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31551.

The correct order of ionic radii is :

Answer»

` I^+ GT I^(-) >I`
`I gtI^+gtI^-`
`I^+gtIgtI^-`
`I^(-)>IGTI^+`

ANSWER :D
Discussion
31552.

The correct order of increasing strength of compounds (1) CH_(3) COOH ""(2) NO_(2)CH_(2)COOH (3)CF_(3) COOH""(4) C_(2)H_(5) - COOH

Answer»

`4 GT 3 gt 2 gt 1`
` 3 gt 2 gt 1 gt 4`
` 3 gt 1 gt 2 gt 4`
` 3 gt 4 gt 2 gt 1`

ANSWER :B
Discussion
31553.

The correct order of increasing solubility of AgCl in (A) water, (B)0,1 M NACI, (C)0.1 M, BaCl2, (D)0,1 M NH_(3) is

Answer»

`DgtAgtBgtC`
`DgtCgtBgtA`
`BgtAgtDgtC`
`AgtDgtBgtC`

Solution :The SOLUBILITY decreases by COMMON ion EFFECT.
`A,[Cl^(-)]=0,B,[Cl^(-)]=0.1`
`C,[Cl^(-)]=0.2,D,[Cl^(-)]=0`
[Soluble complex is formed `[Ag(NH_(3))_(2)]Cl`]
Discussion
31554.

The correct order of increasing thermal stabilities of the compound is (i)K_2CO_3 , MgCO_3 (ii), CaCO_3 (ii) and BeCO_3 (iv) is:

Answer»

IltIIltIIIltIV
IVltIIltIIIltI
IVltIIltIltIII
IIltIVltIIIltI

Answer :B
Discussion
31555.

The correct order of increasing %s-character in the hybrid orbitals of following molecule/ion is :- (I) CO_(3)^(-2) (II) XeF_(4) (III) I_(3)^(-) (IV) NCl_(3) (V) BeCl_(2)

Answer»

`II LT III lt IV lt I lt V`
`II lt IV lt IIIlt V lt I`
`III lt II lt I lt V lt IV`
`II lt IV lt III lt I lt V`

ANSWER :A
Discussion
31556.

The correct order of increasing solubility in water is:

Answer»

`KF lt NaF lt LiF`
`NaHCO_(3) lt KHCO_(3) lt RbHCO_(3)`
`K_(2)CO_(3) lt Na_(2)CO_(3) lt Li_(2)CO_(3)`
`LiNO_(3) lt NaNO_(3) lt KNO_(3)`

Answer :B
Discussion
31557.

The correct order of increasing solubility of AgCI in (A) water(B) 0.1 M NaCI (C ) 0.1 M BaCI_2(D) 0.1 M NH_3 is

Answer»

`A LT B lt C lt D`
`B lt C lt A lt D`
`C lt B lt D lt A`
`C lt B lt A lt D`

ANSWER :D
Discussion
31558.

The correct order of increasing s-character (in percentage) in the hybrid orbitals of following molecules/ions is :- (A) CO_(3)^(-2) ""(B) NCl_(3)""(C ) BeCl_(2)

Answer»

`B LT A lt C`
`A lt B lt C`
`C lt A lt B`
`C lt B lt A`

ANSWER :A
Discussion
31559.

The correct order of increasing s-character (in percentage) in the hybrid orbitals of following molecules/ions is : (I)CO_(3)^(2-)(II)XeF_(4)(III) I_(3)^(-)(IV) NCl_(3)(V) BeCl_(2)

Answer»

`IIltIIIltIVltIltV`
`IIltIVltIIIltVltI`
`IIIltIIltIltVltIV`
`IIltIVltIIIltIltV`

SOLUTION :`underset(sp^(3))9CO_(3)^(-) ``underset(sp^(3)d^(2))(XeF_(4))``underset(sp^(3)d)(I_(3)^(-))``underset(sp^(3))(NCl_(3))``underset(sp)(BeCl_(2))`
Discussion
31560.

The correct order of increasing radii of the ions Br^(-), F^(-), O^(2-) and S^(2-) is as follows

Answer»

`Br^(-)ltF^(-)ltO^(2-)ltS^(2-)`
`S^(2-)ltO^(2-)ltF^(-)LTBR^(-)`
`F^(-)ltO^(2-)ltS^(2-)ltBr^(-)`
`F^(-)ltBr^(-)ltO^(2-)ltS^(2-)`

SOLUTION :`F^(-)` and `O^(2-)` are ISOELECTRONIC but NUCLEAR charge of `F^(-)gtO^(2)`. Hence, ionic radius of `F^(-)ltO^(2-)`. So the order is `F^(-)ltO^(2-)ltS^(2-)ltBr^(-)`.
Discussion
31561.

The correct order of increasing reactivity of C-X bond towards nucleophile in the following compounds is: .

Answer»

(II)lt(III)lt(I)lt(IV)
(IV)lt(III)lt(I)lt(II)
(III)lt(II)lt(Ilt(IV)
(I)lt(II)lt(IV)lt(III)

Solution :ARYL HALIDES are less reactive towards nucleophilic substitutions reaction as compared to alkyl halides. In alkyl halides, involving `C-X` bond cleavage, (`S_(N^(1))` mechanism) the reactivity order is : `3^(@) GT 2^(@) gt 1^(@)` among the aryl halides the compound with electron withdrawing `-NO_(2)` group is more reactive as compared to simple aryl halide.t hus, the order of reactivity is:
(I)lt(II)lt(IV)lt(III).
Discussion
31562.

The correct order of increasing reactivity of C –X bond towards nucleophile in the following compound is

Answer»

`IV LT III lt I lt II`
`II lt II lt I lt IV`
`I lt II lt IV lt III`
`II lt III lt I lt IV`

SOLUTION :`I lt II lt IV lt III`
Discussion
31563.

The correct order of increasing oxidizing power in the series

Answer»

`VO_(2)^(+) lt Cr_(2)O_(7)^(2-) lt MnO_(4)`
`Cr_(2)O_(7)^(2-)ltVO_(2)^(+) lt MnO_(4)`
`Cr_(2)O_(7)^(2-)ltMnO_(4) lt VO_(2)^(+)`
`MnO_(4)lt Cr_(2)O_(7)^(2-) ltVO_(2)^(+) `

SOLUTION :`VO_(2)^(+) lt Cr_(2)O_(7)^(2-) lt MnO_(4)`greater the oxidation state, HIGHER is the oxidising power.
Discussion
31564.

The correct order of increasing oxidizing power in the series is

Answer»

`VO_(2)^(+) LT Cr_(2)O_(7)^(2-) lt MnO_(4)^(-)`
`Cr_(2)O_(7)^(2-) lt Vo_(2) lt MnO_(4)`
`Cr_(2)O_(7)^(2-) lt MnO_(4) lt VO_(2)`
`MnO_(4) lt Cr_(2)O_(7) lt VO_(2)`

Answer :A
Discussion
31565.

thecorrectorder of increasing oxidizingpowerin theseries .

Answer»

`VO_(2)^(+) LT Cr_(2)O_(7)^(2-) lt MnO_(4)^(-)`
`Cr_(2) O_(7)^(2-) lt VO_(2)^(+) lt MnO_(4)^(-)`
`Cr_(2)O_(7)^(2-) lt MnO_(4)^(-) lt VO_(2)^(+)`
`MnO_(4)^(-) lt Cr_(2)O_(7)^(2-) lt VO_(2)^(+)`

Solution :`VO_(2)^(+) lt Cr_(2)O_(7)^(2-) lt MnO_(4)^(-)` greater the oxidation state, HIGHER is the oxidising POWER.
Discussion
31566.

The correct order of increasing oxidising power in the series is

Answer»

`VO_(2)^(+) lt Cr_(2)O_(7)^(2-) lt MnO_(4)^(-)`
`Cr_(2)O_(7)^(2-)lt VO_(2)^(+) lt MnO_(4)^(-)`
`Cr_(2)O_(7)^(2-) ltMnO_(4)^(-) lt VO_(2)^(+)`
`MnO_(4)^(-) lt Cr_(2)O_(7)^(2-) ltVO_(2)^(+)`

ANSWER :A
Discussion
31567.

The correct order of increasing order of size is

Answer»

`S LT O lt SE lt C `
`O lt CLT S lt Se`
`O lt Se lt S lt C`
`C lt O lt S lt Se `

Answer :B
Discussion
31568.

The correct order of increasing ionic character is

Answer»

`BeCl_(2)ltMgCl_(2)ltCaCl_(2)ltBaCl_(2)`
`BeCl_(2)ltMgCl_(2)ltBaCl_(2)ltCaCl_(2)`
`BeCl_(2)ltBaCl_(2)ltMgCl_(2)ltCaCl_(2)`
`BaCl_(2)ltCaCl_(2)ltMgCl_(2)ltBeCl_(2)`

ANSWER :A
Discussion
31569.

The correct order of increasing frequency of electromagnetic radiations is

Answer»

`MicrowaveltUVltIRlt'gamma-rays`
`Microwave ltRadiowave lt VISIBLE lt X-rays`
`UVlt RADIOWAVE lt X-rays lt gamma-rays`
`Radiowave ltIR ltVisible ltX-rays`

ANSWER :D
Discussion
31570.

The correct order of increasing field strengths

Answer»

`BR^(-) GT SCN^(-) gt Cl^(-) gt I^-`
`Br^(-) gt SCN^(-) gt Cl^(-) gt I^(-)`
`I^(-) lt Br^(-) lt SCN^(-) lt Cl^(-)`
`I^(-) lt Cl^(-) lt SCN^(-) lt Br^(-)`

ANSWER :C
Discussion
31571.

The correct order of increasing ease of protonation is

Answer»

`II lt III lt IV lt I`
`II lt IV lt III lt I`
`II lt III lt I lt IV`
`II lt I lt III lt IV`.

Solution :the presence of group with `+ R` effect (like `OMe`) INCREASES the BASICITY more at the p-position than ortho- and presence of `- R` group `(NO_(2))` decreases thre basicity. The presence of `+ I` group on N increases the basicity but less as compared to `+ R` group at para position. DUE to the presence of electron WITHDRAWING carbonyl group directly at N-decreases the basicity. So
Discussion
31572.

The correct order of increasing dipole moment of the following compounds is : .

Answer»

`IltIVltIIltIII`
`IVltIltIIltIII`
`IVltIltIIIltII`
`IVltIILtIltIII`

Solution :DIPOLE moment depends UPON POLARITY which is RELATED to the relative position of the substituents in the ring.
Discussion
31573.

The correct order of increasing C-O bond strength of CO,CO_(3)^(2-),CO_(2) is :

Answer»

`CO_(3)^(2-) LT CO_(2) lt CO`
`CO_(2) lt CO_(3)^(2-) lt CO`
`CO lt CO_(3)^(2-) lt CO_(2)`
`CO lt CO_(2) lt CO_(3)^(2-)`

ANSWER :A
Discussion
31574.

The correct order of increasing C-O bond length of CO, CO_(3)^(2-) and CO_(2) is :

Answer»

`CO_(3)^(2-)LT CO_(2)lt CO`
`CO_(2)lt CO_(3)^(2-)lt CO`
`CO lt CO_(3)^(2-)lt CO_(2)`
`CO lt CO_(2)lt CO_(3)^(2-)`

Solution :`CO^(-)` has TRIPLE BOND, `CO_(2)` has about 1.5 bond and `CO_(3)^(2-)` ION has 1.33 bond.
Discussion
31575.

The correct order of increasing C- O bond length of CO, CO_(3) ^(-2)and CO_(2) is :-

Answer»

`CO_(3)^(-2) lt CO_(2) lt CO`
`CO lt CO_(2) lt CO_(3)^(-2)`
`CO lt CO_(3)^(-2) lt CO_(2)`
`CO_(2) lt CO_(3)^(-2) lt CO`

ANSWER :B
Discussion
31576.

The correct order of increasing bond angles in the following species is

Answer»

`ClO_(2)^(-) LT Cl_(2)O lt ClO_(2)`
`Cl_(2)O lt ClO_(2) lt ClO_(2)^(-)`
`ClO_(2) lt Cl_(2)O lt ClO_(2)^(-)`
`Cl_(2)O lt ClO_(2)^(-)`

Solution :
In `ClO_(2)`, CL is `sp^(2)`-hybridized and the bond ANGLE is `118^(@)`. In `Cl_(2)O`, O is `sp^(3)`-hybridized. However, due to repulsions between two big sized Cl atoms, the bond angle increases from `109^(@)`-28' to `111^(@)`. In `ClO_(2)^(-)`, Cl atom is also `sp^(3)`-hybridized but due to lp-bp repulsions, the angle decreases from `1096(@)`-28' to `103^(@)`. Thus the increasing order of bond angles is : `ClO_(2)^(-) lt Cl_(2)O lt ClO_(2)`
Discussion
31577.

The correct order of increasing bond angles in the following species is :

Answer»

`Cl_(2)O LT ClO_(2)^(-) lt ClO_(2)`
`ClO_(2)^(-) lt Cl_(2)IO lt ClO_(2)`
`Cl_(2)O lt ClO_(2)ltClO_(2)^(-)`
`ClO_(2) lt Ckl_(2)O lt ClO_(2)^(-)`

Answer :B
Discussion
31578.

The correct order of increasing bond angles in the following species are:

Answer»

`Cl_(2)O lt ClO_(2) lt ClO_(2)^(-)`
`ClO_(2) lt Cl_(2) lt ClO_(2)^(-)`
`Cl_(2)O lt ClO_(2)^(-) lt ClO_(2)`
`ClO_(2)^(-) lt Cl_(2)O lt ClO_(2)`

Solution :The correct order of INCREASING bond ANGLE is
`Cl_(2)O lt ClO_(2)^(-) lt ClO_(2)`
Discussion
31579.

Thecorrectorderof increasingbollingpointof thefollowingcompound is underset((I))(C_(3) - CONH_(2))underset((II))(CH_(3)COCl) underset((III))(CH_(3)COOCH_(3)) underset((IV))(CH_(3)-overset(O)overset(||)(C) - O- overset(O)overset(||)(C) - CH_(3))

Answer»

` I lt II lt III lt IV`
`II ltIII lt IV lt I`
`II lt IV lt III lt I`
`II lt III lt I lt IV`

SOLUTION :`II lt III lt IV`dueto highestboilingpointbecause of theprsenceof H - BONDING .
Discussion
31580.

The correct order of increasing boiling poitns of compounds : Pentan-1-ol(I), Butan-1-ol(II), Butan-2-ol(III), Ethanol (Iv), Methanol (V), Porpan-1-ol(VI)is

Answer»

I lt II lt III lt IV lt V lt VI
VI lt V lt IV lt III lt II lt I
V lt IV lt VI lt III lt II lt I
V lt IV lt VI lt II lt III lt I

Solution :More the BRANCHING lesser the b.pt.
Discussion
31581.

The correct order of increasing bond angle is

Answer»

`OF_(2)ltClO_(2)ltH_(2)OltCl_(2)O`
`OF_(2)ltH_(2)OltCl_(2)OltClO_(2)`
`OF_(2)ltH_(2)OltClO_(2)ltCl_(2)O`
`ClO_(2)ltOF_(2)ltH_(2)OltCl_(2)O`

Answer :B
Discussion
31582.

The correct order of increasing boiling points is

Answer»

n-butane LT 1-butanol lt n-butyl CHLORIDE lt isobutane
n-butane lt isobutane lt n-butyl chloride lt 1-butanol
isobutane lt n-butyl chloride lt n-butane lt 1-butanol
isobutane lt n-butane lt n-butyl chloride lt 1-butanol.

Solution :Increase in branching decreases SURFACE area of the molecule and therefore, results in lesserVan der Waal's forces . CONSEQUENTLY, isobutane has lesser boiling point than n-butane. Alkyl chlorides have higher boiling than correspondingalkanes because they are polarand stronger dipole-dipole force OPERATE between the molecules of alkylchloride. Alcohols have higher boiling point than corresponding alkyl chloride, becausealcohols molecules are associated through strong H-bonds
Discussion
31583.

The correct order of increasing boiling of the following aqueous solutions 0.0001 M NaCl (I), 0.0001 M Urea (II), 0.001 M MgCl_(2) (III), 0.01 M NaCl (IV) is

Answer»

`I LT II lt III lt IV `
`IV lt III lt II lt I`
`II lt I lt III lt IV `
`III lt II lt IV lt I `

Solution :`Delta T = i xx k_(b) xx m`
`i xx m` of (0.001 M) NaCl is HIGHEST, hence its boiling point will also increase the MAXIMUM.
`0.01 M NaCl, i xx m=2xx0.01 = 0.02`
`0.001 M MhCl_(2), i xx m = 3xx0.001 = 0.003`
`0.0001 M NaCl, i xx m = 2xx 0.0001 =0.0002`
`0.0001 M` urea, `i xx m=1xx0.0001=0.0001`
Discussion
31584.

The correct order of increasing boiling point is

Answer»

`H_(2)S, H_(2)O, H_(2)Te, H_(2)Se`
`H_(2)O, H_(2)S, H_(2)Se, H_(2)Te`
`H_(2)Te, H_(2)Se, H_(2)S, H_(2)O`
`H_(2)S, H_(2)Se, H_(2)Te, H_(2)O`

Solution :As the size increases from S to Te, the VAN der WAALS forces of attraction interacting the molecules `H_(2)M` increase and hence the boiling point increases in that ORDER. However, water has the HIGHEST boiling point because of intermolecular H - bonding. Thus, `H_(2)S` has the lowest boiling point.
Discussion
31585.

The correct order of increasing basicity of the given conjugate bases (R = CH_(3)) is

Answer»

`RCObar(O) lt HC -= bar(C) lt bar(N)H_(2) lt bar(R)`
`RCObar(O) lt HC -= bar(C) lt bar(R) lt bar(N)H_(2)`
`bar(R) lt HC -= bar(C) lt RCObar(O) lt bar(N)H_(2)`
`RCObar(O) lt bar(N)H_(2) lt HC -= bar(C) lt bar(R)`

Solution :Acidic strength ORDER
`CH_(3)-underset(O)underset(||)(C)-OH GT HC -= CH gt NH_(3) gt CH_(4)`
Basic order of conjugate bases is
`CH_(3)COO^(Θ) lt HC -= C^(Θ) lt overset(Θ)(N)H_(2) lt overset(Θ)(C)H_(3)`
Discussion
31586.

The correct order of increasing basicity of the following compound is

Answer»

`I lt II lt III lt IV`
`II lt III lt IV lt I`
`II lt IV lt III lt I`
`III lt II lt IV lt I`.

Solution :`p-OCH_(3)` group has `+ R` effect, and its presence increases basicity. The `p-NO_(2)` group has a STRONG `- R` effect and its presence DECREASES the basicity. Therefore, the strongest base is compound I and the weakest base is the compound III. The compound III is the weakest base due to the presence of `-overset(O)overset("||")(C)-` group

The ORDER of basicity is
`III lt II lt IV lt I`
Discussion
31587.

The correct order of increasing basicity in aqueous solution is

Answer»

`NH_(3) lt C_(6)H_(5)NH_(2) lt (C_(2)H_(5))_(2)NH lt C_(2)H_(5)NH_(2) lt (C_(2)H_(5))_(3)N`
`C_(6)H_(5)NH_(2)ltNH_(3)lt(C_(2)H_(5))_(3)N lt C_(2)H_(5)NH_(2)lt (C_(2)H_(5))_(2)NH`
`C_(6)H_(5)NH_(2)ltNH_(3)ltC_(2)H_(5)NH_(2)(C_(2)H_(5))_(3)N lt (C_(2)H_(5))_(2)NH`
NONE of the above

Answer :B
Discussion
31588.

The correct order of increasing basic nature of the bases NH_(3),CH_(2)NH_(2) and (CH_(3))_(2)NH is-

Answer»

`CH_3NH_2 lt NH_3 lt (CH_3)_(2)NH`
`NH_3 lt CH_3NH_2 lt (CH_3)_(2)NH`
`CH_(3)NH_2 lt (CH_3)_(2)NH lt NH_(3)`
`(CH_3)_(2)NH lt NH_(3) lt CH_(3)NH_(2)`

ANSWER :B
Discussion
31589.

The correct order of increasing acidic strenth is

Answer»

PHENOL < ETHANOL < chloroacetic ACID < ACETIC acid
ethanol < phenol < chloroacetic acid < acetic acid
ethanol < phenol < acetic acid < chloroacetic acid
chloroacetic acid < acetic acid < phenol < ethanol

Answer :C
Discussion
31590.

The correct order of increasing acidic strength is_____.

Answer»

PhenolltEthanolltChloroacetic acidltAcetic acid
EthanolltPhenolltChloroacetic acidltAcetic acid
EthanolltPhenolltAcetic acidltChloroacetic acid
Chloroacetic acidltAcetic acidltPhenolltEthanol

Solution :Due to -I-effect of Cl, chloroacetic acid is a STRONGER acid than acetic acid. Further, due to STABILIZATION of phenoxide ion by resonance and no such stabilization in CASE of ethoxide ion, PHENOL is a stronger acid than ethanol. Thus, the overall acid STRENGTH increases in the order: ethanolltphenolltacetic acidltchloroacetic acid.
Discussion
31591.

The correct order of increasing basic nature for the bases NH_3 CH_3NH_2 and (CH_3)_2 NH in aqueous solution

Answer»

`CH_3NH_2 lt NH_3 lt (CH_2)_2NH`
`(CH_3)_2NH lt NH_3 lt CH_3NH_2`
`NH_3 lt CH_3 NH_2 lt (CH_2)_2NH lt NH`
`CH_3NH_2 lt (CH_3)_2 NH lt NH_3`

Solution :If the ALKYL group 1S bigger than CH3 group there is steric hindrance to H-bonding and hence + 1 effect predominates over H-bonding `2 gt 3 gt 1`
There 18 an important role of the INDUCTIVE effect, solvation effect and steric hindrane of alkyl group. Which decide the basic STRENGTH of alkyl amine in the aqueous state. `(CH_3)_2 NH gt CH_3 OI H_2 gt NH_3`
Discussion
31592.

The correct order of increasing acidic strength is _____.

Answer»

phenol LT ETHANOL lt ethanol lt chloroacetic ACID lt acetic acid
ethanol lt phenol lt chloroacetic acid lt acetic acid
ethanol lt phenol lt acetic acid lt chloroacetic acid
chloroacetic acid lt acetic lt phenol lt ethanol

Answer :C
Discussion
31593.

The correct order of increasing acid strength of the compounds: (A) CH_(3)CO_(2)H (B) MeOCH_(2)CO_(2)H (C) CF_(3)CO_(2)H

Answer»

`B lt D lt ALT C `
` D lt A lt C lt B`
`D lt A lt BltC`
`A lt D lt CLTB `

Answer :C
Discussion
31594.

The correct order of increasing acidic character is

Answer»




ANSWER :C
Discussion
31595.

The correctorderof increaese rate of hydrolysis of the followingcompound is underset((I))(CH_(3)COOEt) underset((II))(C_(2)H_(5)COOEt)underset((III))("iso - pr- COOEt") .

Answer»

`I LT II lt III`
`III lt III lt I`
` I ltIII lt II`
`III lt I lt II`

SOLUTION :`I lt II lt III`dueot stearichindrance .
Discussion
31596.

The correct order of hybridization of the central atom in the following species NH_(3), [PtCl_(4)]^(2-), PCl_(5) and BCl_(3) is

Answer»

<P>`dsp^(2),dsp^(3),sp^(2)` and `sp^(3)`
`sp^(3),dsp^(2),dsp^(3),sp^(2)`
`dsp^(2),sp^(2),sp^(3),dsp^(3)`
`dsp^(2),sp^(3),sp^(2),dsp^(3)`

SOLUTION :Hybridization of N in `NH_(3)=sp^(3),` that of `Pt^(2+)` in `[PtCl_(4)]^(2)=dsp^(2)` that of P in `PCl_(5)=dsp^(3)` and that of B in `BCl_(3)=sp^(2)`
Discussion
31597.

The correct order of hybridisation of the central atom in the following species. NH_(3),XeO_(2)F_(2),SeF_(4),NO_(2)^(+)

Answer»

`SP^(3),sp^(3),sp^(3)d,sp`
`sp^(3),sp^(3)d,sp^(3)d,sp`
`sp^(3),sp^(3)d^(2),sp^(3)d,sp^(2)`
`sp^(2),sp^(3)d,sp^(3)d^(2),sp`

ANSWER :B
Discussion
31598.

The correct order of hydration energy of alkaline earth metal ions is:

Answer»

`Be^(2+) GT MG^(2+) gt Ca^(2+) gt Sr^(2+) gt Ba^(2+)`
`Ba^(2+) gt Be^(2+) gt Ca^(2+) gt Mg^(2+) gt Sr^(2+)`
`Mg^(2+) gt Be^(2+) gt Ba^(2+) gt Ca^(2+) gt Sr^(2+)`
NONE of these

Answer :A
Discussion
31599.

The correct order of equlibrium constants for the reactions is H_(2)CO+H_(2)Ooverset(k_(1))hArrH_(2)C(OH)_(2) CH_(3)CH_(2)CHO+H_(2)Ooverset(k_(2))hArrCH_(3)CH_(2)CH(OH)_(2) CH_(3)COCH_(3)+H_(2)Ooverset(K_(3))hArrCH_(3)C(OH)_(2)CH_(3)

Answer»

`K_(1)gtK_(2)gtK_(3)`
`K_(1)ltK_(2)ltK_(3)`
`K_(1)gtK_(3)gtK_(2)`
`K_(1)ltK_(3)ltK_(2)`

Solution :The reaction are known as hydration of `C=O` group. The bulkier the groups ATTACHED to the C, GREATER is trhe steric effect, the higher will be the energy during the energy changes in hybrid state and the equlibrium is more likely to lie towards the unhydrated compound. The +I- effect of alkyl groups also decreases the reactivity of `C=O` towards uncleophilic ADDITION of water. THUS, the trend in equlibrium constants is `K_(1)gtK_(2)gtK_(3).`
Discussion
31600.

The correct order of first ionisation potential among following elements , Be, B, C, N and O is :

Answer»

B ltBe LT C lt O lt N
B ltBe lt C lt N lt O
B ltBe lt C lt N lt O
Be LTB lt C lt O lt N

Answer :A
Discussion