InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1701. |
Give balanced equations to show the preparation of hydrogen by the following: alkali |
| Answer» SOLUTION :`Pb+2NaOHtoNa_(2)PbO_(2)+H_(2)` | |
| 1702. |
Give an example of the law of constant proportion. |
| Answer» Solution :In ammonia `(NH_(3))`, nitrogen and HYDROGEN are always present in the RATIO 14:3 by mass. | |
| 1703. |
Give an example of (i) gas in liquid solution (ii) gas in gas solution. |
|
Answer» SOLUTION :(i) Soda WATER is an example of GAS in liquid solution. (ii) ATMOSPHERIC air is an example of gas in gas solution. |
|
| 1704. |
Give an example of a mixture which exhibits following characteristics. (a) Two non-mixcible components.(b) Two volatile components with appreciable difference in boiling points. (c ) Two coloured components.(d) Water containing certain suspended particles. (e) Water containing a soluble salt.(f) A volatile and a non-volatile component. |
|
Answer» Solution :(a) A mixture of kerosene and WATER. (b) A mixture of ether (b.p. = `35^(@)C`), and ethyl alcohol (b.p. = `78^(@)C`). (c ) A mixture of blue/black ink. (d) A colloidal solution of starch. (e) A mixture of copper SULPHATE in water. A mixture of ammonium CHLORIDE and sodium chloride. |
|
| 1705. |
Give an example for each of the following statements. a. a compound in which two Covalent bonds are formed b. a compound in which one lonic bond is formed c. a compound in which two Covalent and one Coordinate bonds are formed d. a compound in which three covalent bonds are formed. e. a compound in which Coordinate bond is formed |
|
Answer» Solution :a. Formation of oxygen molecule `(O_(2))` Each oxygen atom has six valence electrons (2,6). These two atoms achieve a stable electronic configuration (octet) by sharing two PAIR of electrons. Hence a double bond is formed in between the two atoms, (b) b. Formation of Magnesium CHLORIDE `(MgCl_2)` Magnesium Chloride `(MgCl_2)` is an ionic compound formed when the magnesium form loses two electrons to gain the noble state which is accepted by chloride ion. c. Formation of coordinate covalent bond between `NH_3 to BF_3` molecules `NH_3 to BF_3` is a compound formed by coordinate covalent bonding. Here one pair of electrons from ammonia molecule is shared with electron deficit boron trifluoride. This type of bonding is also known as Dative bond. d. Formation of NITROGEN molecule `(N_2)` Nitrogen molecule `(N_2)` is formed by three covalent bonds where three PAIRS of electrons are shared between the two to acheive a stable configuraton. (e) c. Formation of coordinate covalent bond in ammonium lon `(NH^(4+))` In ammonia molecule the central nitrogen atom hus five valenceelectrons (2.5) AMONG which three electrons are shared with three hydrogen atoms and still it has an unshared lone pair of electrons. This lone pair electrons are donated to a Hydrogen ion and thus a N-H coordinate covalent bond is formed in ammonium ion molecule `(NH^4+))`. |
|
| 1706. |
Give an example each for the mixture having the following characteristics. (a) gases (b) Two volatile components (c ) Two immiscible liquids. |
|
Answer» Solution :(a) A mixture of naphthalene (volatile) and common salt (non-volatile). The separation can be DONE by sublimation. (b) A mixture of ACETONE boiling point = `56^(@)C`) and water (boiling point = `100^(@)C`) separation can be done by distillation. (c ) A mixture of kerosene oil and water. Separation can be done in a separating funnel. (d) Same as in (a) (E) A mixture of blue/black ink. Separation canbe done by CHROMATOGRAPHY. |
|
| 1707. |
State the law of conservation of mass. |
|
Answer» SOLUTION :When ice melts into water is a physical CHANGE. Take a PIECE of ince in small flash, cork is and weight it. (W(ice) gm). Heat the FALSK gentyl and ice (SOLID) slowly melts into water (liquid). Weight the flash again (water gm). It is found there is no change in the weight i.e.. `W_(("ice")=W_(("water"))` `1ce underline ("Heat" (Delta))` water This shows law of conservation of mass holds true for physical change. |
|
| 1708. |
Give a common example of suspension. |
| Answer» Solution :Muddy WATER is the COMMON EXAMPLE of SUSPENSION. | |
| 1709. |
Geometry of alpha-sulphur is ________________ |
| Answer» SOLUTION :N/A | |
| 1710. |
Generally electron affinity values of elements decrease from top to bottom in a groupof non metallic element .However elements of 2nt period have lowerelectron affinity values than do the corresponding element of 3rdperiod .comment on this statement |
|
Answer» Solution :(i) comparison of atomic size of 2nd and 3rd period elements (ii) effect of number of electrons on size (iii) ENERGY CHANGES that TAKE PALCE by the addition of an electron in the III SHELL and the II shell |
|
| 1711. |
General metallurgical process are given below. Arrange them in correct sequence. (1) conversion of ore to oxide. (2) refining (3) dressing of ore (4) extraction of metal (5) concentration of ore |
|
Answer» 51423 (ii) concentration of ore (III) conversion of ore to oxide (iv) EXTRATION of metal (v) REFINING |
|
| 1712. |
Gaseous substance exerts pressure on the walls of the container. |
| Answer» Solution :The intermolecular forces between the particles in the gaseous form is very much less, and hence the components of this STATE can move freely in the vessel. As the components move freely in the vessel, they strike with each other and also on the WALL of the container. THUS, gaseous substance exerts pressure on the wall of the container. | |
| 1713. |
Galliu is more electronegative of the elements decrease down the group .It is due to ______ |
|
Answer» increase in the atomic size |
|
| 1714. |
From the symbol ""_(20)^(40)Ca, write electronic configuration and valence electrons. |
|
Answer» SOLUTION :Electronic CONFIGURATION: 2, 8, 8. 2. VALENCE electrons : 2. |
|
| 1715. |
From the list, given below, select the correct answers for [Isobars, Isotopes, Efflorescence, Hygroscopy, Charles's law, Boyle's law, Kelvin, Thermal dissociation, Thermal decomposition]. At constant temperature, the volume of a given mass of dry gas is inversely proportional to its pressure. |
| Answer» SOLUTION :Boyle.s LAW | |
| 1716. |
From the list, given below, select the correct answers for [Isobars, Isotopes, Efflorescence, Hygroscopy, Charles's law, Boyle's law, Kelvin, Thermal dissociation, Thermal decomposition]. Atoms of the same element having the same atomic number but different mass numbers. |
| Answer» SOLUTION :ISOTOPES | |
| 1717. |
From the list, given below, select the correct answers for [Isobars, Isotopes, Efflorescence, Hygroscopy, Charles's law, Boyle's law, Kelvin, Thermal dissociation, Thermal decomposition]. A phenomenon where a compound absorbs moisture from the atmosphere when it is exposed to it but not enough to form a solution. |
| Answer» SOLUTION :HYGROSCOPY | |
| 1718. |
From the list, given below, select the correct answers for [Isobars, Isotopes, Efflorescence, Hygroscopy, Charles's law, Boyle's law, Kelvin, Thermal dissociation, Thermal decomposition]. Decomposition of a compound by the action of heat, on cooling, original substance is formed. |
| Answer» SOLUTION :THERMAL DISSOCIATION. | |
| 1719. |
From the given graph, arrange the following in an ascending order : 1. energy of the reactant 2. energy of the product 3. threshold energy 4. activation energy of the backward reaction 5. activation energy of the forward reaction |
|
Answer» 2 1 4 5 3 (ii) energy of the REACTANT (iii) activation energy of the forward reaction (iv) activation energy of the BACKWARD reaction (v) threshold energy |
|
| 1720. |
From the following statements Choose those applicable to covalent compounds. • Dissolves in organic compounds • Dissolves in water • High melting and boiling point. • Found in solid liquid and gaseous states. • Conducts electricity. |
|
Answer» |
|
| 1721. |
From hydrogen, sodium, zinc and argon select Element which burns in oxygen with a pop sound. |
| Answer» SOLUTION :HYDROGEN | |
| 1722. |
From a mixture of water and oilthe constituents can be separtedby usinga …………….. |
|
Answer» |
|
| 1723. |
From a mixture of sandand water constituents can beseparated by ……………. |
|
Answer» |
|
| 1725. |
Freonsreleased from air- conditioners rise up in air and interact with the ozone layer . |
|
Answer» |
|
| 1726. |
Fractional distillation of ethyl alcohol-water mixture gives a mixture of 95.6 % ethyl alcohol and 4.4 % water. Further separation can be brought about either by the addition of CaO or by the additon of a water soluble salt such as potassium acetate. Justify the formation of pure ethyl alocohol in both the cases. |
|
Answer» SOLUTION :(i) method of SEPARATION (ii) changes in the boiling point of water on addition of water-soluble salt (iii) method of separation (IV) method of separation (V) changes in the boiling point of water on addition of water-soluble salt (vi) method of separation |
|
| 1727. |
Fractional distillation is suitable for separation of miscible liquids with a boiling point difference of about 25 K or less. What part of fractional distillation apparatus makes it efficient and possess an advantageover a simple distillation process. Explain using a diagram. |
| Answer» Solution :It is the fractionating column which fits into the distillation flask. It is packed with a number of glass beads. As the vapours of both the VOLATILE liquids rise upwards in the distillation flask, the beads obstruct their MOVEMENT i.e. it slows down. The vapours of higher boiling liquid condense to the liquid state and in doing so they release CERTAIN energy known as latent heat of condensation. The energy which is released is taken up by the molecules of lower boiling liquid. As a result, they vapourise more quickly and PASS through the water condenser and condense as a liquid in the receiver. The higher boiling liquid remains in the distillation flask only. For further DETAILS about the fractional distillation. | |
| 1728. |
Four students A,B,C and D were given funnels filter paper test tubes ,test tube stands common salt, chalk powder starch and glucose powder they prepared the true solution suspension and collloidal solution .Test tubes were arranged as shown in the figure. observe the filtrate obtained in the test tubes and residue on filter paper . conclude about filtrate residue and type of solution. |
Answer» SOLUTION :
|
|
| 1729. |
Four students A,B,C and Dare asked to prepare colloidal solution .The following diagrams shown the preparation done by them .Name the student who will able to prepare colloidal solution.Write two properties of colloidal solutions. |
|
Answer» Solution :Onlystudent 'A' has prepared th ecolloidal SOLUTON Egg as such does not MIX with water .Only white of an egg forms COLLOIDAL solution on stirring in water .Both sugar and common salt form true solution in water .The two properties of colloidal solution are: (i) Colloidal solution ar of hetergenous nature consisting of disperesed phase and dispersion medium (II) Collloidal solution show Tydall effect |
|
| 1730. |
Formation of a compound is always associated with energy changes . |
|
Answer» |
|
| 1731. |
For the symbol H,D and T tabulate three sub-atomic particles found in each of them. |
Answer» SOLUTION :
|
|
| 1732. |
For the symbol, H,D and T tabulate, three sub - atomic particles found in each of them |
| Answer» SOLUTION :`{:("SYMBOL","PROTON","NEUTRON","ELECTRON"),(H,1,0,1),(D,1,1,1),(T,1,2,1):}` | |
| 1733. |
For the symbol H, D and T tabulate three subatomic particles found in each of them. |
Answer» SOLUTION :
|
|
| 1734. |
For the separation of red ink from blue ink a technique is used which is described below. Arrange the statements in a proper sequence. (1) The blue and red ink form spots at certain distances on the paper. (2) Paper chromatography is used for the sepration. (3) Paper and solvent are taken as stationary and mobile phases, respectively. (4) A narrow strip of paper with a line drawn is cut and a mixture of red and blue ink with the help of capillary is placed on the line marked on the paper. (5) The papar is suspended in the closed jar with the help of hook. |
|
Answer» 2 4 3 5 1 (ii) paper and solvent are taken as stationary and MOBILE phases, respectively. (iii) A narrow strip of paper with a LINE drawn is cut and mixture of RED and blue ink with the help of capillary is PLACED on the line marked on the paper. (iv) The paper is SUSPENDED in the closed jar with the help of hook. (v) The blue and red inks are separated on the paper by adsorption technique. |
|
| 1735. |
For the reaction PCl_(5) hArr PCl_(5)+Cl_(2), there is no effect of pressure. |
|
Answer» |
|
| 1736. |
For the reaction involving the formation of 1 mole fo water molecule from hydrogen and oxygen, the rate of rection with respect to reactants is given as |
|
Answer» `R=(1)/(2)(DELTA [H_(2)])/(Delta t)` |
|
| 1737. |
For the reaction H_(2)+I_(2) hArr 2HI, express the rate of reaction with respect to all reactants and products. |
| Answer» | |
| 1738. |
For the reaction, A+2B to 5C+3D the rate of formation of C is 0.06 mole/L/sec and final concentration of B is 0.04 mole//L^(-1) at 2 sec. Find out the initial concentration of B and also the change in concentration of B. |
|
Answer» Solution :RATE of DISAPPEARANCE of `B=(-1)/(2)([B])/(Delta t)` Rate of formation of `C=(1)/(5)([C])/(Delta t)` Rate disappearance of `B=(2)/(5)` rate of formation of C `=(2)/(5)xx0.06=0.024 " moles L"^(-1) s^(-1)` We KNOW `r_(B)=(-Delta[B])/(Delta t)` Rate of disappearance of `B=("initial concentration - final concentration ")/(" change in TIME ")` `0.024=(x-0.04)/(2)` `0.024xx2=x-0.04` `0.048+0.04=x=0.088 " mole" //L` `therefore` Initial concentration of B is 0.088 mole/L `therefore` Change in concentration of B=0.088-0.04=0.048 mole/L |
|
| 1739. |
For the reaction 2X+3Y to 4Z + 6Q |
|
Answer» RATE of consumption of X is 3 times the rate of FORMATION of Q |
|
| 1740. |
For the hypothetical reaction 4A_((g))+5B_((g)) to 4C_((g))+6D_((g)), if the rate of reaction in terms of disappearance of A is -(Delta[A])/(Delta t), then write the rate expressions in terms of concentration of B, C and D. |
|
Answer» SOLUTION :Reaction, `4A_((g))+5B_((g)) to 4C_((g))+6D_((g)) " or" A+(5)/(4)Bto C+(6)/(4)D` Then rate of disappearence of `A=(-Delta[A])/(Delta t)` `therefore` rate of reaction `=(-Delta[A])/(Delta t)` Rate4 expression in terms of concentration of B, C and D is `=-(4)/(5)(Delta[B])/(Delta t)=(Delta [C])/(Delta t)=(4)/(6) (Delta [D])/(Delta t)` |
|
| 1741. |
For the formation of one mole of nitric oxide from its constituents rate of formation of nitric oxide is ______ the rate of consumption of one of the reactants |
|
Answer» `(1)/(2)` TH `=(-Delta[N_(2)])/(Delta t)=(-Delta[O_(2)])/(Delta t)=(1)/(2). (Delta[NO])/(Delta t)` `implies ` rate of formation of `NO_(2)=2xx` rate of CONSUMPTION of `N_(2) " or" O_(2)` |
|
| 1742. |
For the following statements write T for True and F for False: (a) J. J. Thomson proposed that the nucleus of an atom contains only nucleons. (b) A neutron is formed by an electron and a proton combining together. Therefore,it is neutral. (c) The mass of an electron is about (1)/(2000) times that of proton. (d) An isotope of iodine is used for making tincture iodine, which is used as a medicine. |
| Answer» SOLUTION :(a)F (B) F (C) T (d) F | |
| 1743. |
For the following statements, write True (T) or False (F). If the statement is false, correct the statement. (d) -26 is greater than -25. |
|
Answer» Solution :a.J J Thomson proposed that the nucleus of an atom contains only nucleons. - FALSE. b.A neutron id formed by an electron and a proton combining together. Therefore it is neutral. - False c.The MASS of an electron is about `(1)/(2000)` times that of proton. - True d. An ISOTOPES of iodine is used for making tincture iodine, which is used as a medicine - False |
|
| 1744. |
For the equilibrium reaction, dissociation of calcium carbonate K_(c ) is equal to _____. |
|
Answer» |
|
| 1745. |
For the equilibrium, N_(2)+3H_(2) hArr 2NH_(3), if deuterium is introduced into the reaction mixture after equilibrium, the final composition of equilibrium mixture is |
|
Answer» `NH_(3), ND_(3)` |
|
| 1746. |
For fractional distillation, the difference in their boiling points should be _____ . |
|
Answer» |
|
| 1747. |
For every 10^(@)C rise in temperature, the rate of reaction is generally _____. |
| Answer» | |
| 1748. |
For any substance, why does the temperture remain constant during the change of state? |
| Answer» Solution :The heat energy supplied to a substance during the CHANGE of state (at its MELTING point or boiling point) is all used up in OVERCOMING (or breaking) the force of attraction between its particles without increasing its KINETIC energy. Since the heat (or latent heat) supplied during the change of state does not INCREASE the kinetic energy of the substance, therefore, no rise in temperature takes place. The temperature remains constant. | |
| 1749. |
For any substance, why does the temperature remain constant during the change of state? |
| Answer» Solution :During the change of state of any SUBSTANCE, the heat supplied or released is utilized in PHASE change. Such heat is called latent heat so, the temperatureon any substance REMAIN constant during the change of state. | |
| 1750. |
For an equilibrium, H_(2(g))+I_(2(g)) hArr 2HI((g)), if 'x' is the degree of dissociation at equilibrium, derive the value of K_(c ) for the given reaction. Also give K_(c ) for the equilibrium, if the reaction is started with 1 mole of hydrogen iodide. |
|
Answer» SOLUTION :`(i) K_(c )=([HI]^(2))/([H_(2)][I_(2)])` `K_(c )=(["Products"]^("coefficients"))/(["REACTANTS"]^("coefficients"))` (ii) composition at equilibrium (III) calculation of `K_(c )` |
|