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11651.

Vanishing cream is an example of:

Answer»

SOLID EMULSION
Foam
Lyophile sol
Suspension

Answer :A
11652.

Write the characteristics of catalysts.

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Solution :(i) For a chemical reaction, catalyst is needed in very small quantity. (ii) There may be some physical changes, but the catalyst remains unchanged in mass and chemical composition in a chemical reaction. (iii) A catalyst itself cannot initiate a reaction. (IV) A SOLID catalyst will be more effective if it is taken in a finely divided FORM. (v) A catalyst are specific in nature. (vi) In an equilibrium reaction, presence of catalyst reduces the time for attainment of equilibrium and hence it does not affect the position of equilibrium and the value of equilibrium CONSTANT. (vii) A catalyst is highly effective at a PARTICULAR temperature called as optimum temperature. (viii) Presence of a catalyst generally does not change the nature of products
11653.

Which of the following peptide is obtained in a blood plasma of person with high blood pressure ?

Answer»

OXYTOCIN
VASOPRESSIN
ANGIOTENSIN
GONADOTROPIN

SOLUTION :Angiotensin
11654.

Which electrochemical equation is used in the reduction of molten metal salt?

Answer»

SOLUTION :`TRIANGLEG^(0) = -NFE^(0)`.
11655.

What happens when : (a) (CH_(3))_(3)C-O-CH_(3) is treated with HI, (b) Anisole is treated with CH_(3)COCl/anhydrous AlCl_(3). (c) Phenol is treated with Br_(2)/CS_(2)? Write chemical equations in support of your answer.

Answer»

Solution :(a) METHANOL and 2-methyl-2- iodopropane are formed.
`CH_(3)-overset(CH_(3))overset("|")UNDERSET(CH_(3))underset("|")"C "-O-CH_(3)+HI rarr CH_(2)OH +CH_(3)-overset(CH_(3))overset("|")underset(CH_(3))underset("|")"C "-I`
(b) 2-methoxyacetophenone and 4 - methoxyacetophenone are formed.

(c ) o - Bromophenol and p - bromophenol are formed.
11656.

Which of the following statement is/are correct? (i) An element of a substance contains only one kind of atoms. (ii) In CO_2, carbon and oxygen chemically combined in a fixed proportion of 3 : 8 by mass. (iii) The constituents of the pure substances can be separated by single physical methods. (iv) Milk is a homogeneous mixture.

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(i) and (II)
(i) , (III) and (IV)
Only (i)
(i) , (ii) , (iii) and (iv)

ANSWER :A
11657.

The temperature dependence of rate constant (k) of a chemical reaction is written in terms of Arrhenius equation , K = Ae^(-E^(**) //RT) . Activation energy (E^(**)) of the reaction can be calculated by plotting

Answer»

log K vs `(1)/(logT)`
k vs T
k vs `(1)/(log T)`
log k vs `(1)/(T)`

Solution :k = `Ae^(-E^(0) //RT) underset(y) ("log")k = underset(C) ("log") A - underset("mx")(E^(0))//RT therefore` log k vs `(1)/(T)`.
11658.

Which of the following graph represents Freundlich adsorption isotherm

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ANSWER :C
11659.

The two complexes of nickel, [Ni(CN)_(4)]^(2-) and [Ni(CO)_(4)], have different structures but possess same magnetic behaviour. Explain.

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SOLUTION :`[Ni(CN)_(4)]^(2-)` : In this complex, Ni is in + 2 oxidation state. It is a case of `dsp^(2)` hybridisation. This is a SQUARE PLANAR complex. All the electrons are paired. Therefore, this complex is diamagnetic.
[Ni(CO)4J : In this complex, Ni is in O oxidation state. It is a case of `sp^(3)` hybridisation. This is a tetrahedral complex. Here also all the electrons are paired and the complex is diamagnetic.
11660.

Whichis morestables? Fe^(3+)or Fe^(2+) - explain .

Answer»

Solution :`FE(Z=26)"" Fe to Fe^(2+)+2e^(-)`
`Fe to Fe^(3+) +3e^(-)`
`Fe^(2+)` [Number of electrons 24]
Electronic configuration `=[Ar]3D^(6)`
`Fe^(3+)` [Number of electrons 23]
Electronic configuration `=[Ar]3d^(5)`
Among `Fe^(3+) and Fe^(2+), Fe^(3+)` is more stable DUE to half filled d-orbital. This can be explained by Aufbau principle. Half filled and completely filled d-orbitals are more stable than partially filled d-orbitals. So `Fe^(3+)` is more stable than `Fe^(2+)`.
11661.

Which of the following nuclear reactions will generate an isotope

Answer»

Neutron particle emission
Positron emission
`alpha-` particle emission
`beta-`particle emission

Solution :`._(Z)^(A)X rarr ._(Z)^(A -1)X + ._(0)^(1)N`
11662.

When a salt reacts with water resulting into formation of acidic or basic solution, the process is referred to as salt hydrolysis. The pH of salt solution can be calculated using the following equations. pH = ( 1)/(2) ( p K_(w) + pK_(a) + log C)for salt of weak acid and strong base. pH = (1)/(2) ( pK_(w)- pK_(b) - log C )for salt of weak base and strong acid. pH = (1)/(2) ( pK_(w) + pK_(a) - pK_(b))for salt of weak acid and weak basepK_(b) of NH_(3)is 4.74 and pK_(b) of A^(-), B^(-) and C^(-)are 4,5 and 6 respectively. Aqueous solution of0.01 M has pHin the increasing order.

Answer»

`NH_(4)A ltNH_(4)B lt NH_(4) C`
`NH_(4)C lt NH_(4)B lt NH_(4)A`
`NH_(4)C lt NH_(4) A lt NH_(4) B = 7`
all have equal

ANSWER :B
11663.

Total number of isomeric aldehydes and ketones having the molecular formula C_(5)H_(10) are.

Answer»


Solution :Seven isomers are POSSIBLE. These are:
Aldehydes: `CH_(3)CH_(2)CH_(2)CH_(2)CHO`,
`CH_(3)CH_(2)CH(CH_(3))CHO,(CH_(3))_(2)CHCH_(2)CHO,(CH_(3))_(3)C CHO.`
KETONES: `CH_(3)COCH_(2)CH_(2)CH_(3),CH_(3)COCH(CH_(3))_(2),CH_(3)CH_(2)COCH_(2)CH_(3)`.
11664.

Which will give a white precipitate with AgNO_3 in

Answer»

`[Co(NH_3)_5cI](NO_2)_2`
`[Pt(NH_3)_6]CI_4`
`[Pt(en)CI_2]`
`[Cu(NH_3)_4]SO_4`

ANSWER :B
11665.

Whichof the following form pentacetatewithaceticanhydide ?

Answer»

GLUCOSE
FRUCTOSE
LACTOSE
Both a & b

Answer :D
11666.

Which of the following esters on reaction with excess Grigrand reagent give a tertiary alcohol, which on heating give an alkene which exhibits geometrical isomerism

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`CH_3CH_2 COOC_2 H_5+CH_3 MGBR`
`HCOOC_2H_5 +CH_3CH_2MgBr`
`CH_3 COOC_2H_5 +CH_3 CH_2 MgBr `
`HCOOC_2 H_5 +CH_3 MgBr`

Solution :`CH_3-CH_2 - UNDERSET(CH_3) underset(|)overset(OH) overset(|)C-CH_3 ` NoGeometricalisomerism
`(b )Hunderset(CH_3) underset(|) underset(CH_2) underset(|) overset(OH) overset(|)C-CH_2 CH_3tounderset("Exhibit isomerism")(CH_3 -CH_2 -CH =CH -CH_3)`
` (C )CH_3 - underset( CH_3)underset(|) underset(CH_2) underset(|) overset(OH) overset(|) C-CH_2 -CH_3tounderset("Exhibitsgeometricalisomerism ") (CH_3-CH= underset(CH_3) underset(|) C-CH_2 -CH_3)`
11667.

Which one of the following is an antihistamine

Answer»

Terpineol
Chloramphenicol
Zantac
SALVARSAN

Solution :`{:("Iproniazid",rarr,"Tranquilizer"),("Salvarsan",rarr,"Antimicrobial"),("Zantac (RANITIDINE)",rarr,"ANTIHISTAMINE"),("Chloramphenicol",rarr,"ANTIBIOTIC"),("Terpineol",rarr,"Antiseptic"):}`
11668.

Which of the following shows variable valency ?

Answer»

B
Al
Tl
None

Answer :C
11669.

The total number of acyclic and cyclic isomers including geometrical isomers possible for the molecular formula, C_(5) H_(10)are

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10
8
9
11

Solution :ELEVEN
ACYCLIC isomers
(i) `CH_(3) CH_(2) CH_(2) CH = CH_(2)` ( 1 - pentene)

11670.

Which of the following is most reactive towards water ?

Answer»

RCOOCl
`RCOOR`'
`RCONH_(2)`
`RCOOCOR`.

ANSWER :A
11671.

Which of the following shows highest oxidation number of combined state:

Answer»

Os
Ru
Both (1) and (2)
None

Answer :C
11672.

When Cl_2 is passed through hot and concentrated solution of KOH, the following compound is formed.

Answer»

`KCLO`
`KClO_(3)`
`KClO_(3)`
`KClO_(4)`

ANSWER :B
11673.

Which can be used as monomer in a polymerization reaction?

Answer»

`C_2H_3Cl`
`C_2H_4`
`C_2H_5Cl`
`C_2H_3COOH`

ANSWER :A::B::D
11674.

Which of the following molecules has highest dipole moment ?

Answer»

`CH_3Cl`
`CH_2Cl_2`
`CHCl_3`
`"CCL"_4`

ANSWER :A
11675.

What are primary amines? Give one example.

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Solution :`1^(@)` amnes are formed when one H-atom of ammonia is replaced by an alkyl, aryl or aralkyl group. For For example,
`UNDERSET("ETHYLAMINE")(CH_(3)CH_(2)NH_(2)""underset("Aniline")(C_(6)H_(5)NH_(2))""underset("Benzylamine")(C_(6)H_(5)CH_(2)NH_(2))`
11676.

Which of the following converts acetone to acetone oxime

Answer»

`H_2N-NH_2`
2,4 - DNP
`C_6H_5NHNH_2`
`NH_2OH`

ANSWER :D
11677.

Which of the following does not exist(s) ?

Answer»

`ICl_(3), Cl_(3)^(-)`
`FCl_(3),Cl_(3)`
`IF_(7)`
`BrF_(3)`

SOLUTION :No d-orbital is present in the VALENCY shell of fluorine and excitation is not POSSIBLE. F does not exhibit positive oxidation state. So, the FORMATION `FCl_(3)` possible
11678.

Which one of the following will have the highest. coagulating power for ferrie hydroadde sol?

Answer»

NaCl
`BaCl _(2)`
`K_(2)CrO_(2)`
`K_(4)[FE(CN)_(6)]`

Solution :`Fe (OH)_(3)` is a positively charged sol. Greater the charge on the negative part of the COAGULANT, `([Fe (CN)_(6)^(4-))` higher will be the coagulating power.
11679.

What is the electrochemical equivalent of a substance when 150 gm of it is deposited by 10 ampere of current passed for 1 sec?

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Solution :GIVEN :
Amount of the substance deposited,
`""m=150g`
current strength = 1 = 10 ampere
`""Time=t=1sec`.
By Faraday.s first LAW,
Formula : m = ZIt
Solution : `therefore Z=m/(It)=150/(10 times 1)`
ELECTROCHEMICAL equivalent
`""`= 15.0 gm `coloumb^(-1)`
11680.

Which of the following is not a resonance form of para-amino-benzaldehyde ?

Answer»




ANSWER :B
11681.

Which of the following statements are correct :

Answer»

The COORDINATION number of each type of ion in CsCl is 8.
A metal that crystallises in BCC structure has a coordination number 12.
A unit CELL of an ionic crystal SHARES some of its ions with other unit cells
The length of the unit cell in NaCl is 552 pm.
` [r_(Na^(+))=95 pm: r_(Cl)=181 pm]`

ANSWER :A::C::D
11682.

Wave lengths of the light absorbed by [Ni(H_(2)O)_(6)]^(2+) and [Ni(e n)_(3)]^(2+) are respectively lambda_(1) and lambda_(2). What is the relation between lambda_(1) and lambda_(2)

Answer»

SOLUTION :`lambda_(1) GT lambda_(2)`
11683.

Which substance has the strongest London dispersion forces ?

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`SiH_(4)`
`CH_(4)`
`SnH_(4)`
`GeH_(4)`

SOLUTION :London dispersion force `prop` molecular mass of COVALENT molecule.
11684.

What is importance of Enzyme in daily life ?

Answer»

Flow of oxygen.
Producing ENERGY.
Catalysation of biochemical reaction.
STABILISATION energy of photosynthesis.

SOLUTION :Catalysation of biochemical reaction.
11685.

Which of the following statements is not true about the complex ion [CrCl(NO_(2))(en)_(2)]^(+) ?

Answer»

It has two geometrical isomers cis and trans.
cis and transforms are not DIASTEREOMERS to each other
Only the cis isomer displays optical ACTIVITY
It has three optically active isomers : d, 1 and reso forms.

Solution :Cis and trans isomers of `[CrCl(NO_(2))(LN)_(2)]` are not mirror images. HENCE, they are diastereomers.
11686.

Which of the following statement, about the advantage of rasting of sulphide ore before reduction is not true?

Answer»

The `DeltaG_(y)^(@)`of the sulphide is greater than those for `CS_2` and `H_(2)S`.
The `DeltaG_(f)^(@)` is negative for roasting of sulphide ore to oxide.
Roastingof thesulphidetotheoxideis thermodynamically feasible.
Carbon and HYDROGEN are suitable reducing agents for metal sulphides.

Solution :The STANDARD FREE energies of formation `(DeltaG_(f)^(@))` of most of the sulphides are greater than those of `CS_(2)` and `H_(2)S`. Hence, either carbon nor hydrogen can reduce metal sulphides to metal. The standard free energies of formation of oxides are much lower than those of `SO_(2)`. Therefore, oxidation of metal sulphides to metal oxides is thermodynamically favourable. Hence, sulphide ore is roasted to the oxide before REDUCTION.
11687.

The total number of isomers (including steroisomers ) of hydrocarbon with molecular formula C_(4)H_(8) is:

Answer»

2
4
5
6

Answer :D
11688.

The standard entropy change for the reaction C_3H_(6(g)) + 9/2O_(2(g)) to 3CO_(2(g)) + 3H_2O_((l)) is – 339.23 JK-1 at 25^@C. Calculate the standard reaction enthalpy change if the standard Gibbs energy of formation of C_3H_(6(g)), CO_(2(g)) and H_2O_((l)) are 62.78, – 394.36 and –237.13 kJ."mol"^(–1)respectively.

Answer»

SOLUTION :`-2058.2 KJ "MOLE"^(-1)`
11689.

When NH_(4)NO_(3) is gently heated, an oxide of Nitrogen is formed. What is the oxidation state of Nitrogen in this oxide ?

Answer»

`+4`
`+2`
`+3`
`+1`

ANSWER :4
11690.

Which of the following is an example of condensation polymer (or) Which of the following is not an example of addition polymer

Answer»

POLYTHENE
PVC
ORLON
Terylene

Answer :D
11691.

Which of the following is not a natural polymer :

Answer»

GLYCOGEN
CELLULOSE
PEPSIN
Polybutadiene

Answer :D
11692.

The voltage of the cell consisting of Li(s) and F_(2)(g) electrodes is 5.92 V at standardcondition at 298 K. What is the voltage if the electrolyte consists of 2 M LiF. (ln 2=0.693, R="8.314 JK"^(-1)"mol"^(-1) and F = "96500 C mol"^(-1))

Answer»

5.90 V
5.937 V
5.88 V
4.9 V

Answer :C
11693.

Which the resonance structure of the following species : (i) :overset(-)CH_(2)-C-=N: (ii) CH_(3)CH=CH-overset(+)CH-CH_(3) (iii) overset(+)CH_(2)-CH=CH-overset(-)CH_(2) (iv) CH_(3)-overset( :O: )overset(||)C-overset(-)underset(..)CH_(2) (B) Write resonance structure for the intermediate carbocation in the aromatic chlorination of benzene. (C) Write the main resonance structure of the conjugate base of a 1, 3-diketone. (D) Write the resonance structure of CH_(2)=CH-CHO. Indicate relative stability of the contributing structures.

Answer»

SOLUTION :

Structure I: More stable, because it has more number of covalent bonds and have no formal charge. Each carbon and oxygen atom has an octet.
Structure II: Less stable, because it has negative charge on more ELECTRONEGATIVE atom and positive charge on more electropositive atom.
Structure III: LEAST stable, because it does not contribute as oxygen has positive charge and carbon has negative charge.
11694.

What is added to Al_(2)O_(3) in the electrolytic extraction of aluminium?

Answer»

SOLUTION :`Na_(3)AlF_(6)`.
11695.

Total number of rotational conformers of n-butane are:

Answer»

2
6
5
3

Answer :C
11696.

Which of the following is not a method for coagulation of lyophobic sols ?

Answer»

By electrophoresis
By MIXING oppositely charged sols
By adding electrolyte
By adding a protective COLLOID

Solution :Addition of protective colloid is a method of PREVENTION of coagulation .
11697.

Which of the following will be most stable diazonium salt RN_(2)^(+)X^(-) ?

Answer»

`CH_(3)N_(2)^(+)X^(-)`
`C_(6)H_(5)N_(2)^(+)X^(-)`
`CH_(3)CH_(2)N_(2)^(+)X^(-)`
`C_(6)H_(5)CH_(2)N_(2)^(+)X^(-)`

SOLUTION :Diazonium salt containing aryl group DIRECTLY linked to the nitrogen atom is most stable due to RESONANCE stabilisation between the benzene nucleus and N-atom. Diazonium ion act as a electrophile.
11698.

Whatare essential andnon-essentialamino aicds? Giveone exampleof eachtype.

Answer»

SOLUTION :(i) Essential AMINOACIDS: AMINO acidswhich are notsynthesised by the human bodyare calledessentialamino ACIDS .
(ii) Non - essentailacids: Amino acidswhichare synthesisedby human bodyare callednon -eessentail amino acids .
EXAMPLE: Glycine , Aspraticacids , etc .
11699.

Whichofthefollowingisaweakacid ?

Answer»

` C _ 6 H _6`
`CH _ 3 COOH `
`CH _ 2= CH _ 2`
` CH _ 3COCH _3`

SOLUTION :Duetodelocalizationof ELECTRONSIN benzene,itis LEAST acidicinnature.
11700.

Which of the following noble gases has the highest negative electron gain enthalpy value ?

Answer»

Helium
Krypton
Argon
Neon

Solution :ELECTRON gain enthalpy for noble gases is POSITIVE and it BECOMES Jess positive with increase in size of atom Value of electron gain enthalpy
`He- 48 " kJ MOL"^(-1), Ne- 116 " kJ mol"^(-1)`
Ar, `Kr-96 " kJ mol"^(-1), Xe-77 " kJ mol"^(-1)`
Hence, Ne has highest NEGATIVE electron gain enthalpy.