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Rs.212

Explanation:

Let x is the price of the article.

Thus, as per given question;

1620 = x + x × (15/100)

1620 = 115x/100

115x = 1620 × 100

x = (1620×100)/115

x = 1408

Hence, increase in price = 1620 – 1408 = 212.

We have, 1/6

In percentage, 1/6 x 100% 

= 50/3 

= 16.6% [to convert in percent, multiply by 100]

We have, 15% of 20

= 15/100 x 20 

= 3

We have, 1.56

In percentage, 1.56 x 100% = 156%

Correct answer is (a) 60.

Weight of Nikhil increased from 60 kg to 66 kg. Then, the increase in weight is 10 %.

Given, 90000 of the 2,50,000 identified plant species in the world are specified as rain forest.

Need to find out the percentage.

⇒ In percentage = 90000/250000 x 100

= 900/25

= 36%

Hence, 36% of world’s identified plant species are found in rain forests.

Given, weight of jyothi = 56 kg

Where 67% of a person’s total body weight is water

⇒ Now, x% of n = x/100 x n

⇒ Water in jyoti body = 67/100 x 56

= 3752/100

= 37.52 kg

Hence, 37.52 of her weight is water.

Fill in the blanks to make the statements true.

2.5 = 250%

Correct answer is (a). 60

Given, Madhu’s room measured = 6 m × 3 m

Also, her carpet covers = 8m²

Need to find out percentage of floor covered by the carpet

⇒ Area of the room = 6 × 3 = 18 m²

⇒ Now, Area covered by the carpet in percentage

= Area Cover By Carpet/ Area of the Room x 100

⇒ Area covered by the carpet in percentage = 8/18 x 100

= 800/18

= 44.44%

Hence, area covered by the carpet in percentage is 44.44%.

2.5 = 250 %

2.5 = 2.5 × 100

= 250%

Weight of Nikhil increased from 60 kg to 66 kg. Then, the increase in weight is 10 %.

From the question it is given that, Weight of Nikhil increased from 60 kg to 66 kg.

So, weight increase = 66 – 60

= 6 kg

Then, percentage increase = (Weight increase/Initial weight) × 100%

= (6/60) × 100

= 600/60

= 60/6

= 10%

A fraction with its denominator 100 is called a per cent.

(8/5) = 160 %.

(8/5) is written in percentage as = (8/5) × 100

= 8 × 20

= 160 %

15 kg is 30 % of 50 kg.

Let us assume the percentage be P.

So, P% of 50 kg =15 kg

(P/100) × 50 = 15

P = (15 × 100)/50

P = 1500/50

P = 150/5

P = 30

120 % of 50 km = 60 km.

It can be written as = (120/100) × 50

= 6000/100

= 60 km

18¾% = 3 : 16

18¾% = 75/4 %

= (75/4) × (1//100)

= 3: 16

30% of ₹ 360 = ₹ 108.

It can be written as = (30/100) × 360

= 10800/100

= ₹ 108

30% of Rs 360 = Rs 108.

18 3/4% = 3 :16

Correct answer is 324

Correct answer is (c)  520%

Correct answer is (a) 200

Correct answer is (d) 140 m

These Class 8 Maths MCQ Questions of Comparing Quantities with Answers are prepared by the subject experts from Sarthaks are according to the CBSE syllabus and NCERT guidelines.  The chapter deals with the concept of ratios and percentages, along with other main topics and concepts. Students can also refer to Maths formulas for Class 8 Comparing Quantities Roots for better exam preparation and score more marks.

The objective types questions (MCQ questions for class 8 Maths) are also available chapter-wise at Sarthaks eConnect to make students learn each concept thoroughly and help them to score better marks in exams. These MCQ Questions for Class 8 Comparing Quantities will allow students a chance to test their knowledge and also prepare for the examination.

Practice MCQ Question for Class 8 Maths chapter-wise

1. The ratio of 50 paise to Rs. 1 is

(a) 1 : 2
(b) 2 : 1
(c) 1 : 1
(d) 1 : 5

2.  The ratio of 10 m to 1 km is

(a) 1 : 10
(b) 10 : 1
(c) 1 : 100
(d) 100 : 1

3. The ratio of Speed of a cycle 15 km per hour to the speed of scooter 30 km per hour is 1:2

(a) True
(b) False
(c) Ambiguous
(d) Cannot be determined

4. The ratio 1 : 4 converted to percentage is

(a) 50%
(b) 25%
(c) 75%
(d) 4%

5. The fraction 2/5 converted to percentage is

(a) 20%
(b) 30%
(c) 40%
(d) 50%

6. Out of 40 students in a class, 25% passed. How many students passed?

(a) 20
(b) 10
(c) 30
(d) 40

7. Out of 100 students of a class, 30% like to watch T.V. How many students like to watch T.V. ?

(a) 70
(b) 50
(c) 60
(d) 30

8. There are 50 students in a class of which 40 are boys and the rest are girls. The ratio of the number of boys and number of girls is

(a) 2:3
(6) 1:5
(c) 4:1
(d) 2:5

9. 40% of 50 students of a class are good at Science. How many students are not good at Science ?

(a) 20
(b) 30
(c) 10
(d) 40

10. Apala has Rs 200 with her. She spent 80% amount she had. How much money is left with her ?

(a)Rs 10
(b) Rs 20
(c) Rs 30
(d) Rs 40

11. The marked price of a book is Rs 100. The shopkeeper gives 25% discount on it. What is the sale price of the book?

(a) Rs 100
(b) Rs 25
(c) Rs 125
(d) Rs 75

12. A shopkeeper offers 10% discount on the marked price of his articles and still makes a profit of 20%. What is the actual cost of the article marked Rs.500 for him?

(a) Rs 350
(b) Rs 375
(c) Rs 400
(d) Rs 300

13. Meenu purchased a fridge for Rs 10000 and sold it for Rs 8000. Find her loss.

(a) Rs 8000
(b) Rs 10000
(c) Rs 2000
(d) Rs 12000

14. Saroj purchased a fan for Rs 1000 and sold it for Rs 1200. What is her profit ?

(a) Rs 1000
(b) Rs 1200
(c) Rs 200
(d) Rs 800

15. Vimla purchased a watch for Rs 500. She sold it at a loss of 20%. Find the selling price.

(a) Rs 500
(b) Rs 400
(c) Rs 300
(d) Rs 200

16. Kanti purchased a sewing machine for Rs 2000. She sold it at a loss of 40%. Find the selling price.

(a) Rs 1200
(b) Rs 400
(c) Rs 800
(d) Rs 2800

17. If 60% of x is 1200 , then the value of ‘x’ is

(a) 1000
(b) 2000
(c) 3000
(d) 4000

18. The list price of an article is Rs.220. If it is sold at a discount of 20% , what is its selling price

(a) 100
(b) 44
(c) 176
(d) 200

19. A table marked at Rs.15000 is available for Rs.14400 . Find the discount percent?

(a) 2%
(b) 4%
(c) 5%
(d)  7%

20. The present population of a town is 25,000. It grows at 4%, 5% and 8% during first year, second year and third year respectively, the population after 3 years is

(a) 29,484
(b) 24,576
(c) 28,696
(d) 30,184

21. The C.I. on a certain sum for 2 years is Rs 410  and S.I. is Rs 400.  What is the rate of interest per annum?

(a) 5%
(b) 6%
(c) 8%
(d) 10%

22. What sum lent out at Cl will amount to Rs. 968 in 2 years at 10% p.a. interest?

(a) Rs. 800
(b) Rs. 1200
(c) Rs. 1000
(d) None

23. The ratio of speed of cycle 12 km per hour to the speed of scooter 36 km per hour is

(a) 1:2
(b) 1:3
(c) 1:4
(d) None of the above

24. Waheeda bought an air cooler for Rs. 3300 including a tax of 10%. The price of the air cooler before VAT was added is:

(a) Rs. 2000
(b) Rs. 3000
(c) Rs. 2500
(d) Rs. 2800

25. A sum of money, at compound interest, yields Rs. 200 and Rs. 220 at the end of first and second year respectively. The rate % is:

(a) 20
(b) 15
(c) 10
(d) 5

Answer:

1. Answer: (a) 1 : 2

Explanation: Rs 1 = 100 paise

50 paise : 100 paise or 50 : 100 or 1 : 2.

2. Answer: (c) 1 : 100

Explanation: 1 km = 1000 m

10 m : 1000 m or 10 : 1000 or 1 : 100

3. Answer: (a) True

Explanation: Required Ratio is

= 15/30

= 1/2

 = 1 : 2

4. Answer: (b) 25%

Explanation: 1 : 4 

= 1/4 x 100% 

= 25%.

5. Answer: (c) 40%

Explanation: 2/5 = 2/5 x 100% 

= 40%

6. Answer: (b) 10

Explanation: Out of 100, passed = 25

∴ Out of 40, passed

=  25/100 x 40

= 10.

or

25% of 40 

= 25/100 x 40 

= 10

7. Answer: (d) 30%

Explanation: Number of students who like to watch T.V.

= 30% of 100

= 30/100 x 100 

= 30

8. Answer: (c) 4:1

Explanation: Number of Girls = 50 – 40 = 10

Required ratio = 40 : 10 

= 4 : 1

9. Answer: (b) 30

Explanation: Out of 100, good at Science = 40

∴ Out of 50, good at Science

= 40/100 × 50

= 20.

or

Number of students good at science

= 40% of 50 

= 40/100 x 50 

= 20

∴ Number of students not good at Science

= 50 – 20

= 30

10. Answer: (d) Rs 40

Explanation: Out of Rs 100, money spent = Rs 80

∴ Out of Rs 200, money spent 

= 80/100 x 200 

= Rs 160

or

Money spent = 80% of Rs 200

= 200 x 80/100 

= Rs 60

∴ Money left = Rs 200 – Rs 160 

= Rs 40

 11. Answer: (d) Rs 75

Explanation: Discount on Rs 100 = 25

∴ Sale price = 100 – 25

= Rs 75

12. Answer: (b) Rs 375

Explanation: M.P = Rs. 500 Discount = 10%

∴ S.P. = Rs.500 - 10% of Rs.500 

= 90% of Rs.500 

= 90/100 × Rs.500 

= Rs.450

Profit = 20% C.P. \(=\frac{450\times 100}{120}\)

= Rs.375

13. Answer: (c) Rs 2000

Explanation: Loss = C.P. – S.P. 

= 10000 – 8000

= Rs 2000

14. Answer: (c) Rs 200

Explanation: Gain = S.P. – C.P. 

= 1200 – 1000

= Rs 200

15. Answer: (b) Rs 400

Explanation: 100 – 20 = 80

∵ If C.P. is 100, then S.P. = Rs 80

∴ If C.P. is Rs 500, then S.P.

= 80/100 x 500 

= Rs 400

16. Answer: (a) Rs 1200

Explanation: 100 – 40 = 60

∵ If C.P. is Rs 100, then S.P. = Rs 60

∴ If C.P. is Rs 2000, then S.P.

= 60/100 x 2000 

= Rs 1200

17. Answer: (b) 2000

Explanation: Given that 60% of x is 1200

\(\frac{60}{100}\times x=1200\)

\(x=1200\times\frac{100}{60}\).

x = 2000

18. Answer: (c) 176

Explanation: List (Marked) Price of the frock = 220, Rate of discount = 20%

Amount of discount \(=\frac{20}{100}\times220\)

= 44

∴ Selling Price of the frock = Marked Price − Discount

= 220−44

= 176

19. Answer: (b) 4%

Explanation: Discount = \(\%\frac{15,000-14,400}{15,000}\times100\)

= 4%

20. Answer: (a) 29,484

Explanation: Let the rate of popukation be p,q,r respectively.

Therefore, population after 3 years is

\(=p(1+\frac{p}{100})(1+\frac{q}{100})\)\((1+\frac{r}{100})\)

 \(=2500\times(1+\frac{4}{100})(1+\frac{5}{100})\)\((1+\frac{8}{100})\)

\(=25000\times\frac{26}{25}\times\frac{21}{20}\times\frac{27}{25}\)

= 29,484

21. Answer: (a) 5%

Explanation: It is given that simple interest in 2 years = Rs.400

⇒  Simple interest for 1 year = Rs.200

⇒  Hence, Compound interest for 1 year = Rs.200

⇒  Given compound interest for 2 years = Rs. 410

∴   Compound interest for 2 years = Compound interest 1st year + Compound interest 2nd year

⇒  Compound interest for 2nd year = Rs.410 - Rs.200 = Rs.210

⇒  That is interest on Rs.200 for 1 year = Rs.210-Rs.200 = Rs.10

\(I=\frac{P\times T\times R}{100}\)

\(10=\frac{200\times1\times R}{100}\)

2R = 10

 R = 5%

22. Answer: (a) Rs. 800

Explanation: A= Rs. 968,T =2 years, R =10%,P=?

\(A=P(1+\frac{R}{100}t)\)

\(A=P(1+\frac{R}{100})^n\)

\(968=P(1+\frac{10}{100})^2\)

\(968=P(\frac{11}{10})^2\)

\(P=\frac{968\times10\times10}{11\times11}\)

P = Rs. 800

23. Answer: (b) 1:3

Explanation: Speed of cycle/Speed of scooter

= 12/36 

= 1/3

= 1:3

24. Answer: (b) Rs. 3000

Explanation: 10% VAT on Rs.100 will make it Rs.110

So, for price including VAT Rs.110, the original price is Rs.100

Then, Price including VAT Rs. 3300, the original price

= Rs. \((\frac{100}{110}\times 3300)\)

= Rs. 3000.

25. Answer: (c) 10

Explanation: Given, Amount = Rs. 220, Principle = Rs. 200, Time =1 year

1 year simple interest and compound interest are equal.

So Interest

=220−200

= Rs. 20

S. I = \(\frac{PRT}{100}\)

\(R=\frac{S.I\times100}{P\times T}\)

\(R=\frac{20\times100}{200\times1}\)

R = 10%

Click here Practice MCQ Question for Comparing Quantities Class 8

Two ratios a:b and c:d are said to be proportional, if a/b = c/d or ad = bc.

But in the given ratios 3/4 and 9/16, 3 x 16 ≠ 4 x 9.

Hence, the ratios are not proportional. To make a ratio proportional to another ratio, we just simply multiply both numerator and denominator by same number.

In our given case, student had multiply numerator by 3 and denominator by 4, which is incorrect.

Correct answer is 156%

If two ratios are equivalent, then the four quantities are said to be in Proportion.

Correct answer is (c) 2 : 1

Correct answer is (i) 1250, (ii) 1250, (iii) 800,

Devangi buys a chair for Rs 700 and sells it for Rs 750. She earns a profit of 7 1/7% in the transaction.

120 % of 50 km = 60 km.

Savitri obtained 440 marks out of 500 in an examination. She secured 88% marks in the examination.

In a class of 50 students, 8 % were absent on one day. The number of students present on that day was 46.

When converted into percentage, the value of 6.5 is More than 100%.

Given, 6.5

= 6.5 × 100

= 650%

(c) 0.01%

= [(25/100) × (50/100) × (100/100)]/ (25 × 50)

= [¼ × ½ × 1]/(1250)

= [1/8] × (1/1250)

= 1/10000

= 0.0001 × 100

= 0.01%

Overhead

Overhead expenses are the additional expenses incurred by a buyer for an item over and above its cost of purchase.

Given, video game available in store A and store B at rate = Rs. 750

Store B sells video game on sales offer = Rs.600

Store A sells video game at discount = 25%

We need to find out at which store is the game least expensive.

⇒ Now, we know x% of n = x/100 x n

⇒Discount = 25/100 x 750

= 750/4

= 187.5

So, the price of the video game at store A = 750 – 187.5

= 562.5

Hence, at store A the video game is less expensive.

Let the marked price be x.

Discount percent = Discount / Marked price x 100

20 = Discount/x x100

Discount = 20/100 x x = 1/5x

Also,

Discount = Marked price − Sale price

1/5x = x - Rs 1600

x - (1/5)x = Rs 1600

(4/5)x = Rs 1600

x = Rs ( 1600 x 5/4 ) = Rs 2000

Thus, the marked price was Rs 2000.

Correct answer is (d) Rs 1100

(b) 350 km

From the question it is given that,

90% of x is 315 km, it can be written as, (90/100) × x = 315

x = (315 × 100)/90

x = 31500/90

x = 350 km

Given that, rate of atta, detergent and namkeen are 200, 371 and 153 respectively with discount % as 16%, 22.10% and 18.30% respectively.

We have, price = rate - discount

price of atta = 200- 16/100 x 100

= 200 - 32

= Rs.168

price of detergent = 371 - 22.10/100 x 100

= 371 - 81.991

= Rs.289

price of namkeen = 153 - 18.30/100 x 100

= 153 - 27.99

= Rs.185

⇒ total amount of the bill she has to pay = price of atta + price of detergent + price of namkeen

= 168 + 289 + 185

= Rs.582

(b) 1 year

Explanation: 

P = Rs.100000, R = 12% per annum compounded half-yearly.

Amount = Rs.112360

Since we know,

A = P (1+R/100)^T

112360 = 100000(1+12/100)^T

112360/100000 = (1+12/100)^T

(1.1236)¹ = (1.12) ^T

If we compare the base terms, 1.1236 is approximately equal to 1.12

Hence, T = 1 year.

Correct answer is  (b) 350 km

627000

Explanation: 

Investment amount = 600000

Loss in first year = 5%.

So, investment in first year = 600000 – (5/100) x 600000 

= 600000 – 30000 

= 570000

In second year, the gain is 10%.

So, net result = 570000 + (10/100) x 570000 

= 570000 + 57000 

= 627000

Rate – 10% and 1.5 years

If amount on the principal of 7 6000 is written as 6000 [1 + 5/100]³  of and compound interest payable half-yearly, then rate of interest per annum is 10% and time (in years) is 1 1/2 yr.

Correct answer is (d) Rs 350

Rs.80000

Explanation: 

Selling price of the article = ₹112000

Gain% = 40%

Say, x is the cost price of the article.

Since, cost price = selling price – profit % on cost price

Therefore, Selling price = cost price + profit % on cost price

Hence,

112000 = x + x × (40/100)

112000 = x + (2/5)x

112000 = 7x/5

x = (112000 × 5)/7

x = 80000

20/3%

Explanation: 

Say, the selling price of one geometry box = Rs.1

So, the selling price of 140 geometry boxes = 1 × 140 = Rs.140

Selling price of 10 geometry boxes = Rs.10

Loss = Rs. 10

Loss percentage = Loss/CP × 100

= 10/(140+10) × 100

= 10/150 × 100

= 20/3%