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Given, Cost of T-shirt = RS.1200

Also, cost of Jeans = Rs 1000.

And cost of Skirts = Rs 1350

Here, 2 skirts = 1350 + 1350 = 2700

We need to find out cost of items with sales tax

⇒ Total cost = 1200 + 1000 + 2700

= Rs. 4900

⇒ Sikha have to pay sales tax = 7%

Now, we know that the Total Sales Tax = Cost x Sales Tax

⇒ Total Sales Tax = (4900 x 7)/100

= 343

⇒ Now, The cost price with the sales tax Total Cost = Cost + Total Sales Tax.

⇒ Total cost = 4900 + 343

= Rs. 5243

So, the total cost to be paid to sikha is Rs. 5243

If the price of sugar is decreased by 20%, then the new price of 3kg sugar originally costing ₹ 120 will be ₹ 96

From the question it is given that, price of 3kg sugar originally costing ₹ 120

The price of the sugar is decreased by 20%

Then, the new price of sugar = 120 – 20% of original price

= 120 – (20/100) × 120

= 120 – (2400/100)

= 120 – 24

= ₹ 96

Given, price of CD = 120

Also, discount is 25% of original price.

We need to find out selling price.

⇒ Now, we know x% of n = x/100 x n

⇒25% discount on Rs.120 = 25/100 x 120

= 120/4

= Rs. 30

∴ Discount = Rs.30

⇒Now, Selling price after discount = original cost price - discount

⇒ Selling price after discount = 120-30

= Rs.90

Hence, the selling price is RS.90

(a) Given, original price of the toy = Rs.90

We need to find out the sales price

If price, reduced to 66% of the original price then the price becames = 90 - 66/100 x 90

= 90 – 59.4 = 30.6

(b) We have discounted amount as 66% of 90

⇒ 66/100 x 90

= 59.4

Hence, the amount saved is 59.4

The price includes VAT.

Thus, 8% VAT means that if the price without VAT is Rs 100, then price including VAT will be Rs 108.

When price including VAT is Rs 108, original price = Rs 100

When price including VAT is Rs 5400, Original price = Rs (100/108 x 5400) = Rs 5000

Thus, the price of the hair-dryer before the addition of VAT was Rs 5,000.3

It is given that on Sunday, 845 people went to the zoo and on Monday, 169 people went.

Decrease in the number of people = 845 - 169 = 676

Percentage decrease =( Decrease in the number of people x 100 / Number of people who went to zoo on sunday )%

= ( 676/845 x 100)% = 80%

Correct answer is (c) 8

If a bicycle was bought for Rs 650 and sold for Rs 585, then the percentage of profit is 10.

False

Given, commission received = 50,000

Also, commission percentage = 4%

Need to find out the price of the property

Let the price of the property = Rs.y

⇒ Now, x% of n = x/100 x n

⇒ 4/100 x y = 50000

⇒ y = (50000 x 100)/4

⇒ Y = 50000 × 25 = Rs.1250000

Hence, the selling price of the property is Rs.1250000

P = ₹ 2500, T = 4 years, I = ₹1500 

R = ? 

Now, I = (P×R×T)/100 

Therefore, 1500 = (2500×R×4)/100 

R = (1500×100)/(2500×4) = 15 

So, the rate of interest is 15%.

Principal = ₹75000 

Amount = ₹80000 

Interest = Amount – Principal 

= ₹80000 – ₹75000 

= ₹5000

Correct answer is (d) Rs 13500

Interest on Rs 1200 for 11/2 years at the rate of 15% per annum is Rs 180.

False

Rs 6400 were lent to Feroz and Rashmi at 15% per annum for 3 1/2 and 5 years respectively. The difference in the interest paid by them is Rs 150.

False

Correct answer is (b) 7%

Correct answer is (c) Rs 100 

Correct answer is (c) 20%

(c) ₹ 100

From the question it is given that,

Principal= ₹ 12000

Time = 1 month = 1/12

Rate = 10%

Then, we know the formula of Simple interest I = (P × R × T)/100

I= (12000 × (10) × (1/12))/100

I = ₹ 100

Interest on ₹ 3000 at 10% per annum for a period of 3 years is ₹ 900.

From the question it is given that,

Principal= ₹ 3000

Time = 1 month = 3

Rate = 10%

Then, we know the formula of Simple interest I = (P × R × T)/100

I= (3000 × (10) × 3))/100

I = ₹ 900

(b) ₹ 3660

From the question it is given that,

Principal= ₹ 3000

Time = 2 Years

Rate = 11%

Then, we know the formula of Simple interest I = (P × R × T)/100

I= (3000 × (11) × 2)/100

I = (3000 × 11 × 2)/100

I = ₹ 660

Amount = P + I

= 3000 + 660

= ₹ 3660

100 km.

40% of 250 km is 100 km.

True

0.05 is equivalent to 5%.

False

If 25% of a journey is 800 km, the total distance of the journey is 3000 km.

(c) 20%

Let us assume Mohan’s income be ‘P’ and Raman’s income be ‘Q’

From the question it is given that,

Mohan’s income is 25% more than Raman’s income i.e. x = y + 25% of y

x = y + (25/100) y

x = y (1 + (25/100))

x = y ((100 + 25)/100)

x = y(125/100)

Then, the difference between both the income is = (125/100)y – (25/100)y

So,

Raman’s income as compared to Mohan’s income,

= (difference)/ (Mohan’s income) × 100

= ((25y/100)/(125y/100)) × 100

= (25/125) × 100

= 20%

If 25% of a journey is 800 km, the total distance of the journey is 3000 km.

False

MCQ Questions for Class 7 Maths with Answers were arranged dependent on the most recent exam pattern. We have given Comparing Quantities Class 7 Maths MCQs Questions with Answers to assist understudies with understanding the idea well overall. 

Here you can get Class 7 Maths MCQ Questions for Comparing Quantities with Answers. Contrasting Quantities are extremely useful with a score of good marks on the board exam. We have covered Important MCQ Questions on Comparing Quantities for Class 7 Maths. NCERT MCQ Questions for Class 7 Maths Comparing Quantities, are important for NCERT Solutions for Class 7 Maths. Start Practice Class 7 Maths MCQ Questions for Comparing Quantities with Answers for scoring high in the Board exam.

Practice MCQ Questions for Class 7 Maths

1. The fraction 2/5 converted to percentage is

(a) 20%
(b) 30%
(c) 40%
(d) 50%

2. Out of 100 students of a class, 30% like to watch T.V. How many students like to watch T.V.?

(a) 70
(b) 50
(c) 60
(d) 30

3. There are 50 students in a class of which 40 are boys and the rest are girls. The ratio of the number of boys and number of girls is

(a) 2:3
(6) 1:5
(c) 4:1
(d) 2:5

4. Apala has Rs 200 with her. She spent 80% amount she had. How much money is left with her?

(a)Rs 10
(b) Rs 20
(c) Rs 30
(d) Rs 40

5. A shopkeeper offers a 10% discount on the marked price of his articles and still makes a profit of 20%. What is the actual cost of the article marked Rs.500 for him?

(a) Rs 350
(b) Rs 375
(c) Rs 400
(d) Rs 300

6. If 60% of x is 1200, then the value of ‘x’ is

(a) 1000
(b) 2000
(c) 3000
(d) 40000

7. The present population of a town is 25,000. It grows at 4%, 5% and 8% during first year, second year and third year respectively, the population after 3 years is

(a) 29,484
(b) 24,576
(c) 28,696
(d) 30,184

8. The ratio of Rs 10 to 50 paise is

(a) 20 : 1
(b) 10 : 1
(c) 5 : 1
(d) 1 : 20

9. The ratio of 6 kg to 400 g is

(a) 10 : 1
(b) 15 : 1
(c) 12 : 1
(d) 6 : 1

10. The ratio of 3 m to 60 cm is

(a) 4 : 1
(b) 3 : 1
(c) 5 : 1
(d) 2 : 1

11. The cost of 3 envelopes is ₹ 15. Find the cost of 5 envelopes.

(a) ₹ 20
(b) ₹ 25
(c) ₹ 30
(d) ₹ 40

12. The cost of 8 pencils is ₹ 10. Find the cost of 20 pencils.

(a) ₹ 20
(b) ₹ 25
(c) ₹ 24
(d) ₹ 30

13. 1/4  as a percent is

(a) 20%
(b) 25%
(c) 30%
(d) 12%

14. 0.1 as percent is

(a) 1%
(b) 10%
(c) 100%
(d) 0.1%

15. Out of 40 children in a class, 10 are boys. What is the percentage of boys?

(a) 10%
(b) 40%
(c) 4%
(d) 25%

16. A shop has 50 televisions, out of which 5 are defective, defective? What percent are

(a) 5%
(b) 10%
(c) 50%
(d) 25%

17. A basket is full of bananas, mangoes, and apples. If 50% are mangoes, 30% are apples, then what percent are bananas?

(a) 10%
(b) 20%
(c) 25%
(d) 40%

18. Priya bought an air cooler for Rs. 3300 including a tax of 10%. The price of the air cooler before VAT was added is:

(a) Rs. 2000
(b) Rs. 3000
(c) Rs. 2500
(d) Rs. 2800

19. A sum of money, at compound interest, yields Rs. 200 and Rs. 220 at the end of first and second year respectively. The rate % is:

(a) 20
(b) 15
(c) 10
(d) 5

20. If 60% of x is 1200, then the value of ‘x’ is

(a) 1000
(b) 2000
(c) 3000
(d) 4000

21. In a particular kind of pulses, the quantity of protein is 25%. How much protein is there in 4 kg of that pulse?

(a) 1kg
(b) 2kg
(c) 3kg
(d) 4kg

22. Komal purchased a coat for 7 600. She had to pay 4% sales tax on it. Find the amount of sales tax.

(a) ₹ 24
(b) ₹ 16
(c) ₹ 20
(d) ₹ 32

23. A shopkeeper bought a table for ₹ 500 and sold it for ₹ 400. Find the loss percentage.

(a) 10%
(b) 20%
(c) 40%
(d) 50%

24. A school team won 6 games this year against 4 games won last year. What is the percent increase?

(a) 10%
(b) 25%
(c) 75%
(d) 50%

25. The difference between the greatest and least numbers of 5/9, 1/9,11/9 is

(a) 2/9
(b) 4/9
(c) 10/9
(d) 2/3

Answer:

1. Answer: (c) 40%

Explanation: 2/5 = 2/5 x 100% 

= 40%

2. Answer: (d) 30%

Explanation: Number of students who like to watch T.V.

= 30% of 100

= 30/100 x 100 

= 30

3. Answer: (c) 4:1

Explanation: Number of Girls = 50 – 40 = 10

Required ratio = 40 : 10 

= 4 : 1

4. Answer: (d) Rs 40

Explanation:Out of Rs 100, money spent = Rs 80

∴ Out of Rs 200, money spent 

= 80/100 x 200 

= Rs 160

or

Money spent = 80% of Rs 200

= 200 x 80/100 

= Rs 60

∴ Money left = Rs 200 – Rs 160 

= Rs 40

5. Answer: (b) Rs 375

Explanation: M.P = Rs. 500 Discount = 10%

∴ S.P. = Rs.500 - 10% of Rs.500 

= 90% of Rs.500 

= 90/100 × Rs.500 

= Rs.450

Profit = 20% C.P. \(=\frac{450\times 100}{120}\)

= Rs.375

6. Answer: (b) 2000

Explanation: Given that 60% of x is 1200

\(\frac{60}{100}\times x=1200\)

\(x=1200\times\frac{100}{60}\).

x = 2000

7. Answer: (a) 29,484

Explanation: Let the rate of popukation be p,q,r respectively.

Therefore, population after 3 years is

\(=p(1+\frac{p}{100})(1+\frac{q}{100})\)\((1+\frac{r}{100})\)

 \(=2500\times(1+\frac{4}{100})(1+\frac{5}{100})\)\((1+\frac{8}{100})\)

\(=25000\times\frac{26}{25}\times\frac{21}{20}\times\frac{27}{25}\)

= 29,484

8. Answer: (a) 20 : 1

Explanation: Rs 10 : 50 paise 

= 10 × 100 paise: 50 paise

= 1000 : 50

= 20 : 1

9. Answer: (b) 15 : 1

Explanation: 6 kg : 400 g 

= 6 × 1000 g : 400 g

= 6000 : 400 

= 15 : 1

10. Answer: (c) 5 : 1

Explanation: 3 m : 60 cm 

= 3 × 100 cm : 60 cm

= 300 : 60 

= 5 : 1.

11. Answer: (b) ₹ 25

Explanation: 3 : 5 = 15 : x

\(\frac{3}{5}=\frac{15}{x}\)

x = 25

12. Answer: (b) ₹ 25

Explanation: 8 : 20 = 10 : x

\(\frac{8}{20}=\frac{10}{x}\)

x = 25

13. Answer: (b) 25%

Explanation: \(\frac{1}{4}=\frac{1}{4}\times100\%\)

= 25%

14. Answer: (b) 10%

Explanation: \(0.1=\frac{1}{10}\)

\(=\frac{1}{10}\times100\%\)

= 10%

15. Answer: (d) 25%

Explanation: Percentage of boys = \(\frac{10}{40}\times100\%\)

=  25%

16. Answer: (b) 10%

Explanation: Percentage of defective television = \(\frac{5}{50}\times100\%\)

=  10%

17. Answer: (b) 20%

Explanation: Required percentage

= 100% – (50% + 30%)

= 20%

18. Answer: (b) Rs. 3000

Explanation: 10% VAT on Rs.100 will make it Rs.110

So, for price including VAT Rs.110, the original price is Rs.100

Then, Price including VAT Rs. 3300, the original price

= Rs. \((\frac{100}{110}\times 3300)\)

= Rs. 3000

19. Answer: (c) 10

Explanation: Given, Amount = Rs. 220, Principle = Rs. 200, Time =1 year

1 year simple interest and compound interest are equal.

So Interest

=220−200

= Rs. 20

S. I = \(\frac{PRT}{100}\)

\(R=\frac{S.I\times100}{P\times T}\)

\(R=\frac{20\times100}{200\times1}\)

R = 10%

 20. Answer: (b) 2000

Explanation: Given that 60% of x is 1200

\(\frac{60}{100}\times x=1200\)

\(x=1200\times\frac{100}{60}\).

x = 2000

21. Answer:  (a) 1kg

Explanation: Required amount of protein

\(=\frac{25}{100}\times4\)

= 1 kg

22. Answer:  (a) ₹ 24

Explanation: Amount of sales tax

\(=600\times\frac{4}{100}\)

= ₹ 24

23. Answer:  (b) 20%

Explanation: Loss percentage = \(\frac{CP-SP}{CP}\times 100\%\)

\(=\frac{500-400}{500}\times 100\%\)

= 20%

24. Answer:  (d) 50%

Explanation: The increase in the number of wins (or amount of change) =6 − 4 = 2

Percentage increase = \(=\frac{amount\;of\;change}{original\;amount\;or\;base}\times 100\)

\(=\frac{2}{4}\times100\)

= 50%

25. Answer:  (c) 10/9

Explanation: Amongst the given fractions \(\frac{5}{9},\frac{1}{9}\;and\;\frac{11}{9}\) the smallest is 1/9 and the largest is 11/9.

Now, consider the subtraction of the greatest and least fraction as follows:

\(\frac{11}{9}-\frac{1}{9}=\frac{10}{9}\)

Hence, the difference between the greatest and least numbers is 10/9.

Click here for Practice MCQ Questions for Comparing Quantities Class 7

Correct answer is (c) Rs 450

Correct answer is (a) 36%

Correct answer is (c) 40%

(c) 40%

From the figure,

Total number of parts in the given figure = 10 × 10 = 100

Out of 100 parts 60 parts are shaded.

So, unshaded parts = 100 – 60 = 40 parts

Then percentage of unshaded parts = (40/100) × 100

= 0.4 × 100

= 40%

(a) 36%

From the figure,

Total number of parts in the given figure = 10 × 10 = 100

Out of 100 parts 36 parts are shaded.

Then percentage of shaded parts = (36/100) × 100

= 0.36 × 100

= 36%

2: 3 = 66 2/3%

= (2/3) × 100

= 66 2/3%

Bill amount

Sales tax=Tax % of bill amount

Length of shrink cloth = 10% of 5 m = 10/100 x 5 = 1/2 m

Length of cloth after wash = 5 - 1/2 = 9/2 = 4.5 m

Nancy got marks = 426 out of 600.

Percentage marks = 426/600 x 100% = 71%

Rohit got marks = 560 out of 800.

Percentage marks = 560/800 x 100% = 70%

Hence, Nancy's performance is better, since she got 1% more than Rohit.

Sales tax is charged on the sale of an item by the government and is added to the bill amount.

Sales tax = Tax % of bill amount

90 is 50% more than 60.

Let us assume the number be Q.

From the question, Q is 50% more than 60

So, Q = 60 + (50/100) × 60

= 60 + (3000/100)

= 60 + 30

= 90

False

From the question it is given that,

Ankita obtains 336 marks out of 600

So, percentage of marks = (336/600) × 100

= 0.56 × 100

= 56%

False

= (12/100) × 120

= 1440/100

= 14.4

Discount = Discount % of marked price

[ discount is a reduction given on marked price]

False

Let us assume 8 hours be Q% of 4 days

So, 8 = (Q/100) × 4 × 24

Q = 25/3

Q = 8 1/3

Initial number = 150

Final number = 162

Increased number = 162 – 150 = 12

Percent of increased number = 12/150 X 100

= 120/15 

= 8%

Increase of a number from 150 to 162 is equal to increase of 8% per cent.

False

0.018 × 100 = 1.8%

False

Because, 75 % = 75/100

= ¾

False

250 cm = 250/100

= 2.5 m

We know that, 1 km = 1000 m

Then, 4 % of 1 km = (4/100) × 1000

= 40 m

We have, 9/40

In percentage, 9/40 x 100% = 22 1/2%

Discount = Marked price – Selling Price

We have, 1/100

In percentage, 1/100 x 100% = 1%

True.

= (50/100) × 50

= 0.5 × 50

= ₹ 25