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1401.

The standard oxidationpotentials of Zn,Cu Ag and Ni electrodes are + 0.76 - 0.34 - 0.80 and + 0.25 Vrepectively which of he following reactin will provide maximumvoltage

Answer»

`Cu+2Ag^(+)(aq)rarrCu^(2+)(aq)+2Ag`
`Zn+2Ag^(+)(aq)rarrZn^(2+)(aq)+2Ag`
`H_(2)Ni^(2+)(Aq)rarr2H^(+)(aq)+Ni`
`Zn+Cu^(2+)(aq)rarrZn^(2+)(aq)+Cu`

Solution :Standard oxiditionpotentialof ZnCu Agand Nielectrodes are + 076 - 0.34 - 0.80 and+ 0.25 V respectively
Given `Zn^(2+) +2e^(-) rarr ZnE_(cell)=- 0.76 V`
`Cu^(2+) +2e^(-) rarr Cu , E_(Cell) =+0.34 V`
`AG^(+) +E^(-) rarr Ag, E_(cell) =+ 0.80 V`
`BI^(2+) +2e^(-)rarr Ni , E_(cell) =- 0.25 V`
`a Cu+2Ag(aq) rarr Cu^(2+) (aq)+2 Ag`
B `Zn+2Ag^(+)(Aq)rarr Zn^(23+) (aq)+2 Ag`
`E_(cell)=1.56 V`
1402.

Three fused benzene rings are found in

Answer»

Napthalene
Anthracene
Phenanthroline
Triphenyl methane

Answer :B
1403.

Using IUPAC norms, write the systematic names of the following: [Mn(H_(2)O)_(6)]^(2+)

Answer»

SOLUTION :Hexaaquamanganese(II) ION
1404.

The strength of 10 volumeof H_(2)O_(2) solution is

Answer»

10
68
60.7
30.36

Solution :10 vol means that 1 ml of `H_(2)O_(2)` GIVES
10 ml of `O_(2)` at NTP
`2xx34 22400 ml`
=68 g
now from aboveequation it is clear that 22400 ml`O_(2)` at NTP is obtained from68 g of `H_(2)O_(2)`
`THEREFORE ml` of `O_(2)` at NTP is obtained from
`=(68)/(22400)xx10`
`=0.03035 g H_(2)O_(2)`
1000 ml will contain =`0.03035 xx1000 g`
`=30.35 g H_(2)O_(2)`
1405.

Write the IUPAC names of the following coordination compounds : (i) [Cr(NH_3)_3Cl_3] (ii) K_3[Fe(CN)_6] (iii)[CoBr_2(en)_2]^+, (en = ethylenediamine)

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Solution :(i) triamminetrichlorido chromium (III) (II) potassium HEXACYANOFERRATE (III)
(iii) DIBROMIDOBIS (ethane-1, 2-diamine) cobalt (III) ION
1406.

What happens when a carboxylic acid is treated with lithium aluminium hydride ?

Answer»

ALDEHYDE is formed.
Primary alcohol is formed
KETONE is formed
GRIGNARD reagent is formed

Answer :B
1407.

Which reaction is occurred to form Fe(OH)_(3) colloid from concentrated solution of FeCl_(3) ?

Answer»

Oxidation
Reduction
Double decomposition
HYDROLYSIS 

SOLUTION :Hydrolysis
1408.

Which one of the following alcohols on oxidation gives carboxylic acid with lesser number of carbon atoms?

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`(CH_(3))_(2)-CH-CH_(2)OH`
`CH_(3)CH_(2)CHOHCH_(3)`
`CH_(3)-(CH_(2))_(3)-CH_(2)OH`
both (a) and ( c)

ANSWER :B
1409.

What are the products obtained when copper reacts with concentrated nitric acid?

Answer»

SOLUTION :COPPER nitrate, NITROGEN DIOXIDE and water `Cu+4HNO_3toCu(NO_3)_2+2NO_2+H_2O`
1410.

Write the IUPAC names of the following compounds K_2[PdCl_4]

Answer»

SOLUTION :Potassiumtetrachloridopalladate(II)
1411.

Which halide is not oxidised by MnO_(2)

Answer»

F
Cl
Br
1

Solution :FLUORINE has HIGHEST `E^(@)` value and more reactive than `MnO_(2)`.
1412.

Which of the following choices match (es) with CO_(2) at P = 1 atm and T = 273 K?

Answer»

`Zne1`
ATTRACTIVE forces are dominant
PV = nRT
P(V - NB) = nRT

Answer :A::B
1413.

Xe(g) + PtF_(6)(g) to A overset(PtF_(6))underset(25^(@)C) to B overset(PtF_(6))underset(60^(@)C) to C The products A, B and C are respectively.

Answer»

`XE^(+)[PtF_(6)]^(-), [XeF]^(+)[Pt_(2)F_(11)], [XeF]^(+)[Pt_(3)F_(16)]^(-)`
`[XeF]^(+)[PtF_(6)]^(-),[XeF]^(+)[Pt_(3)F_(16)]^(-)`
`[XeF]^(+)[PtF_(6)]^(-), [XeF_(2)]^(+)[Pt_(2)F_(11)]^(-) , [XeF_(3)]^(+)[Pt_(3)F_(16)]^(-)`
`Xe^(+)[PtF_(6)]^(-), [XeF]^(+)[PtF_(6)]^(-), [XeF]^(+) [Pt_(2)F_(11)]^(-)`

Answer :D
1414.

What happens whenaniline is treated with methyl chloridein presenceof AlCl_(3) ?

Answer»

It UNDERGOES Friedel Craftreaction to forma mixtureofp- methyl and o - METHYLANILINE
It doesnot undergoFriedel Craftreaction because`AlCl_(3)` REACTS with aniline insteadof REACTING with alkyl halide
Aniline gets positivechargeand deactivatedforelectrophilicsubstitution
Both(b) and (c )

Answer :d
1415.

The value of activation energy for a chemical reaction primarily depends on

Answer»

temperature
nature of the REACTING species
the collision frequency
CONCENTRATION of the reacting species

Answer :B
1416.

Xylenes on oxidation with acidic KMnO_4 gives

Answer»

Terphthalic ACID
PHTHALIC acid
Isophthalic acid
All of these

Answer :D
1417.

Which one of the following is not a vinyl polymer

Answer»

PVC 
POLYSTYRENE 
POLYACRYLONITRILE 
PTFE 

ANSWER :D
1418.

which one has the highest bp

Answer»

Acetone
ETHYLE ALCOHOL
Diethyl ether
Chloroform

Solution :Ethyl alcohol has a intermolecualr hydrogen bond.
1419.

Which of the following acts only as reducing agent

Answer»

`KMnO_4`
`CaOCl_2`
`H_2S`
`HNO_2`

SOLUTION :OXIDATIONNUMBER of SULPHUR is MINIMUM in `H_2S(-2)`.
1420.

Urea can be distinguished from acetamide using:

Answer»

NAOH SOLUTION
BIURET test
Tollens' reagent
Fehling's solution

Answer :B
1421.

Which of the following is the correct option according to their given against properties

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`NgtPgtOgtS` (ORDER of ionisation potential)
`NltPltOltS` (Order of electron AFFINITY)
`OltNltPltS` (order of atomic radii)
`NltPltO=S` (Order of CONVALENCY)

Solution :(i) Ordr of I.P. `=NgtOgtPgtS`
(ii) Order of A.R. `=PgtSgtNgtO`
(III) COVALENCY of 's' is greater than 'O'
1422.

Which one of the following would not react with conc. HCl and anhy. ZnCl_(2) at room temperature?

Answer»

`(CH_(3))_(3)COH`
`(CH_(3))_(2)CHOH`
`CH_(3)-CH_(2)-UNDERSET(CH_(3))underset(|)(CH)-OH`
`CH_(3)CH_(2)CH_(2)OH`

ANSWER :D
1423.

The term LABS abbreviates as :

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LABORATORY
Lauryl acidic benzene SULPHATE
LINEAR alkyl benzene sulphate
None

Answer :C
1424.

The vapour pressure of H_(2)O is 23.756mmHg at 25^(@)C. What is the vapour pressure of a solution of 28.5g of sucrose, C_(12)H_(22)O_(11)(342) in 100g of H_(2)O ?

Answer»

<P>

SOLUTION :Mole of sucrose `=(28.5)/(342)=0.0834`
MOLES of `H_(2)O=(100)/(18)=5.55`
`:.` mole fraction of SOLUTE `=(0.0834)/(0.0834+5.55)`
`=0.0148`
We have,
`(p^(0)-p)/(p^(0))=` mole fraction of solute……..(Eqn. 1)
`(23.756-p)/(23.756)=0.0148`
`p=23.404mm`
1425.

The total energy of molecules is divided equally amongst the various degrees of freedom of a molecule. The distribution of kinetic energy along x, y, z axis are E_(K_(x)), E_(K_(y)), E_(K_(z)) Total K.e =E_(K_(x)) + E_(K_(y)) + E_(K_(z)) Since the motion of molecule is equally probable in all the three directions, therefore E_(K_(x)) = E_(K_(y)) = E_(K_(z)) =1/3 E_(K) =1/3 xx 3/2 kT = 1/2 kT, where k =R/N_(A) = Botzman constant. K.E. = 1/2 kT per molecule or =1/2 RT per mole. In vibration motion, molecules possess both kinetic energy as well as potential energy. This means energy of vibration involves two degrees of fiuedom. Vibration energy =2 xx 1/2kT =2 xx 1/2RT [therefore two degrees of freedom per mole] If the gas molecules have n_(1) translational degrees of freedom, n_2 rotational degrees of freedom and n_(3) vibrational degrees of freedom, that total energy = n_(1)[(kT)/2] + n_(2) [(kT)/2] + n_(3) [(kT)/2] xx 2 Where 'n' is atomicity of gas. The vibrational kinetic energy of CO_2 molecule is

Answer»

2kT
4kT
8kT
kT

ANSWER :B
1426.

What is the importance of ozone for plant and animal life on earth?

Answer»

Solution :Ozone layer AROUND EARTH (ozone blanket) protects the PLANTS and animals from the harmful EFFECTS of the ULTRAVIOLET radiations of the sun.
1427.

What are A, Band C in the following reaction?CH_3CO_2 Na overset( "soda lime"//Delta ) to ACH_3 CO_2H overset(LiAIH_4) to B,CH_3 CO_2 Na overset (" Kolbe' selectrolysis") to C

Answer»

` {:(A,,B,,C) ,( C_2H_6 ,,C_2H_5OH ,,CH_4) :}`
` {:(A,,B,,C) ,( CH_4 ,,C_2H_5OH ,,C_2H_6) :}`
` {:(A,,B,,C) ,( C_2H_6 ,,CH_3COCH_3 ,,C_3H_8) :}`
` {:(A,,B,,C) ,( (CH_3CO)_2O ,,C_2H_6 ,,C_2H_6) :}`

ANSWER :B
1428.

The total energy of molecules is divided equally amongst the various degrees of freedom of a molecule. The distribution of kinetic energy along x, y, z axis are E_(K_(x)), E_(K_(y)), E_(K_(z)) Total K.e =E_(K_(x)) + E_(K_(y)) + E_(K_(z)) Since the motion of molecule is equally probable in all the three directions, therefore E_(K_(x)) = E_(K_(y)) = E_(K_(z)) =1/3 E_(K) =1/3 xx 3/2 kT = 1/2 kT, where k =R/N_(A) = Botzman constant. K.E. = 1/2 kT per molecule or =1/2 RT per mole. In vibration motion, molecules possess both kinetic energy as well as potential energy. This means energy of vibration involves two degrees of fiuedom. Vibration energy =2 xx 1/2kT =2 xx 1/2RT [therefore two degrees of freedom per mole] If the gas molecules have n_(1) translational degrees of freedom, n_2 rotational degrees of freedom and n_(3) vibrational degrees of freedom, that total energy = n_(1)[(kT)/2] + n_(2) [(kT)/2] + n_(3) [(kT)/2] xx 2 Where 'n' is atomicity of gas. How many total degrees of freedom are present in H_(2)molecules in all types of motions ?

Answer»

3
5
6
4

Answer :C
1429.

Which of the following C_(6)H_(6) structures will not give only one C_(6)H_(5)Br isomer

Answer»




ANSWER :B
1430.

Which of the following reactions will give alkyne

Answer»

`CH_3CH_2undersetunderset(Cl)|CH-undersetunderset(Cl)|CH_2underset(NaNH_2)OVERSET(H_2O)to`
`CH_3CH_2CHBr_2 undersetDeltaoverset"ALC KOH"to `
`CH_3-undersetunderset(Br)|oversetoverset(Br)|C-undersetunderset(Br)|oversetoverset(Br)|C-CH_3 overset"Zn/alcohol"to `
Potassium maleate `overset"electrolysis"to`

Solution :`CH_3CH_2underset"Cl"underset|CH-underset"Cl"underset|CH_2underset((ii)H_2O)overset((i)NaNH_2)to` give first `CH_3CH_2C-=overset thetaCNa^(+)NH_3`
`CH_3CH_2C-=oversetthetaCNa^(+) + H - OH to CH_3CH_2C-=CH+Na^(+)+OH^(-)`
Hence in (a) alkyne is formed.
`CH_3CH_2CHBr_2 undersetDeltaoverset"alc.KOH"to CH_3CH_2C-=CH`
This is againa dehydrohalogenation reaction. Hence (b) GIVES alkyne.
`CH_3-undersetunderset"Br"|oversetoverset"Br"|C-undersetunderset"Br"|oversetoverset"Br"|C-CH_3undersetDeltaoverset"Zn+alc."to CH_3-C-=C-CH_3`
Hence (c ) gives alkyne. Potassium maleate on electrolysis gives `CH-=CH` which is again alkyne. Hence (d) is CORRECT
1431.

Which of the following is the most stable alkene

Answer»

`R_2C=CR_2`
RCH=CHR
`RCH_2=CH_2R`
`CH_2=CH_2`

Solution :We know that GREATER the number of ALKYL groups ATTACHED to double bonded CARBON atoms, more stable is the alkene. Therefore most stable is `R_2C=CR_2`
1432.

Write the formula of the noble gas species that is isostructural with (i) ICI (i) BrO_(3)^(-)

Answer»

SOLUTION :(i) ICI is isostructural with `XeF_2` since both are linear.
(ii) `BrO_(3)^(-)`is isostructural with `XeO_3` since both are PYRAMIDAL.
1433.

Which of the following statements is not correct about penicillium ?

Answer»

PENICILLIN G has a narrow spectrum.
It is EXTRACTED from antibacterial fungus Penicillium.
Ampicillinand AMOXYCILLIN are synthetic modifications of penicillins.
It has bacteriostatic EFFECT.

SOLUTION :Penicillin has bactericidal effect.
1434.

Which divalent metal ion has maximum paramagnetic character among the first transition metals ? Why ?

Answer»

SOLUTION :`MN^(2+)` because of MAXIMUMNUMBER of UNPAIRED electrons , viz. 5
1435.

Which of the following is not favourable for SO_(3) formation 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)),DeltaH=-45.0 kcal

Answer»

High pressure
High temperature
Decreasing `SO_(3)` CONCENTRATION
INCREASING reactant concentration

Solution :The reaction is exothermic so high temperature will FAVOUR backward reaction.
1436.

Which atom can have more than eight valence electrons when it is forming covalent bonds ?

Answer»

`H`
`N`
`F `
`Cl`

Solution :Due to presence of vacant d-orbital excitation occurs in Cl-atom and it can have more than eight VALENCE electrons when it is FORMING hypervalent compound like `HClO_(4)`.
1437.

Which substances are used to reduce the obesity instead of sugar ?

Answer»

Non caloric ARTIFICIAL sweeteners
Caloric artificial sweetener
Mineral 
All of the GIVEN 

Solution :Non caloric artificial sweeteners
1438.

Which of the following is true is respect of chemical adsorption (chemisorption)?

Answer»

`∆Hlt0, ∆Sgt0, ∆Ggt0`
`∆Hlt0, ∆Slt0, ∆Glt0`
`∆Hgt0, ∆Sgt0, ∆Glt0`
`∆Hgt0, ∆Slt0, ∆Ggt0`

ANSWER :B
1439.

Which of the following is isostructural with diamond?

Answer»

Solid `H_3BO_3`
Boron NITRIDE `(BN)_x`Carborundum (SiC)

ANSWER :A::B::C
1440.

Which mixture of the solutions will lead to the formatiin of negatively charged colloidal [AgI]I^(-) sol?

Answer»

`"50 mL of 0.1 M "AgNO_(3)+"50 mL of 0.1 M KI"`
`"50 mL of 1 M "AgNO_(3)+"50 mL of 1.5 M KI"`
`"50 mL of 1 M "AgNO_(3)+"50 mL of 2 M KI"`
`"50 mL of 2 M "AgNO_(3)+"50 mL of 1.5 M KI"`

Solution :The MOLES of KI is more in A, D then `AgNO_(3)`, so they CREATE negatively charged COLLOIDS by the adsorption of `I^(-)` IONS.
1441.

Which of the following is true in the case of Zn-CuSO_(4) cell ?

Answer»

The FLOW of electrons take plave from copper to zinc
`E_("red")^(0)` of copper ELECTRODE is less than that of zinc electrode
Zinc ACTS as anode and copper as anode
`E_("ox")^(0)` of zinc electrode is less than that of copper electrode

Solution :`E_("red")^0 Cu GT E_("red")^(0)Zn`
1442.

The rms speed of the molecules of a gas of density 4 kg m^(-3) and pressure 1.2 xx 10^5 Nm^(-2) is :

Answer»

`120 MS^(-1)`
`300 ms^(-1)`
`600 ms^(-1)`
`900 ms^(-1)`

Answer :B
1443.

Which among the following pairs cannot be distinguished by idoform test ?

Answer»

`CH_3CHO " and " C_6H_5CH_2CHO`
`CH_3OH " and " C_2H_5OH`
`CH_3CHO " and " C_2H_5OH`

Solution :Ehtanol gives POSITIVE iodoform TEST
`CH_3-undersetoverset(||)(O)(C)-Hoverset(I+2_NaOH)(to)UNDERSET("yellow PPT")underset("iodoform")(CHI_3darr)+HCOO^(-)NA^(+)`
`CH_3-undersetoverset(|)(OH)(CH)-Hoverset(I+2_NaOH)(to)underset("yellow ppt")underset("iodoform")(CHI_3darr)+HCOO^(-)Na^(+)`
1444.

What volume of oxygen (NTP) will be required to react with 1 g of Ca?

Answer»

Solution :As Ca combines with `O_(2)` to give CaO , from the FORMULA of CaO,
We have
moles of Ca = moles of O (atoms)
`(wt. of Ca)/( at . wt.) = ("vol . of O atoms at NTP")/("vol . OCCUPIED by 1 moleof O ATOMSOF NTP")`
`(1)/(40)= (vol . of O)/( 11.2)`
` :. ` vol of O = `(11.2)/( 40) = 0 . 28` litre.
1445.

What happens when nitromethane reacts with chlorine in presence of NaOH ?

Answer»

SOLUTION :`CH_3NO_2 + 3Cl_2 + NAOH RARR Cl_3CNO_2 + 3NaCl + 3H_2O`
1446.

Which of the following solution will have pH = 9 at 298 K ?

Answer»

`1XX 10^(-9)` M HCL solution
`1 xx 10^(-5)` M NaOH solution
`1 xx 10^(-9)` M NaOH solution
Both (A) and (B)

ANSWER :B
1447.

The volume (in mL) of 0.1 M AgNO_(3) required for complete precipitation of chloride ions present in 30 mL of 0.01 M solution of [Cr(H_(2)O)_(5)Cl]Cl_(2), as silver chloride is close to

Answer»


Solution :`[Cr(H_(2)O)_(5)Cl]Cl_(2)+2 AgNO_(3)rarr 2 AgCl+[Cr(H_(2)O)_(5)Cl](NO_(3))_(2)`
Number of ionizable `Cl^(-)` ions in the complex = 2 Millimoles of `Cl^(-)` ions = Molarity `xx` volume `xx 2 = 0.01 xx 30 xx 2 = 0.6`
Therefore, `Ag^(+)` required for complete precipitation of `Cl^(-)` ions = 0.6 millimoles
As Millimoles = Molarity `xx` V ml
0.6 = `0.1xxV`
V = 6 ml.
1448.

Which one of the following is used as a binder in paints ?

Answer»

Titanium dioxide
Novolac
Phthalocynine
SILICONS

Solution :Binder REFERS to SUBSTANCES that hold the PARTICLES of PIGMENT together in paint.
1449.

When liquid 'A' is treated with a freshly prepared ammoniacal silver nitrate solution, it gives bright silver mirror. The liquid forms a white crystalline solid on treatment with sodium hydrogen sulphite. Liquid 'B' also forms a white crystalline solid with sodium hydrogen sulphite but it does not give test with ammoniacal silver nitrate. which of the two liquids is aldehyde? Write the chemical equations of these reactions also.

Answer»

SOLUTION :(i) Since liquid 'A' FORMS a white crystaline SOLID on treatment with `NaHSO_(3)`, it may be an aldehyde or a METHYL ketone. Further since liquid 'A' forms a bright silver mirror on treatment with a freshly prepared ammoniacal solution of `AgNO_(3)`, therefore, liquid 'A' is an aldehyde.
(ii) Since liquid 'B' forms a white crystalline solid on treatment with `NaHSO_(3)`, it may be an aldehyde or a methyl ketone,
Further since liquid 'B' does not give test with ammoniacal `AgNO_(3)` solution, therefore, liquid 'B' must be a methyl ketone.
Chemcial equations for the reactions discussed are:
.
1450.

Which one among the following equations is correctly balanced ?

Answer»

`NaOH+Al+H_(2)O to 2H_(2)+NaAlO_(2)`
`2NaOH+2Al+2H_(2)OTO 3H_(2)+2NaAlO_(2)`
`2NaOH+2Al+3H_(2)O to 4H_(2)+2NaAlO_(2)`
`2NaOH+2Al+H_(2)O to H_(2)+2NaA10_(2)`

Solution :Sodium hydroxide, aluminium and WATER REACTS to form sodium aluminium oxide and HYDROGEN gas.