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31601.

The correct order of first ionisation enthalpy of carbon,nitrogen,oxygen and fluorine is:

Answer»

`CgtNgtOgtF`
`OgtFgtNgtC`
`FgtNgtOgtC`
`FgtOgtNgtC`

ANSWER :C
Discussion
31602.

The correct order of equivalent the electrolyte is dissociated more the correct order of equivalent conductances at infinite dilution in water at room temperature for H^(+),CH_(3)COO^(-) and HO^(-) ions is

Answer»

`HO^(-) gt H^(+) gt K^(+) gt CH_(3)COO^(-)`
`H^(+) gt HO^(-) gt K^(+) gt CH_(3)COO^(-)`
`H^(+) gt K^(+) gt HO^(-) gt CH_(3)OO^(-)`
`H^(+)GTK^(+)gtCH_(3)COO^(-) gt HO^(-)`

Answer :B
Discussion
31603.

The correct order of equivalent conductances at infinite dilution in water at room temperature of H^(+) , K^(+),CH_(3)COO^(-) and HO^(-) ions is

Answer»

`HO^(-) GT H^(+) gt K^(+) gt CH_(3)COO^(-)`
`H^(+) lt HO^(-) gt K^(+) gt CH_(3)COO^(-)`
`H^(+) gt K^(+) gt HO^(-) gt CH_(3)COO^(-)`
`H^(+)gt K^(+) gt CH_(3)COO^(-) gt HO^(-)`

Solution :`H^(+) lt HO^(-) gt K^(+) gt CH_(3)COO^(-)`
Discussion
31604.

The correct order of equivalent conductance at infinite dilution of LiCl, NaCl and KCl is

Answer»

LiClgtNaClgtKCl
KClgtNaClgtLiCl
NaClgtKClgtLiCl
LiClgtKClgtNaCl

Solution :As we go down the group (i.e., from `Li^(+)` to `K^(+)`), the ionic radius INCREASES, DEGREE of solvation DECREASES and hence EFFECTIVE size decreases resulting into increase in ionic mobility. Hence equivalent conductance at infinite dilution increases in the same ORDER.
Discussion
31605.

The correct order of equivalent conductance at infinite dilution of LiCl, NaCl and KCl is:

Answer»

`LiClgtNaClgtKCl`
`KClgtNaClgtLiCl`
`NaClgtKClgtLiCl`
`LiClgtKClgtNaCl`

ANSWER :B
Discussion
31606.

The correct order of equivalentconductance at infinitedilution of LiCI, NaCI and KCI is

Answer»

LiCI GT NACI gt KCI
KCI gt NaCI gt LiCI
NaCI gt KCI gt LiCI
LiCI gt KCI gt NaCI

ANSWER :B
Discussion
31607.

The correct order of E.P. of given solution is …... (i) 0.1 M CH_3COOH_((aq)) (ii) 0.1 M CH_3COOH(C_6H_6) (iii) 0.1 M CF_3COOH_((aq)) (iv) 0.1 M CH_3COONa_((aq))

Answer»

`ivltiiiltiltii`
`ivgtiiigtigtii`
`iiiltivltiltii`
`ivltiltiiiltii`

ANSWER :A
Discussion
31608.

The correct order of equatorial FSF bond angle in the folllowing compound. (I)SF_(4)(II) OSF_(4)(III) H_(2)CSF_(4)

Answer»

`IIIgtIIgtI`
`IgtIIIgtII`
`IgtIIgtIII`
`IIgtIIIgtI`

ANSWER :D
Discussion
31609.

The correct order of energies of d-orbitals of metal ion in a square planar complex is

Answer»

`d_9xy)=d_(YZ)=d_(zx) GT d_(x^(2)-y^(2))=d_(x^(2))`
`d_(x^(2)-y^(2))=d_(x^(2)) gt d_(xy) =d_(yz)=d_(zx)`
`d_(x^(2)-y^(2)) gt d_(x^(2)) gt d_(xy)=d_(yz)=d_(zx)`
`d_(x^(2)-y^(2))gt d_(xy) gt d_(x^(2))gtd_(zx)=d_(yz)`

ANSWER :D
Discussion
31610.

The correct order of energies of d-orbitals of metal ion in a square planar complex is :

Answer»

`d_(XY)=d_(YZ)=d_(zx)gtd_(X^(2)-y^(2))=d_(z^(2))`
`d_(x^(2)-y^(2))=d_(z^(2))=d_(xy)gtd_(yz)=d_(zx)`
`d_(x^(2)-y^(2))gtd_(z^(2))gtd_(xy)gtd_(yz)=d_(yz)`
`d_(x^(2)-y^(2))gtd_(xy)gtd_(z^(2))gtd_(zx)=d_(yz)`

Answer :D
Discussion
31611.

The correct order of E_(M^(2+)//M)^(o) values with negative sign for the four successive elements Cr,Mn,Fe and Co is

Answer»

CrgtMngtFegtCo
MngtCrgtFegtCo
CrgtFegtMngtCo
FegtMngtCrgtCo

Solution :ORDER of standard reduction POTENTIAL
`Mn gt Cr gt Fe gt CO`
(ACCORDING to electrochemical series).
Discussion
31612.

The correct order of E_(M^(2+) //M)^(@) values with negative sign for the four successiveelements Cr, Mn, Fe and Co is

Answer»

`Fe GT Mn gt Cr gt Co`
`Cr gt Mn gt Fe gt Co`
`Mn gt Cr gt Fe gt Co`
`Cr gt Fe gt Mn gt Co`

Solution :`E^(@)` values for `Mn^(2+) //Mn` with NEGATIVE SIGNS are `:`
`Cr = - 0.91 V,Mn= -1.18V, Fe = - 0.44 V, Co= - 0.28 V`
THUS, the order is `Mn gt Cr gtFe gt Co`
Discussion
31613.

The correct order of E_(M^(2+)//M)^(@) Values with negative sign for the four successive elements Cr, Mn, Fe and Co is:

Answer»

`MngtCrgtFegtCo`
`CrgtFegtMngtCo`
`FegtMngtCrgtCo`
`CrgtMngtFegtCo`

Solution :`E_(Mn^(2+),Mn)^(@)=-1.18V,E_(CR^(2+),Cr)^(@)=-0.91V`
`E_(Fe^(2+),Fe)^(@)=-0.44V,E_(CO^(2+),Co)^(@)=-0.28V`
Discussion
31614.

The correct order of E_(m^(2+)//M) values with negative sign for the four successive elements Cr, Mn, Fe and Co is :

Answer»

`Fe GT Mn gt CR gt Co`
`Cr gt Mn gt Fe gt Co`
`Mn gt Cr gt Fe gt Co`
`Cr gt Fe gt Mn gt Co`

ANSWER :C
Discussion
31615.

The correct order of electronegativities of N,O,F and P is

Answer»

<P>F>N>P>O
F>O>P>N
F>O>N>P
N>O>F>P

Solution :Electronegativity INCREASES LEFT to RIGHT in a period and decreases down the group.
Discussion
31616.

The correct order of electron gain enthalpy with negative sign of F, Cl, Br and I, having atomic numbers 9, 17, 35 and 53 respectively is

Answer»

`I GT BR gt CL gt F`
`F gt Cl gt Br gt I`
`Cl gt F gt Br gt I`
`Br gt Cl gt I gt F`

SOLUTION :`Cl gt F gt Br gt I`.
Discussion
31617.

The correct order of electron gain enthalpy with negative sign of F,Cl, Br and I, having atomic number 9,17,35 and 53 respectively is:

Answer»

FgtClgtBrgtI
ClgtFgtBrgtI
BrgtClgtIgtF
IgtBrgtClgtF

Solution :`ClgtFgtBrgtI`
Discussion
31618.

The correct order of electron gainenthalpy values(Delta_(eg)H)fo the halogenatoms is

Answer»

`F lt CI lt BR lt I `
` I lt Br lt F lt CI `
`I LTBR lt CI lt F `
`CI lt Br lt I lt F`

SOLUTION :N/A
Discussion
31619.

The correct order of electron affinity of B, C, N, O is

Answer»

`O gt C gt N gt B`
`B gt N gt C gt O`
`O gt C gt B gt N`
`O gt B gt C gt N`

Solution :`underset(140.9)Ogtunderset(122.3)Cgtunderset(83)Bgtunderset(0)N` Values of ELECTRON affinity increases on going from left to right in periods but the value of electron affinity of `V^(th)` A elements is less than that of `IV^(th)` A ELEMENT, this is due to half filled p-orbital present.
Discussion
31620.

The correct order of E _(m^(2+)//M)^(@) values of which gnegative sign for the four sucessive elements Cr, Mn, Fe and Co is

Answer»

`MN gt Cr gt Fe gt Co`
`Cr gt Fe gt Mn gt Co`
`Fe gt Mn gt Cr gt Co`
`Cr gt Mn gt Fegt Co`

Solution :The VALUE of `E_(Mn^(2)//M) ^(@)` for given metal IONS are
`E_(Mn^(2*)//Mn)* *1.18V.`
`E_(Cr^(2*)//Cr)^(@)* * 0.9V,`
`E_(Fe^(2*)//Fe)^(@)* *0.44V and E_(Ca^(2*)//Co)^(* *) 0.28V.`
The correct order of `E_(M^(2*)//M)^(@)` VALUES without considering negative sign would be
`Mn^(2+)gt Cr^(2+) gtFe^(2+)gtCo^(2+)`
Discussion
31621.

The correct order of dipole moments of HF, H_(2)S and H_(2)O is :

Answer»

`HF LT H_(2)S lt H_(2)O`
`HF lt H_(2)S gt H_(2)O`
`HF gt H_(2)S gt H_(2)O`
`HF gt H_(2)O gt H_(2)S`

Solution :Higher the ELECTRONEGATIVITY DIFFERENCE, higher will be the polarity F is most electronegative followed by Oand then S.
Discussion
31622.

The correct order of ease with which the alcohol dehydrates to form an alkene is ……

Answer»

`3^(@) GT 2^(@) gt 1^(@)`
`2^(@) gt 3^(@) gt 1^(@)`
`1^(@) gt 2^(@) gt 3^(@)`
`3^(@) LT 2^(@) lt 1^(@)`

SOLUTION :`3^(@) gt 2^(@) gt 1^(@)`
Discussion
31623.

The correct order of dipole moment is ?

Answer»

`CH_4 LT NF_3 lt NH_3 lt H_2 O `
` NF_3 lt CH_4 lt NH_3 ltH_2 O`
` NF_3 lt NF_3 ltCH_4 ltH_2 O`
` H_2O ltNH_3 lt NF_3 lt CH_4 `

ANSWER :A
Discussion
31624.

The correct order of dipole moment is :

Answer»

`PCl_(3)F_(2)gtPF_(3)Cl_(2)`

`CH_(3)FltCH_(3)Cl`
`SO_(2)ltSO_(3)`

Solution :`mu_(SO_(3))=0,mu_(SO_(2))ne0`
Discussion
31625.

The correct order of Delta_(0) for the given complexes, would be : (P) [CoF_(6)]^(3-)""(Q) [Co(H_(2)O)_(6)]^(3+) (R) [Co(NH_(3))_(6)]^(3+)""(S) [Rh(NH_(3))_(6)]^(3+)

Answer»

`PgtQgtRgtS`
`PgtQgtSgtR`
`SgtRgtQgtP`
`SgtRgtPgtQ`

ANSWER :C
Discussion
31626.

The correct order of decreasing boiling pointsof the following hydrocarbons is - a) n-butane b) 2-methylbutane c) n-pentane d) 2,2-dimethylpropane

Answer»

`(a) GT (B) gt (C ) gt (d) `
`(b) gt (c ) gt (d) gt (a) `
`(d) gt (c ) gt (b) gt (a) `
`(c ) gt (b) gt (d) gt (a) `

ANSWER :D
Discussion
31627.

The correct order of dehydration of alcohols form ethers is

Answer»

`1^(@) GT2^(@) GT 3^(@)`
`1^(@) lt2^(@) lt 3^(@)`
`2^(@) gt3^(@) gt 1^(@)`
`3^(@) lt1^(@) lt 2^(@)`

Solution :`1^(@) gt2^(@) gt 3^(@)`
Discussion
31628.

The correct order of decreasing strenth of trichloroacetic acid (A), trifluoracetic acid (B), acetic acid (C) and formic acid (D) is

Answer»

`B GT A gt D gt C`
`B gt D gt C gt A`
`A gt B gt C gt D`
`A gt C gt B gt D`

ANSWER :A
Discussion
31629.

The correct order of decreasing third ionisation enthalpy of Ti, V, Cr, Mn is :

Answer»

`Mn gt CR gt V gt TI`
`Ti gt V gt Cr gt Mn`
`Cr gt Mn gt V gt Ti`
`V gt Mn gt Cr gt Ti`

Solution :`Ti LT V lt V lt Ti`
`3d^(2) 3d^(3)3d^(4) 3d^(5)`
Discussion
31630.

The correct order of decreasing reactivity of the given compound towards hydrolysis under identical condition is:

Answer»

`CH_(3)COCl gt CH_(3)CONH_(2)gt (CH_(3)CO)_(2)O gtCH_(3)COOCH_(3)`
`CH_(3)COCl gt (CH_(3)CO)_(2)O gt CH_(3)COOCH_(3) gtCH_(3)CONH_(2)`
`CH_(3)COOCH_(3)gt CH_(3)COCl gt (CH_(3)CO)_(2)O gtCH_(3)CONH_(2)`
`(CH_(3)CO)_(2)O gt CH_(3)COCl gt CH_(3)COOCH_(3) gtCH_(3)CONH_(2)`

Answer :B
Discussion
31631.

The correct order of decreasing polarisability of ion is :

Answer»

`CL^-,BR^-,L^-,F^-`
`F^-,I^-,Br^-,cl^-`
`I^-,Br^-,Cl^-,F^-`
`F^-,Cl^-,Br^-, I^-`

Answer :C
Discussion
31632.

The correct order of decreasing polarity is :

Answer»

`HF GT SO_2 gtH_2O gt NH_3 `
`HFgtH_2OgtSO_2gtNH_3 `
` HFgtNH_3gtSO_2gtH_2O `
`H_2OgtNH_3gtSO_2gtHF`

ANSWER :B
Discussion
31633.

The correct order of decreasing ionic nature of lead dihalides is :

Answer»

`PbF_2 gtPbCl_2 gtPbBr_2 gtPbI_2`
`PbF_2 gtPbBr_2 gtPbCl_2 gtPbI_2`
`PbF_2 ltPbCl_2gtPbBr_2ltPbI_2`
`PbI_2ltPbBr_2 LT PbCl_2ltPbF_2`

ANSWER :A
Discussion
31634.

The correct order of decreasing H-C-H angle in the following molecule is

Answer»

`I gt II gt III`
`II gt I gt III`
`III gt II gt I`
`I gt III gt II`

Solution :(B) : II `gt I gt III`

Look at the structure carefully. In cyclopropane, C-C bonds are bent and not pure `sigma`-bonds. Overlapping is greatest when orbitals overlap "end-on." i.e. VIA `sigma`-bonding. `PI`-bonds overlap laterally. The overlap in cyclopropane is NEITHER end-on nor lateral but in between. So, it is intermediate between `sigma`- and `pi`-bonding.


THUS, the corect order of decreasing H-C-H angle is,II `gt I gt III`
Discussion
31635.

The correct order of decreasing hardness of the following compound is :

Answer»

DIAMOND > BORAZON > CARBORUNDUM > Corundum
Borazon > Diamond > Carborundum > Corundum
Corundum > Carborundum > Borazon > Diamond
None

Answer :A
Discussion
31636.

The correct order of decreasing boiling points of CH_3CONH_2 (A), CH_3COCl (B), CH_3COOH (C ),(CH_3CO)_2O (D) is :

Answer»

AgtDgtCgtB
AgtBgtCgtD
DgtCgtBgtA
None of the above STATEMENT is correct

Answer :A
Discussion
31637.

The correct order of decreasing basicity of the following species is: H_(2)O, OH^(-), CH_(3)OH, CH_(3)O

Answer»

`CH_(3)OH lt H_(2)O lt OH^(-) lt CH_(3)O^(-)`
`OH^(-) gt CH_(3)O^(-) gt H_(2)O gt CH_(3)OH`
`H_(2)O lt CH_(3)OH lt CH_(3)O^(-) lt OH^(-)`
`CH_(3)O^(-) gt OH^(-) gt CH_(3)OH gt H_(2)O`

Answer :D
Discussion
31638.

The correct order of decreasing electronegativity values among the elements I-beryllium, II-oxygen, III-nitrogen and IV-magnesium is

Answer»

`(II)gt(III)gt(I)gt(IV)`
`(III)gt(IV)gt(II)gt(I)`
`(I)gt(II)gt(III)gt(IV)`
`(I)gt(II)gt(IV)gt(III)`

SOLUTION :ELECTRONEGATIVITY VALUES of given elements are as follows:
`{:(Be-1.5(I),Mg-1.2(IV)),(O-3.5(II),N-3.0(III)),(i.e.IIgtIIIgtIgtIV,):}`
Discussion
31639.

The correct order of decreasing boiling points of (A) CH_3CONH_2 (B) CH_3COCl (C) CH_3COOH (D) (CH_3CO)_2O is :

Answer»

`AgtDgtCgtB`
`AgtBgtCgtD`
`DgtCgtBgtA`
NONE of the above

Answer :A
Discussion
31640.

The correct order of decreasing basicity of the following species is : H_(2)O, OH^(-), CH_(3)OH, CH_(3)O-

Answer»

`CH_3OH LT H_2O lt OH^(-) lt CH_3O^(-)`
`CH_3O^(-) GT OH^(-) to CH_3OH gt H_2O`
`H_2O lt CH_3OH lt CH_3O^(-) lt OH^(-)`
`OH^(-) gt CH_3O^(-) gt CH_3OH gt H_2O`

ANSWER :B
Discussion
31641.

The correct order of decreasing acidity of the following is : (I) br>

Answer»

`IgtIIgtIIIgtIV`
`IIgtIgtIIIgtIV`
`IgtIIIgtIVgtII`
`IIgtIgtIVgtIII`.

ANSWER :C
Discussion
31642.

The correct order of decreasing acidity of nitrophenols will be

Answer»

m-nitrophenolgtp-nitrophenolgto-nitrophenol
o-nitrophenolgtm-nitrophenolgtp-nitrophenol
p-nitrophenolgtm-nitrophenolgto-nitrophenol
p-nitrophenolgto-nitrophenol-m-nitrophenol

Solution :`NO_(2)` GROUP does not SHOW -R-effect at m-position, therefore, m-nitrophenol is the weakest acid. DUE to intramolecular H-bonding (i.e., chelation) o-nitrophenol is LESS acidic than p-nitrophenol.
Discussion
31643.

The correct order of decreasing acidic nature of H_(2)O, ROH, CH -= CH and NH_(3) is

Answer»

`CH -= CH gt H_(2)O ROH gt NH_(3)`
`H_(2)O gt ROH gt CH -= CH gt NH_(3)`
`ROH gt NH_(3) gt CH -= CH gt H_(2)O`
`H_(2)O gt ROH gt NH_(3) gt CH -= CH`

Solution :`{:("COMPOUND",,pK_(a)),(ROH,,(16-18)),(H_(2)O,,14),(NH_(3),,4.75 (pK_(b))),(HC -= CH,,26):}`
SMALLER the `pK_(a)` stronger the acid.
`:.` The order of decreasing ACIDIC nature is
`H_(2)O gt ROH gt HC -= CH gt NH_(3)`.
Discussion
31644.

The correct order of decreasing acid strength of trichloroacetic acid (A), trifluoroacetic acid (B), benzoic acid (C) and formic acid (D) is

Answer»

AgtBgtCgtD
AgtCgtBgtD
BgtAgtDgtC
BgtAgtCgtD

Solution :SINCE F is more electronegative than CL, therefore, `CF_(2)COOH(B)` is a stronger acid than `C Cl_(3)COOH`. Further, since +R-effect of `C_(6)H_(5)` group outweighs its -I-effect, therefore, `C_(6)H_(5)COOH(C)` is a weaker acid than HCOOH (D). Thus, the overall acid strength decreases in the order: BgtAgtDgtC.
Discussion
31645.

The correct order of decreasing acid strength of trichloroacetic acid (A), trifluoroacetic acid (B), acetic acid (C) and formic acid (D) is

Answer»

`A GT B gt C gt D`
`A gt C gt B gt D`
`B gt A gt D gt C`
`B gt D gt C gt A`

Solution :`F_(3)C COOH gt Cl_(3)C COOH gt HCOOH gt CH_(3)COOH`, i.e., `B gt A gt D gt C`, i.e., option (c) is CORRECT
Discussion
31646.

The correct order of decreasing acid strength of (A) trichloroacetic acid (B) trifluoroacetic acid (C) acetic acid (D) and formic acidis:

Answer»

`AgtBgtCgtD`
`AgtCgtBgtD`
`BgtAgtDgtC`
`BgtDgtCgtA`

ANSWER :C
Discussion
31647.

The correct order of Cl–O bond order is :

Answer»

`ClO_(3)^(-) LT ClO_(4)^(-) lt ClO_(2)^(-) lt CLO^(-)`
`ClO^(-) lt ClO_(4)^(-) lt ClO_(3)^(-) lt ClO_(2)^(-)`
`ClO^(-) lt ClO_(2)^(-) lt ClO_(3)^(-) lt ClO_(4)^(-)`
`ClO_(4)^(-) lt ClO_(3)^(-) lt ClO_(2)^(-) lt ClO^(-)`

Answer :C
Discussion
31648.

The correct order of chemical reactivity with water according to electrochemical series ………. .

Answer»

`K gt Mg gt Zn gt CU`
`Mg gt Zn gt Cu gt K`
`K gt Zn gt Mg gt Cu`
`Cu gt Zn gt Mg gt K`

Solution :The standard REDUCTION POTENTIAL of `K^(+), Mg^(2+), Zn^(2+), Cu^(2+)` INCREASES in this order.
Discussion
31649.

The correct order of chemical reactivity with water according to electrochemical series is :

Answer»

`K gt Mg gt Zn gt CU`
`Mg gt Zn gt Cu gt K`
`K gt Zn gt Mg gt Cu`
`Cu gt Zn gt Mg gt fK`

ANSWER :A
Discussion
31650.

The correct order of catalytic activity of Cr, V, Fe and Mn metals in increasing order is ….

Answer»

`FE lt Mn lt V lt CR`
`V lt Fe lt Cr lt Mn`
`Cr lt V lt Fe lt Mn`
`V lt Cr lt Mn lt Fe`

ANSWER :D
Discussion