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1101.

Which of the following electrolytes will have maximum coagulating value for AgI//Ag^(+) sol?a) Na_2Sb) Na_3PO_4c) Na_2SO_4d) NaCl

Answer»

`Na_2S`
`Na_3PO_4`
`Na_2SO_4`
`NaCl`

SOLUTION :`AgI // Ag^(+)`is a positively charged sol and can be easily coagulated by adding negatively charged IONS having high valency. COAGULATION value is just the reverse of it. Electrolyte whose negative ion (anion) has LEAST negative charge will require maximum amount and hence will have maximum coagulating value. Thus, `Cl^(-)` (from NaCl) will have maximum coagulating value.
Discussion
1102.

Three solutions of strong electrolytes 25 mL of 0.1 M HX, 25 mL of 0.1 M H_2 Y and 50 ml of 0.1 N Z(OH)_2are mixed.What is the pOH of the solution ? [Given log 5 = 0.7]

Answer»

1.6
7
11.6
12.4

Answer :d
Discussion
1103.

Which of the following is not possible?

Answer»

n=3,l=0,m=0
n=3,l=1,m=-1
n=2,l=0,m=-1
n=3,l=1,m=0

Answer :C
Discussion
1104.

Which is the strong oxidizing agent on the basis of E^(@) value by following value : [Fe(CN)_(6)]^(4-) to [Fe(CN)_(6)]^(3-)+e^(-),E^(@)=-0.35V Fe^(2+) to Fe^(3+) +e^(-),E^(@)=-0.77V

Answer»

`FE^(2+)`
`Fe^(3+)`
`[Fe(CN)_(6)]^(3-)`
`[Fe(CN)_(6)]^(4-)`

SOLUTION :`Fe^(3+)`
Discussion
1105.

Which of the following compounds decolourises aqueous bromine and does not give white fumes of HCI on reaction with PCI_5 ?

Answer»

`CH_3CH_2CH_2CH_2OH`
`CH_3OCH_2CH=CH_2`
`CH_3OCH_2CH_2CH_2OHS`
`CH_3CH=CHCH_2CH_2OH`.

SOLUTION :
Discussion
1106.

Which one of the following is not an application of adsorption ?

Answer»

Ion exchange PROCESS in softening of HARD water
Chromotographic analysis
Clarification of sugar
Theory of HOMOGENEOUS catalysis

Answer :D
Discussion
1107.

The standard Gibbs energy change at 300 K for the reaction 2A hArr B+C is 2494.2 J. At a given time, the composition of the reaction mixture is [A]=(1)/(2), [B] =2and [C]=(1)/(2). The reaction proceeds in the :[R = 8.314 J/K/mol, e = 2.718]

Answer»

forward direction because `Q gt K_(C )`
reverse direction because `Q gt K_(c )`
forward direction because `Q lt K_(c )`
reverse direction because `Q lt K_(c )`

Solution :`2A hArr B+C, Delta G^(@)=2494.2 J`
`Delta G^(@)=-2.303 RT LOG K_(c )`
`THEREFORE - 2.303 RT log K_(c ) = 2494.2`
`-2.303xx8.314xx300 log K_(c ) = 2494.2`
`log K_(c )=-(2494.2)/(2.303xx8.314xx300)=0.4342`
`K_(c )=` antilog `(0.4342)=0.367`
Now `[A]=(1)/(2), [B]=2`and`[C]=(1)/(2)`
`Q_(c )=([C][B])/([A]^(2))=((1)/(2)xx2)/(((1)/(2))^(2))=4`
Since `Q_(c )gt K_(c )`, reaction will SHIFT in backward direction.
Discussion
1108.

What happens when (i) Chlorobenzene is treated with Cl_(2)//FeCl_(3) (ii) Ethyl chloride is treated with AgNO_(2) (iii) 2-bromopentane is treated with alcoholic KOH ? Write the chemical equations in support of your answer.

Answer»

Solution :(i) Chlorobenzene is treated with `Cl_(2)//FeCl_(3).`

In the presence of an iron catalyst, chlorine reacts rapidly with BENZENE to give chlorobenzene and `HCl, FeCl_(3),` catalyst substitutes a halogen for an H ATOM.
(II) Ethyl chloride is treated with `AgNO_(2)`:
`CH_(3)CH_(2)Cl+AgNO_(2)rarrCH_(3)CH_(2)NO_(2)+AgCl`
(iii) 2-bromopentane is treated with alcoholic KOH
`CH_(3)-overset(Br)overset(|)CH-CH_(2)-CH_(2)-CH_(3)overset(KOH(alc.Delta))rarrCH_(3)-CH=CH-CH_(2)-CH_(3)+HBr`
Discussion
1109.

What is the two dimensional coordination number of a molecule in (i) square close-packed layer (ii) hexagonal close-packed layer.

Answer»

SOLUTION :(i) 4 (II) 6
Discussion
1110.

Which of the following species are hypervalent ? (I) ClO_(4)^(-) ""(II) BF_(3) (III) SO_(4)^(-2)""(IV) CO_(3)^(-2)

Answer»

I, II, III
I, III
III, IV
I, III, IV

Answer :B
Discussion
1111.

Which among the following amines can be directly oxidised to the corresponding nitro compound by potassium permanganate?

Answer»

`CH_(3)NH_(2)`
`(CH_(3))_(2)CH-NH_(2)`
`(CH_(3))_(2)NH`
`(CH_(3))_(3)C-NH_(2)`

Solution :`1^(@)` AMINES CONTAINING tert-alkyl grous are EASILY oxidised to the CORRESPONDING nitro compound i.e., option (d) is correct.
`(CH_(3))_(3)C-NH_(2)overset(KMnO_(4))to (CH_(3))_(3)C-NO_(2)`
Discussion
1112.

Which of the following has highest ionisation enthalpy in the second period from Li to Ne?

Answer»

N
Li
Ne
F

Answer :C
Discussion
1113.

Which of the following are primary precursors of photochemical smog ?

Answer»

`CO_(2)` and PAN
`NO_(2)` and hydrocarbons
`O_(3)` and PAN
`NO_(2)` and PAN

ANSWER :B
Discussion
1114.

Which of the following is phospholipids?

Answer»

Vitamin-A
prostaglandians
Lecithin
Vitamin-D

Answer :C
Discussion
1115.

The strongest Bronsted base in the following anion is…….

Answer»

`ClO^-`
`ClO^(2-)`
`ClO^(3-)`
`ClO^(4-)`

Solution :HCLO is the weakest ACID and its CONJUGATE base `ClO^-` is the STRONGEST base
Discussion
1116.

Which one of the following is the majorconstituent of plant cell wells?

Answer»

STARCH
CELLULOSE
Glycogen
AMYLOSE

Answer :C
Discussion
1117.

What conditions would you use for each reaction?

Answer»

Solution :We recognize that synthesis by path (a) would require a Markovnikov addition of WATER to the ALKENE. So, we COULD use EITHER acid-catalyzed hydration or oxymercuration-demercuration.

Synthesis by path (b) REQUIRES an anti-Markovnikov addition, so we would choose hydroboration-oxidation.
Discussion
1118.

Which of the following is not an example of addition polymer:

Answer»

Polyethene
Polystyrene
NEOPRENE
Treylene

Answer :D
Discussion
1119.

Which of the following will form only one oxime on reaction with NH_(2)OH solution ?1

Answer»




ANSWER :B::C
Discussion
1120.

Which method is usefull synthesis of ether

Answer»




`(CH_(3))_(3)CBr+CH_(3)CH_(2)ONA rarr`

Answer :A,B,C
Discussion
1121.

When chlorine water is slowly cooled, we get greenish yellow crystals of

Answer»

`Cl_(2). 2H_(2)O`
`Cl_(2). 8 H_(2) o`
`Cl_(2) . 5H_(2) O`
`Cl_(2). 6H_(2)O`

Solution :Chlorine water is slowly cooled, we get greenish YELLOW CRYSTALS of `Cl_(2). 8 H_(2)O`.
Discussion
1122.

Which of the following statements are correct during halogenation of alkane

Answer»

The yield of the alkyl halide depends upon the bond dissociation energy of the type of C-H bond
The yield of the ALKANE depends upon the number of a particular type of C-H available
The fluoro compounds cannot be prepared because of high bond energy of F-F
Iodo compounds cannot be prepared by this METHOD because the backward reaction is thermodynamically more favourable

Solution :During the HALOGENATION of alkanes the yield depends upon (i) Bond dissociation energy of C-H bond which is (##ERRL_CHM_V02_C21_E03_105_S01##) More easily the bond can be cleaved, greater will be the yield of the corresponding alkyl halide. (reativity factor). `rArr` Choice (a) is correct
(ii)As a chemical reaction TAKES place due to the collision between the molecules or radicals, more is the possibility for a type of collision, more is the possiblity of the yield corresponding to alkyl halide.
Hence, if a type of C-H bond is more in number then one can expect greater number of collision of `X^dot` with the C-H bond and hence greater will be the yield (number factor)
`rArr` Choice (b) is correct.
(iii)During the iodination of alkanes,
`CH_4+I_2 to CH_3-I+HI`
due to low bond energy of HI and C-I, so backward reaction is thermodynamically more favourable Hence , choice (d) is correct .
(IV)During fluorination , H-F is formed , the bond energy of HF is so very high that the exothermicity lead to explosion that is why fluoro compounds are not prepared by this method .
`rArr` Choice (c ) is incorrect.
Discussion
1123.

Xenon difluoride is

Answer»

Linear
Angular
Trigonal
Pyramidal

Answer :A
Discussion
1124.

Which of the following compound will not give Friedel-Crafts reaction?

Answer»




Solution :PRESENCE of strong electron WITHDRAWING GROUP inhasbitants the FRIED craft alkylation
Discussion
1125.

Which of the following is pyrophosphorous acid

Answer»

`H_(4)P_(2)O_(6)`
`H_(3)PO_(2)`
`H_(4)P_(2)O_(5)`
`H_(3)PO_(4)`

Answer :C
Discussion
1126.

Why are gases and liquids considered as fluid?

Answer»

Solution :A fluid is a substance that can flow. Gases and liquids are called fluids as they can flow. Because of the weak INTERMOLECULAR forces of attraction in liquid and gases, molecules in them are not held at fixed positions and are ALWAYS in a state of random motions, MOVING past ONE another easily. This MOLECULAR behaviour of liquids and gases accounts for their flow property.
Discussion
1127.

Which bond is present in physical adsorption ?

Answer»

Ionic
VAN DER WAALS
H-BOND
Dative bond 

SOLUTION :van der Waals
Discussion
1128.

What is crystal field solitting energy?

Answer»

SOLUTION :`(i)` In an octahedral complex, the `d`-orbitals of the central metal ion divide into two sets of different energies. The separation in energy is the crystal field splitting energy.
`(ii)` The `d` orbitals lying along the axes `dx^(2)`, `y^(2)` and `dz^(2)` orbitals will experience STRONG repulsion and raise in energy to a greater extent than the orbitals with lobes DIRECTED between the axes (`d_(xy)` , `d_(yz)` and `d_(zx)`). THUS the degenerate `d`-orbitals now split into two sets and the process is called crystals filled splitting.
Discussion
1129.

What is meant by lanthanoidcontraction ?

Answer»

Solution :The regular decrease in the atomic and IONIC radii of lanthanoids with INCREASING atomic number is CALLED LANTHANOID CONTRACTION.
Discussion
1130.

What would be the equivalent weight of the reductant in the reaction : [Fe(CN)_(6)]^(-3)+H_(2)O_(2)+2OH^(-)rarr2[Fe(CN)_(6)]^(4-)+2H_(2)O+O_(2) [Given : Fe=56,C=12,N=14,O=16,H=1]

Answer»

17
212
34
32

Answer :A
Discussion
1131.

Which point defect in crystals of a solid does not change the density of the solid ?

Answer»

SOLUTION :FRENKEL DEFECT.
Discussion
1132.

Which of the following is not correct observation on Ellingham diagram ?

Answer»

A metal can reduce the oxide of other metal which LIES above it in ELLINGHAM diagram .
CO is more effective than C as a reducing agent below `710^(@)C`
`DeltaG^(@)` of metal OXIDES is higher than that of `CO_(2)` hence oxidation of metal suphides to oxides is not favourable.
Need for conversion of metal sulphide to metal oxide before reduction can be explained thermodynamically.

Solution :`DeltaG^(@)` of metal oxides is LOWER than of`CO_(2)` hence oxidation of metal suphide to metal oxide is favourable.
Discussion
1133.

Which one among the following methodsis not effective in removing arsenic from contaminated ground water ?

Answer»

Boiling
Reverse OSMOSIS
ION EXCHANGE
Coagulation adsorption

Solution :Boiling is not effective in removing arsenic from contaminated GROUNDWATER .
Discussion
1134.

Westronis:

Answer»

`CHCl=CHCl`
`CHCl_2cdotCHCl_2`
`CH_2Cl-CH_2Cl`
None

Answer :B
Discussion
1135.

Which among the group -15 elements does NOT exists as tetra atomic molecule?

Answer»

NITROGEN
PHOSPHORUS
Arsenic
ANTIMONY

Solution :Nitrogen EXISTS as `N_(2)`, diatomic
Discussion
1136.

What is the harmful effect to hyperacidity ?

Answer»

SOLUTION :Hyperacidity produces SUDDEN stomach pain. It MAY lead to vomiting , loss of appetite fiatulence and heartburn. It is also responsible for CHRONIC indigestion and in severe cases cause gastric ULCERS.
Discussion
1137.

Which of 0.1 M HCl and 0.1 M KCl do you expect to have greater molar conductance and why?

Answer»

Solution :Compare to 0.1 M HCl and 0.1 M KCl, 0.1 M HCl has greater molar conductance.
Molar conductance of `"0.1 M HCl"=39.132xx10^(-3)"Sm"^(2)"mol"^(-1)`.
Molar conductance of `"0.1 M KCl"=12.896xx10^(-3)"Sm"^(2)"mol"^(-1)`.
Because, `H^(+)` ion in aqueous being smaller SIZE than `K^(+)` ion and `H^(+)` ion have greater MOBILITY than `K^(+)` ion. when mobility of the ion increases, conductivity of that IONS also increases. HENCE, `"0.1 M HCl"` solution has greater molar conductance than `"0.1 M KCl"` solution.
Discussion
1138.

Which of the following odixation state is not shown by Manganese?

Answer»

`+1`
`+2`
`+4`
`+7`

ANSWER :A
Discussion
1139.

What is the effect of adding a catalyst on (a) activation energy E_a and (b) Gibbs energy (DeltaG) of a reaction ?

Answer»

SOLUTION :(a) Activation energy is lowered on ADDITION of a CATALYST.
(b) Gibb.s energy `(DeltaG)` remains UNCHANGED.
Discussion
1140.

Which one of the following pairs of substances on reaction will not evolve H_2 gas ?

Answer»

IRON and `H_2SO_4` (aq0
Iron and steam
Copper and HCl
Sodium and ETHYL alcohol

Answer :C
Discussion
1141.

Which of the following is true with respect to enzymes ?

Answer»

Enzymes LACK nucleophilic groups.
Enzymes are highly specific both in BINDING substrate and in catalysing their reactions
Enzymes are fibrous proteins.
Enzymes completely gets utilised in the reaction.

SOLUTION :Enzymes are highly specific both in binding substrate and in catalysing their reactions.
Discussion
1142.

The vapor pressure of acetone at 20^(@)C is 185 torr. When 1.2 g of a non-volatile solute was dissolved in 100 g of acetone at 20^(@)C, it vapour pressure was 183 torr. The molar mass (g mol^(-1)) of solute is:

Answer»

128
488
32
64

Solution :`(P_(A)^(@)P_(S))/P_(S)=(W_(B)xxW_(A))/(W_(A)xxM_(B))`
`((185-183))/((183))=((1.2 G)XX(58 g mol^(-1)))/((100g)xxM_(B))`
`M_(B)=((1.2g)xx(58g mol^(-1))xx(183))/(2xx(100g))=63.68g mol^(-1)`
=64 g `mol^(-1)`
Discussion
1143.

Which one of the following is an incorrect statement for physisorption ?

Answer»

it is a reversible process
It requries LESS HEAT of adsoption
it requires activation energy
It TAKES PLACE at low temperature

Solution :N//A
Discussion
1144.

Write the structures of the following compounds 1-Chloro-4-ethylcyclohxane.

Answer»

SOLUTION :
Discussion
1145.

What is the role of t-butyl peroxide in the polymerisation of ethene?

Answer»

SOLUTION :t -buryl peroxide acrs as a FREE radical INITIATOR in the POLYMERISATION of ethylene.
Discussion
1146.

Which is not true for glucose ?

Answer»

`-CH_(2)OH` Group
`-CHO` group
FOUR `-CHOH` group
ONE `C= O` group

Solution :One `C = O` group
Discussion
1147.

van't Hoff equation is

Answer»

`(d//dT)LNK=(-DeltaE//RT^(2))`
`(d//dT)lnK=+(E//RT^(2))`
`(d//dT)lnK=(-DeltaE//RT)`
`K=Ae^(-E//RT)`

SOLUTION :B,D
Discussion
1148.

When 0.1 mol CoCl_(3) (NH_(3))_(5) is treated with excess of AgNO_(3), 0.1 mol of AgCl are obtained. The conductivity of solution will correspond to

Answer»

1 : 3 electrolyte
1 : 2 electrolyte
1 : 1 electrolyte
3 : 1 electrolyte

Solution :FORMATION of 0.2 MOL of AgCl from 0.1 mol of the complex means that there are two ionizable CL. Hence, formula is `[Co(NH_(3))_(5)Cl]Cl_(2)`, i.e., 1 : 2 type electrolyte.
Discussion
1149.

Write the IUPAC name of CH_(3)-underset(Cl)underset(|)(CH)-CH_(2)-COOH

Answer»

SOLUTION :3-chlorobutanoic ACID.
Discussion
1150.

Which noble gas was first of all detected in solar chromosphere:

Answer»

Helium
Neon
Argon
Krypton

Answer :A
Discussion