 
                 
                InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2751. | Derive the rate expression of opposing reaction. | 
| Answer» A catalyst is a substance that alters therateof a chemicalreactionbut remains chemically unchanged afterwards. The catalyst increases therateof thereactionby providing a differentreactionmechanism to occur with a lower activation energy. | |
| 2752. | For the following reactions, mention the formulas, names and physical statesof the products:( 1 ) 3Fe(s) + 4H2O(g) â7.(2 ) P45) + 6C12(g)-> | 
| Answer» | |
| 2753. | (a)Derive the rate expression of opposing reaction. | 
| Answer» | |
| 2754. | LNTEGRATED RATE LAW METHOD | 
| Answer» Therate lawis a differentialequation, meaning that it describes the change in concentration of reactant (s) per change in time. Using calculus, the rate lawcan beintegratedto obtain anintegrated rate equationthat links concentrations of reactants or products with time directly | |
| 2755. | The arsenious sulphide sol has negativecharge. The maximum coagulating power forprecipitating it is of(A) 0.1 N Zn(NO3)2 (B) 0.1 N Na PO,(C) 0.1 N ZnSO, (D) 0.1 N AICI, | 
| Answer» option D is the right answer need complete solution I think (D) is a write answer | |
| 2756. | The first order rate constant for the decomposition of ethyliodide by the Reaction of C2H51-âC2H4 + HI at 600k is1.60 x 10- sec. Its energy of activation is 209 kj/m.Calculate rate constant of the reaction at 700k. | 
| Answer» Ea= 209 kJ mol-1 = 209 x 103J mol-1T₁ = 600 K, k₁= 1.6x10-5s-1T₂= 700 K, k₂ = ?R = 8.314 JK-1 mol-1log(K₂/K₁) = Ea/2.303R [ (T₂-T₁)/T₁T₂] =209x 103/2.303 x 8.314 x [700 – 600)/ 600 x 700] =2.5989(K₂/K₁) = antilog 2.5989 = 397.1K₂ = 397.1 x K₁= 397.1 x 1.6x10-5s-1K₂ =6.35 x 10-3s-1 | |
| 2757. | 5051525353545556+4/-1Single ChoiceWhich one of the following characteristics isassociated with adsorption?AG and AH are negative but AS ispositiveAG and AS are negative but AH ispositiveAG is negative but AH and AS arepositiveAG, AH and AS all are negativeSubmit | 
| Answer» | |
| 2758. | T8231, 1.61The first order rate constant for the decomposition of ethyliodide by the Reaction of C,H51-â C-H4 + H1 at 600k is1.60 x 10-5 sec. Its energy of activation is 209 ă¸m.Calculate rate constant of the reaction at 700k. | 
| Answer» T1= 600K ,k1=1.60x10^-5s-1T2=700k ,k2=? ,Ea=209 kJ mol-1 Applying Arrhenius equation, logk2/k1= Ea/2.303R(1/T1-1/T2)=log(1.60x10^-5) + 209000 J mol-1/ 2.303x8.314 JK-1mol-1(700-600/600x700)=(-5+0.2041) + 2.5989 = -2.197 = 3.8030K2=antilog3.8030=6.353x10^-3s-1 | |
| 2759. | 4.2.2 RateExpressionand RateConstant | 
| Answer» Rate expressionis an equation forratelaw and it relates therateof a reaction to therate constantand concentration of the reactants.Rate constantis therateof the reaction when the concentration of the reactants is unity. It is defined by k. this is not wrong answer | |
| 2760. | (b) Write rate law(c) Calculate rate constant of the reaction. | 
| Answer» b)A rate law relates the concentration of the reactants to the reaction rate ina mathematical expression. It is written in the form rate = k[reactant1][reactant2], where k is a rate constant specific to the reaction. The concentrations of the reactants may be raised to an exponent (typically first or second power | |
| 2761. | give at least five characteristic of rate constant | 
| Answer» 5. Different reactions have different values of k. Thanks. | |
| 2762. | B0 o T£ g nwé‘vmufizj—vmww S Y | 
| Answer» Magnesium burns in air to form Magnesium oxide (MgO) | |
| 2763. | 60. What volume of 0.8 M AICl, solution should be mixed with 50 ml of 0.2M CaCl2 solution to get solution of chloride ioconcentration equal to 0.6 M5 | 
| Answer» not understood | |
| 2764. | A mass of 98 g of sulfuric acid, H2SO4, is dissolved in water to prepare a 0.500 M solution. What is thevolume of the solution? | 
| Answer» The question asks for volume, so we want to calculate litres, L (or mL)2.The concentration of the solution is:0.500 molL 3.Because the question involves mass, we will need to know the molar mass of H2SO4 Using a periodic table we find the molar mass of H2SO4 to be 98.1g·mol-1 Put this information together to solve the problem, arranging the information to end up with the desired unit: L=1 L0.500 mol×1 mol98.1 g×98.0 g=2.00 L answer | |
| 2765. | P.182OP2-CBSE CH-SM&GS 4215. (a) Two fnasks of equal volume connected by a narrow tube (of negligible volume) are at27 C and contain 0.7 moles of H2 at 0.5 atm. One of the flask is then immersed into abath kept at 127"C, while the other remains at 27*C. Calculate the final pressure and thenumber of moles of H2 is each flask.(b) 1 gm of an alloy of Al and Mg reacts with excess HCI to form AICls. MgCh2 and H2. Theevolved H; collected over mercury at O°C occupied 1200 ml at 699 mm Hg. What is thecomposition of alloy? | 
| Answer» a)PV=nRT 0.5v=0.7R300 so v=420R In 2nd case the pressure will be same in both flasks and sum of moles of gas will be 0.7 Flask 1- PV=aRT P420R=aR300 a=1.4P Flask2- PV=bRT P420R=bR400 b=1.05P a + b = 2.45P = 0.7 P = 0.28 a= 0.294, b= 0.392 | |
| 2766. | b0 | 
| Answer» 8. | |
| 2767. | Indicate the nature of bonding in CCl, and CaH(A) covalent in CCl4 and electrovalent in CaH(B) electrovalent in.both CCi, and CaH(C) covalent in both CCl, and CaH2(D) electrovalent in CCl and covalent in CaH,The totol2. | 
| Answer» CCl4 has a covalent bond. and electrovalent in CaH2 | |
| 2768. | 36.Two closed vessel A and B of equal volume containing airat pressure P, and temperature T, are connected to eachother through a narrow open tube. If the temperature ofone is now maintained at T and other at T2 (where Ti T)then that what will be the final pressure?(a) T₁/2P₁T₂(b) 2P₁T₂/T₁+T₂(c) 2P₁T₂/T₁-T₂(d) 2P₁/T₁+T₂ | 
| Answer» option -b tnx | |
| 2769. | 8. When a gas filled in a closed vessel is heatedthrough 1°C, its pressure is increased by 0.4%The initial temperature of the gas was | 
| Answer» | |
| 2770. | ), 5 moles of SO2 and 5 moles of O2 are allowed toreact to form SO3 in a closed vessel. At theequilibrium stage 60% of SO2 is used up. Thetotal number of moles of SO2, O2 and SO3 in thevessel now iS(a) 10.0(c) 10.5(b) 8.5(d) 3.9 | 
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| 2771. | During an experiment, a signalfrom a spaceship reached theground station in five minutes.What was the distance of thespaceship from the groundstation? The signal travels at thespeed of light, that is, 3 x 108m s-. | 
| Answer» Time taken=5min=5×60s=300secspeed of signal u =3×10^8 m/sDistance=??we know thatspeed= Distance/timeDistance= Speed×Timeputting the valueDistance= 3×10^8 × 300Distance = 9×10^10m Hello friend!!! Your question is to find the distance of this distance of spaceship from the ground when the signal travelling at the speed 3 into 10 to the power 8 reach the ground after 5 minutes. ♦1 minute is equal to 60 seconds ♦5 minutes is equal to 60×5 seconds = 300 seconds ★So the distance = speed × time = 300 × 3 ×10 to the power 8 =9 × 10 to the power 10 meters ★So the distance of the spaceship from the ground is 9 × 10 to the power 10 meters yes this is a correct answer distance=speed×timed=3×10^8×300d=9×10^10m correct answer is 9×10^10m | |
| 2772. | Q. In a face-centered cubic latticeunit cells?ell is shared equally by how many | 
| Answer» A unit cell is shared by the other unit cell attached to it’s all surfaces means A unit cell is shared by other 6 unit cell (because number of surfaces of unit cell is 6) | |
| 2773. | What uis difference between multicellular and uni cellular | 
| Answer» The maindifference between unicellularandmulticellular issome organisms are made-upofsingle cell termed asunicellularwhile multicellularare made-upoftwo or more cells.Single celledorganismis calledunicellularorganism. They depend on simple diffusion to ride out and live. difference 1:-1.unicellular organisms are single celled organisms.2.multicellular organisms have more than one cell. difference 2:-1.the unicellular organisms do various activities on its own.2.multicellular organisms depend on other cells to perform various activities. difference 3:-1.unicellular organisms include eukaryotes and prokaryotes2.multicellular organisms include eukaryotic cells only. difference 4:-1.unicellular organisms contain nucleus and some other components.2.but multicellular organisms contain all components like mitochondria so on. difference 5:-1.unicellular organisms reproduce by asexual reproduction.2.multicellular organisms reproduce by sexual reproduction. difference 6:-1.ex.amoeba, bacteria , paramaecium .... etc. are examples for unicellular organisms.2.plants,animals,zygote,including humanbeings are examples of multicellular organisms. difference 7:-1.an injury of unicellular organisms affect the whole body which cause to death.2.an injury of cell in multicellular organisms doesnot affect the whole body. difference 8:-1.life period is very short in unicellular organisms.2.life period is larger than the unicellular organisms in multicelled. difference 91.unicellular organisms donot have certain shape2.multicellular organisms have definite shape. difference 10 1.unicellular includes hetrotrophic.2.multicellular organisms includes both autotrophic and hetrotrophic. | |
| 2774. | JACXS-CHEICScieCathode rays are flow of(2) ProtonsElectrons(3) Neutrons(4) Atoms | 
| Answer» The cathode is a negatively-charged conductor, and the anode is a positively-charged conductor. Electrons, which have a negative charge, flow off the cathode and are attracted towards the anode. A small hole in the anode allows some electrons to pass through it, creating a beam of electrons. (1) is correct option | |
| 2775. | a) Give four examples of thermoset polymer | 
| Answer» The mainthermosettingplastics are epoxy resin, melamine formaldehyde, polyester resin and urea formaldehyde. Good electrical insulator, hard, brittle unless reinforced, resists chemicals well. Used for casting and encapsulation, adhesives, bonding of other materials. Like my answer if you find it useful! | |
| 2776. | 2.Balance the following chemical equations. (ASI)a) NaOH + H,so, → Na,so, +-H2Ob) Hg (NO,), + KI → Hig 12 + KNO.c) H2 + O2 → H2O | 
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| 2777. | Which soil would have the higpercolation rate? | 
| Answer» Thesandysoil has the largest particle size while the clay has the smallest particle size. This tells us that the percolation rate depends directly on particle size and is the highest forsandysoil while theclay soil has the highest retention capacity. | |
| 2778. | राकै 6०1८. « «,» «०2 ४८८०हा Ehln ye | 
| Answer» Displacement1in these reaction ,more reactive metal displace less reactive metal from its compound2 it is a slow reaction3 change of colour take place4 e.g fe++cuso4 ---->feso4++cu double displacement1 there is an exchange of ions between two reactant2 it is a fast reaction3 precipitate are formed4 e.g agno3++nacl-->agcl++nano3 | |
| 2779. | Tabulate the differences inthe characterisites of statesof mattera) | 
| Answer» | |
| 2780. | (a) Tabulate the differences inthe characterisitcs of statesal of matter | 
| Answer» 1.ShapeThey Have definite shape - solidThey do not have definite shape - liquidThey do not have definite shape - gas2.VolumeThey have definite volume - solid They do not have definite volume - liquidThey do not have definite volume - gas3.DensityThey have high density. - solidLiquids have less density than solids. - liquidLiquids have least density. - gas4.Kinetic energy of particles. Least - solidMore than solids - liquidMaximum - gas5.Compressibility Negligible - solidLow - liquidHigh - gas Rigidity: It is the property of matter to resist the change of its shape.Compressibility: It is the property of matter in which its volume is decreased by applying force.Fluidity: It is the ability of matter to flow.Filling a gas container: On filling a gas takes the shape of the container.Shape: Having definite boundaries.Kinetic energy: It is the energy possessed by the particles of matter due to its motion.Density: It is the ratio of mass with per unit volume | |
| 2781. | (1) Give two examples of illustrating the law of conservation of momentum. | 
| Answer» An example in a toy is a Newtons Cradle. The momentum of one or more of the balls is conserved. | |
| 2782. | 4.800 ml of a mixture of O, and O, weight 1.2gm at NTP. The volume of O, in themixture is1. 80 ml3. 200 ml2. 160 ml4. 400 ml | 
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| 2783. | hat volume of 0.10 M H,SO, must be added to50 mL of a 0.10 M NaOH solution to make asolution in which the molarity of the H,SO, is0.050 M?(A) 400 mL(C) 100 mL(B) 50 mL(D) 150 mL | 
| Answer» answer is 100 | |
| 2784. | (D) 300m3. What volume of 0.10 M H,So,must be added to 50 mL of a 0010 M NaO1 I solution to make a solution inwhich the molarity of the H,SO, is 0.050 M.(A) 400 mL(B) 50 mL(C) 100 mL(D) 150 mL | 
| Answer» Given: Normality of H2SO4 =M1 = 0.05 M Normality of NaOH = M2 = 0.1 M Vol. Of NaOH= V2= 50 ml Vol. Of H2SO4 =V1 = ? Now,, (M1 × V1) / n1 = (M2 × V2) / n2 Here n1 = n2 = coefficient of NaOH and H2SO4 which is 1 So,, M1×V1 = M2 × V2 Keeping values in it , we get ,. 0.05 × V1 = 0.10 × 50 V1 = (0.10×50) / 0.05 = 5/ 0.05 = [100 ml ] Ans…….. | |
| 2785. | wiBorddese of -the folloand 02calculate the | 
| Answer» bond order of N2 = 6/2 = 3 , for O2 = (6-2)/2 = 2 for O2+ = (6-1)/2 = 5/2 = 2.5 For O2- = (6-3)/2 = 1.5 | |
| 2786. | Give the bencht dot toucture 8bany Con pouda.a u sing nee vs Calls | 
| Answer» | |
| 2787. | How much water Should be added to 100 mL ofseminormal HCl solution to make it decinormal? | 
| Answer» N1V1= N2V20.5*100= 0.1*V2500ml | |
| 2788. | For the reaction 3A(g) + B(g) 2C(g) at a giverntemperature, Kc 9.0. What must be the volume ofthe flask, if a mixture of 2.0 mol each of A, B and Cexist in equilibrium?(A) 6 L (B) 9L (C)36L (D) of these | 
| Answer» | |
| 2789. | Write monomers of nylon 66. | 
| Answer» Nylon 66is made of twomonomers each containing 6 carbon atoms, hexamethylenediamine and adipic acid, which givenylon 66its name. | |
| 2790. | 25.(a) Name the monomers of (i) Buna-N and (ii) SBR | 
| Answer» | |
| 2791. | 19.Namethetypeofreactioninvolved in the formation of the follovwpolymers from their respective monomers(i) PVC.(ii) Nylon6(iii) PHBV | 
| Answer» 1.Addition2.Hydrolysis/ Condensation 3.condensation | |
| 2792. | Terylene is an example of polyester. | 
| Answer» Yes Terylene is example of polyester thank u so much ## | |
| 2793. | Write the equation for the formation of terylene. | 
| Answer» | |
| 2794. | 19. Write monomers of terylene and nylon-66. | 
| Answer» Monomers are relatively small and simple molecules or units of a large molecule or a polymer. Monomers bond together to form a polymer. The monomers of terylene are ----1. Ethylene Glycol2. Terephthalic Acid Terylene is a synthetic fibre used for making clothes. It is elastic, highly durable, wrinkle-free. The acid is benzene-1,4-dicarboxylic acid (old name: terephthalic acid). The alcohol is ethane-1,2-diol (old name: ethylene glycol). Nylon 66 is made up of 2 monomers - Each consists of 6 carbon atoms.1) Hexamethylenediamine2) Adipic acid | |
| 2795. | List two types of reactions in which this reaction can be placed. | 
| Answer» I can't understand your question exothermic reaction and endothermic reaction | |
| 2796. | 62. Write chemical equations for thesynthesis of(i) Terylene (ii) Neoprene(iii) Teflon Delhi 2011c | 
| Answer» tq | |
| 2797. | - Why terylene has more application in manufactureof clothes? Explain. | 
| Answer» Terylene is extensively used in textile industry to make hard wear clothes like sarees , taoestry and dress material. Terylene is made by a process of polymerizing ethylene glycol and terepthalic acid. It is also mixed with natural fibre like cotton and wool to make more variety of clothes. Terylene was exhibited to the Imperial Chemical Industries in 1946, and by 1948 the first polyester lace curtains were commercially available. It quickly became a very popular fabric because of its versatility. Terylene requires little time and effort to clean. In addition, polyester combines well with natural fibers, such as cotton. This winning combination make fabrics both easy to care for and comfortable. | |
| 2798. | list two types of reaction in which this reaction can be placed | 
| Answer» I can't understand your question the two types of reaction are - exothermic and endothermic reactions. displacement reation and Double displacement reation reduction and oxidation reaction | |
| 2799. | WHAT IS FRUCTOSE? | 
| Answer» Fructose, or fruit sugar, is a simple ketonic monosaccharide found in many plants, where it is often bonded to glucose to form the disaccharide sucrose. ... Crystalline fructose is the monosaccharide, dried, ground, and of high purity. High-fructose corn syrup is a mixture of glucose and fructose as monosaccharides. exact short defination it is a hexose sugar especially found in honey and fruits. | |
| 2800. | The volume of oxygen at N.T.P the mass ofwhich is 8 gm. is- | 
| Answer» O2= 16×2=32 gm = 1mole 1mole of volume = 22.4lt32 gm oxygen contain 22.4lt volume1 gm oxygen contain = 22.4/328 gm of oxygen contain = 22.4×8/32= 5.6 lt | |