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P-type - In P-type doping, gallium is the dopant. Gallium have only three outer electrons. When mixed into the silicon lattice, they form "holes" in the lattice where a silicon electron has nothing to bond to.

1. Changuna Sankar: P-type - In P-type doping, gallium is the dopant. Gallium have only three outer electrons. When mixed into the silicon lattice, they form "holes" in the lattice where a silicon electron has nothing to bond to.

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n - type

Arsenic (As) has five and Silicon (Si) has four valence electrons in their respective outermost shell. When Si is doped with As, four electron of As forms covalent bond with the four electrons of Si while one electron remains free for conduction. N- type of semiconductor is denoted by positive ion and free electron.

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for electroplating annode is made up of the the metal that is to be plated on the surface of cathode with electrolytic solution. Where power supply is directed from cathode to annode through electrolytic solution breaking electrolytic solution leading to the formation of ions of the metal that is to be plated on cathode. If you connect cathode to negative and annode to positive instead of cathode to positive and annode to negative , the electrolytic process happens. Instead there accumulates posit8ve ions at negative channel and may lead to shortcut. But in most cases the process itself doesn't start.

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The equation for the reaction between PbO and HCl is as follows:

PbO + 2HCl------------> PbCl2 + Cl + H2O

Therefore 1 moles of PbO require 2 moles of HCl to give 1 mole of PbCl2.

Calculate the reagent, between HCl and PbO, that is the limiting reagent.

Pb-207.2 Cl-35.5 O-16 H-1

moles=mass/molar mass

moles of PbO = 6.5/(207+16) = 6.5/223.2 = 0.029148if 1 mole = 2 moles of HClthen 0.029148= 2x0.029148= 0.058296

moles of HCl= 3.2/(1+35.5) = 3.2/36.5 = 0.08767if 2 moles of HCl= 1 mole of PbOthen 0.08767= 1x 0.8767/2 = 0.04384

Therefore PbO is the limiting reagent.Calculate moles of PbCl2 produced as follows:if 1 mole of PbO = 1 mole of PbCl2then 0.029148 will give= 1 x 0.029148 moles

Therefore moles of PbCl2 produced = 0.029148 moles

खाद्य परिरक्षणखाद्यको उपचारित करने और संभालने की एक ऐसी प्रक्रिया है जिससे उसके खराब होने (गुणवत्ता, खाद्यता या पौष्टिक मूल्य में कमी) की उस प्रक्रिया को रोकता है या बहुत कम कर देता है, जो सूक्ष्म जीवाणुओं द्वारा होती या तेज कर दी जाती है। यद्दपि कुछ तरीकों में, सौम्यबैक्टीरिया, जैसेखमीरयाकवकका प्रयोग किया जाता है ताकि विशेष गुण बढ़ाए जा सके और खाद्य पदार्थों को संरक्षित किया जा सके (उदाहरण के तौर पर पनीर और शराब).पौष्टिकमूल्य, संरचना औरस्वादबनाना और उसका अनुरक्षण, खाद्य के रूप में उसके गुणों को संरक्षित रखने के लिए महत्वपूर्ण है। यह सांस्कृतिक रूप से आश्रित है क्योंकि जो एक संस्कृति के लोगों के लिए खाने योग्य है, वह दूसरी संस्कृति के लोगों के लिए नहीं भी हो सकती है।

संरक्षण प्रक्रिया में आम तौर परबैक्टीरियाकवकऔर अन्यजीवाणुकी वृद्धि को रोकना और साथ ही साथसड़ी हुई दुर्गन्धपैदा करने वालीवसाकेऑक्सीकरणकी गति को धीमा करना शामिल है। इसमें वह प्रक्रिया भी शामिल है जिसके तहत भोजन तैयार करते समय प्राकृतिक परिपक्वन और विवर्णता का प्रावरोध किया जाता है, जैसे कटे हुए सेबों में प्रतिक्रिया स्वरूपपाचकरस संबंधी भूरापनका होना. कुछ संरक्षण विधियों में खाद्य पदार्थ को उपचार के पश्चात सीलबंद करने की आवश्यकता होती है, ताकि उन्हें जीवाणुओं द्वारा पुनः दूषित करने से बचाया जा सके; अन्य, जैसे कि सुखाना, खाद्य पदार्थों को लंबे समय तक बिना किसी विशेष नियंत्रण के संग्रहित रखने में सहायता करते हैं।

Answer: (i)3 atomsbecause H2S molecule hastwo atomsof hydrogen and one atom of sulphur. (ii)5 atomsbecause PO43- ion has one atom of phosphorus andfour atomsof oxygen

1) the hydrogen = 2 atom the oxygen =4 atom=6atoms2) the phosphorus = 1 atomthe oxygen =4 atom= 5 atom

please question clean rakhe

2 is the correct answer

Ans :- Therefore,acidiccharacter increases.H2Te haslessbond dissociation enthalpythan H2S. So,lessenergy is required to break H2Tebond & releasing [H]+ is easier & hence theacidityofH2Teis higher. Whereas,H2Shas High Bond Dissociation Energy & hence theacidityofH2S is less.

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O is more electronegative than S,this is the reason why H2O is more polar than H2S.

Ethene + permanganate + water → Ethan- 1,2 diol + manganese (IV) oxide + hydroxide

3 CH2=CH2(g) + 2 KMnO4 (aq) + 4 H2O (l) → 3 CH2OHCH2OH (aq) + 2 MnO2 (s) + 2 KOH (aq)

how can calculate the eight H + ion

Examples of primary standardsused in redox titrations include pure iron, NaC2O4 (sodium oxalate), As2O3 (arsenic trioxide), K2Cr2O7 (potassium dichromate), KBrO3 (potassium bromate), KIO3 (potassium iodate) and KH(IO3)2 (potassium hydrogen iodate).

option A

it's 72/60 times for a healthy

सिलिकॉन(Silicon);प्रतीक:S i) एकरासायनिक तत्वहै। यहपृथ्वीपरऑक्सीजनके बाद सबसे अधिक पाया जाने वाला तत्व है। सिलिकॉन के यौगिकएलेक्ट्रॉनिक अवयव, साबुन, शीशे एवंकंप्यूटर चिप्समें इस्तेमाल किए जाते हैं। सिलिकॉन की खोज१८२४मेंस्वीडनके रसायनशास्त्रीजोंस जकब बज्रेलियसने की थी।आवर्त सारिणीमें इसे १४वें स्थान पर रखा गया है।

सिलिकॉन एक मेटलॉइड है। इसे आवर्त सारणी पर कार्बन समूह, समूह 14 के सदस्य के रूप में भी वर्गीकृत किया गया है। यह एक धातु और एक अधातु के बीच गुण है। वे भंगुर होते हैं, लेकिन धातु की तरह दिखते हैं, जिसमें अधिकांश गुण एक अधातु के समान होते हैं।

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2NOCl(g) <==> 2NO(g) + Cl2(g) 0.64 atm ...........0.24 atm..0.12 atm..... P(total) = 1.00 atm

Kp = P(NO)² P(Cl2) / P(NOCl)² Kp = (0.24)² (0.12) / (0.64)² Kp = 0.017 ≃ 17 × 10⁻³ atm

option b

SO2 aur Cl2 ka percentage 30% diya h to apne 40 kyo liya h..

temperature aur pressure ka koi use nhi h kya,kp depends upon temperature and pressure

Amorphous solids are a type of solid that lacks definition in shape, pattern and long-range order. They are opposite to crystalline solids, which have a defined shape, pattern, and long range order. Amorphous solids do not have a well-defined melting point.

TheInternetis the global system of interconnected computer networks that use theInternetprotocol suite (TCP/IP) to link devices worldwide.

👍👍correct easy and simple answer

sanded by laasya tak

Question you have submitted is incomplete. Please post a complete question.

Basic ConceptsinChemistry. The following topic areas are the mostbasic conceptsthat a sucessfulchemistrystudent needs to master:ChemicalNomenclature(this unit required for credit) Atomic Structure.

X-200.--> 90 (say)X-199 --> 8 (say)X-202. -->2(say)200*90+199*8+202*2/90+8+219996/100=199.96=200amu(approx)

199amu 199amu 199amu

Element is a type of pure substances.

I know this.......

Ans :- Newton's law of universal gravitation states that a particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Moles of urea = molecules/avogadro no

= 6.02X10^20 / 6.022 X 10^23

= 10^-3 moles

So it will have 10^-2 mole in 1 litre of solution

because

Molarity/concentration = mole / litre

= 10^-3/1L

= 10^-2M

The molar mass of urea is 60g/mol. That means that every mole of urea has a mass of 60 grams and that in every gram of urea there are 0.01667 moles . Based on that, we can calculate the moles in 5.6 grams of urea.

5.6 grams * 0.01667 moles per gram = 0.09333 moles

We know that in every mole there are 6.022140857 × 10^23 units of the substance, in this case molecules.

6.022140857 × 10^23 molecules per mole * 0.09333 moles = 5.6207 x 10^22 molecules

The molecular formula of urea is CO(NH2)2 so there are 4 hydrogen atoms in every molecule of urea.

The approximate number of hydrogen atoms in a molecule of urea is 2.248 * 10^23

No of atoms of Nitrogen = half of the number of atoms of H

= 1.12 x 10^23 atoms of N

No of atoms of C or O = half of the number of atoms of N

= 0.56 x 10^23 atoms of C or O

= 5.6 x 10^22 atoms of C or O

Urea = NH2CONH2

M.wt = 60

5.6 g urea = 5.6/60 = 0.093 moles

1 mole of urea contains 4N atoms of H

0.093 moles contains 0.093 x 4N atoms of H

= 2.24 x 10^23 atoms of H

No of atoms of Nitrogen = half of the number of atoms of H

= 1.12 x 10^23 atoms of N

No of atoms of C or O = half of the number of atoms of N

= 0.56 x 10^23 atoms of C or O

= 5.6 x 10^22 atoms of C or O

molar mass of urea = 16+12+16+16 = 60

% of nitrogen by mass in 1 mole of Urea = 28/60 = 46.66%

now mass of N in 5g urea = 5*(46.66/100) = 2.33g

Hydrogen atomic mass : 1 amuOxygen atomic mass: 16 amuPhosphorus atomic mass : 31 amu (30.97+)

compound: H3 PO4: Total = 3 * 1+ 31 + 16 * 4 = 98 amu

% by mass of Hydrogen: 100*1/98 = 1.02 % of Oxygen: 100* 64 /98 = 65.31 % roundednumber of Phosphorous: 100* 31 / 98 = 31.63%

tribasic acid... this is because it has 3 hydrogen ions to donate (h3po4)

H3PO4,phosphoric acid, can be written O=P(OH)3. It has threeacidicprotons (attached to oxygen) and is therefore tribasic. hence option b

Biodiversity or biologicaldiversitymeans the variety ofliving organismspresent on a particular region. There are about 20 lacorganismsknown on the Earth which differ from one another in external form, internal structure, mode of nutrition, habitat, etc.

Answer:d) a)&c)Explanation

enzymes are heterogeneous catalysis

Homogeneous catalysis is a class of catalysis in which the catalyst occupies the same phase as the reactants.

Examples of Homogeneous Catalysts

Acid catalysis, organometallic catalysis, and enzymatic catalysis are examples of homogeneous catalysis. Most often, homogeneous catalysis involves the introduction of an aqueous phase catalyst into an aqueous solution of reactants. In such cases, acids and bases are often very effective catalysts, as they can speed up reactions by affecting bond polarization

option B should be correct.

nope. this is a multiple answer correct question