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751.

The radius of the atom is about ....... Times more than the radius of nucleus. (10^(2) , 10^(4) , 10^(5))

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ANSWER :`10^(5)`
752.

The quantity of matter present in an object is called its

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Mass
Volume
Density
Vapoure pressure

Answer :A
753.

The proton is ……… charged.

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SOLUTION :POSITIVELY
754.

The proportion of humidity in Mumbai as compare to Ahmedabad is more. OR We experience more humid after first rain.

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Solution :The concentration of water vapour in the atmosphere is CALLED humidity. At a definite temperature there is a FIXED proportion of water vapour in our surrounding. When it rains, the temperature decreases somewhat, so the speedof evaporation decreases as there is ALREADY more portion of water particles. Hence humidity in Mumbai as compared to Ahmedabad is more.
755.

The property which characterized a colloidal particleis itsability to scatter …………….

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ANSWER :LIGHT
756.

The property to flow is unique to fluids. Which one of the following statements is correct ?

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Only gases behave like fluids
Gases and SOLIDS behave like fluids
Gases and LIQUIDS behave like fluids
Only liquids are fluids.

Solution :The gases as WELL as liquids can behave as fluids. There is hardly and FLUIDITY in solids as the particles are very closely packed.
757.

The property of diffusion is very fast due to

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High speed
LOW speed
LARGE space between them
Both a and C

Answer :D
758.

The properites of a compund different from those of its ……………….

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ANSWER :CONSTITUENTS
759.

The process of turning a liquid mixture into an emulsion is called ________

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ANSWER :Emuulsification.
760.

The process of converting free...................... of the atmosphere into compound of nitrogen is called ..............

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SOLUTION :NITROGEN, nitrogen FIXATION
761.

The process formation of cloud is called……………(evaporation, condensation, sublimation)]

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ANSWER :CONDENSATION
762.

The process drying of wet clothes is called …….. (evaporation,condensation, cooling)

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ANSWER :EVAPORATION
763.

The presence of waterin the human body regulates

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BODY temperature
blood PRESSURE
RESPIRATION
PERSPIRATION

ANSWER :A
764.

The presence of nulceus in an atom was first detected by

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DALTON
Niels BOHR
THOMSON
RUTHERFORD

Answer :D
765.

The postulates of Bohr's atomic model are given below. Arrange them in the correct sequence : (1) As long the electron revolves in a particular orbit, the electron does not lose its energy. Therefore, these orbits are called stationary orbits and the electrons are said to be in stationary energy states. (2) Electrons revolve round the nucleus in specified circualr paths called orbits or shells. (3) The energy associated with a certain energy level increases with the increase of its distance from the nucleus. (4) An electron jumps form a lower energy level to a higher energy level by absorbing energy. But when it jumps from a higher to lower energy level, energy is emitted in the form of electromagnetic radiation. (5) Each orbit or sheel is associated with a definite amount of energy. Hence, these are also called energy levels and are designated as K,L,M and N, respectively.

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13452
23514
25314
21435

Solution :(i) Electrons revolve around the nucleus in specified circular paths called orbits or shells.
(ii) Each orbit or shell is associated with a definite amount of energy. Hence, these are also called energy levels and are designated as K,L,M and N, respectively.
(iii) The energy associated with a certain energy level increases with the INCREASE of its DISTANCE from the nucleus.
(iv) As long as the electron revolves in a particular orbit , the electrons does not lose its energy. Therefore, these orbits are called stationary orbits and the electrons are said to be in stationary energy states.
(v) An electron jumps from a lower energy level to a higher energy level by absorbing energy. But when it jumps from a higher to lower energy level, energy is EMITTED in the form of electromagnetic radiation.
766.

The positive of hydrogen is not justified even in modern table and it is called rogue element why?

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Solution :Hydrogen has only one ELECTRON in the first SHELL .Therefore it becomes stables EITHER by losing an electon like alkali metals or by gaining an electons lilke HALOGENS since its has smiliarties in chemical proterites with alkali metals as well as halogens its position is not hutiifed EVEN in modern periodic table and it is known as rogue element
767.

The porperties which increase on going down the group are_______

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ionisation energy and electro negativity
atom size and ionisation energy
electro negativeity and atomic AIZE
metallic CHARACTER and REDUCING POWER

ANSWER :d
768.

The pigments of a flower can be separted by..................

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ANSWER :CHROMATOGRAPHY
769.

The physical state of water at 273 K, which is the melting point of ice will be observed as..

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SOLID
liquid
vapour
solid as WELL as liquid

Answer :A::D
770.

The phosphate ion is represented by ...............

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SOLUTION :`PO_(4)^(3-)`
771.

The phenomenon of changing of a liquid into vapours at any temperature below its boiling point is called……..

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ANSWER :EVAPORATION
772.

The phenomenon observed when a beam oflight is passed through a colloidal solution is

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Peltier EFFECT
LUMINESCENCE
PHOSPHORESCENCE
TYNDALL effect

ANSWER :D
773.

The percentage composition of a hydrocarbon 'X' is 90 per cent carbon and 10 per cent hydrogen respectively .Write the structural formule of two successive and preceding homologues of X

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Solution :(i) identification of atomic ratio
(ii)calculation of simple atomic ratio from atomic RANO
(iii) calculation of integral ratio and molecular for- mula from simple atomic ratio
(iv) PREDICTION of succeeding and PRECEDING HOMOLOGUES of abovehydrocarbon
774.

The particles present in the nucleus of an atom are-(a). the proton and the electron(b). the electron and the neutron(c). the proton and the neutron(d). none of these

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the PROTON and the ELECTRON
the electron and the neutron
the proton and the neutron
none of these

Answer :C
775.

The particles of steam (water vapour)at 373 K have more…..than that in water at the same temperature. (rigidity, energy, density)

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ANSWER :ENERGY
776.

The particles of ______ solution show Tyndall effect.

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ANSWER :COLLOIDAL
777.

The particles of a colloid can pass through a filter paper

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ANSWER :t
778.

The particle of suspension will be of size.

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ANSWER :GREATER than 100 NM
779.

The ozone layer in the atmosphere absorbs

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ANSWER :F
780.

The order of vapour pressures of four solids is P lt lt R lt Q lt S. Which of the following has the tetrachloride can be separated.

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<P>P
Q
R
S

Solution :RATEOF sublimation is directlyproportional to vapourpressure. Hence, 'S' undergosublimation more easilyat ROOMTEMPERATURE.
781.

The ............ on a proton is equal in magnitudebut opposite in sign to that of an .............

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SOLUTION :CHARGE , ELECTRONS
782.

The numner of protons, neutrons and electrons present respectively in ""_(35)^(80)Br …………… .

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80, 80, 35
35 , 55 , 80
35 , 35 , 80
35 , 45 , 35

Answer :D
783.

The numbers of protons , neutrons and electrons present in an atom of argon are , respectively ,

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18,18 and 22
22,18 and 18
18,22 and 18
18,16 and 18

Answer :C
784.

The number of protons and neutrons is always equal in an atom of an element .

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ANSWER :F
785.

The number of protons and electrons are the same in an atom. Then why is it wrong to say that atomic number of an atom is equal to the number of electrons?

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Solution :The number of protons is GENERALLY equal to the number of ELECTRONS. The number of protons does not change. But the number of electrons can change if the atom loses or galns electrons. THEREFORE the atomic number of an atom is the nubmer of protons and not the number of ELECTRON.
786.

The number of oxygen atoms in 64 g of oxygen is .......... .

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SOLUTION :`2.4088 XX 10^(24)`
787.

The number of oxygen atoms in 20gram of sulphur trioxide is the same as those present in the X g of ozone. The atomic mass of sulphur and oxygen are 32u and 16u respectively. Find the value of X.

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Solution :No. of oxygen atoms in 20g of SULPHUR TRIOXIDE `(SO_(3))`
Molar MASS of `SO_(3)=32+3xx16=80G`
80g of `SO_(3)` have oxygen atoms=`3xxN_(A)`
20g of `SO_(3)` have oxygen atoms= `=(3xxN_(A)xx(20g))/((80g))=0.75N_(A)`
Step-II: Mass (X) of ozone having same no. of oxygen atoms
`"Molar mass of "O_(3)=3xx16=48g`
`3xxN_(A)"oxygen atoms are present in ozone"=48g`
`0.75xxN_(A)"oxygen atoms are present in ozone"=(48g )xx(10.75xxN_(A))/((3xxN_(A)))=12g`
`therfore X=12g`
788.

The number of neutrons present in "_(3)^(7) Li is ……………… .

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ANSWER :4
789.

The number of neutrons in an atom of hydrogen is

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1
2
0
3

Answer :C
790.

The number of proton, neutrons and electrons in the nucleus of ._(11)Na^(23) are respectively

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23
11
34
12

Answer :D
791.

The number of electrons present in the outermost shell of an atom is known as ... .

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ANSWER :VALENCY
792.

The number of electrons .............. or .............. by anatom determines the ............... of the element concerned .

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SOLUTION :LOST , GAINED , VALENCY
793.

The number of electrons in the outermost shell in the atom of an inert element is

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0
1
2
8

Answer :D
794.

The number of bromine molecles required for the Decolurisation of 1 mole of ehtene and etyne are respectively

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ONE and three
two and three
one and two
two and FOUR

SOLUTION :`H_2C=CH_2+Br_2rarrBrH_2C-CH_2Br`
`HC-=CH+2Br_2-H-underset(br)underset(|)overset(Br)overset(|)C-underset(br)underset(|)overset(Br)overset(|)C-H`
One mole of cthcnc requires one mole of BROMINE and one mole of ethyne requires two moles of bro mine for Decolourisation
795.

The number of atoms present in a molecule of a substance is called its_______

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molecularity
ATOMICITY
valency
REACTIVITY

Answer :B
796.

The nucleus of an atom of an element contains 11 protons and 12 neutrons . Determine the atomic number and mass number of the element.

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SOLUTION :ATOMIC number=number of PROTONS =11
MASS number=number of protons+number of neutrons =11+12=23
797.

The nucleus of an atom is massive and positively charged .How will you justify?

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798.

The nucleus of an atom is neutral.

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ANSWER :F
799.

The non-SI and SI units of some physical quantities are given in Column A and Column B respectively. Match the units belonging to the same physical quantity.

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Solution :(a)-(iv), (B)-(iii), (c )-(V), (d)-(ii), (E )-(i)
800.

The negatively charged particle discovered by . J. Thomson is called..... . (proton, neutron. electron)

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ANSWER :ELECTRON