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23601.

When ethanal is heated with Fehling's solution,it gives a preciptate of

Answer»

CU
CuO
`Cu_(2)O`
`Cu_(2)O + CuO`

SOLUTION :We know that ,
`2 CuO + CH_(3) CHO to Cu_(2)O darr + CH_(3) COOH`.
Thus when ethanal `(CH_(3)CHO)` is heated with Fehling's solution, it gives a red precipitate of cuprous oxide `(Cu_(2)O)`.
Discussion
23602.

Value of Henry'sconstant K_(H)…

Answer»

increases with increases in temperature.
remains constant
first INCRESES, the decreases,

SOLUTION :is the CORRECT answer.
Discussion
23603.

Which of the following is diamagnetic?

Answer»

`[ZN(NH_3)_4]^(2+)`
`[CU(CN)_4]^(2-)`
`[NiCl_4]^(2-)`
`[Ni(NH_3)_4]^(2+)`

Answer :A
Discussion
23604.

Which of the following compound have wrong IUPAC name

Answer»

`CH_(3)-CH_(2)-CH_(2)-COO-CH_(2)CH_(3) RARR` ethyl butanoate
`{:(CH_(3)-CH-CH_(2)-CHO rarr),("|"),(""CH_(3)):}` 3-methyl-butanal
`{:(CH_(3)-CH-CH-CH_(3) rarr),("|""|"),(""OH" "CH_(3)):}` 2-methyl-3-butanol
`{:(""O),("||"),(CH_(3)-CH-C-CH_(2)-CH_(3)rarr),("|"),(""CH_(3)):}` 2-methyl-3-pentanone

Answer :C
Discussion
23605.

Which of the following compounds would undergo S_(N)1 reaction faster and why ?

Answer»

Solution :The (B) will result in the formation of more STABLE BENZYL carbocation and thus will UNDERGO `S_(N)1` REACTION faster.
Discussion
23606.

Xenon is crystallized in the fcc lattice and the edge of unit length is 620 pm. What is the nearest neighbour distance and radius of xenon atom ?

Answer»

Solution : EDGE length, a = 620 PM. For fcc lattice, nearest NEIGHBOUR distance, `d = a sqrt2`
`= (620)/(sqrt2) =(620)/(1.414) = 438.3` pm
For fcc lattice, radius of atom,
`r=(a)/(2SQRT2)=(620)/(2 xx 1.414)`
= 219.25 pm
Discussion
23607.

Which of the following can reduce Tollen's reagent ?

Answer»

`HCOOH`
`C_6H_5NHOH`
`CH_3CHO`
ALLL of these

ANSWER :D
Discussion
23608.

Which of the following gas has the highest heat of combustion

Answer»

Methane
Ethane
Ethylene
Acetylene

Solution :LARGER the NUMBER of C and H atoms, greater is the HEAT of combustion.
Discussion
23609.

Tourmalene is a class of cyclosilicates with general formula. (Ca, K, Na) (Al, Fe, Li, Mg, Mn)_(3)(Al, Cr, Fe, V)_(6) (BO_(3))_(3) (Si, Al, B)_(6)O_(18)(OH, F)_(4) Which of the following is not a correct example of tourmalene ?

Answer»

`CaAl_(3)Fe_(6)(BO_(3))_(3)S_(6)O_(18)F_(4)`
`Ca_(2)Li_(3)V_(6)(BO_(3))_(3)Si_(6)O_(18)(OH)_(4)`
`KMg_(3)Cr_(6)(BO_(3))_(3)Si_(6)O_(18)F_(4)`
`CaAl_(9)(BO_(3)_(3)Si_(6)O_(18)(OH)_(4)`

Solution :You are not expected to have a PRIOR knowledge of tournaline.It is simply a common-sense based question based on adding all the CHANGES.
`(1)+2+3xx3+x xx 6-3xx3+4xx6-2xx18-1xx4`
`=6 xx -14 ne 0` for `x=+2` or `+3` (possible on FE)
`(2)+2xx2+1xx3+3xx6-3xx3+6xx4-18xx2-1xx4=0`
it fits so it is possible
`(3)+1xx1+2xx3+3xx6-3xx3+4xx6-2xx18-1xx4=0`
`(4)+2xx1+9xx3-3xx3+6xx4-2xx18-1xx4=0`
Discussion
23610.

Two bulbs of equal volumes connected through a stopcock, contained 0.7 mole of H_(2) gas at 0.5 atm pressure and 27^(@)C (at the open position of the stopcock). IF the first bulb was heated to 127^(@)C keeping the other at the same temperature, i.e, 27^(@)C, what will be the final pressure and moles in each bubl ?

Answer»

Solution :Let the volume of each bulb be v litres.
For the two connected bulbs : p = 0.5 atm, n = 0.7 moles
T = 27 + 273 = 300 K and VOL. = 2V.
We have, pV = nRT
`0.5(2V) = 0.7 XX 0.0821 xx 300`
V = 17.22 litres
When one of the bulbs is maintained at `127^(@)C`, i.e, 400 K and the other at 300 K, let the moles of `H_(2)` in these bulbes be `n_(1)` and `n_(2)` RESPECTIVELY.
`therefore n_(1) + n_(2) = 0.7` .....(1)
Since stopcock is OPEN, the pressure in each bulb will be the same. Let it be p atm. Thus for the bulb at 400 K.
`p xx V = n_(1) xx 0.0821 xx 400`
or `17.22 p = 32.8 n_(1)`
or `p = 1.90 n_(1)` ......(1)
And for the second bulb at 300 K,
`p xx 17.22 = n_(2)xx 0.0821 xx 300`
`p = 1.42 n_(2)` .......(3)
From equations (1), (2) and (3), we get
p = 0.571 atm, `n_(1) = 0.3` mole, `n_(2) = 0.4` mole.
Discussion
23611.

What is the pH of a 1 M CH_3COONa solution? K_2 of acetic acid = 1.8 xx 10^-5 and K_w = 10^-14 mol^2 litre^-2:

Answer»

2.4
3.6
4.8
9.4

Answer :D
Discussion
23612.

Which of the following is/are correct for aq. lyophilic sols ?

Answer»

Its SURFACE tension is lower than that of `H_(2)O`
Its surface tension is lower than that of
Its surface tension is higher than that of water
Its VISCOSITY is EQUAL to that of water

Answer :A::B
Discussion
23613.

The reduction of nitro compounds is most preferred in the presence of

Answer»

PD/`H_2` in ethanol
Sn + HCl
Linelydivided Ni
iron scrap and HCl

Solution :Reduction with iron scrap and hydrochloric ACID is preferred because `FeCl_2` formed gets hydrolysed to release hydrochloric acid during the REACTION. Thus only a SMALL AMOUNT of hydrochloric acid is required to initiate the reaction.
Discussion
23614.

Which of the following reaction will go faster if the concentration of the nucleophile is increased ?

Answer»



`(CH_3)_3 C Clunderset(CH_3COOH)overset(H_2O)to`

Solution :Rate of `S_N2` reaction INCREASES by INCREASING CONCENTRATION of nucleophile
Discussion
23615.

Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines. (i) (CH_3)_2 CHNH_2 (ii) CH_3 (CH_2)NH_2 (iii) CH_3 NHCH(CH_3)_2 (iv) (CH_3)_3 CNH_2 (v) C_6 H_5 NHCH_3 (vi) (CH_3 CH_2)_2 NCH_3 (vii) m-BrC_6 H_4 NH_2

Answer»

SOLUTION :(i) Propan-2-amine `(1^@)`
(II) Propan-1-amine `(1^@)`
(III) N-methylpropane-2-amine `(1^@)`
(iv) 2-Methylbenzeneamine `(2^@)`
(VI) N-Ethyl-N methylethananmine `(3^@)`
(vii) 3-Bromobenzanamine or 3-Bromoamine `(1^@)`
Discussion
23616.

Which of the following compound does not exist:-

Answer»

`KrF_(2)`
`XeF_(4)`
`NeF_(2)`
`XeO_(3)`

Solution :Only Kr and XE only two element of inert gas form COMPOUND but MAINLY Xe form compound.
Discussion
23617.

Which of the following is acidic ?

Answer»

`In(OH)_(3)`
`Al(OH)_(3)`
`TL(OH)_(3)`
`B(OH)_(3)`.

Answer :D
Discussion
23618.

What is the mole fraction of a solute in 2.5 m aqueous solution ?

Answer»

Solution :2.5 m AQUEOUS solution means 2.5 moles of the solute are present in 1000 G of water, i.e.,
Moles of solute = `2.5,"Moles of SOLVENT"=(1000)/(18)=55.55`
`therefore"Mole fraction of solute in the solution"=(2.5)/(2.5+55.55)=0.043`
Discussion
23619.

Write the construction and working of dry cell.

Answer»


ANSWER :
Discussion
23620.

The simplest formula of a compound containing 21.9% Mg, 27.8% P and 50.3% O by mass is :

Answer»

<P>`MgP_(2) O_(4)`
`Mg_(2) P_(2) O_(7)`
`Mg_(3) P_(4)`
`Mg_(2) P_(3) O_(5)`

Answer :B
Discussion
23621.

Which of the following is widely used as an electrolyte for silver plating ?

Answer»

`K[AU(CN)_2]`
AgCl
`[Ag(NH_(3))_(2)]CL`
`k[Ag(CN)_2]`

ANSWER :D
Discussion
23622.

What happens when: H_2Sgas is passed through CuSO_4 solution.

Answer»

Solution :A black precipitate of copper sulphide FORMS. `CuSO_4 + H_2S rarr H_2SO_4 + CUS`
Discussion
23623.

Which of the following reaction(s) can be used for the preparation of alkyl halides? (I) CH_(3)CH_(2)OH+HCl overset("anhyd. "ZnCl_(2))to (II) CH_(3)CH_(2)OH+HCl to (III) (CH_(3))_(3)COH+HCl to (IV) (CH_(3))_(2)CHOH+HCl overset(ZnCl_(2))to

Answer»

(I) and (II) only
(IV) only
(III) and (IV) only
(I),(III) and (IV) only

Solution :`1^(@) and 2^(@)` alcohols react with HCl only in PRESENCE of anhyd. `ZnCl_(2)` as catalyst while in case of `3^(@)` alcohols, `ZnCl_(2)` is not required. Thus, reaction (II) cannot be USED to prepares ALKYL halides. While all other reactions can be used. in other WORDS, option (d) is CORRECT.
Discussion
23624.

which of the following is hydroxy acid:

Answer»

LACTIC ACID
TARTARIC acid
CITRIC acid
All

Answer :D
Discussion
23625.

What is the action of benzene diazonium chloride on: (a) Phenol in alkaline medium (b) Aniline

Answer»

Solution :(a) Phenol in alkaline medium : Phenol is dissolved in sodium hydroxide solution to give a solution of sodium phenoxide.

The solution is cooled in ice and cold benzene diazonium chloride solution is added. There is a reaction between the dizaonium ion and the phenoxide ion and yellow-orange solution or precipitate is formed.
The product formed is known as azo COMPOUND in which two benzene RINGS are linked by a nitrogen bridge.

(b) ANILINE : sone coloured azo compounds are frequently used as dyes known as azo dyes. The one MADE from PHENYLAMINE (aniline) is known as "aniline" yellow
Discussion
23626.

Which of the following reagents would be best for converting C_(6)H_(5)CO NH_(2) to C_(6)H_(5)CH_(2)NH_(2)

Answer»

`LiAlH_(4)` in ether
(i) `P_(2)O_(5)` & heat, (ii) `LiAIH_(4)` in ether
`H_(2)` & Pt. catalyst
Aqueous NaOBr

Solution :Hoffmann hypobromite `"Rea"^(n)`
Discussion
23627.

When aniline reacts with oil of bitter almonds (C_6H_5CHO) condensation takes place and benzal derivatives are formed . These are known as :

Answer»

IODIDE of MILLON's base
Schiff's REAGENT
BENEDICT reagent
Schiff's bases

Answer :D
Discussion
23628.

The structural formula of ten compounds ,(I) through (X) are drawn below, you may selectany one ofthese structure. Answer the following question about that compound. A. How many chiral centre are present in this compound ? (a) 0(b) 1(c ) 2 (d) 3 (e ) 4 (f) 5 B. Is this compound chiral or achiral ? (a) Chiral(b) Achiral C. What symmetry element are present in this compound ? (a) None(b) Plane of symmetry(c ) Center of symmetry

Answer»


SOLUTION :`{:("Compound", A,B,C),(I,c,a,a),(II,c,b,b),(III,c,a,a),(IV,c,b,b),(V,c,a,a),(VI,c,a,a),(VII,c,a,a),(VIII,E,b,b),(IX,e,a,a),(X,e,b,b):}`
Discussion
23629.

Which of the following reactions is used to make a fuel cell ?

Answer»

`Cd_((s)) + 2Ni(OH)_(3(s)) to CdO(s) + 2Ni(OH)_(2(s)) + H_2O_((l))`
`Pb_((s)) + PbO_(2(s)) + 2H_2SO_(4(aq)) to 2PbSO_(4(s)) + 2H_2O_((l))`
`2H_(2(G)) + O_(2(g)) to 2H_2O_((l))`
`2Fe_((s)) + O_(2(g)) + 4H_((aq))^(2+) + 2H_2O_((l))`

Answer :C
Discussion
23630.

The shape of XeF_(5)^(-) will be

Answer»

square pyramidal
TRIGONAL bipyramidal
planar
pentagonal bipyramidal

Solution :`XeF_(5)^(-)` is `SP^(3)d^(3)` HYBRIDIZED with two lone PAIRS of electrons and HENCE has pentagonal bipyramid geometry and pentagonal planar shape.
Discussion
23631.

The stuctureof majorproductof followingreactionis(##AKS_TRG_AO_CHE_XII_V02_B_C03_E02_105_Q01.png" width="80%">

Answer»




SOLUTION :
Discussion
23632.

Which of the following represents the expression for 3/4 th life of 1st order reaction

Answer»

`(2.303)/(K)log.3//4`
`(2.303)/(k)LOG3`
`(2.303)/(k)LOG4`
`(k)/(2.303)log4`

ANSWER :C
Discussion
23633.

you are supplied with 500 mL each so 2N HCI and 5N HCI. What is the maximym volume of 3M HCI that you can can prpare using only these two solutions ?

Answer»

250 mL
5090 mL
750mL
1000 mL

SOLUTION :For solution, consult EXAMPLE 2,14 (Text PART).
Discussion
23634.

Which one is weakest base

Answer»

AMMONIA
Methylamine
DIMETHYLAMINE
TRIMETHYLAMINE

Solution :`(CH_(3))_(2)NHgtCH_(3)NH_(2)gt(CH_(3))_(3)NgtNH_(3)`
`2^(@)` amine is most basic `1^(@)` amine`3^(@)` amine Ammonia is least basic
Discussion
23635.

Which classof drugs is used in sleeping pills ?

Answer»

Solution :Tranquilizers are essential components of sleeping pills. It is the class of CHEMICAL compounds used for the treatement of stress and mild or EVEN SEVERE mental DISEASES. These relieve anxiety irritability or EXCITEMENT by inducing a sense of well beings.
Discussion
23636.

What is the main cause of charge on a colloidal solution?

Answer»

SOLUTION :The charge on COLLOIDAL particles is mainly because of the preferrential ADSORPTION of common ion of the electrolyte on the SURFACE of the colloidal particles, e.g., `Fe^(3+)` from `FeCl_3` on the surface of `Fe(OH)_3 `particles.
Discussion
23637.

Which of the following alkaline earth metal sulphates has hydration enthalpy higher than the lattice enthalpy?

Answer»

`CaSO_(4)`
`BeSO_(4)`
`BaSO_(4)`
`SrSO_(4)`

Solution :`BeSO_(4)` has HYDRATION ENERGY GREATER than its lattice energy.
Discussion
23638.

Which of the following reactions are correctly interpreted?

Answer»




ANSWER :A::C::D
Discussion
23639.

Which one is an unsaturated compound

Answer»

`C_6H_14`
`C_4H_8`
`C_3H_7OH`
`CH_3OH`

ANSWER :B
Discussion
23640.

Which one of the alcohol cannot be prepared by grignard reagent?

Answer»

METHANOL
ethanol
iso PROPYL alcohol
phenyl methanol

ANSWER :A
Discussion
23641.

Write the structural formula off 4-chloro-2-pentane.

Answer»

Solution :`overset(1)(C)H_(3)overset(2)(C)H=overset(3)(C)H-overset(CL)overset(|)overset(.^(4)C)H-overset(5)(C)H_(3)`.
Discussion
23642.

Which of the following represents a synthetic detergent?

Answer»

`C_(15)H_(31)COOk`
`CH_3-(CH_2)_(16)-COONa`
`C_4H_9COONa`

SOLUTION :
Discussion
23643.

The term order and molecularity are common in chemical kinetics. Write two factor influencing rate of a reaction

Answer»

SOLUTION :CONCENTRATION of REACTANTS and TEMPERATURE
Discussion
23644.

Thiol group is present in

Answer»

Cystine
Cysteine
Methionine
Cytosine

Solution :
Discussion
23645.

What transition in He^(+) ion shall have the same wave number as the first line in Balmer series of hydrogen atom?

Answer»

`4to3`
`6to4`
`6to3`
`6to2`

ANSWER :B
Discussion
23646.

Whichof thefollowingplotis inaccordancewith theArrheniusequation ?

Answer»




ANSWER :A
Discussion
23647.

The temperature of the system decreases in an:

Answer»

ADIABATIC expansion
Isothermal compression
Isothermal expansion
Adiabatic compression

Answer :A
Discussion
23648.

Two particles A and B are in motion. If the wavelength associated with the particle A is 5xx 10^(-8) m , calculate the wavelength of particleB, if its momentum is half of A.

Answer»

<P>

SOLUTION :According to de-Broglie relation,
`lamda = h/p " or " p = h/lamda `
for particle A , `p_A= (h)/(lamda_A)`
Here, `p_A` and `lamda_A`are the momentum and wavelength of particle A.
for particle B `p_B = (h)/(lamda_B)`
Here` p_B` and `lamda_B` are the momentum and wavelength of particle B.
But `p_B = 1/2 p_A`
` THEREFORE (h)/(lamda_B) = 1/2 (h)/(lamda_A)`
`(lamda_A)/(lamda_B) = 1/2 ` or`lamda_B = 2lamda_A`
But `lamda_A = 5 xx 10^(-8) m`
`lamda_B = 2lamda_A = 2 xx 5 xx 10^(-8) m = 10 xx 10^(-8) m= 10^(-7) m`
Discussion
23649.

What is the action of hydrazine on acetone?

Answer»

Solution :ACETONE with hydrazine forms acetone HYDRAZONE.
`UNDERSET("acetone") (CH_(3)-overset(O)overset("||")C-CH_(3))+H_(2)N-NH_(2) overset(H^(+))to underset("acetone hdyrazone") (CH_(3)- overset(""N-NH_(2))overset("||")C-CH_(3)+)H_(2)O`
Discussion
23650.

Which divalent metal ion has maximum paramagnetic character among the first series transition metals ?

Answer»

Solution :`Mn^(2+)` DUE to the presence of MAXIMUM NUMBER (5) of unpaired ELECTRONS.
Discussion