1.

What day of the week was on 15th April 1800?1. Tuesday2. Thursday3. Wednesday4. Saturday

Answer» Correct Answer - Option 1 : Tuesday

Month

Jan

Feb

Mar

Apr

May

Jun

Jul

Aug

Sep

Oct

Nov

Dec

Code

1

4

4

0

2

5

0

3

6

1

4

6

Date: 15thApril1800

Steps to find the day of the week:

Last two digits of the year

00

No. of the leap year (quotient)

00 ÷ 4

quotient= 0

Code of the month

0

Date

15

Total = (0 + 0+ 0+ 15) = 15

And 15÷ 7,we get 1as the remainder.

Code for Centuries:

1600 → 6, 1700 → 4, 1800 → 2,1900 → 0, 2000 → 6, 2100 → 4, 2200 → 2, 2300 → 0

So for 1800→ no odd days will be added.

Total odd days = 2 + 1 = 3

Day code for this method is given below:

Code

Day

1

Sunday

2

Monday

3

Tuesday

4

Wednesday

5

Thursday

6

Friday

7/0

Saturday

So, ‘3’ is the code for Monday.

Hence,‘Tuesday’is the correct answer.

Year- One year has 365 days or 366 days on this basis the year is divided into two parts:

  • Normal year- It has 365 days.
  • Leap year- It has 366 days and is completely divisible by 4.


Century leap year- The year which is exactly divisible by 400. Example - 1200, 1600, 2000 etc.

Counting of Odd days

Ordinary Year:365 days (52 weeks + 1 day)
=1 Odd days
Leap Year:366 days (52 weeks + 2 days)
=2 Odd days



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