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22401.

The S-S bond energy is if DeltaH_(f)^(@)(E_(t)-S-E_(t))=-147kJ//mol,DeltaH_(f)^(@)(E_(t)-S-S-E_(t))=-202kJ//mol and DeltaH_(f)^(@)S(g)=+223 kJ//mol:

Answer»

168 kJ
126 kJ
278 kJ
572 kJ

Answer :C
Discussion
22402.

When fat is heated with NaOH the substances formed are :

Answer»

OIL and `Na_2CO_3`
SOAP and glycerol
Soap and oil
Soapless DETERGENT and water

Answer :B
Discussion
22403.

Which of the following is not present in a nucleotide ?

Answer»

CYTOSINE
Guanine
Adenine
Tyrosine

Solution :Nucleotide contains nitrogenous BASES LIKE adenine, guanine, THYMINE , cytosine and URACIL.
Discussion
22404.

Using IUPAC norms, write the systematic names of the following: [Co(NH_(3))_(6)]Cl_(3)

Answer»

SOLUTION :HEXAAMMINECOBALT(III) CHLORIDE
Discussion
22405.

What is hybridiation of metal involved in a diamagnetic sodium nitroprussaide ?

Answer»

`sp^(3)`
`DSP^(2)`
`d^(2)sp^(3)`
`sp^(3)d^(2)`

Solution :`Na_(2)[Fe(CN)_(5)No]CN` and NO are SFI
HYBRIDIZATION of Fe is `d^(2)sp^(3)`.
Discussion
22406.

Which one of the following reactions of xenon compounds are not feasible ?

Answer»

`3 XeF_(4) + 6 H_(2)O RARR 2Xe + XeO_(3) + 12 HF + 1.5 O_(2)`
`2 XeF_(2) + 2H_(2)O rarr 2Xe + 4HF + O_(2)`
`XeF_(6) + RbF rarr Rb [XeF_(7)]`
`XeO_(3) + 6HF rarr XeF_(6) + 3 H_(2)O`

Solution :The reaction, `XeO_(3) + 6 HF rarr XeF_(6) + 3 H_(2)O` is not feasible since the products ACTUALLY react to give the reactants back.
Discussion
22407.

What type of linkage is responsible for the formation of proteins ?

Answer»
Discussion
22408.

Which one of the following methods is suitable for the preparation of teri-butyl ethyl and why? (ii) (CH_(3))_(3)Coverset(-+)(O)k+CH_(3)CH_(2)-Cl rarr CH_(3)CH_(2)OC(CH_3)_(3)

Answer»

Solution :The `S_(N)2` REACTION that occurs between an alkoxide and an alkyl halide (WILLIAMSON synthesis) is very suscepitble to STERIC hindrance. Since a tertiary alkyl chloride is used in method
Undergoes `S_(N)2` reaction smoothly due to much less steric hindrance at the reacting CENTRE. Therefore, this method is suitable for the preparation of tert-butyl ethyl ether.
.
Discussion
22409.

The sweetest artificial sugar among the following is

Answer»

aspartame
sucralose
ALITAME
sucrose

Answer :C
Discussion
22410.

Which of the following pairs of ions is isoelectronic as well as isostrutural ?

Answer»

`CO_(3)^(2-), NO_(3)^(-)`
`ClO_(3)^(-), CO_(3)^(2-)`
`SO_(3)^(2-), NO_(3)^(-)`
`ClO_(3)^(-), SO_(3)^(2-)`

Solution :`CO_(3)^(2-)` ion has 32 electrons (6 + 3 `xx` 8 + 2) and C is `sp^(2)` hybridized. `NO_(3)^(-)` has 32 electrons and N is also `sp^(2)`-hybridized. Thus, `CO_(3)^(2-) and NO_(3)^(-)` are ISOELECTRONIC as well as isostructural, i.e., OPTION (a) is correct.
`ClO_(3)^(-)` ion has 42 electrons (17 + 3 `xx` 8 + 1) and Cl is `sp^(3)`-hybridized, while `SO_(3)^(2-)` also has 42 electrons and S is `sp^(3)`-hybridized. Thus, `ClO_(3)^(-) and SO_(3)^(2-)` are also isoelectronic and isostructural, i.e., option (d) is correct.
Discussion
22411.

Which one of the following pairs of isomers and types of isomerism are correctly matched ? (i) [Co (NH_(3))_(5) (NO_(2))] Cl_(2) and [Co(NH_(3))_(5) (ONO)] Cl_(2) ...(Linkage) (ii) [Cu (NH_(3))_(4)][PtCl_(4)] and [Pt(NH_(3))_(4)][CuCl_(4)]...(Coordination) (iii)[PtCl_(2)(NH_(3))_(4)] Br_(2) and [PtBr_(2) (NH_(3))_(4)] Cl_(2)...(lonization) Select the correct answer using the codes given below:

Answer»

(II) and (III)
(i), (ii) and (iii)
(i) and (iii)
(i) and (ii)

ANSWER :B
Discussion
22412.

Which of the following statements(s) is (are) correct with reference to the ferrous and ferric ions?

Answer»

`Fe^(3+)` gives brown COLOUR with potassium FERRICYANIDE.
`Fe^(2+)` gives blue precipitate with potassium ferricyanide.
`Fe^(3+)` gives red colour with potassium thiocyanate.
`Fe^(2+)` gives brown colour with ammonium thiocyanate.

Solution :`Fe^(2+)` ions give blue ppt. with `K_(3) [Fe(CN)_(6)]` . The blue ppt. appears due to the FORMATION of Turnbull.s blue , `K Fe[Fe(CN)_(6)] . Fe^(2+) + K_(3) [ Fe(CN)_(6)] to underset("(Turnbull.s blue)") underset("ferricyanide") underset("Potassium FERRO-")(K Fe[Fe(CN)_(6)] + 2K^(+)`
The red colouration that appears in case of `Fe^(3+)` ions on REACTION with potassium thiocyanate (KCNS) is due to formation of `[Fe(CNS)_(3)]`
`Fe^(3+) + 3 KCNS to underset("Ferric thiocyanate (red)") ([Fe(CNS)_(3)]) + 3K^(+)`
Discussion
22413.

Write one use of dopamine and atropine alkaloid.

Answer»

SOLUTION :DOPAMINE : NEUROTRANSMITTER
Atropine ALKALOID : `0.5-1.0%` solution ophthalmic examination.
Discussion
22414.

Which catalyst is used in the hydrolysis of urea?

Answer»

micoderma
zymase
pepsin
UREASE

Solution :urease
Discussion
22415.

Which oxide of chlorine is paramagnetic?

Answer»

`Cl_2O`
`ClO_2`
`Cl_2O_4`
`Cl_2O_6`

ANSWER :B
Discussion
22416.

The structure of pyrophosphoric acid is :

Answer»




ANSWER :B
Discussion
22417.

Which of the following would be paramagnetic ?

Answer»

`ZN^(2+)`
`CU^(2+)`
`Sc^(3+)`
`Mn^(2+)`

Answer :D
Discussion
22418.

The size of particulates of H_2SO_4 fog lies in the range :

Answer»

` 5 -100 NM`
`100-500 nm`
`500 -1000 nm`
`1000 -10000 nm`

Answer :C
Discussion
22419.

What happens when vapour of formic acid are alone passed over MnO at 673 K ?

Answer»

Solution :When vapours of FORMIC ACID alone are PASSED over MnO at 673 K, formaldehyde is produced.
`UNDERSET"(formic acid)"(2HCOOH)overset"MnO/673K"(RARR)underset"(Formaldehyde)"(HCHO+CO_2+H_2O)`
Discussion
22420.

Which noble gas is not easily to liquefy

Answer»

Ne
He
Xe
Ar

Answer :B
Discussion
22421.

Which of the following arrangements represents the increasing order (smallest of largest) of ionic radii of the given species O^(2-),S^(2-),N^(3-),P^(3-)?

Answer»

`O^(2-) LT N^(3-) lt S^(2-), P^(3-)`
`O^(2-) lt P^(3-) lt N^(3-), s^(2-)`
`N^(3) lt O^(2-) lt P^(3-) lt S^(2-)`
`N^(3-) ltS^(2-)ltO^(2-)ltP^(3-)`

SOLUTION :For isoelectronic species ionic radii decreases as the charge on ION decreases. Further on MOVING down in a group ionic radii increases. Hence the correct ORDER is
`O^(2-)ltN^(3-)ltS^(2-)ltP^(3-)`
Discussion
22422.

Which ion has the maximum magnetic moment ?

Answer»

`Mn^(3+)`
`Cu^(2+)`
`Fe^(+3)`
`V^(+3)`

ANSWER :C
Discussion
22423.

Which class of compounds shows H-bonding even more than in alcohols

Answer»

Phenols
Carboxylic acids
Ethers
Aldehydes

Solution :FORMS H-bonding by MEANS of TWO highly ELECTRONEGATIVE atoms PRESENT in it.
Discussion
22424.

Which one of the following has the highest boiling point?

Answer»

`CH_(3)CH_(2)CH_(2)CH_(2)CH_(3)`
`CH_(3)CH_(2)CH_(2)CH_(2)OH`
`CH_(3)CH_(2)CH_(2)CH_(3)`
`CH_(3)CH_(2)CH_(2)CL`

ANSWER :B
Discussion
22425.

Which of the following is homocyclic compound :-

Answer»

FURAN
PYRROL
PYRIDINE
CHLOROBENZENE

ANSWER :D
Discussion
22426.

Which one of the following is different from others?

Answer»

DANIEL cell
Voltaic cell
Galvanic cell
Electrolytic cell

Answer :D
Discussion
22427.

Write IUPAC name of the complex: Na_(3)[Cr(OH)_(2)F_(4)]

Answer»

SOLUTION :SODIUM tetrafluoridodihydroxochromate(TIT).
Discussion
22428.

Which one of the following metals is extracted by a carbon reduction process ?

Answer»

Sodium
Iron
Aluminium
Magnesium

SOLUTION :The less ELECTROPOSITIVE METALS such as Fe,Zn,Sn etc. are extractedfrom their oxides by reduction with carbon or coal .
`Fe_(2)O_(3) +3C to 2Fe+3CO `
`Fe_(2)O_(3)+3CO to underset("Iron")(2Fe)+3CO_(2)`
Discussion
22429.

The standard electrode potential for the following reaction is + 1.33V.What is potential at pH=2.0? Cr_2O_7^(2-) (aq. 1M) + 14H^(+)(aq) + 6e^(-) to 2Cr^(3+) (aq. 1M0 + 7H_2O(l)

Answer»

`+1.820V `
` + 1.990 V `
`+1.608 V `
`+1.0542V`

Solution :`E^(-) = E^(0)(-0.0941)/(n) log Q , E = 1.33 - (0.0591)/(6) log ""([Cr^(+3)]^(2))/([Cr_2O_7^(-2)][H^(oplus)]^(14))`
`= 1.33 - (0.0591)/(6) log""((1)^(2))/((1) XX (10^(-2))^(14))= 1.33 + (0.0591)/(6) log 10^(-28) = 1.33 + (0.0591)/(6) xx (-28)`
` = 1.33 to 0.2788 = 1.05212 V `
Discussion
22430.

Which of the following statement is not correct about P_(2) ?

Answer»

It will GIVE non-resolvable PRODUCT with MeMgBr
It can not give effervescence of `CO_(2)` with `NaHCO_(3)`
It gives alkane on SODALIME decarboxylation
It can change blue litmus into red

Solution :N//A
Discussion
22431.

The solution containing 4g of KBr dissolved in 100 g of water freezes at - 1.24^(@)C. The molar mass of KBr is (K_(f) = 1.86 K kg "mol"^(-1)

Answer»

102
120
39
60

Solution :`M_(2) = i(K_(f) XX W_(2))/(Delta T_(f) xx W_(1)) xx 1000`
`= 2 xx (1.86 xx 4)/(1.24 xx 100) xx 1000 = 120`
`M_(2) "For" KBr = 39 + 80 = 119`
Discussion
22432.

The stability of particular oxidation state of a metal in aqueous solution is determined by

Answer»

Enthalpy of SUBLIMATION of the METAL
Ionisation energy
Enthalpy of HYDRATION of the metal ion
All of these

ANSWER :D
Discussion
22433.

Which of the following reagents cannot be used to oxidize primary alcohols to aldehydes?

Answer»

CRO3 in ANHYDROUS medium
Pyridinium chlorochromate
`KMnO_(4)` in ACIDIC medium
Heating in PRESENCE of Cu at 573 K

Solution :PRIMARY alcohols can be oxidised to aldehydes with `KMnO_(4)` in aqucous or alkaline medium. Acidified `KMnO_(4)` oxidises alcohols to carboxylic acids directly.
Discussion
22434.

Which of the following reagents will convert nitromethan into methyl amine :

Answer»

`Zn//HCl`
`Zn//NaOH`
`Zn//C_2H_5OH`
`Ni//H_2`

ANSWER :A
Discussion
22435.

Why are the group - 16 elements called chalcogens?

Answer»

Solution :Chalcogens means ore FORMING. The elements of group - 16 are called chalcogens because many METALS are found as OXIDES and sulphides and a few as selenides and tellurides.
Discussion
22436.

Whichbranchedchainisomer of thehydrocarbonwithmolecularmass720 givesonlyoneisomer ofmonosubtitued alkylhalide ?

Answer»

NEOPENTANE
ISOHEXANE
NEOHEXANE
TERITIARY butyl choride

ANSWER :A
Discussion
22437.

Which of the following complexes are heteroleptic ?

Answer»

`[Cr(NH_(3))_(6)]^(3+)`
`[Fe(NH_(3))_(4)Cl_(2)]^(+)`
`[Mn(CN)_(6)]^(4-)`
`[CO(NH_(3))_(4)Cl_(2)]`

Solution :(b) and (d) CONTAIN more than ONE type of ligand.
Discussion
22438.

Write major product in the following reactions : (a) F_(3)C-CH=CH_(2)+Hirarr (b) CV_(6)H_(5)-CH=CHCH_(3)+HBr overset("Peroxide")rarr (c) CH_(3)CH=underset(CH_(3))underset(|)C-CH_(3)+CHBr_(3)overset("Peroxide")rarr (d) C_(6)H_(5)-CH=CH_(2)+B_(2)H_(6) underset(NaOH)overset(H_(2)O_(2))rarr (e) CH_(3)-CH=CH-CH=CH_(2)underset(520^(@)C)overset(HCl)rarr

Answer»


SOLUTION :N//A
Discussion
22439.

Which of the following is amphoteric oxide : Mn_(2)O_(7),Cr_(2)O_(3),CrO,V_2O_5,V_2O_4

Answer»

`V_2O_5,Cr_2O_3`
`Mn_2O_7,CrO_3`
`CrO,V_2O_5`
`V_2O_5,V_2O_4`

Solution :OXIDES in the lower OXIDATION state are basic `(i.e. CrO, V_2,O_2)`, those in higher oxidation state `(e.g. Mn_2O_7, CrO_3)` are ACIDIC and in the intermediate state `(e.g., Cr_2,O_3, V_2O_5)` are amphotertic.
Discussion
22440.

What is the difference between a nucleoside and a nucleotide ?

Answer»

Solution :A nucleoside is formed when 1- position of a pyrimidine (cytosine , thymine or URACIL) or 9-position of a purine (guannine or adenine) base is ATTACHED to C-1 of sugar (ribose or deoxyribose ) by a `beta`-linkage. Thus , in general , nucleosides may be represented as : Sugar -Base. For EXAPLE , STRUCTURE (I) represents a nucleoside.

A nucleoside contains all the THREE basic components of nucleic acids ,i.e., a phosphoric acid group , a pentose sugar and a nitrogenous base. These are obtained by estertification of `C_(5)'-OH` group of the pentose sugar by phosphoric acid. Thus , in general , a nucleotide is represented as
`"Sugar -Base" -O-overset(O)overset(||)underset(O)underset(||)P-OH`
For example , structure (II) represents a nucleotide.
Discussion
22441.

What prompted Bartlett to the discovery of noble gas compounds ?

Answer»

Solution :The IONISATION enthalpy of Xe is similar to that of `O_2`. He FIRST prepared the compound `O_2^(+) PtF_6^(-)`. It PROMPTED Bartlett to prepare compound in which `O_2` of `O_2^(+)PtF_6^(-)` could be replaced by Xe. This is how `Xe^(+) PtF_6^(-)` was prepared.
Discussion
22442.

To get a n-type semiconductor from silicon, it should be doped with a substance with valency

Answer»

2 
1 
3 
5 

Solution :Impurity with HIGHER valency than ATOMS of SEMICONDUCTORS results in n-type of semi conductor.
Discussion
22443.

The time taken for 10% completion of a first order reaction is 20 mins. Then for 19% completion, the reaction will take

Answer»

40 mins
60 mins
30 mins
50 mins

Solution :`t = (2*303)/(k) LOG (a)/(a-x) therefore 20 = (2*303)/(k) log ""(a)/(a-0*10a)`
or `20 = (2*303)/(k)log""(100)/(90)`
In 2ND case, `t= (2*303)/(k)log""(a)/(a-0*19a)`
`= (2*303)/(k) log ""(100)/(81)=(2*303)/(k)log((10)/(9))^(2)""…(ii)`
Eqn. (ii) Eqn. (i) gives `(t)/(20) =2` or `t = 40 min.`
Discussion
22444.

Which equation is true Langmuir adsorption isotherm at low pressure?

Answer»

<P>`(x)/(m)=(1)/(n)XXP`
`(x)/(m)=ap`
`(x)/(m)=(b)/(a)`
`(x)/(m)=(a)/(b)`

Solution :`(x)/(m)=ap`
For Langmuir adsorption `(x)/(m)=(ap)/(1+bp)`
If PRESSURE is lower then, p = 0
`therefore""bp=0`
`therefore""1+bp=1`
`therefore""(x)/(m)=(ap)/(1+bp)=(ap)/(1)` So, OPTION (B) is RIGHT
Discussion
22445.

Which process occurs in the electrolysis of aqueous solution of nickel chloride at nickel anode:

Answer»

`Ni^(2+) +2E RARRNI`
`2H^+ +2e rarrH_2`
`2CI^rarrCI_2+2e`
`Ni rarr Ni^(2+) +2e`

Answer :D
Discussion
22446.

which of the following is a highly basic oxide

Answer»

`SO_2`
`SO_3`
`TeO_3`
`TeO_3`

Solution :In a GROUP from top to bottom BASIC nature of oxides increases and the element which contains less NUMBER of oxygens is more basic in nature.
Discussion
22447.

Under what reaction conditions (acidic, basic), the coupling reaction aryldiazonium chloride aniline is carried out?

Answer»

Solution :Under strongly basic conditions, benzenediazonium CHLORIDE is CONVERTED into diazohydroxide/diazoate both of which are not electrophilic and hence do not couple with aniline.
`C_(6)H_(5)-overset(+)(N)-=NC l^(-)+OH^(-)hArr underset("Diazohydroxide (does not couple)")(C_(6)H_(5)N=N-OH) overset(NaOH)hArr underset("Sodium diazoate (does not couple)")(C_(6)H_(5)-N=N-O^(-)NA^(+))`
On the other hand, in highly acidic conditions, aniline gets converted into anilinium ion. as a result, aniline is no longer nucleophilic acid hence will not couple with diazonium chloride. therefore, the reaction is carried out under MILD conditions, i.e., pH 4-5.
`underset("Aniline")(C_(6)H_(5)NH_(2))+H^(+) to underset("Anilinium ion (does not couple)")(C_(6)H_(5)-overset(+)(N)H_(3))`
Discussion
22448.

Which of the following does not contain C_(sp^(3))-X bond?

Answer»



`CH_(3)CH=CH-OVERSET(CH_(3))overset("|")(CH)-X`

ANSWER :B
Discussion
22449.

Which one of the following is not a bioindicator of water pollution

Answer»

Sludge-worms
Blood-worms
Stone files
Sewage fungus

Answer :C
Discussion
22450.

Write the monomer units of bakelite.

Answer»

SOLUTION :PHENOL `(C_6H_5OH)` and FORMALDEHYDE (HCHO).
Discussion