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Number of Days between8thDecember, 2006 and8thDecember, 2007→ 365 days = 364 + 1 day = 52 weeks + 1 day or in other words 1 odd day.

Since, 8th December 2007 is a Saturday. 8th December 2006 will be the day previous to Saturday that is Friday.

Hence, Friday is the correct answer.

The angle between the hour hand and the minute hand when the clock shows 6:35 am can be calculated using the following formula:

Angle = l11M/2 – 30H l

Where M = minutes and H = hours

Here, M = 35 and H = 6

Therefore, angle = l (11 × 35)/2 - 30 × 6l = 192.5 – 180 = 12.5

Hence, 12.5° is the correct answer.

The correct answer isThursday.

• The year 2018 is not a leap year.
• So, 15th February 2019 will be a Friday.
• The year 2019 is not a leap year so there are 28 days in February.
• So the number of days after 15th February 2019 to 18th April 2019 are 13 + 31 + 18 = 62
• Number of odd days in 62 days = 6
• Thus, on 18th April 2019, the day will be Friday + 6 days = Thursday.
• Hence, "option 4" is the correct answer.

26th April 2007 = 2006 years + period from 1.1.2007 to 26.4.2007

Number of odd days in 1600 years = 0

Number of odd days in 400 years = 0

Number of odd days in 6 years = 1 leap year + 5 ordinary years

= (1 × 2 + 5 × 1) ÷ 7 = 7 ÷ 7 = 0 odd days

Number of days from 1.1.2007 to 26.4.2007 = 31 + 28 + 31 + 26 = 116 days

→ 116 days = 16 weeks + 4 odd days

Total odd days = 0 + 0 + 0 + 4 = 4 = 4 odd days

‘4’ is the code for Thursday.

Hence, ‘Thursday’ is the correct answer

Year- One year has 365 days or 366 days on this basis the year is divided into two parts:

• Normal year- It has 365 days.
• Leap year- It has 366 days and completely divisible by 4.

Century leap year- The year which is exactly divisible by 400. Example - 1200, 1600, 2000 etc.

Counting of Odd days

Ordinary Year: 365 days (52 weeks + 1 days)

=1 Odd days

Leap Year: 366 days (52 weeks + 2 days)

=2 Odd days

11 August 2018 is a Saturday so 11 August 2017 was a Friday (2018 is not a leap year).

21 April 2017 to 11August 2017 = 10+ 31 + 30 + 31 + 11= 113 days i.e. 16 weeks + 1 odd day

20 April2017 + 113 days or 1 odd day = 11 August 2017

So, Friday -1 day = Thursday

Hence, the correct answer is 'Thursday'.

Date: 15thApril1800

Steps to find the day of the week:

Total = (0 + 0+ 0+ 15) = 15

And 15÷ 7,we get 1as the remainder.

Code for Centuries:

1600 → 6, 1700 → 4, 1800 → 2,1900 → 0, 2000 → 6, 2100 → 4, 2200 → 2, 2300 → 0

So for 1800→ no odd days will be added.

Total odd days = 2 + 1 = 3

Day code for this method is given below:

So, ‘3’ is the code for Monday.

Hence,‘Tuesday’is the correct answer.

Year- One year has 365 days or 366 days on this basis the year is divided into two parts:

• Normal year- It has 365 days.
• Leap year- It has 366 days and is completely divisible by 4.

Century leap year- The year which is exactly divisible by 400. Example - 1200, 1600, 2000 etc.

Counting of Odd days

Ordinary Year:365 days (52 weeks + 1 day)
=1 Odd days
Leap Year:366 days (52 weeks + 2 days)
=2 Odd days

Month codes:

Code for Days:

Code for Centuries:

1600 → 6

1700 → 4

1800 → 2

1900 → 0

2000 → 6

2100 → 4

2200 → 2

2300 → 0

For,

15April2029,

Date = 15

Code for April= 6

Code for Century = 6

2029= 2000 + 29

For, 2000 it is 6

For,

29it is 29

And,

29/ 4 = 7

Adding all these = 15+ 6+ 6 + 29+ 7= 63

63 / 7 = 0(here we consider the remainder)

0 is the code for Sunday.

15 April 2029is Sunday.

Hence, Sundayis the correct answer.

5thday of the month = Friday - 4 = Monday

Now, to find the day on 21stof the same month, we will need to find the number of odd days between 5thand 21st of the month.

Odd days = 21- 5 = 16 = 2 odd days

Now, odd days in 16 days are 2.

Monday + 2 odd days = Wednesday.

Therefore, the day on 21stof the given month is Wednesday.

Given,

17thday of a month is three days earlier than Thursday, which is Monday.

Thus on 19th day, it will be Wednesday.

Hence, the correct answer isWednesday.

Given,

The second day of a month is Friday.

The total number of days between second of this month and last day of next month = Remaining days of this month + 31

But, we don't have enough information about how many days the current month have, we cannot determine number of odd days.

Hence,data inadequate is the correct answer.

Given, 3rdDay of the month = Friday

So,7× 3 = 21

21 + 3 = 24so, 24th day will be also Friday.

Therefore, 4th day after twenty first =21 + 4 = 25since, 24 is Friday , 25th will beSaturday.

Hence, option 3 is the correct answer.

Three days earlier than Friday→ Friday - 3 = Tuesday.

If the seventh day of a month is three days earlier than Friday.

It means the 7th day of the month is Tuesday.

As 7th of the month is Tuesday, so 14th of the month is Tuesdayagain.

14 + 5 = 19⇒ Tuesday+ 5 = Sunday

Therefore, Sundaywillbe on the nineteenth day of the month.

Hence, ‘Sunday’ is the correct answer.

According to the given information,

7th day of the month is 3 days earlier than Friday i.e., 7th day is Tuesday.

14th day also be Tuesday.

14 + 5 → Tuesday + 5 = Sunday.

19th of the month is Sunday.

Hence, “Sunday” is the correct answer.

Hence, ‘Saturday’ is the correct answer.

Given:

If the day after the day after tomorrow =three daysbefore Friday

Three days before Friday is Tuesday

The day after the day after tomorrow = Tuesday then, the present day is Saturday.

Hence, Saturdayis the answer.

1996 is a leap year while 1997 and 1998 are nonleap years.
Total number of days in these three years = 366 + 365 + 365 = 1096 days
1096÷ 7 = 156 weeks and 4 days
As the year started with Monday, implies, the 156th week would end on Sunday. The next four days would be Monday, Tuesday, Wednesday, and Thursday.
Thus the years 1998 would end on Thursday and the year 1999 would start on Friday.

Hence, the year 1999 will start with Friday.