1.

The average atomic mass of an element Y is 35.54. Find the percentages of isotopes ""_(17)^(37)Y and ""_(17)^(35)Y.

Answer»

Solution :Let the percentage of `""_(17)^(35)`Y = x
`therefore` Then the percentage of `""_(17)^(35) Y = 100 - x `
Average atomic MASS = `((37 xx x)+(35 xx (100 - x)))/(x + (100- x))`
`therefore 35.5 = (37x + 3500 - 35x)/(100)`
`therefore 3550 = 37x - 35x + 3500`
`therefore` 50 = 2x
THUS, the percentage of `""_(17)^(37)` Y = 25%
the PERCENTAGES of `""_(17)^(35)` Y = 75 %


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