1.

For the reaction, A+2B to 5C+3D the rate of formation of C is 0.06 mole/L/sec and final concentration of B is 0.04 mole//L^(-1) at 2 sec. Find out the initial concentration of B and also the change in concentration of B.

Answer»

Solution :RATE of DISAPPEARANCE of `B=(-1)/(2)([B])/(Delta t)`
Rate of formation of `C=(1)/(5)([C])/(Delta t)`
Rate disappearance of `B=(2)/(5)` rate of formation of C
`=(2)/(5)xx0.06=0.024 " moles L"^(-1) s^(-1)`
We KNOW `r_(B)=(-Delta[B])/(Delta t)`
Rate of disappearance of `B=("initial concentration - final concentration ")/(" change in TIME ")`
`0.024=(x-0.04)/(2)`
`0.024xx2=x-0.04`
`0.048+0.04=x=0.088 " mole" //L`
`therefore` Initial concentration of B is 0.088 mole/L
`therefore` Change in concentration of B=0.088-0.04=0.048 mole/L


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