

A positive half-cell potential implies that the element can lose its electrons more readily than hydrogen.

Answer»


SOLUTION :The OPPOSITE is TRUE.
Discussion
88032.

A positive colloid will be formed when

Answer»

`NH_(4)OH`is added dropwise in DILUTE solution of`FeCl_(3)`
`H_(2)S`is passed in dilute`AsCl_(3)`solution
Dilute `AgNO_(3)`solution is added to saturated Agl solution
Gelatin is DISSOLVED in WATER

ANSWER :C
Discussion
88033.

A positive chromyl chloride test is given by a salt containing

Answer»

`BR^-`
`CL^-`
`SO_3^(2-)`
`I^-`

ANSWER :B
Discussion
88034.

A positive change in enthalpy occurs in:

Answer»

`H_2(G)+1/2O_2(g)rarrH_2O(g)`
`N_2(g)+3H_2(g)rarr2NH_3(g)`
`MgCO_3(s)rarrMgO(s)+CO_2(g)`
`H_2(g)+1/2O_2(g)rarrH_2O(L)`

ANSWER :C
Discussion
88035.

A positive catalyst increases the rate of a chemical reaction by

Answer»

INCREASING the activation energy
decreasing the activation energy
increasing the AVERAGE K.E. of the molecules
none of these

Solution : The POSITIVE catalyst lowers down the activation energy. The greater is the decrease in the activation energy CAUSED by the catalyst higher will be the rate of reaction. In the presence of a catalyst, the reaction follows a path of LOWER activation energy.
Discussion
88036.

Positive carbylamine test is not shown by?

Answer»

N,N-dimethylaniline
2,4-dimethylaniline
N-methyl-o-methylaniline
p-methyl benzylamine

Answer :B
Discussion
88037.

A positive carbylamine test is given by

Answer»

N,N-dimethylaniline
2,4-dimethylaniline
N-methyl-o-methylaniline
p-methylbenzylamine

Solution :2,4-Dmethylaniline and p-methylbenzylamine are `1^(@)` AMINES and HENCE GIVE positive carbylamine test.
Discussion
88038.

A positive carbylamine test given by :

Answer»

<P>N,N- demethyl ANILINE
2,4- dimethyl aniline
N- methyl -o- methyl aniline
p- methyl BENZYL aniline

Answer :D
Discussion
88039.

A positive carbylamine test is given by :

Answer»

N,N-dimethylaniline
4-methylaniline
N-methyl-o-methylailine
N-methylaniline

Solution :N//A
Discussion
88040.

A positive cabylamine test is not given by

Answer»

N, N-dimethylaniline
2,4-Dimethylaniline
2-Methyl-4-ethylaniline
p-Methylbenzyl AMINE

Solution :`2^(@)` & `3^(@)` amine does not give carbyl amine test.
Discussion
88041.

A polyvalent metal weghing 0.1 g and having atomic weight 51 reacted will dil H_2SO_4 to give 43.9 " mL of " H_2 at STP. This solution containing the metal in the lower oxidation state was found to require 58.8 " mL of " 0.1 permanganate for complete oxidation. What are the valencies of the metal.

Answer»

Solution :Suppose the lower oxidationnumber of the metal is X .
GIVEN that :
` {:("metal "+,H_(2)SO_(4) to ,H_(2)),(0.1 g ,,43.9 " mL at STP"),((0.1)/(51//X)EQ,,(43.9)/(11200)eq):}`
(eq . Wt. of the metal= `51/X ` and volume occupied by 1 eq. of hydrogen at NTP = 11200 mL )
Now , eq. of the metal = eq. of hydrogen
`(0.1)/(51//X) = (43.9)/(11200 ) , X = 2 `
Further, the metalis CHANGING from lower OXIDATION number 2 to higher oxidation number , say , Y .
` :. ` eq. wt of the metal ` = 51/(" change in ON") = 51/(Y-2)`
Eq. of metal = eq. of `KMnO_(4)`
` = (" m.e of " KMnO_(4))/(1000)`
` :. "" (0.1)/(51/(Y-2)) = (0.1 xx 58.8)/1000`
` :. "" Y = 5 ` .
Discussion
88042.

A polystyrene of formula Br_(3) C_(6) H_(2)(C_(8)H_(8))_(n)was prepared by heating styrene with tribromobenzyl peroxide in the absence of air. It was found to contain 10% bromine by weight. Find the nearest value of n (M.W. of Br = 80) :-

Answer»

5
10
20
30

Answer :D
Discussion
88043.

A polystyrene of formula Br_(3)C_(6)H_(2)(C_(8)H_(8))_(n) was prepared by heating styrene with tribromobenzyl peroxide in the absence of air. It was found to contain 10.46% bromine by weight .Find the value of n. (Br = 80)

Answer»


ANSWER :`19.~~(19)`
Discussion
88044.

A polymer used in paints is :

Answer»

NOMEX
Thiokol
Saran
Glyptal

Answer :D
Discussion
88045.

A polymeric substance, tetra fluoro ethylene, can be represented by the formula (C_(2)F_(4)) where x is a large number. The material was prepared by polymensing C_(2)F_(4) in the presence of sulphur bearing calalyst thal served as a nucleus upon which the polymer grew. The final product was found to contain 0.012% S. What is the value of x if each polymeric molecule conlain 2 sulphur atoms? Assume that the calalyst contribution is negligible amount to the lotal mass of polymer.

Answer»

SOLUTION :`x=5.33xx10^(3)`
Discussion
88046.

A polymer on ozonolysis gives 2,5 hexanedione only.Henece ,the monomer of thepolymer would be :

Answer»




SOLUTION :N//A
Discussion
88047.

A polymer sample is made of 30% molecules of molecular mass 20,000, 40% of molecular mass 30,000 and rest of mass 60,000 . The barM_n is :

Answer»

`36,0000`
`36,000`
`46,000`
`50,000`

ANSWER :B
Discussion
88048.

A polymer of prop -2- enenitrile is called

Answer»

SARAN
ORLON
DACRON
TEFLON

Answer :B
Discussion
88049.

A polymer made from a polymerization reaction that produces small molecules (such as water ) as well as the polymer is classified as a/an… polymer.

Answer»

ADDITION
NATURAL
condensation
ELIMINATION

Answer :C
Discussion
88050.

A polymer is resistant to heat and chemical attack and is also used for coating articles and cook wares to make them non-sticky. The monomer of this polymer is

Answer»

monochlorotrifluoroethylene
tetralfluoroethylene
chloroprene
vinyl chloride

Solution :The POLYMER is TEFLON (or PTEE) `[-F_(2)C-CF_(2)-]_(N)`
Discussion