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901.

The change of a solid directly into gas is called …….. .

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SOLUTION :SUBLIMATION
902.

The change of a liquid into vapour is called ……….

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SOLUTION :VAPORIZATION
903.

The change of a solid into gas is called …… .

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SOLUTION :SOLIDIFICATION
904.

The cation present in NH_(4)OH is

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`OH^(-)`
`NH_(4)^(+)`
`H^(+)`
`NH_(3)^(+)`

Answer :B
905.

The cathode rays are produced when a gas at a very low pressure is subjected to an electric discharge .

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ANSWER :T
906.

The cathode of an electrochemical reaction involves …………………. .

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OXIDATION
REDUCTION
NEUTRALISATION
catenation

Answer :B
907.

The Catalyst used to decrease the rate of decomposition of hydrogen peroxide is ______

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ANSWER :PHOSPHORICACID(`H_3PO_4`)
908.

The bromination of acetylene gives __________ as the final product .

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dibromoethane
TETRABROMOETHANE
tetrabromoethane
dibromoethane

Solution :The BROMINATION of acetylene GIVES TERA BROMO ethane.
909.

The boiling order of boiling points of diethyl ether, acetone and n-butyl alcohol are 35^(@)C, 56^(@)C and 118^(@)C , respectively. Which one is the following correctly represents their boiling points in kelvin scale ?

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306 K, 329 K, 391 K
308 K, 329 K, 392 K
308 K, 329 K and 391 K
329 K, 392 K and 308 K.

Solution :It is the correct representation of the boiling points and is obtained by adding 273 K to the GIVEN temperature.
910.

The boiling point of ethane is, - 88^(@)C.This temperature will be equivalent to :

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285 K
288 K
185 K
361 K

Answer :C
911.

The Bohr model of an atom is given below. Analyse it and find out the following Electron Configuration

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ANSWER :2,8,8
912.

The Bohr model of an atom is given below. Analyse it and find out the following Atomic number

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ANSWER :18
913.

The Bohr model of an atom is given below. Analyse it and find out the following The period and group of the element

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ANSWER :PERIOD - 3 GROUP 18
914.

The Bohr model of an atom is given below. Analyse it and find out the following The common name of the group.

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ANSWER :NOBEL GASES
915.

The best quality caoal with respect to percentage of carbon is "___________"

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SOLUTION :ANTHRACITE
916.

The BEC is formed by cooling a gas of extremely low density, about one hundred thousandth the density of normal air.

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ANSWER :1
917.

The basis of the classifications proposed by Dobereiner, Newlands and Mendeleev was……………….

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ANSWER :ATOMIC MASSES
918.

The average atomic mass of chlorine is 35.5 u.

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ANSWER :TRUE
919.

The average atomic mass of copper is 63.5. It exists as two isotopes which are ._(29)^(63)Cu and ._(29)^(65)Cu. Calculate the percentageof each isotope present in it.

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Solution :LET the PERCENTAGEOF `overset(63)underset(29)Cu` isotope =x
The percentage of `overset(65)underset(29)Cu` isotope =100-x
From the above data the average atomic MASS of Cu=`(63xxx)/(100)+(65xx(10-x))/(100)`
But the given average atomic mass of cu =63.5 `mu`
`therefore (63x XX)/(100)+(65xx(100-x))/(100)=63.5`
63x+6500-65x=6350
-2x=6350-6500=-150
2x=150
x=75`mu`
Percentage of `overset(63)underset(29)Cu` isotipe = 75%
Percentage of `overset(65)underset(29)Cu`=25%
920.

The average atomic mass of an element Y is 35.54. Find the percentages of isotopes ""_(17)^(37)Y and ""_(17)^(35)Y.

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Solution :Let the percentage of `""_(17)^(35)`Y = x
`therefore` Then the percentage of `""_(17)^(35) Y = 100 - x `
Average atomic MASS = `((37 xx x)+(35 xx (100 - x)))/(x + (100- x))`
`therefore 35.5 = (37x + 3500 - 35x)/(100)`
`therefore 3550 = 37x - 35x + 3500`
`therefore` 50 = 2x
THUS, the percentage of `""_(17)^(37)` Y = 25%
the PERCENTAGES of `""_(17)^(35)` Y = 75 %
921.

The average atimic mass of two isopoes with mass numbers A and A+2 is A+0.25. Calculate the percentage abundance of the isotopes.

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Solution :(i) `(n_(1)xxA)+(n_(2)XX(A+2)=(n_1+n_2)(A+0.25)` from
(ii) `87.5% and 12.5%`
922.

The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of isotopes ""_(8)^(16)X and " "_(8)^(18) X in the sample?

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Solution :Let the PERCENTAGE of`""_(8)^(16)` X be x
Then the percentage of`""_(8)^(18)` X is (100-x )
`(16 xx (x)/(100)) + 18 xx ((100 - x)/(100)) = ` 16.2
`therefore (16x + 1800 - 18x )/(100) = 16.2`
`therefore - 2x + 1800 = 16.2 xx 100`
`therefore-2x + 1800 = 1620 `
`therefore - 2x = 1620 - 1800`
`therefore -2x =- 180`
`therefore x = 90`
The percentage of ISOTOP `" "_(8)^(16)` X is 90 and the of `""_(8)^(18)`X is 10.
923.

The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of isotopes ._(8)^(16)X and ._(8)^(18)X in the sample.

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Solution :It is given that the average atomic mas of the sample of element X is 16.2. LET the PERCENTAGE of isotope `._(8)^(18)X` be Y%. THUS the percentage of isotope `._(8)^(16)X` will be `(100-Y)%` therefore
`18xx(y)/(100)+16xx((100-y))/(100)=16.2`
`(18y)/(100)+(16(100-y))/(100)=16.2`
`(18y+1600-16y)/(100)=16.2`
`18Y+1600-16Y=1620`
`2Y+1600=1620`
`2Y=1620-1600`
`-Y=10`
Therefore the percentage of isotope of `._(8)^(18)X` is 10 %
And the percentage of isotope `._(8)^(16)X` is `(100-10)%=90%`.
924.

The atoms of two element A and B contain thesame number of protons but different number of neutrons in their nuclei. What kind of element are A and B?

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SOLUTION :A and B are ISOTOPES
925.

The atomicity of K_(2)Cr_(2)O_(7) is ........

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9
11
10
12

Solution :11
926.

The atomic radius of water is approximately …......... nanometer.

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SOLUTION :`10^(-9)`
927.

The atomic numbers of Ne, Mg. Al and P are 10, 12, 13 and 15. Out of Ne, Mg^(2+),Al^(3+) and P^(3-) , electronic structure of whichelement /ion differs?

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<P>NE
`MG^(2+)`
`Al^(3+)`
`p^(3-)`

Solution :In Ne `Mg^(2+) and Al^(3+)` there are 10 electrons. So their electronic configuration is same. Whie is `P^(3-)` there are 18 electrons. HENCE its electronic configuration differs.
928.

The atomic numbers of certain elements are given below. N=7, O=8, Cl=17 Identify the nature of covalent bonds In the molecules given below O_2

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ANSWER :`O_2` - DOUBLE BOND
929.

The atomic numbers of certain elements are given below. N=7, O=8, Cl=17 Identify the nature of covalent bonds In the molecules given below Cl_2

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ANSWER :`Cl_2`-SINGLE BOND
930.

The atomic number of two elements are given below.Mg = 12,O = 8 Which type of compound we be formed If these two elements combine together?

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ANSWER :IONIC COMPOUND
931.

The atomic numbers of certain elements are given below. N=7, O=8, Cl=17 Identify the nature of covalent bonds In the molecules given below N_2

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ANSWER :`N_2` - TRIPPLE BOND
932.

The atomic number of two elements are given below. Mg = 12, O = 8 Write the electron configuration of these elements.

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ANSWER :Mg - 2, 8, 2 0 - 2, 6
933.

The atomic number of sodium is 11. How many protons are there in the nucleus of sodium atom?How manu electrons does an atom of sodium contain ?How many electrons and protons does an ion of sodium which has a charge of +1 contain ?

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SOLUTION :Protons =11, electrons 11, `Na^(+)` CONTAINS 10 electrons and 11 protons
934.

The atomic number of elements x y and z are (a-z2),a and (a+2) repecitively y is a noble gas (not helium )them (a) prdict the group to whichx y and z belong (b) predict the formula of a molecule formed by x and z

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Solution :(a) As y is a nobles GAS the group of y is 18th group or zero group
X=A-2, group ofX is 16th groupor VI A
Z=A+23,group of Y is 2nd group or IIA
(B)X`rarr` valency =2 (ELECTRONEGATIVE)
Z `rarr` valency =2 (elctropositive)
Hence the formula is ZX
935.

The atomic number of magnesium is 12 and Fluo¬rine is 9. Write the election configuration of these elements.

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ANSWER :`12^(M-2,8,2)` `9^(F-2,7)`
936.

The atomic number of element X is 8, while the atomic number of element Y is 4 . Hence. The valency of these elements is ...... .

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1
2
3
4

Answer :B
937.

The atomic number of calcium is 20. It possesses K, L, M and N shells. Which shel(s) would be Alled incompletely ?

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L, M, N
M, N
N
K, L , M,N

938.

The atomic number of calcium is 20. What is the number of electrons in its M-shell ?

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SOLUTION :`{:(K,L,M,N),(2,8,8,2):}`
`:.` ELECTRONS in M-shell=8
939.

The atomic number of atom is 13. Its mass number is 27. Write the number of electron and neutrons in the atom.

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ANSWER :NUMBER of ELECTRONS = 13
Number of NEUTRONS = `27-13=14`
940.

The atomic number of atom is 13. Its mass number is 27. Write the electron configuration of this element.

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ANSWER :2,8,3
941.

The atomic number of an element that belongs to the IVA group and 4th period is __________

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ANSWER :32
942.

The atomic number of an element is 12. How many protons and electrons are there in an atom of the element ?

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SOLUTION :NUMBER of protons = number of electrons =atomic number =12
943.

The atomic number of an element is 12. What is its valency ?

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SOLUTION :ATOMIC number = 12
`therefore` electronic CONFIGURATION = 2, 8, 2
`therefore` the valency is 2.
944.

The atomic number of 4 elements A,B,C and D are 8,9,10 and 11 , respectively .The order of their atomic volume is

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`AgtBgtCltD`
`AltBltCgtD`
`AgtBltCltD`
`AltBgtCgtD`

ANSWER :C
945.

The atomic number and the mass number of an element M are 12 and 24 respectively . Calculate the number of neutrons in an atom of the element.

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SOLUTION :NUMBER of NEUTRONS =MASS number-atomic number=24-12=12
946.

The atomic masses are always whole numbers .

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ANSWER :F
947.

If the atomic mass of sodium is 23, the number of moles in 46gm of sodium is:

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1
2
`2.3`
`4.6`

ANSWER :B
948.

Assertion : 1 amu is equal to 931.48 MeV. Reason: 1 amu is equal to 1/12th the mass of C^12 atom.

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ANSWER :T
949.

The atomic mass of sodiumis 23. The gram-atomic mass of sodium is ………….

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ANSWER :23 G
950.

The atomic mass of Sodium is 23. The number of moles in 46 g of Sodium is ___

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ANSWER :2