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2351.

Which is not allotrope of carbon?

Answer»

Graphite
Diamond
Soot
Carborundum

Answer :D
2352.

Which of following reducing agent is used to convert carboxylic acid into alcohol ?

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`Na.Hg + H_2O`
`LiAlH_4`
`NaBH_4`
Sn+HCl

Answer :B
2353.

Whichoneof thefollowingcontain a mixtureof glucose ,fructoseand sucrose ?

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SUGARCANE
BEETROOT
HONEY
Mango

Answer :C
2354.

What is the purpose of adding plasticizers in paing manufacturing process ?

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They act as a FILM -forming constituent
They reduce the VISCOSITY
They prevent the polymerization and condensation
They PROVIDING elasticity to the film and minimize its cracking

Solution :The purpose of adding plasticizers in paing MANUFACTURING process is provided elasticity to the film and MINIMISE its cracking.
2355.

The reagent NH_4C1 and aq.ammonia will precipitate:

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`CA^(2+)`
`Al^(3+)`
`Mg^(2+)`
`ZN^(2+)`

Answer :B
2356.

The useful by-products, obtained in the solvay process of manufacturing sodium carbonate, are

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Quick lime and `CO_(2)`
`NaHCO_(3)` and `NH_(4)CL`
`NH_(4)Cl`SOLUTION and quick lime
`NaHCO_(3)` and `CO_(2)`

ANSWER :C
2357.

Which of the following statement is/are false for [TiCl_(4)]" and "[FeCl_(4)]^(-) ?

Answer»

Both tetrahedral and diamagnetic.
Both tetrahedral but FORMER is diamagnetic and later is PARAMAGNETIC.
Square PLANAR and tetrahedral respectively and both are paramagnetic.
Solutions of both complexes are coloured.

Solution :`[FeCl_(4)]^(-)` is paramagnetic.
2358.

Which of the following is not correct :

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Ethylamine and aniline both have `NH_2` group
Ethylamine and aniline both dissolve in HCl
Ethylamine and aniline both react with `CHCl_3`
Ethylamine and aniline both react with `HNO_2` to GIVE HYDROXY compounds in cold

Answer :D
2359.

The shape of XeF_(5)^(+) is :

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TRIGONAL bipyramidal
Square PYRAMIDAL
PENTAGONAL
DISTORTED pentagonal bipyramidal

ANSWER :B
2360.

When 1.0 ml of dil H_2SO_4 is added to 100 ml of a buffer solution of pH :

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BECOMES 7.0
is LESS than 7.0
is more than 7.0
docs not CHANGE

ANSWER :D
2361.

the two compounds pentaamminesulphatocobalt (III) bromide and pentaamminesulphatocobalt (III) chloride represent:

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LINKAGE isomersm
Ionization isomerism
Coordination isomerism
No isomerism

Solution :Complexes `[CO(SO_(4))(NH_(3))_(5)]Br and [Co(SO_(4))(NH_(3))_(5)]CL` are not any isomers to each other.
2362.

Which of the following can exhibit optical isomerism?

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1, 1-Dichloropropane
2, 2-Dichloropropane
1, 3-Dibromopropane
1, 2-Dichloropropane

ANSWER :D
2363.

Urea forms an ideal solution. Determine the vapour pressure of an aqueous solution containing 10 per cent by mass of urea at 40^(@)C=55.3mm Hg).

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Solution :Given`10` per CENT by mass of UREA solution means `10g` urea is dissolved in `100g` of solution
Mass of solute (urea) `=10g`
Mass of SOLVENT (water) `=90g`
Vapour pressure of pure solvent `55.3mm Hg`
Asked vapour pressure of solution `=?`
Formulae: `(P_(A)^(0)-P_(A))/(P_(A)^(0))=(W_(B)//M_(B))/(W_(A)/(M_(A))+(W_(B))/(M_(B)))`
EXPLANATION: `P_(A)^(0)=` vapour pressure of pure solvent, `P_(A)=` vapour pressure of solution
`W_(B)=` Mass of solute, `M_(B)=` Molecular weight solute, `W_(A)=` Mass of solvent
`M_(A)=` Molecular weight of solvent
`(P_(A)^(0))/(P_(A)^(0))=(10//60)/(90/(18)+(10)/(60))=(1)/(31)`
`1-(P_(A))/(P_(A)^(0))=(1)/(31) rArr (P_(A))/(P_(A)^(0))=1-(1)/(31)=(30)/(31)`
`P_(A)=(55.3xx30)/(31)=(1659)/(31)=53.21mm Hg`.
2364.

Using the concept of Z_("eff") (from Slater's rule). Explain the following : "In obtaining the electronic configuration of V^(+) from that of V, an e^(–) is removed from 4s and not from 3d."

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SOLUTION :`Z_("EFF") = 4.3 `
2365.

What are the important concepts of catalysis that adsorption theory explains?

Answer»

Solution :The adsorption theory explains the following
(i) Increase in the activity of a CATALYST by increasing the surface area. Increase in the surface area of metals and metal oxides by reducing the particle size INCREASES the RATE of the reaction. (II) The action of catalytic poison OCCURS when the poison blocks the active centres of the catalyst. (iii) A promoter or activator increases the number of active centres on the surfaces.
2366.

Which of the following diols would cleave into two fragments with HIO_(4)

Answer»

1,3-hexanediol
2,4-hexanediol
1.6-hexanediol
3,4-hexanediol

Solution :`CH_(3) -CH_(2) - UNDERSET(OH) underset(|)CH- -underset(OH) underset(|)CH-CH_(2) -CH_(3) overset(HIO_(4)) to `
`2CH_(3)-CH_(2)-CHO`
2367.

What is the possible product of the reaction in which 1 mole of HNO_3 is reduced by absorption of 4 moles electrons?

Answer»

`0.5 "MOLE of" N_2`
`0.5 "mole" of N_2O`
1 mole of `NO_3`
1 mole of `NH_3`

ANSWER :B
2368.

Which of the following are clectrophilc?

Answer»

`BF_(3) `
`: "CCl"_(2)`
`I^(-)`
`overset(..)(NH_(3))`

Solution :(a, B): Electron DEFICIENT species or a species having +ve charge are electrophiles.
2369.

Valueof magneticmomentof a divalentmetalion is5.92 BM.Toalnumberofelectron in itsatomwould be "_________"

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24
25
26
27

Answer :B
2370.

What do you mean by chirality centre ?

Answer»

Solution :The CENTRAL carbon ATOM whose all four VALENCIES are satisfied by different atoms or group of atom is called chirality CENTRE.
2371.

Vant hoff factor of BaCl_(2) of conc. 0.01 M is 1.98. Percentage dissociation of BaCl_(2) on this conc. Will be

Answer»

49
69
89
98

Solution :`{:(,BaCl_(2),HARR,Ba^(2+),+,2Cl^(-)),("Initially",1,,0,,0),("After dissociation",1-alpha,,alpha,,2alpha):}`
Total `= 1 - alpha + alpha + 2alpha = 1 + 2 alpha`
`alpha = (i-1)/(m-1) = (1.98 - 1)/(3 - 1) = (0.98)/(2) = 0.49`
m= NUMBER of particles in solution
For a mole `alpha = 0.49`
For 0.01 mole `alpha = (0.49)/(0.01) = 49`.
2372.

Which of the following is the weakest base

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NaOH
`Ca(OH)_(2)`
`NH_(4)OH`
KOH

Solution :`NH_(4)OH` gives minimum `OH^(-)` ion. So it is a weak BASE.
2373.

The value of Delta H^(@) for the reaction Cu^(+) (g) + I^(-) (g) to Cu(g) is -446 kJ mol^(-1) . If the ionization energy of Cu (g) is 745 kJ mol^(-1) and the electron affinity of I(g) is -295 kJ mol^(-1) , then the value of Delta H^(@) for the formation of one mole of Cu I (g) and Cu(g) and I(g) is -

Answer»

`-446` kJ
450 kJ
594 kJ
4 kJ

ANSWER :D
2374.

Which resonating struction is most stable ?

Answer»




ANSWER :C
2375.

What is used as washing solution for eyes to free them from microorganism ?

Answer»

Iodine
`KMnO_(4)` 
Bithionol
Dilute solution of BORIC ACID 

Solution :Dilute solution of boric acid
2376.

Why can we not determine the order of a reaction by taking into consideration the balanced chemical equation ?

Answer»

Solution :Balanced chemical EQUATION often leads to incorrect order or rate law.For example,the following reaction appears to be a tenth order reaction.
(i)`CHCL_(3)+Cl_(2)toCCl_(4)+HCl`
Experimental rate equation :k`[CHCl_(3)][Cl_(2)]^((1)/(2))`
(II)`KClO_(3)+6FeSO_(4)+3H_(2)SO_(4)toKCl+3H_(2)O+3Fe_(2)(SO_(4))_(3)`
However,this is ACTUALLY a second order reacton Actually the reaction is complex and occurs in several steps.The order of such reaction MECHANISM order is determined experimentally and gives the actual depence of obsevred rate of reaction on the concentration of reactants.
2377.

Which of the following would enable you to remove SO_(4)^(2–) ions from a mixture of SO_(4)^(2-),C_(2)O_(4)^(2-) and Cl^(–) ions?

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NaOH
KOH
` BA(OH)_(2)`
`BaSO_(4)`

ANSWER :C
2378.

Which is heaviest among the following

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Iron
Copper
GOLD
Silver

Solution :Gold, `[XE]5D^(10)6s^(1).`
2379.

Two ores A1 and A2 of a metal M show the following reactivity: A_(1)=CuCo_(3).Cu(OH)_(3),S=Cu P=Cu_(2)I_(2): G=SO_(2) . Then A_(2) is

Answer»

`CU(OH)_(3)`
`CUO`
`CuCO_(3)`
`Cu_(2)S`

ANSWER :D
2380.

Two reactions of the same order have equal pre-exponential factors, but their activation energies differ by 24.9 kJ per mole. Calculate the ratio between the rate constants of these reactions at 27^@C.

Answer»

SOLUTION :`2.2 XX 10^(-4)`
2381.

Vitamin A deficiency leads to disease known as

Answer»

beri-beri
T.B
Join pain
night blindness

Answer :D
2382.

Which of the following solutions will have maximum freezing point ?

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0.01 M urea
0.01 M KCl
0.01 M `BaCl_(2)`
0.01 M NaCl

Solution :0.01 M urea will have maximum FREEZING POINT because it will have the lowest depression in freezing point ( being non-electrolyte).
2383.

Which of the following M^(4+) cations does not have stable electronic configuration ?

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`CE ^(4+)`
`ND^(4+)`
`Tb ^(4+)`
Both a and B

Answer :B
2384.

What will happen if LiAlH_(4) is added to an ester

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Two units of alcohol are obtained
ONE unit of alcohol ad one unit of acid is obtained
Two units of acids are obtained
None of these

Solution :`R-OVERSET(O)overset(||)(C)-R' overset(AlAlH_(4))R- UNDERSET("Two units of ALCOHOLS")(CH_(3)OH+R'OH)`
2385.

The shape of O_(2)F_(2) is similar to that of

Answer»

`C_(2)F_(2)`
`H_(2)O_(2)`
`H_(2)F_(2)`
`C_(2)H_(2)`

SOLUTION :`H_(2)O_(2)`
2386.

Which of the following statements are correct? (i)Smaller the gold number of lyophiliccolloid, the larger will be its protective power. (ii) Lyophilic sols, in contrast to lyophobic sols caneasily coagulate on addition of small amounts of electrolytes.(iii) Ferric chloride solution is used to stop bleeding from a fresh cut because it coagulates the blood. (iv) The flocculation value of arsenious sulphide solis independent of the anion of the coagulating electrolyte.

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(i),(ii) and (iii)
(i),(iii) and (IV)
(ii),(iii) and (iv)
(i) , (ii) and (iv)

SOLUTION : Lyophilic SOLS are stable and do not COAGULATE easily.
2387.

Which pair of substances gives same gaseous product, when these reactwith water

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Ca and `CaH_(2)`
NA and `Na_(2)O_(2)`
K and `KO_(2)`
BA and `BaO_(2)`

Solution :`Ca+2 H_(2)O to Ca(OH)_(2) +H_(2)`
`CaH_(2) +2H_(2)O to Ca(OH)_(2) +2H_(2)O`
2388.

____is formed when acetic acid is treated with lime water and the product is dry distilled

Answer»

ACETIC ACID
ETHYL AMINE
`C_2H_5OH`
Acetamide

Answer :A
2389.

The shape of CrO_(4)^(2-) is ….and Cr atom involves.l..hydrization.

Answer»

SQUARE PLANAR, `DSP^(2)`
tetrahedral, `sp^(3)`
square planar, `d^(2)sp^(3)`
linear, sp.

Answer :B
2390.

Which among the following is used as solder.

Answer»

CU and Pb
Zn and Cu
Pb and Sn
Fe and Zn

Answer :C
2391.

Which of the following complex acts as reducing agent based on Sidgwick EAN rule?

Answer»

`[Mn(CO)_(5)]`
`[Mn_(2)(CO)_(10)]`
`[Mn_(CO)_(6)]`
`[V(CO)_(6)]^(-)`

SOLUTION :`[UNDERSET(EAN=37)(Mn(CO)_(6)]]to underset(EAN=36)[Mn(CO)_(6)]^(+)+E^(-)`
2392.

What will happen when alum is added in water ?

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It FORMS aqua compounds and it removed.
Sulphur separates sand particles in form of PRECIPITATES.
ALUM converts insoluble impurities into soluble one
It coagulate UNNECESSARY particles 

SOLUTION :It coagulate unnecessary particles
2393.

The same two separate electrolytic was passed through two separate electrolytic cells containing solutions of nickel nitrate and chromium nitrate respectively . If 0.3 g of nickel was deposited in the first cell , the amount of chromium deposited is (At.mass of Ni= 59 , Cr = 52)

Answer»

`0.1` g
`0.17` g
`0.3g`
`0.6g`

SOLUTION :`("WT. of NI")/("Wt. of CR") = ("Eq. of mass of Ni")/("Eq. of mass of Cr")`
`(0.3)/("Wt. of Cr") = (59//2)/(52//3)` or Wt. of Cr = 0.17 g .
2394.

To an acid solution of an anion a few drops of KMnO_(4) solution are added. Which of the following, if present will not decolourise the KMnO_(4) solution

Answer»

`NO_(2)^(-)`
`S^(2-)`
`CL^(-)`
`CO_(3)^(2-)`

SOLUTION :EXCEPT `CO_(3)^(-)` all other ions are reduced by `KMnO_(4)` solution.
2395.

Why are powdered substances more effective adsorbents than their crystalline forms ?

Answer»

Solution :Adsorbate in the POWDER FORM are more effective than its CRYSTALLINE form because, when a substance is in powder form its surface area INCREASES and physical adsorption is in directly PROPORTIONAL to its surface area.
2396.

What happens when methyl bromide is treated with sodium in the presence of dry ether.

Answer»

Solution :The reactions are explained as under :
`UNDERSET("Methyl bromide") (CH_(3) - Br + 2 Na + Br) - CH_(3) underset(("WURTZ REACTION ")) overset("Dry ether") to underset("Ethane") (CH_(3) - CH_(3) + 2 NaBr ) `
2397.

Write the structures of the products of the following reactions

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SOLUTION :
2398.

Write the structures of the products of the following reactions

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SOLUTION :
2399.

Which of the following is not a consequence of the Lathanoid contraction ?

Answer»

5D SERIES elements have a higher IE, than 3D or 4d series
Zr and Hf have a comparable size
Zr and Hf occurs together in the EARTH crust in their minerals
High density of the period 6 elements

Answer :D
2400.

Write the structures of the products of the following reactions

Answer»

SOLUTION :