InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6401. |
7) Calculate no. of atomsi) 3.2 g of sulphurii) 0.5 mole atoms of N2 |
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Answer» Weight of 1 mol sulphur = molar mass of sulphur = 32 g32 g = 1 mol3.2 g = 0.1 mol1 mol has 6.022*10^23 atoms0.1 mol will have 6.022*10^22 atoms |
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| 6402. |
(c) What halie is givelt13Calculate the mass of 12.044 x 1025 molecules of oxygen (02 |
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Answer» G.M.M= 6.022×10^23 molecules32g = 6.022×10^23 molecules32×12.044×10^25/ 6.022×10^23 = 12.044×10^236400g please show full solution |
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| 6403. |
Calculate the total number of atoms present in 22.1 litre of Nitrogen (N_2) gas at NTP |
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Answer» 1 mole of a gas has 22.4 L of volume at STPTherefore, (22.4 L) of nitrogen gas at STP has 22.4/ 22.4 = 1mol Now, 1 mole of N2has 6.022 x 1023molecules Therefore, 1mol of N2has 1 x 6.022 x 1023= 6.022 x 10^23molecules. And 1 molecule of N2has 2 atoms of N Therefore, 6.022 x 10^23molecules of N2have 2 x 6.022 x 10^23=12.044 x 10^23atoms of N i want in ntp |
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| 6404. |
The number of atoms present in 0.5g atom ofnitrogen is same as the atoms in(1) 12g of C(3) 8g of oxygen(2) 32g of S(4) 24g of Mg |
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Answer» The number of atoms in 1 mole of any substance is 6.022× 10^23 atoms . This is according to Avogadro's law and it is referred to as Avogadro's number.Substances with equal moles will have the same the same number of atoms in them. Moles = mass/ molar mass i) Moles of 0.5 g nitrogen: 0.5/14= 0. 0357 moles ii) moles of 12 C molar mass of C = 12= 12/12= 1 mole iii) Moles of 8 g oxygen molar mass of O = 16 8/16 = 0.5 moles iv) Moles of 24 g of Mg Molar mass of Mg = 24 24/24 = 1 mole NB: From the list given there is no element with same number of atoms as 0.5 g of Nitrogen. The question should have read 0.5 MOLES of Nitrogen - then the answer would have been 8g of oxygen 3. 8g of oxygen........ |
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| 6405. |
The number of atoms present in 16g of oxygen is(1) 6.02 x 10i1s(3) 3.01 x 10115(2) 3.01 x 10(4) 6,02 x 101 |
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Answer» 16 g i equal to 0.5 mole of oxygen molecule. we know in one molecule of oxygen there are 2 atom. Hence in 0.5 mole of oxygen molecule, there are 0.5 * 2 mole of atom of oxygen. that is 1 mole of oxygen atom. Number of particle in one mole = 6.022 * 10^233. Thu number of atom in 16 g of oxygen gas = 6.022*10^23 |
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| 6406. |
The number of hetero atoms present in thefollowing compound is/are:NH2(2) 3(4) 4(3) 1 |
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Answer» option 2 is correct. |
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| 6407. |
The construction of large dams leads to social andenvironmentalproblems.List two problems of each category |
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Answer» Social problem: Already poor tribals gets affected the most, loss of land, livelihood, home, property etc.2. Not enough cash compensation offered by the government to the tribal groups, hence no source for balancing their livelihood. Environmental problem: Ecosystem gets disturbed due to unannounced construction of dams.2.Rate of deposition of sediments of sediments gets reduced and rate of erosion remains constant hence resulting in reduced water tables, less deposition of sediments in deltas etc |
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| 6408. |
28) The cannizzaro's reaction is not gives byO (a) Trimethyl acetaldehydesO (c) BenzaldehyeO (b) AcetaldehydeO(d) Formaldehyde |
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Answer» Cannizarro's reaction is given by the compounds with no alpha-hydrogen. Hence, Acetaldehyde (see figure) will not give Cannizarro's reaction |
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| 6409. |
Q. 14. Explain the nature of the covalent bond using the bond formation in. |
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| 6410. |
2016 gm of acetaldehyde produced 13.95 kcal of heat on combustion in Oz. Calculate the heat ofcombustion of CH3CHO(A) 279 kcal(B) 972 kcal(C) 27.9 kcal(D) 2.79 kcal |
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| 6411. |
calculate the energy in kcal/mol of the photons of an electromagnetic radiation of lambda 5700 angastom |
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Answer» E=hc/lwhere l.is wavelengthhenceE=6.626*10^-34*3*10^8/5700*10^-10E=19.878*10^-26/5700*10^-10E=0.0034*10^-16E=34*10^-20J |
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| 6412. |
Write the number of covalent bond present in propane. |
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| 6413. |
34 AH, CHs 12.5 kcalHeat of atomisation of C 171 kcalBond energy of H2 104.3 kcalBond energy C- H 99.3 kcalWhat is C- C bond energy?(1) 1409 kcal(3) 40 kcal(2) 49 kcal(4) 76 kcal |
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Answer» WE need to take 2 atomization of C+4 atomization of H+4 bond energy pf C-H1 heat formation of C2H4 2 x 171 + 4 x 52.1 - 4 x 99.3 - K = 12.5k= 140.7 Kcal |
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| 6414. |
4. Calculate the number of pi bond and sigma bond present in the structure of naphthalene. |
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Answer» there are 5 double bond so there are 5 pi bonds and 12 sigma bonds there are 5 pie bond and 12 sigma bond .because double bond is counted as pie bond hope this will help you like my answer and MARK IT AS BEST ANSWER there are 5 double bond so there are 5 pie bonds and 12 sigma bonds There are 5 pie and 12 sigma bond 5 pie bond and 12 sigma bond |
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| 6415. |
11. Define รงa) State Variables (b) Absolute Temperature12. Define (af Green Chemistry (bEutrophication |
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Answer» 11.a)A state variable is one of the set of variables that are used to describe the mathematical "state" of a dynamical system. Intuitively, the state of a system describes enough about the system to determine its future behaviour in the absence of any external forces affecting the system. b)Absolute temperature, also called thermodynamic temperature, is the temperature of an object on a scale where 0 is taken as absolute zero. Absolute temperature scales are Kelvin (degree units Celsius) and Rankine (degree units Fahrenheit). ... 0K (absolute zero) = - 273.15 Celsius. 12.a)Green chemistry, also called sustainable chemistry, is an area of chemistry and chemical engineering focused on the designing of products and processes that minimize the use and generation of hazardous substances b)Eutrophication is the enrichment of an ecosystem with chemical nutrients, typically compounds containing nitrogen, phosphorus, or both. |
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| 6416. |
what is pi and sigma bond ? |
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Answer» SigmaAndPi Bonds. Asigma bondis a covalentbondwhich is formed by the head on overlap of two atomic orbitals. The combination of overlapping orbitals can be s-s, s-pzor pz-pz. ... But there can be a maximum of twopi bondsbetween two atoms in a molecule. |
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| 6417. |
32Distinguish between a sigma and a pi bond |
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| 6418. |
the following statement is/are not true for n-bond ?13. Wnicis formed by the overlapping of p -p or p- d orbitalsof the follow2. It is stronger than sigma bond3. It is formed when ơ-bond exists alreadyIt is resulted from sideway overlapping of orbitals.4.(A) 1, 2, 3, 4(C) 2 only(B) 2, 3 and 4(D) 1, 2 and 4 |
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Answer» option C , it is weaker than sigma bond. |
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| 6419. |
. Define resonance |
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Answer» Inmechanical systems,resonanceis a phenomenon that occurs when thefrequencyat which aforceisperiodicallyapplied is equal or nearly equal to one of thenatural frequenciesof the system on which it acts. This causes the system tooscillatewith largeramplitudethan when the force is applied at other frequencies. |
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| 6420. |
Q.11Draw the Lewis structures of the following:(a) CH,COOH(b) H SO230, |
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Answer» CH3COOH H2SO4 |
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| 6421. |
25) a) What are sigma and Pi bond?b) Why sigma bond stronger than a Pi bond.lingar cnmhination of atomic orlb |
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Answer» a)Sigma And Pi Bonds. Asigma bondis a covalentbondwhich is formed by the head on overlap of two atomic orbitals. The combination of overlapping orbitals can be s-s, s-pzor pz-pz. ... But there can be a maximum of twopi bondsbetween two atoms in a molecule. b)Pi bonds areusually weakerthan sigma bonds. Quantum mechanics says this is because the orbital paths are parallel so there is much less overlap between the p-orbitals.Pi bondshappen when two atomic orbitals are in contact through two areas of overlap. please like my answer if you find it useful |
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| 6422. |
13. The bond having the minimum bond energy is:(2) O-O(4) P-P(3) S-S |
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Answer» option 2 |
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| 6423. |
63. In PO, the formal charge on each oxygen atomand the P-O bond order respectively are70. |
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Answer» (PO4)3- has total -3 charge being delocalised on four oxygens, hence formal charge of oxygen = (-3/4) & P-O bond order = 1 + (1/4) = (5/4) |
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| 6424. |
WHAT IS RESONANCE? |
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Answer» Resonance is the quality of sound being clear and loud. |
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| 6425. |
19. Draw resonance structures of |
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| 6426. |
Which hybrid orbitals are used by carbon atorn in CH3。H?d |
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Answer» One of the sp3 hybrid orbitals overlap with an sp3 hybridizedorbital fromcarbonto form the C-O sigma bond. Both the sets of lone pair electrons on the oxygen are contained in the remaining sp3 hybridized orbital. Due to the sp3 hybridization the oxygen has a tetrahedral geometry. |
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| 6427. |
20. Among the following statements which is correct?(A) With increase in 's' character electronegativity decreases(B) Pure p- p overlap gives stronger bond than pure s s overlap(C) Size of hybrid orbitals are in the order: sp3 <sp <sp(D) Number of hybrid orbitals are twice the atomic orbitals which are involved in thehybridization. |
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Answer» b is correct statement |
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| 6428. |
RESONANCE |
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Answer» The increase in amplitude of oscillation of an electric or mechanical system exposed to a periodic force whose frequency is equal or very close to the natural undamped frequency of the system. |
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| 6429. |
Resonance hybrid of nitrate ion is |
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Answer» plzz give explanation First is you need to know the number of valence electrons. You can do this by (1) drawing the electron configuration per element or (2) consulting your periodic table. If you chose to draw the electron configuration per element, you will have something like this: N(atomic number = 7) :1s22s22p3(5 outermost electrons) O(atomic number = 8) :1s22s22p4(6 outermost electrons) If you chose to consult your periodic table, just notice thatNbelong to Group 5A whileObelongs to Group 6A. The group number denotes the number of outermost electrons.Now that you know the number of valence electrons per element, you need to compute the total valence electrons for theNO-13ion. 5 + (3 x 6) = 23 electrons But since the whole molecule has a -1 charge, you need to add this too. So thetotal number of valence electrons is 24. The next thing to do is draw. Normally, the first element in the chemical formula is thecentral atom. In this case, theNatom is being surrounded by threeOatoms. |
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| 6430. |
What is the formal charge on various atom in nitrate ion |
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Answer» answer is -1 It's complicated |
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| 6431. |
Test one functional group in the given unknown organic compound L |
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Answer» Reactions of amides: Reaction of NaOH: Amides are decomposed by NaOH to evolve ammonia. The gas can be tested by a moist red litmus paper which is then turned blue. Alkaline hydrolysis of aromatic amides to aromatic acid: The soluble sodium salt of aromatic acid formed from aromatic amides upon hydrolysis is regenerated as white precipitate in acidic medium. Biuret Reaction for aliphatic diamide: When aliphatic diamide is heated at a temperature above its melting point, ammonia is evolved and crystalline biuret is formed. This biuret in alkaline medium gives a violet colour with a drop of copper sulphate solution. |
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| 6432. |
Given the table below, what is the chemical formula for a compound between Rb and the nitrate ion NOs '7 |
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Answer» post the table photo too question repeat please |
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| 6433. |
L/4. The weight of a molecule of the compound Co,20e is(A) 1.09 x 102g (B) 2.988 x 10-22 g (C) 5.025 x 10-2g(D) 16.023x 10-2g |
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Answer» Molecular weight of C6H12O6 is 180u But we have to find it in grams. Since 1u=1.66*10^-24 Therefore 180 u= 1.66*10^-24 *180 =3* 10 ^-22 gram The answer is Option B. |
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| 6434. |
Mole fraction of the solute in a 1.00 molal aqueoussolution isA. 0.0177В.О 0.0344C 1.7700D. 0.1770 |
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Answer» 1.00 molal aqueous solution means that 1 mol of solute is dissolved in 1 Kg of water. Hence,No. Of moles of solute = 1 No. Of moles of water = 1000/18=55.556 MOLE FRACTION OF SOLUTE = No. Of moles of solute/no. Of moles of solute + No. Of moles of solvent MOLE FRACTION = 1/1+55.556 =0.1768[0.0177(approx.) |
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| 6435. |
Claculate the vapour pressure of an aqueous solution of 1.00 molal glucose at 100°C |
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Answer» Let mole fraction of gas is x we know, the relation between mole fraction and molalitymolality = x × 1000/(1 - x)M Here, M is Molecular weight of solvent . for aqueous solution , solvent is water . ∴ Molecular weight of water , M = 18g/mol Now, 1 = x × 1000/(1 - x) × 18⇒18(1 - x) = 1000x ⇒18 = (1000 + 18)x ⇒x = 18/1018 Now, use formula , Relative lowering of vapor pressure = mole fraction of gas ∆P/P₀ = x Here P₀ is initial pressure ,at STP , P₀ = 760 torr so, ∆P = 760 × 18/1018 = 13.44 torr Hence, lowering of vapor pressure = 13.44 torr |
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| 6436. |
2.4 Calculate the mass of urea (NH CONH2) required in making 2.5 kg of0.25 molal aqueous solution. |
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Answer» Molar mass of urea (NH2CONH2) = 2 (1 × 14 + 2 × 1) + 1 × 12 + 1 × 16= 60 g mol - 1 0.25 molar aqueous solution of urea means:1000 g of water contains 0.25 mol = (0.25 × 60)g of urea = 15 g of urea That is, (1000 + 15) g of solution contains 15 g of urea Therefore, 2.5 kg (2500 g) of solution contains = (15 X 2500) / (1000+15) g = 36.95 g = 37 g of urea (approximately) Hence, mass of urea required = 37 g |
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| 6437. |
59. What is the mole fraction of the solute in 2.5 molal aqueous solution ?0.0430.053C) 0.063D) 0.073 |
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Answer» 2.5 molal aqueous solution means 2.5 moles of solute in 1 kg solvent(water) so, moles of solute=2.5 moles of water=1000/18=55.55(approx) so mole fraction = 2.5/(2.5+55.55)=.043 |
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| 6438. |
The mole fraction of the solute in one molalaqueous solution is(a) 0.027 (b) 0.036 (c) 0.018 (d) 0.009 |
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Answer» on rounding off we see that option (c) is correct. |
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| 6439. |
Q3. Name the given compound: |
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Answer» Formaldehyde or Methanal |
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| 6440. |
Mole fraction of ethanol in ethanol water mixture is0.25. Hence percentage concentration of ethanolby weight of mixture is:-(1) 25% (2) 75% (3) 46% (4) 54% |
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| 6441. |
Question.9 Draw the structure of ethanol molecule.Question. 10 What happens when a small piece ofsodium is dropped into ethanol? |
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Answer» Ethanol, also known as ethylalcoholand abbreviated as EtOH, is a colorless, volatile, and flammable liquid that is soluble in water. Its chemical formula is C2H6O, or can be written as C2H5OH or CH3CH2OH. It has one methyl (-CH3) group, one methylene (-CH2-) group, and one hydroxyl (-OH) group If a small piece ofsodium is dropped intosomeethanol, it reacts steadily to give off bubbles of hydrogen gas and leaves a colourless solution ofsodiumethoxide, CH3CH2ONa.Sodiumethoxide is known as an alkoxide |
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| 6442. |
12.A 5.2 molal aqueous solution of methyl alcohol, CH,OH is supplied. What is the mole fraction ofmethyl alcohol in the solution?(A) 1.100(B) 0.090 (C) 0.086 (D) 0.050 |
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Answer» options no c is the correct answer the answer is c i hopr its correct |
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| 6443. |
what is solid carbon dioxide? |
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Answer» Dry ice, sometimes referred to as cardice, is thesolidform ofcarbon dioxide. It is used primarily as a cooling agent. Dry ice sublimates at 194.65 K (−78.5 °C; −109.3 °F), at Earth atmospheric pressures. |
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| 6444. |
the IUPAC name of the given compoundCo (NH3)sCljCl2 is:a) pentaaminocobaltchloride chlorate(b) cobaltpentaamminechlorido chlorideo) pentaamminechloridocobalt (III) chloride(d) pentaaminocobalt(III) chloride |
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| 6445. |
mefal3. Why is solid carbon dioxide known as dry ice? How is it stored? |
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| 6446. |
Q. 8. The IUPAC name of CHsCHO is(a) Acetaldehyde(b) formaldehyde(c) methyl formaldehyde(d) ethanollectricity hera |
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Answer» option a) Acetaldehyde |
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| 6447. |
1.Phosgene is a common name for(a) phosphoryl chloride(b) thionyl chloride(c) carbon dioxide and phosphine(d) carbonyl chloride |
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Answer» HOWEVER, “Phosgene,” actually IS the common name. Systematic name,Carbonyl chloride. Other names, which are common intermediates in the dye, pesticide, and pharmaceutical industries. The chemical first used at Ypres waschlorinegas, or phosgene. |
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| 6448. |
47) The most important compound which accounts for almost80% of the total depletion of ozone layer is(A) Chloride ionChlorofluoro carbon(C) Sulphur ion(D) Magnesium ion |
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Answer» Chlofloro carbon is your answer |
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| 6449. |
at has completely filled K and L shells. Explain. |
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| 6450. |
Na+ has completely filled K and L shells. Explain. |
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Answer» Na+ is a positively charged sodium ion. Normally an atom of sodium has 11 electrons, so according to formula it has 2 electrons in K shell , 8 electrons in L shell and 1 electron in M shell. However Na+ has 10 electrons only, therefore it has 2 electrons in K shell and 8 in L shell. 2 and 8are the full capacity of the K and L shell respectively. Hence it is said ' Na+ has completely filled K and L shells. ' |
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