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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
In the process of extraction of gold. Roasted gold ore `+CN^(-)+H_(2)O overset(O_(2))rarr [X]+OH^(-)` `[X]+Znrarr [Y]+Au` Identify the complexes `[X] ` and `[Y]`.A. `Au(CN)_(2)]^(-), [Zn(CN)_(4)]^(2-)`B. `[Au(CN)_(4)]^(3-), [Zn(CN)_(4)]^(2-)`C. `[Au(CN)_(2)]^(2-), [Zn(CN)_(6)]^(4-)`D. `[Au(CN)_(4)]^(-), [Zn(CN)_(4)]^(2-)` |
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Answer» Correct Answer - A `overset(-)(CN)(aq) + H_(2)O overset(o_(2))rarr[X] +[OH^(-)]` `[X]+Znrarr[Y]+Au` Identify the complexes [X]and[Y]. |
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| 352. |
According to the postulates of Werner for cooedination compoundsA. Primary valency is ionizableB. Secondary valency is ionizableC. Primary and secondary valencies are non-ionizableD. Only primary valency is non-ionizable |
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Answer» Correct Answer - A Primary valencies are ionizable. |
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| 353. |
Ligands in a complex salt are:A. anions ilnked by coordinate bonds to a central metal atom or ionB. cations linked by coordinate bonds to a central metal or ionC. molecules linked by coordinate bonds to a central metal or ionD. ions or molecules linked by coordinate bond to a central atom or ion . |
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Answer» Correct Answer - D Ligands in a complex salt are ions or molecules linked by coordinate bonds to a centrl atom or ion. |
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| 354. |
The complex used as an anticancer agent isA. `cis-[PtCl_(2)(NH_(3))_(2)]`B. `cis-K_(2)[PtCl_(2)Br_(2)]`C. `Na_(2)CoCl_(4)`D. `mer-[Co(NH_(3))_(3)Cl_(3)]` |
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Answer» Correct Answer - A The complex cis-platin is used as anticancer agent |
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| 355. |
The complex used as an anticancer agent isA. mer-`[Co(NH_(3))_(3)Cl_(3)]`B. cis-`[PtCl_(2)(NH_(3))_(2)]`C. cis-`K_(2)[PtCl_(2)Br_(2)]`D. `Na_(2)[CoCl_(4)]` |
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Answer» Correct Answer - B See Comprehensive Review. |
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| 356. |
A group of atoms can function as a ligand only when :A. It is a small moleculeB. It has an unshared electron pairC. It is a negatively charged ionD. It is a positively charged ion. |
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Answer» Correct Answer - B A group of atom or atom can function as a ligand only when it has one or more unshared electron pairs. |
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| 357. |
A group of atoms can function as a ligand only when :A. It is a small moleculeB. It is capable of acting as donor of electron pairC. It is a negatively charged ionD. It is positively charged ion. |
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Answer» Correct Answer - B Conceptual question |
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| 358. |
Generally, a group of atoms can function as a ligand ifA. it is a small moleculeB. it has an unshared pair of electronsC. it is a positively charged ionD. none of these |
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Answer» Correct Answer - B (b) is the correct answer. |
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| 359. |
The correct name of the compound `[Cu(NH_(3))_(4)](NO_(3))_(2)`, according to IUPAC system isA. cuprammonium nitrateB. tetramminecopper(II) nitrateC. tatraaminecopper(II) nitrateD. tetraamminecopper(II) dinitrite |
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Answer» Correct Answer - B See Comprehensive Review. |
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| 360. |
IUPAC name `[Co(NH_(3))_(5)(NO_(2))]Cl_(2)` isA. pentaaminenitrito-N-cobalt II chlorideB. pentaaminenitrito-N-cobalt (III) chlorideC. nitrito-N-pentaaminecobalt III chlorideD. nitrito-N-pentaaminecobalt II chloride. |
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Answer» Correct Answer - B pentaamine -N-cobalt III chloride. |
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| 361. |
IUPAC name of `Na_(3)[Co(NO_(2))_(6)]` isA. sodium cobaltinitriteB. sodium hexanitritocobaltale(III)C. sodium hexanitrocobalt (III)D. sodium hexanitricobaltate(II) |
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Answer» Correct Answer - B (b) is the correct answer. |
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| 362. |
The IUPAC name of `` is :A. tetrachloridoronickel (II) tetramminenickel (II)B. tetraaminnenickle (II) tetrachloridonickel (II)C. tetraamminenickel (II) tetrachlorido-nickelate (II)D. tetrachloridonickel (II) tetramminenic-kelate (0). |
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Answer» Correct Answer - c According to latest IUPAC modification , the correct name is : tetraaminenickel(II) tetrachloridonickele (II) |
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| 363. |
The correct IUPAC name of `AlCl_(3).4(Et.OH)` isA. aluminium(II) chloride-4-ethanolB. aluminium(III) chloride-4-ethanolC. aluminium(IV) chloride-4-hydroxyethaneD. aluminium chloride-4-ethanol |
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Answer» Correct Answer - B Questions based on rules of nomenclature (Refer to Comprehensive Review). |
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| 364. |
What is not true about a ligandA. It can act as Lewis baseB. It can be monodentate or multidentateC. A monodentate ligand cannot be chelating ligandD. A multidentate ligand cannot cause chelation. |
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Answer» Correct Answer - D A multidentate ligand can cause chelation. |
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| 365. |
what is the relationsphip between observed colour of the complex and the wavelength of light absorbed by the complex ? |
| Answer» When white light falls on the complex, some part of it is observed in causing d-d transition or spitting. Higher the crystal field splitting, lower will be the wavelength of the radiations absorbed by the complex. The observed colour of light generated will correspond to the wavelength which is left over. | |
| 366. |
Which of the following complexes are homoleptic ?A. `[Co(NH_(3))_(6)]^(3+)`B. `[Co(NH_(3))_(4)Cl_(2)]^(+)`C. `[Ni(CN)_(4)]^(2+)`D. `[Ni(NH_(3))_(4)Cl_(2)]` |
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Answer» Correct Answer - A::C a,c are both homoleptic since they have only same ligands present. |
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| 367. |
Which among the following is a homoleptic complex ?A. tris (ethane-1,2-diamine) cobalt (III) chlorideB. triamminetriaquachromium (III) chlorideC. diamminechloridonitrito-N-platinum (II)D. pentamminecarbonatocobalt (III) chloride |
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Answer» Correct Answer - A It is homoleptic in nature since all the three ligands (en are the same . |
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| 368. |
The coordination number of a central metal atom in a complex is determined by:A. the number of ligands around a metal ion bonded by sigma-pi-bonds bothB. the number of ligands around a metal ion bonded by pi-bondsC. the number of ligands around a metal ion bonded by sigma bondsD. the number of only anionic ligands bonded to the metal ion. |
| Answer» is the correct answers | |
| 369. |
The coordination number of a central metal atom in a complex is determined by:A. The number around a metal is bonded bt pi-bondsB. The number of only anionic ligands bonded to the metal atomC. the number of ligands aronud a metal ion bonded sigma and pi-bonds bothD. The number of ligands around a metal ion bonded by sigma bonds. |
| Answer» The number of atoms of the ligand that one directly bonded to the central metal atom or ion by coordinate bond is known as the coordination number of metal = number of `sigma` bonds formed by metal with ligand. | |
| 370. |
The coordination number of a central metal atom in a complex is determined by:A. the number of ligands around a metal ion bonded by sigma bondsB. the number of ligands around a metal ion bonded pi-bondsC. the number of ligands aronud a metal ion bonded sigma and pi-bondsD. the number of only anionic ligands bonded to the motal ion. |
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Answer» Correct Answer - A See Comprehensive Review. |
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| 371. |
`CN^(-)` is a strong field ligand. This is due to the fact thatA. it carries negative chargeB. it is pseudo-halideC. it can accept electrons from metal speciesD. it forms high spin complexes with metal species. |
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Answer» Correct Answer - B Cyanide ion is strong field ligand because it is a pseudohalide. Psudohalide ions are stronger coordination ligands and they have the ability to forms `sigma`-bond (from the pseudohalide to the metal) and `pi` -bond (from the metal to pseudo-halide). |
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| 372. |
Which of the following complex has minimum magnitude of `Delta^(0)` ?A. `|Cr(CN)_(6)|^(3-)`B. `|Co(NH_(3))_(6)|^(3+)`C. `|CoCl_(6)|^(3-)`D. `|Cr(H_(2)O)_(6)|^(3+)` |
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Answer» Correct Answer - C `|Cr(CH)_(6)|^(-3)Cr^(3+)=d^(3)=t_(2g)^(3) , CFSE = - 1.2Delta_(0)` `|Co(NH_(3))_(6)|^(3+)(NH_(3)rarr "strong field ligand") Co^(3+) = d^(3)= t_(2g)^(6)e_(g)^(0) , CFSE = 2.4 Delta_(0)` `|CoCl_(6)|^(3-)(Clrarr "weak field ligand")` `Co^(3+) = d^(6) = t_(2g)^(4)e_(g)^(2) , CFSE = - o .4Delta_(0) |Cr(H_(2)O)_(6)|^(3+)` `Cr^(3+) = d^(3) = t_(2g)^(3)e_(g)^(0) = - 1.2Delta_(0)` `:.`"minimum" CFSE is for `|CoCl_(3)|^(3-)` |
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| 373. |
A metal complex having the composition or `(NH_(3))_(4)Cl_(2)Br` has been isolated in two form A and B. The form A reacts with `AgNO_(3)` to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in concentrated ammonia .The formule of the complex B isA. `[Cr(NH_(3))_(4)Br]Cl_(2)`B. `[Cr(NH_(3))_(4)ClBr]Cl`C. `[Cr(NH_(3))_(4)Cl_(2)]Br`D. `[Cr(NH_(3))_(4)]BrCl_(2)` |
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Answer» Correct Answer - C |
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| 374. |
A coordination compound of cobalt has the molecular, formula containing five ammonia molecules, one nitro group and two chlorine atoms for onew cobalt atom. One mole of this compounds three ions in an aqueous solution. On reacting this solution with excess of `AgNO_(3)` solution, we get two moles of AgCI precipitate. The ionic formula for this complex would beA. `[Co(NH_(3))_(4)NO_(2)Cl](NH_(3))Cl]`B. `[Co(NH_(3))_(5)Cl][Cl(NO_(2))]`C. `[Co(NH_(3))_(5)(NO_(2))]Cl_(2)`D. `[Co(NH_(3))]_(5).[(NO_(2))_(2)Cl_(2)]`. |
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Answer» Correct Answer - C The molecular formula of complex is `Co(NH_(3))_(5)NO_(2)Cl_(2)`. As the one mole of compound produces two moles of AgCl with `AgNO_(3)(aq)`, it has two ionisable `Ci^(-)` ions per molecule. Thus , possible ionic formula is `[Co(NH_(3))_(5)No_(2)]Cl_(2)` . It ionises to produce one `[Co(NH_(3))_(5)NO_(2)]^(2+)` and two `Cl^(-)` ions i.e. , in all three ions per molecule. |
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| 375. |
A coordination compound of cobalt has the molecular, formula containing five ammonia molecules, one nitro group and two chlorine atoms for onew cobalt atom. One mole of this compounds three ions in an aqueous solution. On reacting this solution with excess of `AgNO_(3)` solution, we get two moles of AgCI precipitate. The ionic formula for this complex would beA. `[Co(NH_(3))_(4)ClNO_(2)][NH_(3)Cl]`B. `[Co(NH_(3))Cl][ClNO_(2)]`C. `[Co(NH_(3))_(5)NO_(2)]Cl_(2)`D. `[Co(NH_(3))_(5)](NO_(2))_(2)Cl_(2)]` |
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Answer» Correct Answer - C `[Co(NH_3)_5(NO)_2)]Cl_2ltimplies[Co(NH_3)_5(NO_2)]^(+)+ 2Cl^(-)` |
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| 376. |
The existence of two different coloured comlexes with the composition `|Co(NH_(3))_(2)Cl_(2)|^(+)` is due toA. Ionisation isomerismB. Linkage isomerismC. Geometrical isomerismD. Co-ordination isomerism. |
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Answer» Correct Answer - C The cis and trans forms of given complex have different colours. |
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| 377. |
Which of the following is wrongly matched?A. `|Cu(NH_(3))_(4)|^(2+)` - Square planarB. `Ni(CO)_(4)|` - neutral ligandC. `|Fe(CN)_(6)|^(3-) - sp^(3)d^(2)`D. `|Co(en)_(3)|^(3+)` - follows EAN rule |
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Answer» Correct Answer - C `|Fe(CN)_(6)|^(-3)` is an inner orbital octahedral complex with hybridization `d^(2)sp^(3)`. |
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| 378. |
Different theories have been put forward to explain the geometrical of co-ordianation compounds. Out of them , the most practical is the valence bond theory which is based upon the concept of hybridisation . According to this , the complexes with C.N.4 may be either tetrahedral (`sp^(3)` hybridised ) or square planar (`dsp^(2)` hybridised ) in nature. Similarly , in the octahedral complexes , the metal atom or ion is either paramagnetic if one or more orbitals are half-filled and diamagnetic if all are filled in nature. Which has the highest paramagnetic character ?A. `[Cr(H_(2)O)_(6)]^(3+)`B. `[Fe(H_2)O)_(6)]^(2+)`C. `[Cu(H_(2)O)_(6)]^(2+)`D. `[Zn(H_(2)O)_(6)]^(2+)` |
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Answer» Correct Answer - b `Fe^(2+)` ion with maximum number of unpaired electrons (4) shows maximum para-magnesium in the complex `[Fe(H_(2)O)_6]^(2+)` . |
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| 379. |
Different theories have been put forward to explain the geometrical of co-ordianation compounds. Out of them , the most practical is the valence bond theory which is based upon the concept of hybridisation . According to this , the complexes with C.N.4 may be either tetrahedral (`sp^(3)` hybridised ) or square planar (`dsp^(2)` hybridised ) in nature. Similarly , in the octahedral complexes , the metal atom or ion is either paramagnetic if one or more orbitals are half-filled and diamagnetic if all are filled in nature. 5. Which is correct in the case of `` complex ?A. diamagneticB. octahedralC. `ds^(2)p^(3)` hybridisedD. all are correct. |
| Answer» Correct Answer - d | |
| 380. |
Complex `[CoCl_(2)(en)_(2)]^(+)` canA. exist as cis and trans isomersB. exist as pair of optical isomersC. both are correctD. none is correct. |
| Answer» Correct Answer - C | |
| 381. |
The coordination number,oxidation number and the number of d-electrons in the metal ion in the complex `[CoCl_(2)(en)_(2)]Cl` , are respectively (atomic number of CO= 27)A. 4,3 and 6B. 6,2 and 6C. 6, 6 and 3D. 4, 2 and 6 |
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Answer» The complex is : `[CoCl_2(en)_2]`Cl. Complex is octahedral , CN of CO is 6 `Co^(3+)` has `3d^(6)` electronic configuration is +3 |
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| 382. |
For the given complex `[CoCl_(2)(en)(N_(3))_(2)]^(+)`, the number of geometrical iosmers, the number of optical isomers and total number of isomers of all type possible respectively areA. 2, 2 and 4B. 2 ,2 and 3C. 2, 0 and 2D. 0, 2 and 1 |
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Answer» Correct Answer - B The octahedral complex of the type `[M(A A)(x_(2)y_(2))]` i.e. `|CoCl_(2)(en)(NH_(3))_(2)|^(+)` will show two cis and trans isomers . Out of these , cis isomer will be optical active and shows two d & l forms . So the total number of possible isomers will be three . |
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| 383. |
The type of isomersim shown by the complex `[CoCl_(2) (en)_(2)]` isA. geometrical isomerismB. coordination isomerismC. ionization isomerismD. linkage isomerism |
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Answer» Correct Answer - A `[CoCl_2(en)_2]` exhibits geometrical isomerism. For structures , consult section 7. |
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| 384. |
`[Co(NH_(3))_(6)][CI_(2)NO_(2)` and `[CO(NH_(3))_(4)CI(NO_(2))CI` exhibit which type of isomersim ?A. GeometricalB. OpticalC. LinkageD. Ionisation |
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Answer» Correct Answer - D `[Co(NH_(3))_(4)Cl_(2)]NO_(2)` and `[Co(NH_(3))_(4)ClNO_(2)]Cl` are examples of ionisation isomerism |
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