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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 803. |
The molecular mass of H_(2)SO_(4) is 98 amu . Calculate the number of moles of each element in 294 g of H_(2)SO_(4) . |
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Answer» SOLUTION :NUMBER of moles of `H_(2)SO_(4) = (294)/(98) = 3`. From the formula `H_(2)SO_(4)` we know that 1 molecule of `H_(2)SO_(4)` contains 2 ATOMS of H , 1 atoms of S and 4 atoms of O . THUS , 1 mol of `H_(2)SO_(4)` will contain 2 mol of H, 1 mol of S and 4 mol of O atoms . Therefore , in 3 mol of `H_(2)SO_(4)` . number of moles of H = `2 XX 3 = 6` number of moles of O = `4 xx 3 = 12` . |
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| 804. |
The molecular mass of compound is 106 u. Which is that compound? |
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Answer» `CaCO_(3)` = 2(23) + 1(12) + 3(16) = 46 + 12 + 48 = 106 u |
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| 805. |
The molecular mass of ammonia is |
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Answer» 17 g |
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| 806. |
The molecular formula of quicklime is ......... . |
| Answer» Solution :CaO | |
| 808. |
The molecular formula of ethanol is C_(2)H_(5)OH. Find its molecular mass. |
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Answer» 46 u = 2 (12) + 1(16) + 6 (1) = 24 + 16 + 6 = 46u |
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| 809. |
The molecular formula of ethanoic acid is C_(2)H_(4)O_(2). Its empirical formula is |
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Answer» `C_(4)H_(8)O_(2)` |
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| 811. |
The molecular formula of a compound is determined by the valency of the elements present in the compound . |
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| 812. |
The molar ratio of carbon dioxide and water produced by the combustion of one mole of an. Aliphatic hydrocarbon 'X' is 5 : 4. Write the possible structures of X. What happens when 'X' is passed through bromine water? |
| Answer» SOLUTION :The molecular formula of hydrocarbon giving C02 and `H_2O` in 5 : 4 ratio can be `C_5H_8` | |
| 813. |
The mixture of the following substance is made in water. Which will appear semi-transparent (translucent)? |
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Answer» COMMON salt |
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| 814. |
The mixture of sand and ammonium chloride is separated by ______ . |
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Answer» sedimentation |
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| 815. |
The mixture of common salt and sulphur is an example of ____ mixture. |
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| 816. |
The method involved in refining of petroleum is "__________" |
| Answer» SOLUTION :FRACTIONAL DISTILLATION | |
| 817. |
The metallic element, available liquid form at the temperature higher than room temperature, is _____ . |
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| 818. |
The mendelev's periodic table ar and __________ form the anomalopus pair |
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| 820. |
The melting point of a solid is an indication of the ….of the force of attraction betwe particles. |
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| 821. |
The melting point of a non-sublimable solid is 100^(@)C. What do you observe when small piece of this solid is taken in a test tube and placed in boiling water ? |
| Answer» Solution :The solid REMAINS as it is. Water BOILS at `100^(@)`C. Transmission of heat takes place as LONG as thetemperature of the solid is below `0^(@)`C. As soon as the temperature of the solid reaches `100^(@)`C, transmissionof heat from water to the solid stops. HENCE, it does not melt. | |
| 822. |
The maximum number of electrons that can be accommodated in M Shell is |
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Answer» 2 |
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| 824. |
The maximum number of electrons in L shell is 10 . |
| Answer» Solution :CORRECT Statement : The MAXIMUM number of electron in .L SHELL is 8 | |
| 825. |
The maximum number of electorns present in the orbit is respresented by ..... Formula. (3n^(2) , 2n^(2) , 2n) |
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| 827. |
The matter in our surroundings existsin three states, ……. in liquids and …….. in gases. |
| Answer» SOLUTION :SOLID, LIQUID, GASEOUS | |
| 828. |
The mass ratio of hydrogen to oxygen in hydrogen peroxide (H_(2)O_(2)) is ......... . |
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Answer» 1:8 =1:16 |
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| 829. |
The mass ratio of the combining elements in carbon dioxide (CO_(2)) is |
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Answer» `2:8` |
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| 830. |
The mass per unit volume of a substances is called…………..(area, density, pressure) |
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| 831. |
The mass per unit volume of a substance is called density (density = mass / volume). Arrange the following in order of increasing density :Air, Exhaust from chimneys, Honey, Water, Chalk, Cotton and Iron |
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Answer» Solution :The order of increasing densities of the given substances is :Air `lt` Exhaust from chimneys `lt` Cotton `lt` Water `lt` Honey `lt` CHALK `lt` Iron Explanation : (i)Air is mainly a mixture of comparatively light gases like nitrogen, and oxygen, etc., so it has the lowest density. (ii) Exhaust gases from chimneys, in addition to air, ALSO heavier gases like carbon dioxide, SULPHUR dioxide and nitrogen dioxide, etc., so they have slightly higher density than air. (iii)Cotton is a fluffy solid which has a lot of air trapped in its PORES. DUE to lot of trapped air, solid cotton has higher density than exhaust gases from chimneys. (iv) Water is a liquid having quite closely packed particles, so the density of water is higher than that of cotton. (v) Honey is a thick liquid having closely packed heavy particles, so the density of honey is higher than that of water. (vi)Chalk is a porous solid in which the particles are comparatively less closely packed but it has higher density than honey (which is a liquid). (vii) Iron is a highly compact solid in which the particles are very, very closely packed due to which its density is much higher than that of chalk. |
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| 832. |
The mass per unit volume of a substance is called density. (density =mass/ volume) Arrange the following in order of increasing density. air, exhaust from chimneys, honey,water, chalk, cotton and iron. |
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Answer» SOLUTION :AIR < EXHAUST from CHIMNEYS < cotton < WATER< honey |
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| 834. |
(A)The mass of one molecule of a substance is 4.65xx10^(-23)g. What is its molecular mass? What could be substance be? (b)Which have more molecules? 10g of sulphur dioxide (SO_(2)) or 10g of oxygen (O_(2))? |
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Answer» Solution :(a) Mass of one molecules of substance =`4.65xx10^(-23g)` `"Mass of "6.022xx10^(23)"molecules of substance"=6.022xx10^(23)xx(4.65xx10^(-23))=28g` The substances can be carbon MONOXIDE (CO) with molecular mass=12+16=28u or 28g (b) `"MOLAR mass of "SO_(2)=32h+2xx16g=64g` `"64g of sulphur DIOXIDE represent molecules"=6.022xx10^(23)` `"10g of sulphur dioxide represent molecules"=(6.022xx10^(23)xx(10g))/((64g))=9.40xx10^(22)` `"Molar mass of oxygen "(O_(2))=32G ` 32g of oxygen represent molecules =`6.022xx10^(23)` `"10g of oxygen represent molecules"=(6.022xx10^(23)xx(10g))/((32g))=1.88xx10^(23)` |
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| 836. |
The mass of an electron is (1)/(1838) times that of a proton . |
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| 837. |
The mass of a single atom of an element M is 3.15 xx 10^(-23) g . What is its atomic mass ? What could the element be ? |
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Answer» Solution :Gram - atomic mass = mass of `6.022 xx 10^(-23)` atoms = mass of 1 ATOM `xx 6.022 xx 10^(-23)` `= (3.15 xx 10^(-23) G) xx 6.022 xx 10^(23) = 3.15 xx 6.022 g = 18.97 g` `therefore` atomic mass of the element = 18.97 THUS , the element is most likely to be fluorine . |
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| 839. |
The mass number of an atom is 32. There are 6 elec¬trons in the 'M' shell. Write the electron configuration of this element. |
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| 840. |
The mass number of an atom is 32. There are 6 elec¬trons in the 'M' shell. What is the number of neutrons? |
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| 841. |
The mass-mass percentage of solution = ("Mass of solute")/("Mass of solution")xx _____ . |
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| 842. |
The lower is the value of ionsiation potential of an element the greater is its reducing power |
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| 843. |
The list of some colloids is given below. Select them on the basis of type, dispersed phase and dispersing medium. Shaving cream, Milk, Milk of magnesia, Sponge, Jelly, Coloured gemstone, Cloud, Butter, Milky glass, Face cream, Foam rubber, Automobile exhaust, Pumice, Paint, Mud. |
Answer» SOLUTION :Selection of colloids on the BASIS of TYPE, dispersed PHASE and dispersed MEDIUM are given below: 
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| 844. |
The legal measures to prevent plastic pollution come under the _______ Protection Act 1988. |
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Answer» forest |
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| 845. |
The lead pencil contains _________ . |
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Answer» graphite |
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| 846. |
The latent heat of vaporisation of water is : |
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Answer» `2.25 XX 10^(6) J//kg` |
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| 847. |
The latent heat of fusion of ice is : |
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Answer» `33.4 XX 10^(5) J//kg` |
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| 848. |
The kinetic energy of particles in the ............... stateof a substance is maximum |
| Answer» SOLUTION :gasesous | |
| 850. |
The IUPAC name ofCH_3-underset(C_3H_7)underset(|)"CH"-underset(C_2H_6)underset(|)"CH"-underset(C_2H_5)underset(|)"CH"-CH_3 |
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Answer» 3,4 dlmethyl-4-ethyl OCTANE |
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