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301.

Tetraaminecopper (II) ion is a square planar complex with one unpaired electron. According to valence bond theory the hybrid state of copper should beA. `sp^(3)`B. `sp^(2)`C. `dsp^(2)`D. None of above.

Answer» Correct Answer - C
`dsp^(2)`
302.

`K_(3)CoF_(6)` is high spin complex. What is the hybrid state of Co atom in the complex?A. `sp^(3)d`B. `sp^(3)d^(2)`C. `d^(2)sp^(3)`D. `dsp^(2)`

Answer» Correct Answer - B
Hubrid state is `sp^(3)d^(2)`
303.

`[Cu(NH_(3))_(4)]^(2+)` is a square planar complex.The number of unpaired electrons and hybrid state of copper are respectivelyA. 4, `dsp^(2)`B. 1, `sp^(2)`C. 1, `dsp^(2)`D. 4s, `sp^(3)`

Answer» Correct Answer - C
`[Cu(NH_(3))_(4)]^(2+)` is square planar with one unpaired electron and `dsp^(2)`-hybridization of Cu.
304.

In the conplex `[Ni(H_(2)O)_(2)(NH_(3))_(4)]^(2+)` the number of unpaired electrons is

Answer» Correct Answer - D
Two unpaired electrons .
305.

Wht will be the theoretical value of magnetic moment `(mu)` when `CN^(-)` ligands join `Fe^(3+)` ion to yield complexA. `2. 83 ` BMB. `3.87` BMC. `5.92` BMD. `1.73` BM

Answer» Correct Answer - D
n = 1 `:.mu=sqrt(n(n+2))=sqrt(3)" "BM=1.73BM`
306.

Write the structural formula of the following compounds : (i) Dichloridobis (ethylenediamine) cobalt (IV) sulphate (ii) tetraminechloridonitrocobalt (III) sulphate (iii) tetraaquodichloridochromium (III) nitrate

Answer» (i) `[CoCl_(2)(en)_(2)]SO_(4)` (ii) `[Co(NH_(3))_(4)ClNO_(2)]NO_(3)` (iii) `[Cr(H_(2)O)_(4)Cl_(2)]NO_(3)`
307.

`K_(4)[Fe(CN)_(6)]` is aA. double saltB. complex compoundC. neutral moleculeD. none of these

Answer» Correct Answer - B
(b) is the correct answer.
308.

`K_(4)[Fe(CH)_(6)]` is calledA. potassium hexacyanoferrate (II)B. potassium ferricyanideC. potassium hexacyanoferrate(III)D. prussian blue.

Answer» Correct Answer - A
`K_(4)[Fe(CN)_(6)]` , `O.S. of Fe = +2` (check it ) IUPAC name : potassium hexacyanoferrate (II)
309.

The complex `CoCl_(3),3NH_(3)` ionizes to giveA. `2Cl^(-)` ionB. `1Cl^(-)` ionC. `3Cl^(-)` ionD. `0Cl^(-)` ion.

Answer» Correct Answer - D
The complex `CoCl_(3).3NH_(3)` which has no ionisable chlorine is `[Co(NH_(3))_(3)Cl_(3)]`.
310.

The complex `CoCl_(3),3NH_(3)` ionizes to giveA. `2Cl^(-)`ionsB. `1Cl^(-)` ionC. `3Cl^(-)` ionsD. `No Cl^(-)` ion

Answer» Correct Answer - D
`Co^(2+)` has a coordination number of 6. Therefore complex is `[Co(NH_(3))_(3)Cl_(3)]` . It will give on `Cl^(-)` ions in solution.
311.

Nickel `(Z=28)` combines with a uninegative monodentate ligand `X^(-)` to form a paramagnetic complex `[NiX_4]^(2-)`. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively:A. one, tetrahedralB. two, tetrahedralC. one, square planarD. two, square planar.

Answer» is the correct answer because out of the three Cl atoms present, only one represents primary valency (ionisable) .
312.

It which of the following compounds the oxidation state of the nickel atom is zeroA. `KNiCl_(3)`B. `Ni(PF_(3))_(4)`C. `[Ni(NH_(3))_(6)]Cl_(2)`D. `Ni(CO)_(4)`

Answer» Correct Answer - D
O.N. of Ni in `Ni(CO)_(4)` is zero because CO is neutral ligand .
313.

In which of the following complexes the nickel metal is in highest oxidation state:A. `Ni(CO)_(4)`B. `K_(2)NiF_(6)`C. `[Ni(NH_(3))__(6)](BF_(4))_(2)`D. `K_(4)[Ni(CN)_(6)]`

Answer» Correct Answer - B
In `K_(2)NiF_(6)` the O.N. of Ni is `+4`
314.

In Zeigler-Natta polymerisation of ethylene, the active species isA. `AlCl_(3)`B. `Et_(3)Al`C. `CH_(2)CH_(2)`D. `Ti^(III)`

Answer» Correct Answer - D
It is believed that `TiCl_(4)` and trialkyl aluminium react to produce fibrous form of `TiCl_(3)` , which is active metal species in Zeigler-Natta catalyst.
315.

Which of the following will exhibit optocal isomerism ?A. `[Cr(en)(H_(2)O)_(4)]^(3+)`B. `[Cr(en)_(3)]^(3+)`C. trans-`[Cr(en)(Cl_(2))(NH_(3)_(2)]^(+)`D. `[Cr(NH_(3))_(6)]^(3+)`

Answer» Correct Answer - B
`[Cr(en)_(3)]^(3+)` exhibit optical isomerism. When an octahedral complex contains three bidentate groups, it show optically activity and exist in two enantonmeric forms.
316.

Correct formula of the complex formed in the brown ring test for nitrates isA. `FeSO_(4).NO`B. `[Fe(H_(2)O)_(5)NO]^(2+)`C. `[Fe(H_(2)O)_(5)NO]^(+)`D. `[Fe(H_(2)O)_(5)NO]^(3+)`

Answer» Correct Answer - B
The brown complex is `[Fe(H_(2)O)_(5)NO]^(2+)`
317.

Which of the following is expected to be a paramagnetic complex?A. `[Ni(H_(2)O)_(6)]^(2+)`B. `[Ni(CO)_(4)]`C. `[Zn(NH_(3))_(4)]^(2+)`D. `[Co(NH_(3))_(6)]^(3+)`

Answer» Correct Answer - A
In `[Ni(H_(2)O)_(6)]^(2+)` configuration of `Ni^(2+) is [Ar^(18)] 3d^(8)` Hybridisation is `sp^(3)d^(2)` . There are two unpaired electrons and hence complex is paramagnetic.
For structure of `Ni(CO)_(4)` see Q . 44 above . It is diamagnetic.
In `[Zn(NH_(3))_(4)^(2+), Zn^(2+)` has cnfiguration of `[Ar^(18)]3d^(10)`. It is diamagnetic .
For structure of `[Co(NH_(3))_(6)]^(3+)`. See Q. 26 . It is diamagntic
318.

The number of unpaired electrons in the complex ion `[CoF_6]^(3-)` is (Atomic no. of `Co=27`)A. 2B. 3C. 4D. 0

Answer» Correct Answer - C
Cobalt assumes `sp^(3)d^(2)` state and number of umpaired electron in `Co^(3+)` is 4
319.

Among the following , the species having square planar geometry for central atoms are (i) `XeF_(4)` (ii) `SF_(4)` (ii) `|NiCl_(4)|^(2-)` (iv)`|PtCl_(4)|^(2)`A. (i) and (iv)B. (i) and (ii)C. (ii) and (iii)D. (iii) and (iv)

Answer» Correct Answer - A
`XeF_(4)` = square planar `(sp^(3)d^(2))`
`SF_(4)` = distorted trigonal bipyramidal `(sp^(3)d)`
`|NiCl_(4)|^(2-)` = tetrahedral `(sp^(3))`
`|PtCl_(4)|^(2-)` = Square planar `(dsp^(2))`
320.

Which one of following octahedral complexes will not show geometrical isomerism ?A. `M[A_(2)B_(2)]`B. `M[A_(3)B_(3)]`C. `[MA_(4)B_(2)]`D. `[MA_(5)B]`

Answer» Correct Answer - D
The comlex `[MA_(5)B]` cannot show geometrical isomerism.
321.

A similarity between optical and geometrical isomerism is thatA. Each gives equal number of isomers for given compoundB. It in a compound one is present then so is the otherC. Both are included in stereoisomerismD. They have no similarity

Answer» Correct Answer - C
Both optical isomerism and geometical isomerism are examples of stereoisomerism.
322.

Which one of the following will not show geometrical isomerism?A. `[Cr(NH_(3))_(4)Cl_(2)]Cl`B. `[Cu(en)_(2)Cl_(2)]Cl`C. `[Co(NH_(3))_(5)NO_(2)]Cl_(2)`D. `[Pt(NH_(3))_(2)Cl_(2)]`

Answer» Correct Answer - C
Octahadral complexes of type `(MA_(5)B)` do not show geometrical isomerism.
323.

According to Lewis the ligands areA. Acidic in natureB. Basic in natureC. Neither acidic nor basicD. Some are acidic and others are basic.

Answer» Correct Answer - B
As ligands give lone pair to the central metal atom or ion for coordinate bone formation, ligands are bases (Lewis comcept).
324.

In `[Ni(H_(2)O)_(6)]^(2+)` , the hybridisation of central metal ion is `:`A. `dsp^(3)`B. `sp^(3) d^(2)`C. `sp^(3)`D. `dsp^(2)` .

Answer» Correct Answer - B
`sp^(3)d^(2)` hybridisation is involved .
325.

Which of the following has the longest C-O bond length? (C-O bond length of CO is 1.128 `A`)A. `[Fe(CO)_(4)]^(2-)`B. `[Mn(CO)_(6)]^(+)`C. `Ni(CO)_(4)`D. `[Co(CO)_(4)]^(-)`

Answer» Correct Answer - A
Please note that greater the magnitude of negative charge on the carbonyl complex easier will be for the metal atom to make available its electrons to participate in the black bonding. Consequently higher would be the bond order and smaller would be the bond length. Under the circumstances the complex `[Fe(CO)_4]^(2-)` has minimum charge and as a result, C-O bond length would be the maximum.
326.

In `[Ni(H_(2)O)_(6)]^(2+)` , the hybridisation of central metal ion is `:`A. `d^(2)sp^(3)`B. `sp^(3)d^(2)`C. `sp^(3)`D. `dsp^(2)`

Answer» Correct Answer - B
327.

If the bond length of CO bond in carbon monoxide is `1.128 Å`, then what is the value of CO bond length in `Fe (CO)_(5)` ?A. `1.15Ã…`B. `1.128Ã…`C. `1.72Ã…`D. `1.118Ã…`

Answer» Correct Answer - A
The metal -carbon bond in carbonyls possisses both `sigma and pi` character-weak `sigma` bond being formed by donation of electron pair from carbon to metal `(M larr C-=O)` and a stronger `pi` bond being formed by back donation of electrons from filled `d_(xy)` orbital
of metal into empty antibonding `overset(**)pi` 2py orbital of carbon (`pi`M`rarr` C bond ) . The total bonding is thus M = C = O. Thus bond order of C-O bond is raduced from triple bond to double bond . As a rasult , C-O bond length of `1.128Ã…` in CO increases to about `1.15 Ã…` in many carbonyls.
328.

In ferrocene, hybridisation state of iron isA. `sp^(3)d^(2)`B. `d^(2)sp^(3)`C. `dsp^(3)`D. `sp^(3)d^(3)`

Answer» Correct Answer - `d^(2)sp^(3)`
329.

Oxidation state of Fe in ferrocene isA. `+1`B. `+3`C. `+2`D. None of these.

Answer» Oxidation state of Fe in ferrocene is `+2`
330.

Ferrocene isA. `Fe(eta^(5)-C_(5)H_(5))_(2)`B. `Fe(eta^(2)-C_(5)H_(5))_(2)`C. `Cr(eta^(5)-C_(5)H_(5))_(5)`D. `Os(eta^(5)-C_(5)H_(5))_(2)`

Answer» Correct Answer - A
It is `Fe(eta^(5)-C_(5)H_(5))_(2)`.
331.

Coordination compounds have great importance in biological system. In this context which of the following statements is incorrect ?A. Cynacobalamin is `` and contains cobaltB. Haemoglobin is the red pigment of blood and contains ironC. Chlorophylls are green pigments in plants and contain calciumD. Carbodypeptide-A is an enzyme and contains zinc

Answer» Correct Answer - C
Chlorophyll contains Mg and not Ca.
332.

Which of the following statements is incorrect ?A. In `K_(3)[Fe(CN)_(6)]` the ligand has satisfied only the secondary valency of ferric ion .B. In `K_(3)[Fe(CN)_(6)`, the ligand has satisfied both primary and secondary valencies of ferric ionC. In `K_(4)[Fe(CN)_(6)]` the ligand has satisfied both primary and secondary valencies of ferrous ion.D. In `[Cu(NH_(3))_(4)]SO_(4)` the ligand has satisfied only the secondary valency of copper.

Answer» Correct Answer - A
See Comprehensive Review.
333.

Which statement is incorrect ?A. `Ni(CO)_(4)`- Tetrahedral, paramagneticB. `[Ni(CN)_(4)]^(2-)`-Square planar, diamageticC. `Ni(CO)_(4)`-Tetrahedral, diamagneticD. `[NiCl_(4)]^(2-)` - Tetrahedral. Paramagnetic.

Answer» Correct Answer - A
`Ni(CO)_(4)` is a tetrahedral complex ane is diamagnetic due to the absence of unpaired electron.
334.

The incorrect among the following isA. pyridine is a monodentate ligandB. `[Ni(CN)_(4)]^(2-)` is tetrahedral and diamagneticC. organometallic compounds contain at least one metal-carbon bondD. The oxidation state of nickel in `[Ni(CO)_(4)]` is zero.

Answer» Correct Answer - B
`[Ni(CN)_(4)]^(2-)` is square planar complex.
335.

A reagent used for identifying nickel ion is:A. Potassium ferrocyanideB. PhenolphthaleinC. DimethylglyoximeD. Neutral ferric chloride

Answer» Correct Answer - C
DMG form red colured ppt. with `Ni^(2+)` ions .
336.

What is the oxidation state of Fe in introprusside ion ?A. `+1`B. `+2`C. `+3`D. None of these.

Answer» Nitroprusside ion is `[Fe(CN)_(5)NO]^(2+)` . In this ion oxidation state of Fe is (II), there are five `CN^(-)` ligands and one `NO^(+)` ligand.
337.

Which is true for the complex `[Ni(en)_2]^(2+)` ?A. paramagnetic , `dsp^(2)` , square planar , Cn of Ni = 2B. diamagnetic , `dsp^(2)` , square planar , CN of Ni = 4C. diamagnetic , `sp^(3)` , tetrahedral , CN of Ni = 4D. paramagnetic , `sp^(3)` , square planar , CN of Ni = 4

Answer» Correct Answer - B
338.

A compound has the empirical formula `CoCl_(3).5NH_3`. When an aqueous solution of this compound is mixed with excess silver nitrate, 2 mol of `AgCl` precipitates per mol of compound. On reaction with excess HCl, no `NH_4^(+)` is detected. Hence it isA. `[Co(NH_3)_(5)Cl_2]Cl`B. `[Co(NH_3)_(5)Cl]Cl_2`C. `[Co(NH_3)_(5)Cl_(3)]`D. `[Co(NH_3)_(4)Cl_2]Cl.NH_3`

Answer» Correct Answer - B
`[Co(NH_3)_(5)Cl]CL_2` + `2AgNO_3` `darr` `[Co(NH_3)_(5)Cl](NO_3)_2` + 2AgCl.
339.

Write the IUPAC names of the complexes : `[Ag(NH_3)_2]Cl` and `K[Ag(CN)_2]`

Answer» diamminesilver (I) chloride and potassium dicyanoagrentate .
340.

Write the IUPAC name of the complex (i) `[Ag(NH_3)_2][Ag(CN)_2]`

Answer» diammine silver (I) dicyanoargentate .
341.

The isomerism exhibited by the co-ordination complex `[Cr(NH_3)_2(H_(2)O)_(2)Cl_2]^(+)` are :A. ionisation, opticalB. hydrate , opticalC. co-ordinate , geometricalD. geometrical , optical

Answer» Correct Answer - D
The complex exhibits both geometrical and optical isomerism.
342.

The kind of isomerism exhibited by `[Rh(en)_(2)Cl_(2)][Ir(en)Cl_(4)]` and ` [Ir(en)_(3)][RhCl_(6)]` isA. Linkage isomerismB. Ionisation isomerismC. co-ordination isomerismD. Position isomerism.

Answer» Correct Answer - C
This is an example of co-ordination isomerism.
343.

The geometry of `Ni(CO_(4))` and `Ni(PPh_(3))_(2)Cl_(2)` areA. square planar and tetrahedral respectivelyB. both are tetrahedrlC. tetrahedral and square planar respectivelyD. both are square planar.

Answer» `Ni(CO)_(4)and Ni(PPh_(3))_(2)Cl_(2)` have `sp^(2)` hybridization.
344.

The geometry of `Ni(CO_(4))` and `Ni(PPh_(3))_(2)Cl_(2)` areA. both square planarB. tetrahedral and square planarC. both tetrahedralD. square planar and tetrahedral .

Answer» Correct Answer - C
`Ni(CO)_(4)` : Tetrahedral
`Ni^(2+)` (Z = 28) : `[Ar]^(18)3d^(8)`
In `[Ni(PPh_(3))_(2)Cl_(2)]` both the ilgands `PPh^(3)` and Cl are weak and as such cannot pair up the d-electrons. Thus hybridisation is `sp^(3)` and shape is tetrahedral.
345.

The geometry of `Ni(CO_(4))` and `Ni(PPh_(3))_(2)Cl_(2)` areA. both square planarB. tatrahedral and square planarC. both tetrahedralD. square planar and tetrahedral .

Answer» Correct Answer - C
Both `[Ni(CO)_(4)] and [Ni(PPh_(3))_(2)Cl_(2)]` are tetrahedral. Ni(Z =28) : `[Ar]^(18) 4s^(2) 3d^(8)`
`Ni(CO)_(4)` : Two 4s-electrons pairs up with 3d-electrons followed by `sp^(3)` hybridisation to give a tetrahedral complex.
`[Ni(PPh_(3))_(2)Cl_(2)]` : It has `Ni^(2+)` ion with outer configuration of `3d^(8). Ni^(2+)` undergoes `sp^(3-)`-hybridisation `(PPh_(3)) or Cl^(-)` an not force the d-electrons to pair up) and complex is tetrahedral.
346.

Red precipitae is obtained when ethanol solution of dimethylglyoxime is added to ammoniacal `Ni (II)`. Which of the following statement is not true?A. Red complex has a square planar geometryB. Complex has symmetrical H-bondingC. Red complex has a tatrahedral geometryD. Dimethylglyoxime functions as bindentate ligand

Answer» Correct Answer - C
347.

`[NiCl_(2){P(C_(2)H_(5))_(2)(C_(6)H_(5))}_(2)]` exhibits temperature dependent magnetic behaviour. The coordination geometries of `Ni^(2+)` in the paramagnetic and diamagnetic states are:A. tetrhedral and tetrahedralB. square planar and square planarC. tetrahedral and square planarD. square planar and tetrahedral .

Answer» Correct Answer - C
348.

which of the following compounds would have the highest molar conducitivity?A. diamminedichloridoplatinum (II)B. tetraamminedichloridocobalt (III)C. potassium hexacynoferrate (II)D. hexaquachromium (III) chloride

Answer» Correct Answer - C
The structures of all the complexes are as follows :
(a) `[Pt(NH_3)_(2)Cl_2]` (b) `[Co(NH_3)_(4)Cl_2]Cl`
(c ) `K_4[Fe(CN)_6]` (d) `[Cr(aq)_6]Cl_3`
(e) `K_3[Fe(CN)_6]`.
The complex (c ) provides maximum no. of ions (five) in solution and is maximum conducting .
349.

Which of the following complex has same oxidation state of the central metall atom in the cationic and anionic part ?A. `[Pt(py)_(4)][PtCl_(4)]`B. `[Pt(NH_(3))_(4)][PtCl_(6)]`C. `[Pt(NH_(3))_(4)Cl_(2)][PtCl_(4)]`D. `K_(4)[Ni(CN)_(6)]`

Answer» Correct Answer - A
(A) `[Pt(py)_(4)]^(2+) [PtCl_(4)]^(2-)` . In both the parts the O.N. of Pt is `+2`
350.

The tetrhedral complex, bis(benzoylacetonato)beryllium(II) will showA. geometrical isomerismB. optical isomerismC. structural isomerismD. No isomerism.

Answer» Correct Answer - B
The complex shows optical isomerism as it possesses chiral structure .