Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

22601.

Write the products in the following:

Answer»

SOLUTION :
22602.

What is the coordination number of Ni in nickel DMG complex?

Answer»

2
3
6
4

Answer :D
22603.

Write ionicreaction for the reaction between MnO_(4)^(-) ions and oxalate ions at 333K.

Answer»

SOLUTION :`2MnO_(4)^(-)+16H^(+) + 5C_(2)O_(4)^(2-) overset("Heat")(rarr) 2Mn^(2+) +8 H_(2)O + 10 CO_(2)`
22604.

Which of these will not react with acetylene

Answer»

NAOH
Ammonical `AgNO_3`
Na
HCl

Solution :NUCLEOPHILES and alkalies normally do not react with ACETYLENE. THUS NaOH does not react
22605.

Which of the following transitional element is found abudently?

Answer»

Zn
Fe
Hg
Au

Answer :B
22606.

Which of the following is an example of Hydrogen bonded molecular solid?

Answer»

ICE
`SO_2`
`N_2`
`CO_2`

ANSWER :A
22607.

Which of the following alkyl halides is used as a methylating agent ?

Answer»

`C_(2)H_(5)CL`<BR>`C_(2)H_(5)Br`
`C_(2)H_(5)I`
`CH_(3)I`

SOLUTION :`CH_(3)I` is used as methylating agent.
22608.

Which of the following is the correct equation

Answer»

`DeltaU=Q-W`
`W=DeltaU+Q`
`DeltaU=W+Q`
NONE of these

Answer :C
22609.

Which of the following compounds will behave as a reducing sugar in an aqueous KOH solution ?

Answer»




ANSWER :A
22610.

Which alkene in the following is most stable?

Answer»

1-butene
2- butene
1- PENTENE
2-pentene

Answer :B
22611.

Which of the following are essential amino acids?

Answer»

VALINE
Lysine
Alanine
Serine

Answer :A::B
22612.

the total number of optical isomers possible for 2,3-dibromobutane is:

Answer»

3
4
2
0

Answer :A
22613.

Which of the following reaction not possible :

Answer»

`KMnO_4 +SO_2 to `COLOUR CHANGE
`K_2Cr_2O_7 + SO_2 to ` Colour change
`KMnO_4 + CO_2 to ` Colour change
`FeCl_3 +SO_2 to ` Colour change

ANSWER :C
22614.

Which of the following is not an antiseptic drug?

Answer»

Iodoform
Dettol
Gammexane
Genatian violet

Answer :C
22615.

Write the Zwitter ion structure of alanine.

Answer»

SOLUTION :Zwitter ion structure of alanine
`^(+)H_(3)N-OVERSET(COOH)overset(|)UNDERSET(R)underset(|)"CH"-COO^(-)`
22616.

Which maximum oxidation state possessed by actinide?

Answer»

`+5`
`+4`
`+7`
`+8`

Answer :C
22617.

Which of the following is not an antiseptic?

Answer»

Bithional
Boric acid
Mercurochrome solution
HISTAMINE

Solution :Histamine is an ANTACID.
22618.

What is meta merism? Give the structure and IUPAC name of metamers of 2-methoxy propane

Answer»

Solution :Metamerism: It is a special type of isomerism in which molecules with same FORMULA, same FUNCTIONAL group, but different only in the nature of the alkyl group ATTACHED to oxygen.
(i) `CH_3 - overset(CH_3) overset(|)O- CH - CH_3-= `2 - methoxy propane
(ii) `CH_3 - CH_2 - O - CH_2 - CH_3-=`Ethoxy ethane
(iii) `CH_3 - O - CH_2 - CH_2 - CH_3-=` 1 - methoxy propane
Ethoxy ethane and 1-methoxy propane are METAMERS of 2-methoxy propane.
22619.

Which one of the following is an antidepressant drug ? Chloramphenicol, Luminal, Bithional

Answer»

SOLUTION :LUMINAL.
22620.

Transition metal and their compounds are used as catalysts in industry and in biological system. For example, in the Contact Process, vanadium compounds in the + 5 state (V_2O_5 or VO_3^(-)) are used to oxidise SO_(2) " to "SO_3 : SO_(2) + 1/2O_2 overset(v_2o_5) rarr SO_(3) It is thought that the actual oxidation process takes place in two stages. In the first step, V^(5+) in the presence of oxide ions converts SO_(2)"to " SO_3 ' At the same time, V^(5+)is reduced to V^(4+) 2V^(5+) + O^(2-) + SO_(2) rarr 2V^(4+) + SO_(3) In the second step V^(5+_ is regenerated from V^(4+) by oxygen : 2V^(4+) + 1/2 O_(2) rarr 2V^(5+) +O^(2-) The overall process is, of course, the sum of these two step : SO_(2) + 1/2 O_(2) rarr SO_(3)Which of the following ion involved in the above process will show paramagnetism?

Answer»

`V^(5+)`
`V^(4+)`
`O^(2-)`
`VO_(3)^(-)`

SOLUTION :`V^(4+) HARR [AR] 3d^-`
22621.

Using IUPAC norms, write the systematic names of the following : (i) [Co(NH_(3))_(6)]Cl_(3) (ii) [PtCl(NH_(3))_(2)(NH_(2)CH_(3))]Cl(iii) [Ti(H_(2)O)_(6)]^(3+) (iv) [Co(NH_(3))_(4)Cl(NO_(2))]Cl (v) [Mn(H_(2)O)_(6)]^(2+) (vi) [NiCl_(4)]^(2-) (vii) [Ni(NH_(3))_(6)]Cl_(2)(viii) [Co(en)_(3)]^(3+) (ix) [Ni(CO)_(4)]

Answer»

SOLUTION :(i) hexaamminecobalt (III) chloride(ii) diamminechlorido (methyl amine) platinum (II) chloride
(iii) hexaaquatitanium (III) ION (iv) tetraamminechloridonitrito-N-COBALT (III) chloride
(V) hexaaquamanganese (II) ion (vi) tetrachloridonickelate (II) ion
(vii) hexaamminenickel (II) chloride(viii) tris (ethane-1, 2-diamine) cobalt (III) ion
(IX) tetracarbonyl nickel (0)
22622.

Which statement's is/are correct ?

Answer»

Physical adsorption is MULTILAYER non-directional and non-specifice
Chemical adsorption takes more time to ATTAIN equilibrium
Physical adsorption is due to FREE valence of atoms
Chemical adsorption is STRONGER than physical adsorption.

Answer :B::C::D
22623.

The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain.

Answer»

Solution :In aqueous solution, KOH is almost completely ionised to give `OH^(-)`ions which being a STRONG nucleophile brings about a substitution reaction on alkyl halides to FORM alcohols. Also, `OH^(-)`ions are highly solvated. This solvation reduces the basic character of `OH^(-)`ions which, therefore, fail to ABSTRACT a HYDROGEN from the `beta`-carbon of the alkyl chloride to form an alkene.
In contrast, an alcoholic solution of KOH contains ALKOXIDE `(RO^(-))` ions which is a much stronger base than `OH^(-)`ions. It preferentially eliminates a molecule of HCl from an alkyl chloride to form alkenes.
22624.

Transition metal and their compounds are used as catalysts in industry and in biological system. For example, in the Contact Process, vanadium compounds in the + 5 state (V_2O_5 or VO_3^(-)) are used to oxidise SO_(2) " to "SO_3 : SO_(2) + 1/2O_2 overset(v_2o_5) rarr SO_(3) It is thought that the actual oxidation process takes place in two stages. In the first step, V^(5+) in the presence of oxide ions converts SO_(2)"to " SO_3 ' At the same time, V^(5+)is reduced to V^(4+) 2V^(5+) + O^(2-) + SO_(2) rarr 2V^(4+) + SO_(3) In the second step V^(5+_ is regenerated from V^(4+) by oxygen : 2V^(4+) + 1/2 O_(2) rarr 2V^(5+) +O^(2-) The overall process is, of course, the sum of these two step : SO_(2) + 1/2 O_(2) rarr SO_(3)Catalytic activity of transition metals depends on

Answer»

CATALYST UNDERGOES changes in oxidation state
catalyst INCREASES the rate constant
catalyst is regenerated in its ORIGINAL form when the reactants form the products
all are correct

Solution :Catalyst CHAGES its oxidation state in the reaction mechanism
22625.

Zinc can be coated on iron to produce galvanised iron but the reverse is not possible .It is because-

Answer»

zinc has HIGHER negative electrode POTENTIAL than IRON
zinc is LIGHTER than iron
zinc has lower MELTING point than iron
zinc has lower negative electrode potential than iron

Answer :A
22626.

Which of the following statement is (are) correct ?

Answer»

The value of equilibrium CONSTANT for a particular reaction is constant under all conditions of temperature and pressure.
The UNIT of `K_(C)` for the reaction.
`H_(2)O(l)hArrH_(2)O(g)` are mol `L^(-1)`
In the reaction
`CaCO_(3)(s)hArrCaO(s) + CO_(2)(g)`.
`[CaCO_(3)] = [CAO] = 1`
`K_(P)` is always greater than `K_(c)` for a particular reaction

Answer :B
22627.

Which one among the following is the major constituent of soda lime glass ?

Answer»

SODIUM oxide
CALCIUM oxide
Calcium carbonate
SILICA

Solution :Glass is MADE exclusively from natural or nature-identical inorganic raw materials , the majority of which exist or can be produced in Germany. Essentially , a total of six natural raw materials are necessary to produce soda-lime glass (sheet glass and container glass) : approx . 70percent quartz sand `(SiO_(2))` , 13 percent soda `(Na_(2)CO_(3))` , 10 percent lime `(CaCO_(3))` and small quantities of dolomite , feldspar and potash.
22628.

The specific conductance of a saturated solution of a salt MX is2.8 xx 10^(-7) Omega^(-1) cm^(-1) and the equivalent conductances at infinite dilution of M^(+1) and X^(-1) ions are 68 and 72 Omega^(-1) cm2 / equivalent respectively Hence, the K_(sp) of MX is found to be

Answer»

`2 xx 10^(-6)`
`4 xx 10^(-12)`
`10^(-12)`
`4 xx 10^(-6)`

Solution :`^^= ^^_(M^(+)) + ^^_(X^(-)) = 68 + 72 , ^^_(M^(+)) = K xx (1000)/(5) (S=M+ " mole/L")`
`68 + 72 = (2.8 xx 10^(-7) xx 1000)/(S) , S = ( 2.8 xx 10^(-7) xx 1000)/(68 + 72) , S = 2 xx 10^(-6)`
`MX IMPLIES M^(+) + X^(-) , K_(SP) = [M^(+)][X^(-)], K_(sp) = (S)(S)`
` K_(SP) = S^(2) = (2 xx 10^(-6))^(2) = 4 xx 10^(-12)`
22629.

What is the percentage of number of ferro ions in the non-stoichiometric compound Fe_(0.93)O.

Answer»


ANSWER :`15%`
22630.

Write the equation involved in the Reimer-Themann reaction.

Answer»

SOLUTION :(i) Reimer-Tiemann REACTION :
22631.

The units of constant 'a' in van der Waals equation is :

Answer»

`dm^(6)`atm `mol^(-2)`
`dm^(3)` atm `mol^(-1)`
dm atm. `mol^(-1)`
atm `mol^(-1)`

SOLUTION :UNITS of .a. = `L^(2)` atm, `mol^(-2)`
`1L = 1 dm^(3)`
Hence units of .a. = `dm^(6)` atm `mol^(-2)`
22632.

When 7.1gm Na_(2)SO_(4) (molecular mass 142) dissolve in 100 ml H_(2)O, the molarity of the solution is

Answer»

2.0 M
1.0 M
0.5 M
0.05 M

Solution :Molarity `=(w XX 1000)/(ml WT. xx "VOLUME ml.")=(7.1xx1000)/(142xx100)=0.5 M`.
22633.

What are inner transition elements ? Decide which of the following atomic numbers are the atomic numbers of the inner transition elements: 29,59,74,95,102,104

Answer»

Solution :In LANTHANOIDS and actinoids, the differentiating ELECTRON enters in antepenultimate shell i.e., f-orbitals.Hence they are called inner TRANSITION ELEMENTS. Elements with atomic number 59,95,102 are inner transition elements.
22634.

Why a dilute aqueous solution of hydrochloric acid cannot be concentrated by evaporation beyond 22.2%?

Answer»

Solution :A soution of hydrogen CHLORIDE in water which contains 22.2% HCI (by weight) forms a constant boiling mixture having boiling POINT 382.8 K. At 382.8 K, the water and HCI gas escape together and there is no change in the COMPOSITION of the solution. DILUTE HCL, therefore, cannot be concentrated by evaporation beyond 22.2%.
22635.

Which of the following is needed by many bacteria to produce folic acid?

Answer»

PABA
DHPS
TNB
GTN

Solution :PABA
22636.

Which of the following salt are insoluble in water ?

Answer»

CHLORIDES of fe and Mn
Nitrates of Ag and Pb
carbonates of Pb and Cu
phosphates of NA and `NH_(4)`

Solution :Carbonates of leadand copper ar insoluble in water
22637.

Which of the following statements is not true about enzyme inhibitors ?

Answer»

INHIBIT the catalytic activity of the enzyme
Prevent the binding of substrate
Generally a strong COVALENT bond is formed between an INHIBITOR and an enzyme
Inhibitors can be competitive or non-competitive.

Solution :Generally, a weak bond such as H-bonding, VAN der Waals. interactions, etc. is formed between the enzyme and the inhibitor.
22638.

What are the general characteristics of acid and base?

Answer»

Solution :(i) Acid tastes sour, turns the BLUE LITMUS to red and reacts with metals such as zinc and PRODUCES hydrogen gas.
(II) Basic tastes bitter, turns the red litmus to blue and SOAPY to touch.
22639.

Which one of the following statements regarding order is correct ?

Answer»

ORDER should be DETERMINED only by experiment.
Order of complex REACTION are less than 3.
Order can be determined from stoichiometric EQUATION.
Order must be a whole NUMBER.

Answer :A
22640.

Which of the following would undergo hydrolysis most readily with aqueous NaOH to form corresponding hydroxy derivatives?

Answer»




ANSWER :A
22641.

Which of the following statements(s) is (are) correct when a mixture of NaCl and K_(2)Cr_2 O_7, is gently warmed with concentrated H_2 SO_4?

Answer»

A DEEP red vapour is EVOLVED.
The vapours when PASSED into NaOH solution gives a yellow solution of `Na_2 CrO_4`
Chlorine gas is evolved.
Chromyl chloride is formed.

Solution :`4NaCl + K_(2) Cr_(2) O_(7) + 6 H_(2) SO_(4) to underset("(Red vapours)") underset("(chromyl chloride)") (2 CrO_(2) Cl_(2)) + 4 NaHSO_(4) + 2 KHSO_4 + 3 H_2O`
`underset("(red vapours)")(CrO_(2) Cl_(2)) + 4 NaOH to underset("(yellow solution)") (Na_2 CrO_4 + 2) NACL + 2 H_(2)O`
22642.

Whatis the significance o f resistance ratio rho_(300k // rho_(4.2) k

Answer»

Solution :Resistance to the flow of ELECTRONS decrease the conductivity of METALS . It DECREASES with INCREASE in , temperature. But presence of impurity in metals increases conductivity. The resistance ratio, at room temperature and at LIQUID he
22643.

What are fuel cells ? Discuss briefly hydrogen-oxygen fuel cell ?

Answer»

Solution :Fuel CELLS. These are voltaic cells in which the reactants are fed continuously to the ELECTRODES. These are designed to convert the ENERGY from the combustion of fuels such as `H_(2),CO,CH_(4)` etc., directly into electrical energy. The common example is hydrogen-oxygen fuel cell as described below:

In this cell, hydrogen and oxygen are bubbled through a porous carbon electrode into concentrated aqueous sodium hydroxide (See Fig.). The diffusion rates of the gases into the cell are carefully regulated to get MAXIMUM efficiency. In the anode compartment hydrogen is oxidised while oxygen in the cathode compartment is reduced. The net reaction is the same as burning of hydrogen and oxygen to form water. The reactions are given below :
At anode :
`2[H_(2)(g)+2OH^(-)(aq)to2H_(2)O(l)+2e^(-)]`
At cathode :
`O_(2)(g)+2H_(2)O(l)+4e^(-)to4OH^(-)(aq)`
Overall reaction :
`2H_(2)(g)+O_(2)(g)to2H_(2)O(l)`
The catalysts (Pt, Ag or Coo) are also added. This cell RUNS continuously as long as the reactants are fed. These fuel cells are more efficient than conventional methods of generating electricity on a large scale by burning hydrogen, carbon fuels because these fuel cells convert the energy of the fuel directly into electricity.
This cell has been used for electric power in the Apollo space programme.
22644.

Write electronic configuration of Cu^(+2)and Co^(+2)

Answer»

Solution :`CU^(+2) [AR]3d^(@) 4S^(@)`
`Co^(+2)=[Ar] 3d^(@)`
22645.

When CO_2 is bubbled into an aqueous solution of Na_2CO_3 the following is formed:

Answer»

`H_2O`
`OH^-`
`NaHCO_3`
NaOH

Answer :C
22646.

The relative lowering of vapour pressure produced by dissolving 71.5 g of a substance in 1000 g of water is 0.00713. The molecular weight of the substance will be

Answer»

<P>`18.0`
342
60
180

Solution :`(P^(@)-P_(s))/(P^(@))=((W)/(m))/((w)/(m)+(W)/(M))`
or `0.00713 = (71.5//m)/((71.5)/(m)+(1000)/(18))`
22647.

Which of the following organic compound gives carbylamine test ?

Answer»

`beta` -NAPHTHOL
BENZOIC acid
Aniline
Dimethylamine.

ANSWER :C
22648.

Zn(s) + Cl_2 (1 atm ) to Zn^(2+) + 2Cl^(-), the E^(0) of the cell is 2.12 V . To increase E

Answer»

`ZN^(2+) ` CONCENTRATION should be INCREASED
`Zn^(2+)` concentration should be decreased
`Cl^(-)` concentration should be increased
partial pressure of `Cl_2` should be decreased.

ANSWER :B
22649.

When silent electric discharge is passed through O_(2) gas, it converts into O_(3) .If the density of the final sample is 20 times the density of hydrogen gas under similar conditions, calculate the mass percent of O_(2) in the final sample.

Answer»


ANSWER :`40%`
22650.

Which one of the following is used as a catalyst in the polymerisation of propylene?

Answer»

`V_(2)O_(5)`
PT
`TiCl_(4)+ Al(C_(2)H_(5))_(3)`
`Fe// MO`

Solution :`TiCl_(4)+ Al(C_(2)H_(5))_(3)`